計(jì)算機(jī)簡單編程示例

1、.1從鍵盤輸入三個(gè)數(shù)，找出它們的最小值*include <stdio.h>main() float a,b,c,min; printf("input three numbers: "); scanf("%f%f%f",&a,&b,&c); if(a>b) min=b; else min=a; if(min>c) min=c; printf("min=%fn",min);2輸出九九乘法表*include <stdio.h>main() int i,j;for(i=1;i<

2、=9;i+) for(j=1;j<=i;j+) printf("%d*%d=%2d",i,j,i*j); printf("n"); 3編程找出所有水仙花數(shù)*include <stdio.h>main() int x,a,b,c; for(x=100;x<=999;x+) a=x/100; b=x%100/10; c=x%10; if(a*a*a+b*b*b+c*c*c=x); printf("%d ",x); 1從鍵盤輸入三個(gè)數(shù)找出它們的平均數(shù)*include <stdio.h>main() flo

3、at a,b,c,aver; scanf("%f%f%f",&a,&b,&c); aver=(a+b+c)/3; printf("aver=%fn",aver);2輸出兩個(gè)正整數(shù)的所有公約數(shù)*include<stdio.h>main()int a,b,i,n; scanf("%d%d",&a,&b); if(a>b) n=b,b=a,a=n; for(i=1;i<=a;i+) if(a%i=0&&b%i=0) printf("%2d",

4、i); printf("n"); return 0;3輸出一個(gè)3*4的矩陣中的最小值，矩陣的數(shù)據(jù)從鍵盤輸入*include<stdio.h>main()int i,j,min,a34;printf("原矩陣a%d%d:n",3,4);for(i=0;i<3;i+)for(j=0;j<4;j+)scanf("%d",&aij);printf("n");min=a00;for(i=0;i<3;i+)for(j=0;j<4;j+)if(min>aij)min=aij;pr

5、intf("the min number%3d",min);1.從鍵盤輸入圓的半徑，計(jì)算圓的面積和周長*include<stdio.h>*define PI 3.14159main()float r,s,l; printf("請(qǐng)輸入圓的半徑"); scanf("%f",&r); s=PI*r*r; l=PI*r*2; printf("s=%f,l=%fn",s,l);2.從鍵盤輸入10個(gè)數(shù)字，用起泡法從小到大排序*include<stdio.h>int main()int a10;i

6、nt i,j,t;printf("input 10 number:n");for(i=0;i<10;i+)scanf("%d",&ai);printf("n");for(j=0;j<9;j+)for(i=0;i<9-j;i+)if(ai>ai+1)t=ai;ai=ai+1;ai+1=t;printf("the sorted number:n");for(i=0;i<10;i+)printf("%5.0d",ai);printf("n");

7、return 0;3從鍵盤輸入10個(gè)數(shù)，計(jì)算它們的最大值*include<stdio.h>main()float x,max;int i;printf("請(qǐng)輸入第一個(gè)數(shù): ");scanf("%f",&x);max=x;for(i=1;i<=9;i+)printf("請(qǐng)輸入第%d個(gè)數(shù) :");scanf("%f",&x);if(x>max)max=x;printf("10個(gè)數(shù)中最大值:%fn",max);1從鍵盤輸入長方形的長和寬，計(jì)算長方形的面積和周長*

8、include<stdio.h>main()float a,b,s,l; printf("請(qǐng)輸入長方形的長和寬"); scanf("%f%f",&a,&b); s=a*b; l=2*(a+b); printf("s=%f,l=%fn",s,l);2計(jì)算s=1+2+3+100*include<stdio.h>main()int i=2,sum=0; do sum=sum+i; i=i+2; while(i<=100); printf("sum=%dn",sum);3輸出一

9、個(gè)3*3矩陣的轉(zhuǎn)置矩陣，矩陣的數(shù)據(jù)從鍵盤輸入*include<stdio.h>main()int i,j,temp,a33;printf("原矩陣a%d%d:n",3,3);for(i=0;i<3;i+)for(j=0;j<3;j+)scanf("%d",&aij);for(i=0;i<2;i+)for(j=i+1;j<3;j+)if(i!=j)temp=aij;aij=aji;aji=temp;printf("轉(zhuǎn)置矩陣A%d%d:n",3,3);for(i=0;i<3;i+)for(

10、j=0;j<3;j+)printf("%4d",aij);printf("n");1 從鍵盤輸入三個(gè)整數(shù)，找出它們的最大值*include<stdio.h>main()int a,b,c,max;printf("input three number:");scanf("%d%d%d",&a,&b,&c);if(a>b)max=a;elsemax=b;if(max<c)max=c;printf("max=%dn",max);2 從鍵盤輸入一行字

11、符，統(tǒng)計(jì)所輸入字符的個(gè)數(shù)*include<stdio.h>main()int n=0;printf("input a string:n");while(getchar()!='n')n+;printf("%dn",n);3 計(jì)算兩個(gè)正整數(shù)的最小公倍數(shù)*include<stdio.h>main()int m,n,r,g,p,h;printf("請(qǐng)輸入求最小公倍數(shù)的數(shù)：");scanf("%d%d",&m,&n);p=m*n;while(r=m%n)!=0)m=n

12、;n=r;g=n;h=p/g;printf("h=%dn",h);從鍵盤輸入十個(gè)數(shù)，計(jì)算它們的最小值*include<stdio.h>main()float x,min;int i;printf("請(qǐng)輸入第一個(gè)數(shù): ");scanf("%f",&x);min=x;for(i=1;i<=9;i+)printf("請(qǐng)輸入第%d個(gè)數(shù) :");scanf("%f",&x);if(x<min)min=x;printf("10個(gè)數(shù)中最小是:%fn"

13、,min);從鍵盤輸入十個(gè)數(shù)，計(jì)算他們的平均值*include<stdio.h>main()float x,sum,d;int i;printf("請(qǐng)輸入第一個(gè)數(shù):");scanf("%f",&x);sum=x;for(i=1;i<=9;i+)printf("請(qǐng)輸入第%d個(gè)數(shù):",i+1);scanf("%f",&x);sum=sum+x;d=sum/10.0;printf("10個(gè)數(shù)的平均值是:%fn",d);計(jì)算s=1+3+5+7+.+99*include&

14、lt;stdio.h>main()int i=1,sum=0; do sum=sum+i; i=i+2; while(i<=99); printf("sum=%dn",sum);計(jì)算s=2+4+6+8+.+100*include<stdio.h>main()int i=2,sum=0; do sum=sum+i; i=i+2; while(i<=100); printf("sum=%dn",sum);計(jì)算s=n!(n從鍵盤輸入)*include<stdio.h>main()int n,i;double fact=

15、1; printf("請(qǐng)輸入任意數(shù):n"); scanf("%d",&n); for(i=1;i<=n;i+)fact=fact*i;printf("%5.0f%3d!n",fact,n);計(jì)算兩個(gè)正整數(shù)的最大公約數(shù)*include<stdio.h>main()int m,n,r,g,p;printf("請(qǐng)輸入求最大公約數(shù)的數(shù)：");scanf("%d%d",&m,&n);while(r=m%n)!=0)m=n;n=r;g=n;printf("

16、g=%dn",g);數(shù)列: 1 1 2 3 5 . 從第三項(xiàng)起每項(xiàng)數(shù)據(jù)都是其前兩項(xiàng)之和計(jì)算該數(shù)列的前15項(xiàng)。*include<stdio.h>main()int f1=1,f2=1,f3,i; printf("%12dn%12dn",f1,f2); for(i=1;i<=13;i+) f3=f1+f2; printf("%12dn",f3); f1=f2; f2=f3; 輸入一個(gè)3*4矩陣中的最大值，矩陣的數(shù)據(jù)從鍵盤輸入*include<stdio.h>main()int i,j,max,a34;printf("原矩陣a%d%d:n",3,4);for(i=0;i<3;i+)for(j=0;j<4;j+)scanf("%d",&aij);printf("n");max=a00;for(i=0;i<3;i+)for(j=0;j<4;j+)if(max<aij)max=aij;printf("the max number%3d&q