C++實現(xiàn)兩個復(fù)數(shù)相加(共4頁)

1、精選優(yōu)質(zhì)文檔-傾情為你奉上#include "iostream.h"#include <stdio.h>#include <math.h>typedef struct complexint real;int imaginary;void showComplex()if(imaginary=0)cout<<real;else if(real=0)cout<<imaginary<<"i"elsecout<<'('<<real<<'+'

2、;<<imaginary<<"i)"Complex;/運算符重載Complex operator + (Complex a,Complex b)Complex sum;sum.real=a.real+b.real;sum.imaginary=a.imaginary+b.imaginary;return sum;Complex getComplex()Complex com;com.real=0;com.imaginary=0;char comArr100;cin>>comArr;int realflag=0;int imaflag=-1;

3、int realover,ope,imaover,iloc;realover=ope=imaover=iloc=0;for(int i=0;comArri!='0'i+)/*/if(realflag=0 && comArri-'0'>=0 && comArri-'0'<=9)/默認(rèn)從實部開始計算com.real =com.real*10+comArri-'0'realover=i;/cout<<com.real<<endl;else if(comArri='

4、;+')realflag=1;/標(biāo)志輸入了'+'，表示實部計算完畢imaflag=0;/標(biāo)志可以開始計算虛部ope=i;else if(imaflag=0 && comArri-'0'>=0 && comArri-'0'<=9)/計算虛部com.imaginary =com.imaginary*10+comArri-'0'imaover=i;/cout<<com.imaginary<<endl;else if(comArri='i')ima

5、flag=1;/標(biāo)志虛部存在iloc=i;elsecout<<"輸入錯誤!默認(rèn)為0"<<endl;break;/realover=ope=imaover=iloc=0if(iloc!=0&&ope!=0)if(iloc+1=ope)/輸入時虛部在前實部在后int temp=com.imaginary;com.imaginary=com.real;com.real=temp;else if(realover-ope!=-1 | imaover<ope |imaover+1!=iloc)cout<<"輸入錯誤!

6、默認(rèn)為0"<<endl;com.imaginary=0;com.real=0;if(realflag=0 && imaflag=-1)/表示未檢查到輸入'i',表示無虛部com.imaginary=0;/表示未檢查輸入'+',但存在'i',說明無實部。把實部計算值賦值給虛部，實部清0else if(realflag=0 && imaflag=1)com.imaginary=com.real;com.real=0;return com;int main(int argc, char* argv)

7、Complex a;Complex b;Complex sum;cout<<"tt運算符重載，實現(xiàn)兩個復(fù)數(shù)求和n"<<endl;cout<<"輸入第一個復(fù)數(shù)(形如"6+2i")："<<flush;a=getComplex();/scanf("%d+%di",&a.real,&a.imaginary);cout<<"輸入第二個復(fù)數(shù)(形如"6+2i")："<<flush;b=getComplex();/scanf("%d+%di",&b.real,&b.imaginary);/a.real=3;/a.imaginary=4;/b.real=2;/b.imaginary=4;cout<<"這兩個復(fù)數(shù)的和為："<<endl;sum=a+b;a.showCompl