C語言程序設(shè)計100例

1、C語言程序設(shè)計100例（2）MIME-Version: 1.0 Content-Location: file:/C:/0917AA32/anli02.htmContent-Transfer-Encoding: quoted-printable Content-Type: text/html;charset=us-ascii經(jīng)典 c 程序 100 例 =3D=3D11-20【程序 11】題目：古 = 0856; 問題：有一對兔子 ? = 2; 從出生后第 3個月起每個月? = 7; 生一對兔子，小兔子 &= #38271; 到第三個月后每&= #20010;月又生一對兔子，= 551; 如兔子都

2、不死，問每 = ;個月的兔子總數(shù)為多 ？1. 程序分析：兔子 規(guī)律為數(shù)列 1,1,2,3,5,8,13,21 2. 程序源代碼：main()long f1,f2;int i;f1=3Df2=3D1;for(i=3D1;i=3D20;i+) printf(%12ld %12ld,f1,f2); if(i%2=3D=3D0) printf(&qu=ot;n);/* 控制輸出，每 ?= 92; 四個*/f1=3Df1+f2; /*= 069; 兩個月加起來賦值給 = ; 第三個月 */f2=3Df1+f2; /*= 069; 兩個月加起來賦值給 = ; 第三個月 */=3D=3D=3D=3D=3D=

3、3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D【? = 3; 序 12】題目：判 = 6029;101-200 之間有多少個 = 素數(shù)，并輸出所有素 = 5968; 。1.程序分析：判斷素 的方法：用一個數(shù)分別去 ? = 0;2 到 sqrt（ 這個= ; 數(shù)），如 果能被整 ? = 0; ，= 則表明此

4、數(shù)不是素 = 968; ，反之是素數(shù)。2. 程序源代碼：#include math.hmain()int m,i,k,h=3D0,leap=3D1;printf(n);for(m=3D101;m=3D200;m+) k=3Dsqrt(m+1);for(i=3D2;i=3Dk;i+)if(m%i=3D=3D0)= leap=3D0;break;if(leap) printf(%-4d,m);h+;=if(h%10=3D=3D0)=printf(n);= leap=3D1;printf(nThe total is %d,h); =3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3

5、D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D【? = 3; 序 13】題目：打 = 1360; 出所有的“水仙花數(shù)”，所謂“水仙花數(shù)”是指一個三位數(shù) 其各位數(shù)字立方和等于該 ? = 8;本身&= #12290;例如：153是一個“水仙花數(shù)”，因為 153= =3D1的三次方+ 5的三次方 3 的三次方。1. 程序分析：利用 for 循環(huán)控制

6、 1= 00-999 個數(shù)，每個數(shù)分解出? = 0; 位，十位，百位。2. 程序源代碼：main()int i,j,k,n;printf(water flowernumber is:);for(n=3D100;n1000;n+)i=3Dn/100;/* 分?= 9; 出百位 */j=3Dn/10%10;/* 分#= 299; 出十位 */k=3Dn%10;/* 分解= ; 出個位 */if(i*100+j*10+k=3D=3Di*i*i+j*j*j+= k*k*k)printf(%-5d,n);printf(n);=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=

7、3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D【? = 3; 序 14】題目：將 = 9968; 個正整數(shù)分解質(zhì)因 ? = 8; 。例如：輸入 90, 打印出 90=3D2*3*= 3*5 。程分析：對n進行分解質(zhì)因？ = 8;，應(yīng)先找到一個最小 &= #30340;質(zhì)數(shù)k,然后按下述 ? = 3; 驟完成：(1)如果這個質(zhì)數(shù)恰等 &= #20110;

8、n ,則說明分解 ?= 6;因數(shù)的過程已經(jīng)結(jié)束 &= #65292;打印出即可。如果nk, e =94;n能被k整=8500;，則應(yīng)打印出k的值，并用n除以k的商，作=0026;新的正整數(shù)你 n,重復(fù)執(zhí)行第一步 = 290;如果n不能？ = 7;k整除，則用k+1作為k的值，重=2797;執(zhí)行第一步。2. 程序源代碼：/* zheng int is divided yinshu*/main()int n,i;printf(nplease input a number:n);scanf(%d,&n);printf(%d=3D,n);for(i=3D2;i=3Dn;i+)while(n!=3Di)

9、if(n%i=3D=3D0) printf(%d*,i);n=3Dn/i;elsebreak;printf(%d,n);=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D【? = 3; 序 15】題目：利 = 9992;條件運算符的嵌套? = 9;完成此題：學(xué)習(xí)成績 =3D90

10、分的同學(xué)用A表示，60-89分之間的用B表示，60分以下的用C表示。1. 程序分析： (ab= )?a:b 這是 = 6465; 件運算符的基本例 ? = 6; 。2. 程序源代碼：main()int score;char grade;printf(please input a scoren= );scanf(%d,&score);grade=3Dscore=3D90?A:(score=3D6= 0?B:C);printf(%d belongs to %c,score,grade);=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3

11、D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D【? = 3; 序 16】題目：輸=0837;兩個正整數(shù) m和n,求=0854;最大公約數(shù)和最??？= 4;倍數(shù)。1. 程序分析：利用輾除法。2. 程序源代碼： =main()int a,b,num1,num2,temp;printf(please input two numbers:n);scanf(%d,%d,&num1,&nu= m2

12、);if(num1 temp=3Dnum1;num1=3Dnum2;num2=3Dtemp;a=3Dnum1;b=3Dnum2;while(b!=3D0)/* 利用輾除法， ?= 52; 到 b 為 0 為止 */temp=3Da%b;a=3Db;b=3Dtemp;prin tf(go ngyueshu:%dn,a);prin tf(go ngbeishu:%dn, nu m1* nu m2/a);=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D

13、=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D【？ = 3;序17】題目：輸=0837; 一行字符，分別統(tǒng)？= 5;出其中英文字母、空 &= #26684;、數(shù)字和其它字符-=340;個數(shù)。1. 程序分析：利用 while語句,條=;件為輸入的字符不為 2._程序源代碼:#in clude stdio.hmain ()char c;int letters=3D0,space=3D0,digit=3D0,other= s=3D0;prin tf(please in pu

14、t some charactersn);whileKcPDgetcharOypDVT)if(c=3Da&c= ;=3DA &c=3DO&c=3D9)=digit+;elseothers+;prin tf(all in all:char=3D%d space=3D%d digit=3D%d others=3D%dn= letters,space,digit,others);=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3

15、D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D【？ = 3;序18】題目：求 s=3Da+aa+aaa+aaaa+aa.a_的值，其 =；中 a 是一個數(shù)字。？=3;女n2+22+222+2222+22222(此時=共有5 個數(shù)相力n )，幾個數(shù)相加有鍵?= 4; 控制。1. 程序分析：關(guān)鍵是 算出每一項的值。2. 程序源代碼：main ()int a,n,coun t=3D1;long int sn=3D0,tn=3D0;prin tf(please in put a and nn=);sca

16、nf(%d,%d,&a,&n);prin tf(a=3D%d, n=3D%dn,a, n)；v= brwhile(count=3Dn)tn=3Dt n+a;sn=3Ds n+tn;a=3Da*10;+count;printf(a+aa+.=3D%ldn,sn);卜-3D-3D-3D-3D-3D-3D-3D-3D-3D-3D-3D-3D-3D-3D-3D-3D-3D-3D-3D-3D-3D-3D-3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=-3D-3D-3D-3D-3D-3

17、D-3D-3D-3D-3D=3D=3D【？ = 3序19】題目：一個數(shù)如果恰?= 9;等于它的因子之和,&= #36825;個數(shù)就稱為 “完數(shù)”。例如6=3D1+ 2 + 3.編程找出 1000_以內(nèi)的所=; 有完數(shù)。1. 程序分析；請參照 &= #31243;序 -上頁程序14.2. 程序源代碼;main ()static int k10;int i,j,n,s;for(j=3D2;j1000;j+)n=3D 1;s=3Dj;for(i=3D1;iJ;l+)if(j%i)=3D=3D0)n+;s=3Ds-i;kn =3Di;Tif(s=3D=3D0)prin tf(%d is a wan shu,j);for(i=3D0;iN;l+)printf(%d,ki);printf(%dn,kn);=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D【？ = 3序20】題冃；一 =9699;從100米高度自由