c語言物業(yè)管理系統(tǒng)

1、#in clude #in clude #in clude #ifdef _GNUC_ #in clude #in clude #defi ne clear clear #defi ne Sleep(x) usleep(x#OOO) #en dif #ifdef _MSC_VER #in clude #in clude #defi ne clear system(cls) #en dif #defi ne TRUE 1 #defi ne FAUSE 0 typedef struct per char n ame20; int sex; char IDcard19; char pho ne12;

2、 int build_ num; int unit_num; int house_ num; float area; float area_price; float charge; char remarks200; struct per *n ext; PERSON; void zhuce (); in t logi n (); PERSON *Getdata (FILE *fp); void add_pers on (); void del (PERSON *L); void change (PERSON *L); void sort_All (PERSON *L); void pay (P

3、ERSON *L); void sort_B_num (PERSON *L); void menu_1 (); void menu_2 (); int mai n () int check,a; prin tf(t* * Welcome !*); printf(ntt1. 注冊); printf(ntt2.登錄); printf(nttO.退出); printf(nt-請輸入-:); scan f(%d, clear; switch(a) case 0: printf(tt-感謝使用本系統(tǒng)！-); Sleep(2000); exit(0); case 1: zhuce(); clear; ch

4、eck = logi n(); while (check = FAUSE) printf(n用戶名或密碼錯誤。); Sleep(2000); clear; check = logi n(); clear; menu _1(); break; case 2: check = logi n(); while (check = FAUSE) printf （n用戶名或密碼錯誤。）; Sleep(2000); clear; check = logi n(); clear; menu _1(); break; return 0; void menu_1 () FILE *fp; int a; PERSO

5、N *head = NULL; * 歡迎使用 *“ ); printf(ntt1.用戶添加); printf(ntt2.用戶修改); printf(ntt3.用戶刪除); prin tf(ntt4.用戶費用信息查看); printf(ntt5.用戶繳費); printf(nttO.退出); printf(nt-請輸入-:); scan f(%d, clear; switch(a) case 0: printf(-感謝使用!-); Sleep(3000); exit(0); case 1: add_pers on(); menu _1(); break; case 2: soogd 2S 嚴粵懸

6、叵史w怒=)tu_d (HnN hh peII)七 MdMelepooH pe i| M=q=-=rop.erop=)ued04 H e In Seo 宀 三 eaiq oCXIInu tu else pay(head); menu _1(); break; void menu_2 () FILE *fp; int a; PERSON *head = NULL; * 用戶信息查看 * ); prin tf（ntt1.按樓號查看用戶物業(yè)費情況”）； prin tf（ntt2.按費用信息查看用戶物業(yè)費情況）; printf（nttO.退出）; printf(nt-請輸入-:); scan f(%d

7、, clear; switch(a) case 0: printf(感謝使用); Sleep(3000); exit(0); case 1: fp = fope n(data.dat,rb); head = Getdata(fp); if (head = NULL) printf(沒有任何數(shù)據(jù)); Sleep(3000); exit(1); else sort_B_ nu m(head); menu _2(); break; case 2: fp = fope n(data.dat,rb); head = Getdata(fp); if (head = NULL) printf(沒有任何數(shù)據(jù))

8、; Sleep(3000); exit(1); else printf(tt-所有用戶物業(yè)費情況-n); sort_All(head); menu _2(); break; void zhuce () FILE *fp; char ad50,key050,key150; char ch; int i,j; * 用戶注冊 ); printf（nt-請輸入用戶名：”）; scan f(%s,ad); while (1) i = 0; j = 0; printf(nt-請輸入密碼:); /in itscr(); /no echo(); while (ch = getch() != r) if (ch

9、 = 8) prin tf(b ); putchar(b); if (i 0) i-； else putchar(*); /fflush(stdout); keyOi+ = ch; /endwin(); keyOi = 0; printf(nt-請再次輸入密碼：”)； /in itscr(); /no echo(); while (ch = getch() != r) if (ch = 8) prin tf(b ); putchar(b); if (j 0) j-; else putchar(*); key1j+ = ch; /endwin(); key1j = 0; if (strcmp(k

10、ey0,key1) != 0) clear; prin tf(%d,strcmp(key0,key1); printf(t-兩次輸入密碼不符，請重新輸入-); Sleep(2000); clear; else printf(n-用戶 s 注冊成功！-,ad); Sleep(3000); fp = fopen (adm in. txt,a); fprin tf(fp,%sn ”,ad); fclose(fp); fp = fope n(key.txt,a); fprin tf(fp,%sn,keyO); fclose(fp); break; in t logi n () FILE *fp1,*f

11、p2; char ad50,key50; char ch_150,ch_250,ch_0; int i = 0,check = 0; prin tf(tt* * printf(ntt- 用戶名-); scan f(%s,ad); printf(ntt- 密碼-); /ini tscr(); while (ch_0 = getch() != r) if (ch_0 = 8) prin tf(b ); putchar(b); if (i 0) i-; 用戶登錄 *“ ); else putchar(*); keyi+ = ch_0; keyi = 0： / endwin(); fp1 = fope

12、 n( admi n. txt,r); fp2 = fope n(key.txt,廣)； while (!feof(fp1) fscan f(fp1,%s,ch_1); fscan f(fp2,%s,ch_2); /prin tf(%s,ch_1); /prin tf(%s,ch_2); if (strcmp(ad,ch_1) = 0) if (strcmp(key,ch_2) = 0) check = TRUE; break; fclose(fp1); fclose(fp2); retur n check; PERSON *Getdata (FILE *fp) PERSON *head =

13、NULL; PERSON *p1,*p2; p1 = (PERSON*)malloc(sizeof(struct per); while (fread(p1,sizeof(struct per),1,fp) = 1) /prin tf(%s,p1- name); if (head = NULL) head = p2 = p1; else p2 - next = p1; p2 = p1; pl = pl - n ext; pl = (PERSON*)malloc(sizeof(struct per); p2 - next = NULL; free(p1); retur n head; void

14、save (PERSON *head) FILE *fp; PERSON *p; fp = fope n(data.dat,wb+); p = head; while (p != NULL) fwrite(p,sizeof(struct per),1,fp); p = p - n ext; fclose(fp); void add_pers on () PERSON *p1,*p2; PERSON *head = NULL; int n; prin tf(ntt* * 用戶添加 * ); while (1) p1 = (PERSON*)malloc(sizeof(struct per); 樓號

15、 printf(nn請輸入用戶信息：姓名 性別(0.女性;1.男性)身份證 聯(lián)系方式 單元號房號平米數(shù)每平米價格備注nn ”)； scan f(%s,(*p1). name); scan f(%d, scan f(%s,(*p1).IDcard); scan f(%s,(*p1).pho ne); scan f(%d, scan f(%d， scan f(%d, scan f(%f, scan f(%f, scan f(%s,(*p1).remarks); (*p1).charge = (*p1).area * (*p1).area_price * (-1); if (head = NULL)

16、 head = p2 = p1; else p2 _n ext = p1; p2 = p1; printf(nt-用戶添加成功！-); printf(n 是否繼續(xù)添加(1.是;0.否); scan f(%d, if (n = 0) break; p1 = p1 - n ext; p2 - next = NULL; save(head); void del (PERSON *L) PERSON *head,*p1,*p2; PERSON *p; char name20,ID19; int k = 0; int n; p = (PERSON*)malloc(sizeof(struct per);

17、p - next = head = L; while (1) p1 = p; printf(請輸入所要刪除的用戶姓名及身份證號n-); scan f(%s %s, name,ID); while (p1 - next != NULL) if (strcmp( name,p1- n ext- n ame) = 0 p1 - n ext = p2 - n ext; free(p2); k = 1; break; pl = pl - n ext; head = p - n ext; if (k = 0) printf(nt-沒有相關用戶！-); else printf(nt刪除用戶-%s 戒功！ ,

18、name); printf(n是否繼續(xù)刪除(1是;0否); scan f(%d, if (n = 0) break; save(head); void change (PERSON *L) char name20,ID19; PERSON *p; int n ,k = 0; while (1) p = L; printf(-請輸入所需修改用戶的姓名及身份證-n-); sca nf(%s, name); scan f(%s,ID); while (p - next != NULL) if (strcmp(p - n ame ,n ame) = 0 break; p = p - n ext; if

19、 (k = 0) printf(沒有查找到該用戶，是否重新輸入(1.是;0.否)n-); scan f(%d, if (n != 1) break; else clear; printf(t-請輸入用戶 -%s -修改后信息-,p - name); 每平米 printf(”姓名性別身份證聯(lián)系方式樓號單元號房號平米數(shù) 價格 備注”)； scan f(%s,(*p). name); scan f(%d, scan f(%s,(*p).IDcard); scan f(%s,(*p).pho ne); scan f(%d, scan f(%d, scan f(%d, scan f(%f, scan f

20、(%f, scan f(%s,(*p).remarks); (*p).charge = (*p).area * (*p).area_price; printf(修改用戶成功n是否繼續(xù)修改(1.是;0.否); scan f(%d, if (n != 1) break; save(L); void pay (PERSON *L) char name20,ID19; PERSON *head,*p; int n ,k = 0; float mon ey; head = L; while (1) printf(-請輸入所需繳費的用戶及身份證-n-); scan f(%s %s, name,ID); p

21、 = head; while (p - next != NULL) if (strcmp(p - n ame ,n ame) = 0 break; p = p - n ext; if (k = 0) (1.是 ;0.否)n-); printf(”沒有查找到該用戶，是否重新輸入 scan f(%d, if (n != 1) break; else printf(請輸入繳費金額:n-); scan f(%f, p - charge += mon ey; printf(是否繼續(xù)繳費(1.是;0否); scan f(%d, if (n != 1) break; save(head); void sor

22、t_AII (PERSON *L) PERSON *p; PERSON s20,a; int n = 0; int i,j; p = L; while (p - next != NULL) strcpy(s n. name,p - n ame); sn .sex = p - sex; strcpy(s n.l Dcard,p - IDcard); strcpy(s n.ph on e,p - phon e); sn .build_ num = p - build_ num; sn .u nit_num = p - unit_num; sn .house_ num = p - house_ nu

23、m; sn .area = p - area; sn .area_price = p - area_price; sn charge = p - charge; strcpy(s n.remarks,p - remarks); n+; p = p - n ext; for (i = 0; i n; i+) for (j = i+1; j sj.charge) strcpy(a .n ame,sj. n ame); a.sex = sj. sex; strcpy(a .I Dcard,sj. IDcard); strcpy(a.ph on e,sj.ph on e); a.build_ num

24、= sj.build_ num; a.unit_num = sj. unit_num; a.house_ num = sj. house_ num; a.area = sj. area; a.area_price = sj.area_price; a.charge = sj. charge; strcpy(a.remarks,sj.remarks); strcpy(sj. name,si. name); sn .sex = si.sex; strcpy(sj.IDcard,si.IDcard); strcpy(sj.ph on e,si.ph on e); sj.build_ num = si

25、.build_ num; sj.u nit_num = si.u nit_num; sj.house_ num = si.house_ num; sj.area = si.area; sj.area_price = si.area_price; sj.charge = si.charge; strcpy(s n .remarks,si.remarks); strcpy(si. name,a .n ame); si.sex = a.sex; strcpy(si.IDcard,a .I Dcard); strcpy(si.ph on e,a.ph on e); si.build_ num = a.

26、build_ num; si.u nit_num = a.unit_num; si.house_ num = a.house_ num; si.area = a.area; si.area_price = a.area_price; si.charge = a.charge; strcpy(s n.remarks,a.remarks); printf(姓名性別 平米價格費用情況 身份證 備注); 聯(lián)系電話 樓號單元號房號平米數(shù)每 for (i = 0; i next != NULL) if (p - build_ num = 1 ai.sex = p - sex; strcpy(ai.IDcard,p - IDcard); strcpy(ai.ph on e,p - phon e); ai.build_ num = p - build_ num; ai.u nit_num = p - unit_num; ai.house_ num = p - house_ num; ai.area = p - area; ai.area_price = p - are