2016年電大C語言程序設計__期末考試試題及答案小抄參考

1、專業(yè)好文檔c+語言程序設計 期末考試試題及答案姓名 _ 學號 _ 班號 _ 題 號一二（1）二（2）三總 分成 績一、填空1在類中必須聲明成員函數(shù)的 原型 ，成員函數(shù)的 實現(xiàn) 部分可以寫在類外。2如果需要在被調(diào)函數(shù)運行期間，改變主調(diào)函數(shù)中實參變量的值，則函數(shù)的形參應該是 引用 類型或 指針 類型。3 抽象 類只能作為基類使用，而不能聲明它的對象。4進行函數(shù)重載時，被重載的同名函數(shù)如果都沒有用const修飾，則它們的形參 個數(shù) 或 類型 必須不同。5通過一個 常 對象只能調(diào)用它的常成員函數(shù)，不能調(diào)用其他成員函數(shù)。6函數(shù)的遞歸調(diào)用是指函數(shù)直接或間接地調(diào)用 自身 。7拷貝構(gòu)造函數(shù)的形參必須是 本類對

2、象的引用 。二、閱讀下列程序，寫出其運行時的輸出結(jié)果 如果程序運行時會出現(xiàn)錯誤，請簡要描述錯誤原因。1請在以下兩題中任選一題，該題得分即為本小題得分。如兩題都答，則取兩題得分之平均值為本小題得分。（1）程序：- 12 -#include <iostream.h>#include <string.h>class base private: char msg30; protected: int n; public: base(char s,int m=0):n(m) strcpy(msg,s); void output(void) cout<<n<<

3、endl<<msg<<endl; ;class derived1:public baseprivate:int n;public:derived1(int m=1):base("base",m-1) n=m; void output(void) cout<<n<<endl; base:output();class derived2:public derived1private:int n;public:derived2(int m=2):derived1(m-1) n=m; void output(void) cout<

4、<n<<endl; derived1:output();int main()base b("base class",1);derived2 d;b.output();d.output();運行結(jié)果：1base class210base（2）程序：#include <iostream.h>class samppublic:void setij(int a,int b)i=a,j=b;samp()cout<<"destroying."<<i<<endl;int getmuti()return

5、i*j; protected:int i;int j;int main()samp *p;p=new samp5;if(!p)cout<<"allocation errorn"return 1;for(int j=0;j<5;j+)pj.setij(j,j);for(int k=0;k<5;k+)cout<<"muti"<<k<<" is:" <<pk.getmuti()<<endl;deletep;return 0;運行結(jié)果：muti0 is:0mu

6、ti1 is:1muti2 is:4muti3 is:9muti4 is:16destroying.4destroying.3destroying.2destroying.1destroying.02請在以下兩題中任選一題，該題得分即為本小題得分。如兩題都答，則取兩題得分之平均值為本小題得分。（1）程序：#include <iostream.h>#include <stdlib.h>class vector public: vector(int s=100); int& elem(int ndx); void display(void); void set(vo

7、id); vector(void); protected: int size; int *buffer;vector:vector(int s)buffer=new intsize=s;int& vector:elem(int ndx)if(ndx<0|ndx>=size)cout<<"error in index"<<endl;exit(1);return bufferndx;void vector:display(void)for(int j=0; j<size; j+)cout<<elem(j)<&l

8、t;endl;void vector:set(void)for(int j=0; j<size; j+)elem(j)=j+1;vector:vector(void)delete buffer;int main()vector a(10);vector b(a);a.set();b.display();運行結(jié)果：12345678910最后出現(xiàn)錯誤信息，原因是：聲明對象b是進行的是淺拷貝，b與a共用同一個buffer，程序結(jié)束前調(diào)用析構(gòu)函數(shù)時對同一內(nèi)存區(qū)進行了兩次釋放。（2）程序：#include<iostream.h>class cat public: cat(); cat(

9、const &cat); cat(); int getage() return *itsage; void setage( int age ) *itsage=age; protected: int * itsage;cat:cat()itsage=new int;*itsage=5;cat:cat()delete itsage;itsage=null;int main()cat a;cout<<"a's age:"<<a.getage()<<endl;a.setage(6);cat b(a);cout<<&q

10、uot;a's age:"<<a.getage()<<endl;cout<<"b's age:"<<b.getage()<<endl;a.setage(7);cout<<"a's age:"<<a.getage()<<endl;cout<<"b's age:"<<b.getage()<<endl;運行結(jié)果：a's age:5a's age:6b&#

11、39;s age:6a's age:7b's age:7最后出現(xiàn)錯誤信息，原因是：聲明對象b是進行的是淺拷貝，b與a共用同一個buffer，程序結(jié)束前調(diào)用析構(gòu)函數(shù)時對同一內(nèi)存區(qū)進行了兩次釋放。三、閱讀下列程序及說明和注釋信息，在方框中填寫適當?shù)某绦蚨?，使程序完成指定的功?程序功能說明：從鍵盤讀入兩個分別按由小到大次序排列的整數(shù)序列，每個序列10個整數(shù)，整數(shù)間以空白符分隔。用這兩個序列分別構(gòu)造兩個單鏈表，每個鏈表有10個結(jié)點，結(jié)點的數(shù)據(jù)分別按由小到大次序排列。然后將兩個鏈表合成為一個新的鏈表，新鏈表的結(jié)點數(shù)據(jù)仍然按由小到大次序排列。最后按次序輸出合并后新鏈表各結(jié)點的數(shù)據(jù)。 程序

12、運行結(jié)果如下，帶下劃線部分表示輸入內(nèi)容，其余是輸出內(nèi)容：1 3 5 7 9 11 13 15 17 192 4 6 8 10 12 14 16 18 201 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20#include <iostream.h>#include <stdlib.h>/類定義部分template <class t>class node private: node<t> *next; /指向后繼節(jié)點的指針 public: t data; /數(shù)據(jù)域 node (const t&

13、 item, node<t>* ptrnext = null); / 構(gòu)造函數(shù) void insertafter(node<t> *p); /在本節(jié)點之后插入一個同類節(jié)點p node<t> *deleteafter(void); /刪除本節(jié)點的后繼節(jié)點,返回其地址 node<t> *nextnode(void) const; / 獲取后繼節(jié)點的地址;template <class t>class linkedlist private: node<t> *front, *rear; / 表頭和表尾指針 node<t&g

14、t; *prevptr, *currptr; /記錄表當前遍歷位置的指針,由插入和刪除操作更新 int size; / 表中的元素個數(shù) int position; / 當前元素在表中的位置序號。由函數(shù)reset使用 node<t> *getnode(const t& item,node<t> *ptrnext=null); / 生成新節(jié)點，數(shù)據(jù)域為item，指針域為ptrnext void freenode(node<t> *p); /釋放節(jié)點 void copylist(const linkedlist<t>& l); / 將鏈

15、表l 拷貝到當前表 /（假設當前表為空）。被拷貝構(gòu)造函數(shù)、operator=調(diào)用 public: linkedlist(void); / 構(gòu)造函數(shù) linkedlist(const linkedlist<t>& l); /拷貝構(gòu)造函數(shù) linkedlist(void); / 析構(gòu)函數(shù) linkedlist<t>& operator= (const linkedlist<t>& l);/重載賦值運算符 int listsize(void) const; /返回鏈表中元素個數(shù)（size） int listempty(void) const

16、; /size為0時返回true,否則返回false void reset(int pos = 0); /將指針currptr移動到序號為pos的節(jié)點， /prevptr相應移動,position記錄當前節(jié)點的序號 void next(void); /使prevptr和currptr移動到下一個節(jié)點 int endoflist(void) const; / currptr等于null時返回true, 否則返回false int currentposition(void) const; /返回數(shù)據(jù)成員position void insertfront(const t& item); /在

17、表頭插入一個數(shù)據(jù)域為item的節(jié)點 void insertrear(const t& item); /在表尾添加一個數(shù)據(jù)域為item的節(jié)點 void insertat(const t& item); /在當前節(jié)點之前插入一個數(shù)據(jù)域為item的節(jié)點 void insertafter(const t& item); /在當前節(jié)點之后插入一個數(shù)據(jù)域為item的節(jié)點 t deletefront(void); /刪除頭節(jié)點,釋放節(jié)點空間，更新prevptr、currptr和size void deleteat(void); /刪除當前節(jié)點,釋放節(jié)點空間，更新prevptr、cur

18、rptr和size t& data(void); / 返回對當前節(jié)點成員data的引用 void clearlist(void); / 清空鏈表：釋放所有節(jié)點的內(nèi)存空間。;/類實現(xiàn)部分略.template <class t>void mergelist(linkedlist<t>* la, linkedlist<t>* lb,linkedlist<t>* lc)/合并鏈表la和lb,構(gòu)成新鏈表lc。/函數(shù)結(jié)束后，程序的數(shù)據(jù)所占內(nèi)存空間總數(shù)不因此函數(shù)的運行而增加。 while ( !la->listempty() &&

19、!lb->listempty() if (la->data()<=lb->data() lc->insertrear(la->data(); la->deleteat(); else lc->insertrear(lb->data(); lb->deleteat(); while ( !la->listempty() ) lc->insertrear(la->data(); la->deleteat(); while ( !lb->listempty() ) lc->insertrear(lb-&g

20、t;data(); lb->deleteat();int main() linkedlist<int> la, lb, lc; int item, i;/讀如數(shù)據(jù)建立鏈表la for (i=0;i < 10;i+) cin>>item; la.insertrear(item); la.reset();/讀如數(shù)據(jù)建立鏈表lb for (i=0;i < 10;i+) cin>>item; lb.insertrear(item); lb.reset();mergelist(&la, &lb, &lc);/合并鏈表 lc.r

21、eset();/ 輸出各節(jié)點數(shù)據(jù)，直到鏈表尾 while(!lc.endoflist() cout <<lc.data() << " " lc.next(); / 使currptr指向下一個節(jié)點 cout << endl;"if we don't do that it will go on and go on. we have to stop it; we need the courage to do it."his comments came hours after fifa vice-president j

22、effrey webb - also in london for the fa's celebrations - said he wanted to meet ivory coast international toure to discuss his complaint.cska general director roman babaev says the matter has been "exaggerated" by the ivorian and the british media.blatter, 77, said: "it has been d

23、ecided by the fifa congress that it is a nonsense for racism to be dealt with with fines. you can always find money from somebody to pay them."it is a nonsense to have matches played without spectators because it is against the spirit of football and against the visiting team. it is all nonsens

24、e."we can do something better to fight racism and discrimination."this is one of the villains we have today in our game. but it is only with harsh sanctions that racism and discrimination can be washed out of football."the (lack of) air up there watch mcayman islands-based webb, the h

25、ead of fifa's anti-racism taskforce, is in london for the football association's 150th anniversary celebrations and will attend city's premier league match at chelsea on sunday."i am going to be at the match tomorrow and i have asked to meet yaya toure," he told bbc sport."

26、;for me it's about how he felt and i would like to speak to him first to find out what his experience was."uefa has opened disciplinary proceedings against cska for the "racist behaviour of their fans" during city's 2-1 win.michel platini, president of european

27、football's governing body, has also ordered an immediate investigation into the referee's actions.cska said they were "surprised and disappointed" by toure's complaint. in a statement the russian side added: "we found no racist insults from fans of cska."baumgartner t

28、he disappointing news: mission aborted.the supersonic descent could happen as early as sunda.the weather plays an important role in this mission. starting at the ground, conditions have to be very calm - winds less than 2 mph, with no precipitation or humidity and limited cloud cover. the balloon, w

29、ith capsule attached, will move through the lower level of the atmosphere (the troposphere) where our day-to-day weather lives. it will climb higher than the tip of mount everest (5.5 miles/8.85 kilometers), drifting even higher than the cruising altitude of commercial airliners (5.6 miles/9.17 kilo

30、meters) and into the stratosphere. as he crosses the boundary layer (called the tropopause),e can expect a lot of turbulence.the balloon will slowly drift to the edge of space at 120,000 feet ( then, i would assume, he will slowly step out onto something resembling an olympic diving platform.below,

31、the earth becomes the concrete bottom of a swimming pool that he wants to land on, but not too hard. still, he'll be traveling fast, so despite the distance, it will not be like diving into the deep end of a pool. it will be like he is diving into the shallow end.skydiver preps for the big jumpw

32、hen he jumps, he is expected to reach the speed of sound - 690 mph (1,110 kph) - in less than 40 seconds. like hitting the top of the water, he will begin to slow as he approaches the more dense air closer to earth. but this will not be enough to stop him completely.if he goes too fast or spins out

33、of control, he has a stabilization parachute that can be deployed to slow him down. his team hopes it's not needed. instead, he plans to deploy his 270-square-foot (25-square-meter) main chute at an altitude of around 5,000 feet (1,524 meters).in order to deploy this chute successfully, he will

34、have to slow to 172 mph (277 kph). he will have a reserve parachute that will open automatically if he loses consciousness at mach speeds.even if everything goes as planned, it won't. baumgartner still will free fall at a speed that would cause you and me to pass out, and no parachute is guarant

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50、wv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv

51、*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnugk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr

52、9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&

53、amp;gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z

54、89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqvadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z

55、89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wew

56、z#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cp

57、bk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz84!z89amv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vs

58、tt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&am

59、p;muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%madnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5