一些簡單的匯編程序

1、一些簡單的匯編程序集團文件發(fā)布號：（9816-UATWW-MWUB-WUNN-INNUL-DQQTY1編制程序計算S二1+2+3+4+N直到和大于 500為止，并將結果在屏幕上顯示出來（N的值 和最終的和的值）。DATA SEGMENTN DWSUM DWDATA ENDSCODE SEGMENTASSUME CS:CODE, DS:DATASTART:MOV AX, DATAMOV DS, AXMOV AX,0MOV BL,0El: INC BLADD AX,BXCMP AX, 500JBE ElMOV N, BXMOV SUM, AXE2:MOV AX, BXMOV BL, 10DIV B

2、LADD AL, 30HMOV DL, ALMOV CL, AHMOV AH, 2INT 21HADD CL, 30HMOV DL,CLMOV AH, 2INT 21HMOV AH, 2MOV DL,OAHINT 21HMOV AX, SUMCWDMOV BX, 100DIV BXMOVCX,DXADDAL,30HMOVDL,ALMOVAH,2INT21HMOVBL,10MOVAX,exDIVBLMOVCL,AHMOVAH,2ADDAL,30HMOVDL,ALINT21HMOVAH,2ADDCL,30HMOVDL,CLINT21HMOVAH,4CHINT21HCODE ENDSEND STAR

3、T 2.從鍵盤輸入學生成績（A、B、C、D）,自動 匯總并顯示各類分數(shù)的人數(shù)。按下S鍵則停止輸入；若按下A、B、C、D之外的鍵則提示 INPUT ERROR” 信息。DATA SEGMENTMl DB 'Please inputA,B,C,D:，13, 10,'S'M2 DB 13,10,'Input error!',13, 10,'S'M3DB13, 10,' ThenumberofAis:M4DB13, 10, 'ThenumberofBis ：M5DB13, 10, 'ThenumberofCis ：s,M6

4、DB13, 10,' ThenumberofDis：S'DATA ENDSSTACK SEGMENTSTACK ENDSCODE SEGMENTASSUME CS:CODE, DS:DATA, SS:STACKSTART:MOV AX, DATAMOV DS, AXMOV AH, 9MlMOV AH, 2ADC BL, 3OHMOV DL, BLINT 21HMOV AH, 9MOV DX, OFFSET M4INT 21HMOV AH, 2MOV DX, OFFSETINT 21HMOV BX, 0MOVCX, 0El:ADC BH,3OHMOVAH, 1MOV DL, BH

5、INT21HINT 21HMOVAH, 41HMOV AH, 9CMPAL, AHMOV DX,OFFSET M5JNZE2INT 21HINCBLMOV AH, 2JMPElADC CL, 3OHE2:MOV DL, CLMOVAH, 42HINT 21HCMPAH, ALMOV AH, 9JNZE3MOV DX, OFFSET M6INCBHINT 21HJMPElMOV AH, 2E3:ADC CH,3OHMOVAH,43HMOV DL, CHCMPAH, ALINT 21HJNZE4MOV AH, 4CHINCCLINT 21HJMPElCODE ENDSE4:END STARTMOV

6、AH, 44HCMPAH, AL3.動態(tài)輸入20個二位無符號數(shù)，找出其中最大JNZE5數(shù)并顯示。DATAS SEGMENTINCCHMl DB 'Please input 5JMPElnumbers:,13,10,'S'E5:M2 DB ' The biggest number is：S'MOVAH, 24HM3DB ' ', 13, 10,' S'CMPAH, ALMAX DWJZ E6DATAS ENDSMOVAH, 9STACKS SEGMENTMOVDX, OFFSETM2INT21HSTACKS ENDSJMPE

7、lE6:CODES SEGMENTMOVAH, 9ASSUME CS:CODES, DS:DATAS, SS:STACKSMOVDX, OFFSETM3START:INT21HMOV AX, DATASMOV DS, AXMOV MAX, 0LEA DX, MlMOV AH,9INT 21HMOV CL,5MOVAH, 1INT21HSUBAL, 30HMOVBH, ALMOVAH, 1INT21HSUBAL, 30HMOVBL, ALLEADX, M3MOVAH, 9INT21HCMPMAX, BXJNLEXITXCHG MAX, BX4.設數(shù)據(jù)區(qū)有兩個字符串，串1的長度為5,串2的長度為1

8、0。編程：若串2的最后5個字符和 吊1相同，則置FLAG單元為“Y”，否則置為“N” oDATAS SEGMENT51 DB 'DKJFDS'52 DB ' DSFGDDDJFDS'FLAG DB 'THE FLAF IS THE:S'DATAS ENDSCODES SEGMENTASSUME CS:CODES, DS:DATAS, ES:DATASSTART:MOV AX, DATASMOV DS, AXMOV ES,AXLEA DX, FLAGMOV AH, 9INT 21HLEA SI, SILEA DI, S2-5MOV CX, 5REP

9、E CMPSBEXIT: LOOP LPLEA DX, M2MOV AH, 9INT 21HMOV BX, MAXADD BH, 30HMOV DL, BHMOV AH, 2INT 21HADD BL, 30HMOV DL, BLMOV AH,2INT 21HJNEEXITMOVAH, 2MOVDL,' Y'INT21HJMPOVEREXIT:MOVAH, 2MOVDL,，fINT21HOVER:MOVAH, 4CHINT21HCODES ENDSMOV AH, 4CHINT 21HCODES ENDSEND STARTEND START5.編寫打印圖形程序DATAS SEGM

10、ENTs db '10', 13, 10,' S' a dwDATAS ENDSCODES SEGMENTASSUME CS:CODES, DS:DATASSTART:MOV AX, DATASMOV DS, AX mov ex, 10 mov bx, 9mov a, 2MOV DS, AX MOV ES,AX CALL INPUT CALL LOCATE CALL DISPLAYloopl: mov dl, OahRETmov ah, 2MAIN ENDPint 21hINPUT PROC NEARmov dl, OdhPUSH DXmov ah, 2MOV

11、AH, OAHint 21hLEA DX, MONINloop2:INT 21Hmov dl, sbxMOV AH,MONIN+2mov ah, 2MOV AL, MONIX-3int 21hXOR AX, 3030Hinc bxCMP AH, 00emp bx, 9JZ RETURNjbe loop2SUB AH, AHsub bx, aADD AL, 10inc aRETURN:loop looplPOP DXMOV AH, 4CHRETINPUT ENDPINT 21HLOCATE PROC NEARCODES ENDSPUSH SIEND STARTPUSH DIPUSH CX6.用子

12、程序結構編寫程序：從鍵盤入一個二位LEA SI,MONTAB十進制數(shù)的月份（0廣12）,然后顯示相應的DEC AL英文縮寫名。MUL THREEDATAS SEGMENT PARA，DATA，ADD SI, AXTHREE DB 4MOV CX, 03MONIN DB 4,5 DUP()CLDALFMON DB 4,'.','LEA DI, ALFMON-1MONTABREP MOVSBDB' JAN.',' FEB.',' MAR.',' APR.',' MAY.',' JUPOP

13、 CX' JUL.',' AUG.',' SEP.',' OCT.',' NOV.','POP DIDEC.'POP SIDATAS ENDSRETCODES SEGMENT PARA ，CODE,LOCATE ENDPNIAIN PROC FARPUSH DXPUSH DSLEA DX, ALFMON-1SUB AX, AXMOV AH, 09PUSH AXINT 21HMOV AX, DATASPOP DXASSUME CS:CODES, DS:DATAS, ES:DATASDISPLAY PR

14、OC NEARRETDISPLAY ENDPCODES ENDSEND MAIN7.數(shù)組排序DATAS SEGMENTSTRING DB ' INPUT 20NUMBERSOAH, ODH,' $'BUF DB 20 DUP ()DATAS ENDSCODES SEGMENTMOV DI, CXMOV BX, 0E2:;用冒泡法比較，前后比較MOV AL, BUFBXCMP AL,BUFEBX+1JNG E3XCHG AL, BUFEBX+1MOV BUFBX, ALE3:ADD BX, 1LOOP E2MOV CX, DILOOP ElASSUME CS:CODES,

15、 DS:DATASMOVAH, 2START:MOVDL, OAHMOVAX, DATASINT21HMOVDS, AXMOVAH, 2MOVDL,ODHLEADX, STRINGINT21HMOVAH, 9INT21HMOVCL, 20MOVBX,0MOVCX, 20MOVSI,0MOVSI,0L00P2:L00P1:;動態(tài)輸入20個無符號的兩位數(shù)MOVAL,BUFSIMOVAH, 1CBWINT21HMOVBL, 10SUBAL, 30HDIVBLMOVBL, 10MOVBH, AHMILBLMOVAH, 2MOVDX, AXADDAL,30HMOVAH, 1MOVDL,ALINT21HI

16、NT21HSUBAL, 30HMOVAH, 2ADDDL, ALADDBH, 30HMOVBL, DLMOVDL, BHINT21HMOVAH, 2MOVAH, 2MOVDL,5 'MOVDL,，'INT21HINT21HMOVBUFSI,BLINCSIINCSILOOP L00P2;從小到大輸出數(shù)組LOOP L00P1MOV AH, 2MOV CX, 19；比較19次MOV DL, OAHINT 21HMOV AH, 2MOV DL,ODHINT 21HMOV AH, 4CHINT 21HCODES ENDSEND START8.求三個數(shù)中最大的數(shù)DATAS SEGMENTBUF1 DB 3BUF2 DB 9BUF3 DB 7MAX DBSTRING DB ' The max namber is:', 13, 10,'$'DATAS ENDSSTACKS SEGMENTSTACKS ENDSE2:MOV AL, BUF1MOV MAX, ALJMP OVERE3:MOV CL, BUF2MOV MAX, CLJMP OVEROVER:MOV DX,OFFSET STRINGMOV AH, 9INT 21HMOV AH, 2ADD MAX, 30HMOV