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專題18函數(shù)背景下的不等式問(wèn)題考點(diǎn)一利用圖像解不等式一、單選題1.函數(shù)f(x)的圖象如圖所示,則SKIPIF1<0的解集為(

)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<02.已知函數(shù)SKIPIF1<0的圖像如圖所示,則不等式SKIPIF1<0的解集是(

)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<03.已知函數(shù)SKIPIF1<0,若SKIPIF1<0,則實(shí)數(shù)SKIPIF1<0的取值范圍是(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.[0,1]4.若關(guān)于SKIPIF1<0的不等式SKIPIF1<0在SKIPIF1<0上有解,則實(shí)數(shù)SKIPIF1<0的取值范圍是(

)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<05.已知函數(shù)SKIPIF1<0滿足SKIPIF1<0若SKIPIF1<0,則實(shí)數(shù)SKIPIF1<0的取值范圍是(

)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<06.已知定義在R上的奇函數(shù)SKIPIF1<0在SKIPIF1<0上的圖象如圖所示,則不等式SKIPIF1<0的解集為(

)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<07.已知函數(shù)SKIPIF1<0,則SKIPIF1<0的解集為(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<08.定義:設(shè)不等式SKIPIF1<0的解集為M,若M中只有唯一整數(shù),則稱M是最優(yōu)解.若關(guān)于x的不等式SKIPIF1<0有最優(yōu)解,則實(shí)數(shù)m的取值范圍是(

)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<09.定義在SKIPIF1<0上函數(shù)SKIPIF1<0滿足SKIPIF1<0,SKIPIF1<0.當(dāng)SKIPIF1<0時(shí),SKIPIF1<0,則下列選項(xiàng)能使SKIPIF1<0成立的為(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<010.定義在SKIPIF1<0上的函數(shù)SKIPIF1<0滿足SKIPIF1<0,SKIPIF1<0時(shí)SKIPIF1<0,若SKIPIF1<0的解集為SKIPIF1<0,其中SKIPIF1<0,則實(shí)數(shù)SKIPIF1<0的取值范圍為(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<011.已知函數(shù)SKIPIF1<0,若滿足SKIPIF1<0的整數(shù)解恰有3個(gè),則實(shí)數(shù)SKIPIF1<0的范圍為(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0二、多選題12.若SKIPIF1<0,則下列選項(xiàng)可能成立的是(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<013.函數(shù)SKIPIF1<0,若不等式SKIPIF1<0恒成立,則a的值可以為(

)A.SKIPIF1<0 B.SKIPIF1<0 C.1 D.SKIPIF1<014.已知函數(shù)SKIPIF1<0是定義在SKIPIF1<0上的奇函數(shù),當(dāng)SKIPIF1<0時(shí),SKIPIF1<0的圖象如圖所示,那么滿足不等式SKIPIF1<0的x的可能取值是(

).A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.2三、填空題15.若函數(shù)SKIPIF1<0定義在SKIPIF1<0上的奇函數(shù),且在SKIPIF1<0上是增函數(shù),又SKIPIF1<0,則不等式SKIPIF1<0的解集為_(kāi)____________16.不等式SKIPIF1<0的解集為_(kāi)_______.17.已知函數(shù)SKIPIF1<0,則不等式SKIPIF1<0的解集是______.18.已知函數(shù)SKIPIF1<0若函數(shù)SKIPIF1<0有四個(gè)不同的零點(diǎn)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0的取值范圍是________.考點(diǎn)二利用函數(shù)性質(zhì)解不等式1.奇函數(shù)SKIPIF1<0在定義域SKIPIF1<0上是減函數(shù),若SKIPIF1<0,則SKIPIF1<0的取值范圍是(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.已知SKIPIF1<0為定義在SKIPIF1<0上的奇函數(shù),SKIPIF1<0,若SKIPIF1<0總有SKIPIF1<0.則不等式SKIPIF1<0的解集為(

)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<03.已知函數(shù)SKIPIF1<0,則關(guān)于x的不等式SKIPIF1<0的解集為(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<04.已知函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0,SKIPIF1<0,對(duì)任意SKIPIF1<0,SKIPIF1<0,則不等式SKIPIF1<0的解集為(

)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<05.已知函數(shù)SKIPIF1<0在SKIPIF1<0上為奇函數(shù),則不等式SKIPIF1<0的解集滿足(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<06.已知函數(shù)SKIPIF1<0若對(duì)任意的SKIPIF1<0,存在SKIPIF1<0,使SKIPIF1<0,則實(shí)數(shù)SKIPIF1<0的取值范圍是(

)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<07.設(shè)函數(shù)SKIPIF1<0在定義域SKIPIF1<0上滿足SKIPIF1<0,若SKIPIF1<0在SKIPIF1<0上是減函數(shù),且SKIPIF1<0,則不等式SKIPIF1<0的解集為(

)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<08.已知定義域?yàn)镾KIPIF1<0的奇函數(shù)SKIPIF1<0的圖象是一條連續(xù)不斷的曲線,當(dāng)SKIPIF1<0時(shí),SKIPIF1<0,當(dāng)SKIPIF1<0時(shí),SKIPIF1<0,且SKIPIF1<0,則關(guān)于SKIPIF1<0的不等式SKIPIF1<0的解集為(

)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<09.已知函數(shù)SKIPIF1<0是定義在SKIPIF1<0上的偶函數(shù),其導(dǎo)函數(shù)為SKIPIF1<0,當(dāng)SKIPIF1<0時(shí),SKIPIF1<0,且SKIPIF1<0,則不等式SKIPIF1<0的解集是(

)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<010.已知函數(shù)SKIPIF1<0,對(duì)任意的SKIPIF1<0,都有SKIPIF1<0,當(dāng)SKIPIF1<0時(shí),SKIPIF1<0,若SKIPIF1<0,則實(shí)數(shù)SKIPIF1<0的取值范圍為(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<011.已知函數(shù)SKIPIF1<0,若SKIPIF1<0,不等式SKIPIF1<0恒成立,則正實(shí)數(shù)SKIPIF1<0的取值范圍為(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<012.已知函數(shù)SKIPIF1<0,若對(duì)任意正數(shù)SKIPIF1<0,SKIPIF1<0,都有SKIPIF1<0恒成立,則實(shí)數(shù)SKIPIF1<0的取值范圍為(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<013.已知實(shí)數(shù)SKIPIF1<0,SKIPIF1<0,且滿足SKIPIF1<0恒成立,則SKIPIF1<0的最小值為(

)A.2 B.1 C.SK

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