第二章清華數(shù)字電子技術(shù)第五版閻石ppt課件

1、ANOTY A證明方法：推演 真值表左右BCABCCBABCACABACABA)()(1CBABCACBABCBBABA)()()(代入以原變量反變量反變量原變量，0110YY不屬于單個(gè)變量的不屬于單個(gè)變量的上的反號(hào)保管不變上的反號(hào)保管不變DCBDACBCADCCBAYCDCBAY)()()(CBAY )(CBAY)( BAB)(BAA) )()(BABABABABABABABABA)() )()(）4個(gè)（22ABBABABA,）8個(gè)（32ABCCABCBACBABCACBACBACBA,ABCCABCBACBABCACBACBACBABACCBABCACBABCACBA)(與),()(),(

2、763mBCAABCCABAABCCABBCCABCBAY利用公式利用公式可將任何一個(gè)函數(shù)化為可將任何一個(gè)函數(shù)化為1 AA im),()(),(763mBCAABCCABAABCCABBCCABCBAY利用公式利用公式可將任何一個(gè)函數(shù)化為可將任何一個(gè)函數(shù)化為1 AA im),()(),(763mBCAABCCABAABCCABBCCABCBAY利用公式利用公式可將任何一個(gè)函數(shù)化為可將任何一個(gè)函數(shù)化為1 AA imDCBAACDBAADCBCDBDDCBDBCAADCBACBDBCDCBADCBAY)()(.)()(),(DCBAACDBAADCBCDBDDCBDBCAADCBACBDBCDCB

3、ADCBAY)()(.)()(),(DCBAACDBAADCBCDBDDCBDBCAADCBACBDBCDCBADCBAY)()(.)()(),(DCBAACDBAADCBCDBDDCBDBCAADCBACBDBCDCBADCBAY)()(.)()(),(）4個(gè)（22BABABABA,CBACBACBACBACBACBACBACBA imYikkmYikkmY)(kikkikMmYCBACYACDCBABCY21DBCBADCDBCBADEBAADCDBCBACDEBACBADCDBCBACCBADEBADBCACBADCDBCBACY )()()(DBCBADCDBCBADEBAADCDBC

4、BACDEBACBADCDBCBACCBADEBADBCACBADCDBCBACY)()()(DBCBADCDBCBADEBAADCDBCBACDEBACBADCDBCBACCBADEBADBCACBADCDBCBACY)()()(DBCBADCDBCBADEBAADCDBCBACDEBACBADCDBCBACCBADEBADBCACBADCDBCBACY)()()(DBCBADCDBCBADEBAADCDBCBACDEBACBADCDBCBACCBADEBADBCACBADCDBCBACY)()()( im),()()(),CDDCDCCDBADBACCDCBABA

5、DBADCBADCBAYCBCBCACACBAY),(ABCCBCBCACACBAY),(CBCABAABCCBCBCACACBAY),(ABCCBBACACBCBCACACBAY),(CBCABACBBACAABCDDCACBADCDCAABDABCY DCACBADCDCAABDABCY ABCDDAABCD=0DCB+ADD+ABCD+ABCCB+ADCD+ABCBACD+BADCBABCDADCBAY 給給定定約約束束條條件件為為：例：ABCD=0DCB+ADD+ABCD+ABCCB+ADCD+ABCBACD+BADCBABCDADCBAY 給給定定約約束束條條件件為為：例：ABCDDADA =0DCB+ADD+ABCD+ABCCB+ADCD+ABCBACD+BADCBABCDADC