計算機二級C語言題庫之程序填空

計算機二級C語言題庫之程序填空計算機二級C語言題庫之程序填空找Armstrong（水仙花）數(shù)：371=3*3*3+7*7*7+1*1*1#include<stdio.h>#include<math.h>voidmain(){inti,a,b,c;for(i=100;i<=999;i++){a=i/100;_______1_______//b=i%100/10;c=i%10;if(________2________)//a*a*a+b*b*b+c*c*c==iprintf("%disaArmstrongnumber!\n",i);}}輸入1個整數(shù)后，輸出該數(shù)的位數(shù)。（例：輸入3214則輸出4，輸入-23156則輸出5）。#include<stdio.h>voidmain(){intn,k=0;scanf("%d",&n);while(_____1_____){//n!=0輸入的一個小寫字母，將字母循環(huán)后移5個位置后輸出。例如："a"變成"f"，"w"變成"b"。#include<stdio.h>voidmain(){charc;c=getchar();if(______1______)//c>='a'&&c<='u'c=c+5;elseif(c>='v'&&c<='z')______2______//c=(c-'a'+5)%26+'a';putchar(c);}將字符串s中所有的字符'c'刪除。#include<stdio.h>voidmain(){chars[80];inti,j;gets(s);for(i=j=0;______1______;i++)//s[i]!='\0'if(s[i]!='c'){s[j]=s[i];______2______//j++;}s[j]='\0';puts(s);}對x=1，2，……，10，求f(x)=x*x-5*x+sin(x)的最大值。#include<stdio.h>#include<math.h>#definef(x)x*x-5*x+sin(x)voidmain(){intx;floatmax;______1______//max=f(1);for(x=2;x<=10;x++)______2______//if(f(x)>max)max=f(x);printf("%f\n",max);}輸入三個整數(shù)，按由小到大的順序輸出這三個數(shù)。#include<stdio.h>voidswap(______1______)//int*pa,int*pb{/*交換兩個數(shù)的位置*/inttemp;temp=*pa;*pa=*pb;*pb=temp;}voidmain(){inta,b,c,temp;scanf("%d%d%d",&a,&b,&c);if(a>b)swap(&a,&b);if(b>c)swap(&b,&c);if(______2______)//if(a>b)swap(&a,&b);printf("%d,%d,%d",a,b,c);}調(diào)用函數(shù)f，去除數(shù)組中的負數(shù)，輸入數(shù)組x[7]，輸出結(jié)果為：1346#include<stdio.h>//數(shù)組元素的刪除voidf(int*a,int*m){inti,j;for(i=0;i<*m;i++)if(a[i]<0){for(j=i--;j<*m-1;j++)a[j]=a[j+1];_____1_____;//*m=*m-1;}}voidmain(){inti,n=7,x[7]={1,-2,3,4,-5,6,-7};_______2_______;//f(x,&n);for(i=0;i<n;i++)printf("%5d",x[i]);printf("\n");}調(diào)用函數(shù)f計算代數(shù)多項式1.1+2.2*x+3.3*x*x+4.4*x*x*x+5.5*x*x*x*x當(dāng)x=1.7時的值。#include<stdio.h>floatf(float,float*,int);voidmain(){floatb[5]={1.1,2.2,3.3,4.4,5.5};printf("%f\n",f(1.7,b,5));}floatf(_______1________)//floatx,float*a,intn{floaty=a[0],t=1;inti;for(i=1;i<n;i++){t=t*x;y=y+a[i]*t;}_____2_____//returny;}分別統(tǒng)計字符串中英文字母、數(shù)字、和其他字符出現(xiàn)的次數(shù)。#include<stdio.h>#include<ctype.h>voidmain(){chara[80];intn[3]={0},i;gets(a);________1________//for(i=0;a[i]!='\0';i++){if(tolower(a[i])>='a'&&tolower(a[i])<='z')/*統(tǒng)計字母個數(shù)*/n[0]++;elseif(________2________)/*統(tǒng)計數(shù)字個數(shù)*///a[i]>='0'&&a[i]<='9'n[1]++;elsen[2]++;}for(i=0;i<3;i++)printf("%d\n",n[i]);}將輸入的十進制整數(shù)n通過函數(shù)DtoH函數(shù)轉(zhuǎn)換為十六進制數(shù)，并將轉(zhuǎn)換結(jié)果以字符串形式輸出。（例如：輸入十進制數(shù)79，將輸出十六進制4f。）#include<stdio.h>#include<string.h>chartrans(intx){if(x<10)return'0'+x;else_______1________//return'a'+x-10;}intDtoH(intn,char*str){inti=0;while(n!=0){________2________//str[i]=trans(n%16);n/=16;i++;}returni-1;}voidmain(){inti,k,n;char*str;scanf("%d",&n);k=DtoH(n,str);for(i=0;i<=k;i++)printf("%c",str[k-i]);}將輸入的十進制正整數(shù)n通過函數(shù)Dec2Bin轉(zhuǎn)換為二進制數(shù)，并將轉(zhuǎn)換結(jié)果輸出。#include<stdio.h>voidDec2Bin(intm){intbin[32],j;for(j=0;m!=0;j++){bin[j]=______1______;//m%2m=m/2;}for(;j!=0;j--)printf("%d",______2______);//bin[j-1]}voidmain(){intn;scanf("%d",&n);Dec2Bin(n);}數(shù)列的第1、2項均為1，此后各項值均為該項前二項之和。計算數(shù)列第30項的值。#include<stdio.h>_______1______//longf(intn);或者longf(int);voidmain(){printf("%ld\n",f(30));}longf(intn){if(______2______)//n==1||n==2return1;elsereturnf(n-1)+f(n-2);}該程序計算四位學(xué)生的平均成績，保存在結(jié)構(gòu)中，然后列表輸出這些學(xué)生的信息。#include<stdio.h>structSTUDENT{charname[16];intmath;intenglish;intcomputer;intaverage;};voidGetAverage(structSTUDENT*pst)/*計算平均成績*/{intsum=0;sum=______1______;//pst->math+pst->english+pst->computerpst->average=sum/3;}voidmain(){inti;structSTUDENTst[4]={{"Jessica",98,95,90},{"Mike",80,80,90},{"Linda",87,76,70},{"Peter",90,100,99}};for(i=0;i<4;i++){GetAverage(______2______);//st+i}printf("Name\tMath\tEnglish\tCompu\tAverage\n");for(i=0;i<4;i++){printf("%s\t%d\t%d\t%d\t%d\n",st[i].name,st[i].math,st[i].english,st[i].computer,st[i].average);}}輸入m、n（要求輸入數(shù)均大于0）。輸出它們的最大公約數(shù)。#include<stdio.h>voidmain(){intm,n,k;while(scanf("%d%d",&m,&n),______1______);//m<=0||n<=0for(___2___;n%k!=0||m%k!=0;k--);//k=m>n?n:mprintf("%d\n",k);}求出a中各相鄰兩個元素的和，并將這些和存放在數(shù)組b中，按每行3個元素的形式輸出。例如：b[1]=a[0]+a[1]，……，b[9]=a[8]+a[9]。#include<stdio.h>voidmain(){inta[10],b[10],i;printf("\nInput10numbers:");for(i=0