化工機(jī)械基礎(chǔ)第二版課后答案-陳國(guó)桓-主編匯總

1、第一篇習(xí)題參考答案F朋 cosl5°- (F坯 cos45° + P) = 0Fj 3打亍-耳心 cos 45° = 0 臉=蠱嘔=103KMFcos30°-C?= 0M = PLF滬 28.3KNP F cos60°= 0耳二qH巧二覽+場(chǎng)FJ costi- Fh- P(l- ci)coser = 0片=450/TF = 17.32rMFlcofx- FAr = 0均=150M3)©CF =P_A1-1F 二 HEMa -A二丸磁r2-2F = 0a = 01一1尹=F 二 103Pr =j4=4。購乙2-2F = 2P = 2OZ

2、2Vb =2P=旳皿 A1-1F 二 F 二 103pCF /二 MPa2-2F = P=10KNJb =-=AMPa1-12-2=149MFa'AF =P = KNF = 0a= 0<r =3-3 F = KN不能用虎克定律計(jì)算橫截面上的正應(yīng)力，因?yàn)榇藭r(shí)應(yīng)力已遠(yuǎn)遠(yuǎn)超岀彈性范圍b二扌二10(WH<b1.2.3.4.5.6.7.8.9.10.故，強(qiáng)度足夠11.12.廠一二 >in<r °竹匕= 44/7 3嘰 > 陷"1。甌-scn = 24備一 /Ccosa=0為= 203143 mm2= &94 刖切'2a = 30m

3、nld2=Ad =14mm13.p壬 QF)r-=33MPd <tf414.15.(a)(c)(g)A = 0.25 m2坤+'A4a2(e)(b)(d)(f)a - 250mn b =1000/TimT F i(h)9 q 116.(i)(k)(m)1 2= -t?r£+2fc + -H) =148.42 3M = 200 KN.m(l)man(j)(n)b= 4Qmmh =120初尬17.M = PL = 4KN.m18.N=0=11.514 cos30°19.M 二 N0-L5 = L73KHMMd"存5x1曠M = N«.15 =

4、lKNMMd所以，強(qiáng)度不夠20.= P(0.68 - 0.0S) = 4.KKNb護(hù)1221.9a =護(hù)2AEI48116 El=7.4mm現(xiàn)=0.00023OL = 0.0002322.廠Pp=90MPaP!=L AId2寓抗剪：'1抗擠：A23.P57KNr = =28JMP<r blg 禱-二 S3MPa <(?yx /2習(xí)題參考答案24.銷釘所受的的最大剪應(yīng)力為:572P!218xl03r2< T MPa= 49 8% 3.14x0,0163/4 '_銷釘所受的的最大擠壓應(yīng)力為:1S>c1030.016x0.003= 140MPa' 11

5、25.Mr =9550x -9550X A =1193.75ZA r2720_ H53.75KT' 31x10s3.851 xW5w5d = p = 57J5mrS癥。吟論。嗨W =(D4 -dK) = 14492.4乃即M口 1盟r = = 33MPa < M =WLQ27.強(qiáng)度足夠軸的外徑：1: I 'Mr -9550x -9550X A =132.5- r2740=162衛(wèi)偽< r= 50MPa28.強(qiáng)度足夠aj少R決只5%Mr -9550x_ -9550k±一一. - 5348* 怖 r«5吧=0.2/二闌3方觀/強(qiáng)度足夠29.計(jì)算主應(yīng)力

6、和方向的公式為:扌(疔十丐)十+於y十4嚇 匕十込十巧尸扌廟二歹忑將(a)(b)(c)各題帶入得:(a)CF = lMPa- -3MPa= 0(b)CF = lOOMPna2 = SOMPact0 = 0(c)cf1 = 21 旳 MPaa2 = -e.MPa % = 22,5習(xí)題參考答案30主應(yīng)力為:MPa2 = -(ccy)-受主應(yīng)力作用的單元體如下圖中的藍(lán)色線條所表示的:MPa31A點(diǎn)受彎矩和力的組合作用口彌=+ 昱 S <j = lOOMPdtT %A d2 - 1964w2«s2W7 = 785.5wiwi3其中，4, M W,丸代入上式得：I一 15予伽32本題為拉

7、扭組合. 最大剪應(yīng)力在圓軸的外圓周上：r - rMT - PR,Wp- 0 2(/5 0.2x303 5400? Wp最大的拉應(yīng)力作用在軸的上下邊緣處：b 竺，200匕 - 2651Wz32第三強(qiáng)度理論：宀心+ 4八創(chuàng)皿叼33Mr = 9550 x =9550x=120.2ZA'Mr = TR, T = = 120.2/125 = 0 962RM皿=377 = 346,22V旬M=58.3Wa第三強(qiáng)度理論:5X.4MPa < b第四強(qiáng)度理論:34j =304-1.12 fT42300»=7532g = 304 -1 AU = 220MPabfP = 220xlrf2 =177rAAlL*rurmJ"F 50所以，千斤頂穩(wěn)定35S =332 2-1.45«CT4M 413000“i 60d 200g = 332 2-1 4542 = 245CT篤m疔存£三24刃扌/ -屮）三4926/73需用