




版權(quán)說(shuō)明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請(qǐng)進(jìn)行舉報(bào)或認(rèn)領(lǐng)
文檔簡(jiǎn)介
1、usingSystem;using;usingSystem.Linq;usingSystem.Text;usingSystem;usingSystem.IO;usingSystem.Text;namespaceBpANNet(/<summary>/BpNet的摘要說(shuō)明./</summary>publicclassBpNetpublicintinNum;/輸入節(jié)點(diǎn)數(shù)inthideNum;/隱層節(jié)點(diǎn)數(shù)publicintoutNum;/輸出層節(jié)點(diǎn)數(shù)publicintsampleNum;/樣本總數(shù)RandomR;doublex;/輸入節(jié)點(diǎn)的輸入數(shù)據(jù)doublex1;/隱層節(jié)點(diǎn)的
2、輸出doublex2;/輸出節(jié)點(diǎn)的輸出doubleo1;/隱層的輸入doubleo2;/輸出層的輸入publicdouble,w;/權(quán)值矩陣w,這是輸入層與隱藏層之間的權(quán)值矩陣publicdouble,v;/權(quán)值矩陣V,這是隱藏層與輸出層之間的權(quán)值矩陣publicdouble,dw;/權(quán)值矩陣wpublicdouble,dv;/權(quán)值矩陣Vpublicdoublerate;/學(xué)習(xí)率publicdoubleb1;/隱層閾值矩陣publicdoubleb2;/輸出層閾值矩陣publicdoubledb1;/隱層閾值矩陣publicdoubledb2;/輸出層閾值矩陣doublepp;/隱藏層的誤差d
3、oubleqq;/輸出層的誤差doubleyd;輸出層的教師數(shù)據(jù),所謂教師數(shù)據(jù)就是實(shí)際數(shù)據(jù)而B(niǎo)!|publicdoublee;/均方誤差doublein_rate;/歸一化比例系數(shù)用于確定隱藏層的神經(jīng)細(xì)胞數(shù)publicintcomputeHideNum(intm,intn)(doubles=Math.Sqrt(0.43*m*n+0.12*n*n+2.54*m+0.77*n+0.35)+0.51;intss=Convert.ToInt32(s);return(s-(double)ss)>0.5)?ss+1:ss;publicBpNet(double,p,double,t)(構(gòu)造函數(shù)邏輯R=
4、newRandom();this.inNum=p.GetLength(1);this.outNum=t.GetLength(1);this.hideNum=computeHideNum(inNum,outNum);/this.hideNum=18;this.sampleNum=p.GetLength(0);Console.WriteLine("輸入節(jié)點(diǎn)數(shù)目:"+inNum);Console.WriteLine("隱層節(jié)點(diǎn)數(shù)目:"+hideNum);Console.WriteLine("輸出層節(jié)點(diǎn)數(shù)目:"+outNum);Console
5、.ReadLine();將這些矩陣規(guī)定好矩陣大小x=newdoubleinNum;x1=newdoublehideNum;x2=newdoubleoutNum;o1=newdoublehideNum;o2=newdoubleoutNum;w=newdoubleinNum,hideNum;/權(quán)值矩陣w,這是輸入層與隱藏層之間的權(quán)值矩陣v=newdoublehideNum,outNum;dw=newdoubleinNum,hideNum;dv=newdoublehideNum,outNum;閾值b1=newdoublehideNum;b2=newdoubleoutNum;db1=newdouble
6、hideNum;db2=newdoubleoutNum;誤差pp=newdoublehideNum;/隱藏層的誤差qq=newdoubleoutNum;/輸出層的誤差yd=newdoubleoutNum;/輸出層的教師數(shù)據(jù)初始化wfor(inti=0;i<inNum;i+)for(intj=0;j<hideNum;j+)/NextDouble返回一個(gè)介于0.0和1.0之間的隨機(jī)數(shù)。wi,j=(R.NextDouble()*2-1.0)/2;)初始化vfor(inti=0;i<hideNum;i+)for(intj=0;j<outNum;j+)vi,j=(R.NextDo
7、uble()*2-1.0)/2;)rate=0.8;e=0.0;in_rate=1.0;?)訓(xùn)練函數(shù)publicvoidtrain(double,p,double,t)e=0.0;求p,t中的最大值doublepMax=0.0;/sampleNum為樣本總數(shù)for(intisamp=0;isamp<sampleNum;isamp+)(/inNum是輸入層的節(jié)點(diǎn)數(shù)(即神經(jīng)細(xì)胞數(shù))for(inti=0;i<inNum;i+)(if(Math.Abs(pisamp,i)>pMax)(pMax=Math.Abs(pisamp,i);for(intj=0;j<outNum;j+)
8、(if(Math.Abs(tisamp,j)>pMax)(pMax=Math.Abs(tisamp,j);in_rate=pMax;/endisampfor(intisamp=0;isamp<sampleNum;isamp+)(數(shù)據(jù)歸一化for(inti=0;i<inNum;i+)(xi=pisamp,i/in_rate;for(inti=0;i<outNum;i+)(ydi=tisamp,i/in_rate;計(jì)算隱層的輸入和輸出for(intj=0;j<hideNum;j+)(o1j=0.0;for(inti=0;i<inNum;i+)(o1j+=wi,j
9、*xi;/權(quán)值”輸入”的那個(gè)累加的過(guò)程)這個(gè)b1j就是隱藏層的閾值,閾值就是一個(gè)輸入為-1”的累加值x1j=1.0/(1.0+Math.Exp(-o1j-b1j);)計(jì)算輸出層的輸入和輸出for(intk=0;k<outNum;k+)(o2k=0.0;for(intj=0;j<hideNum;j+)(o2k+=vj,k*x1j;)x2k=1.0/(1.0+Math.Exp(-o2k-b2k);)計(jì)算輸出層誤差和均方差for(intk=0;k<outNum;k+)(/ydk是輸出層的教師數(shù)據(jù),所謂教師數(shù)據(jù)就是實(shí)際應(yīng)該輸出的數(shù)據(jù)而已qqk=(ydk-x2k)*x2k*(1.0-x
10、2k);e+=(ydk-x2k)*(ydk-x2k);更新V,V矩陣是隱藏層與輸出層之間的權(quán)值for(intj=0;j<hideNum;j+)(vj,k+=rate*qqk*x1j;計(jì)算隱層誤差for(intj=0;j<hideNum;j+)(/PP矩陣是隱藏層的誤差ppj=0.0;算法參考我的視頻截圖for(intk=0;k<outNum;k+)(ppj+=qqk*vj,k;)ppj=ppj*x1j*(1-x1j);更新Wfor(inti=0;i<inNum;i+)(wi,j+=rate*ppj*xi;)更新b2,輸出層的閾值for(intk=0;k<outNu
11、m;k+)(b2k+=rate*qqk;)更新b1,隱藏層的閾值for(intj=0;j<hideNum;j+)(b1j+=rate*ppj;)/endisampe=Math.Sqrt(e);/均方差/adjustWV(w,dw);/adjustWV(v,dv);/endtrainpublicvoidadjustWV(double,w,double,dw)for(inti=0;i<w.GetLength(0);i+)for(intj=0;j<w.GetLength(1);j+)wi,j+=dwi,j;publicvoidadjustWV(doublew,doubledw)(f
12、or(inti=0;i<w.Length;i+)(wi+=dwi;數(shù)據(jù)仿真函數(shù)publicdoublesim(doublepsim)(for(inti=0;i<inNum;i+)xi=psimi/in_rate;/in_rate為歸一化系數(shù)for(intj=0;j<hideNum;j+)(o1j=0.0;for(inti=0;i<inNum;i+)o1j=o1j+wi,j*xi;x1j=1.0/(1.0+Math.Exp(-o1j-b1j);)for(intk=0;k<outNum;k+)o2k=0.0;for(intj=0;j<hideNum;j+)o2k
13、=o2k+vj,k*x1j;x2k=1.0/(1.0+Math.Exp(-o2k-b2k);x2k=in_rate*x2k;)?returnx2;/endsim保存矩陣w,vpublicvoidsaveMatrix(double,w,stringfilename)StreamWritersw=File.CreateText(filename);for(inti=0;i<w.GetLength(0);i+)(for(intj=0;j<w.GetLength(1);j+)(sw.Write(wi,j+"");)sw.WriteLine();)sw.Close();)
14、保存矩陣b1,b2publicvoidsaveMatrix(doubleb,stringfilename)(StreamWritersw=File.CreateText(filename);for(inti=0;i<b.Length;i+)(sw.Write(bi+"");)sw.Close();)讀取矩陣W,VpublicvoidreadMatrixW(double,w,stringfilename)(StreamReadersr;try?(sr=newStreamReader(filename,Encoding.GetEncoding("gb2312&q
15、uot;);?Stringline;inti=0;while(line=sr.ReadLine()!=null)?(strings1=line.Trim().Split('');for(intj=0;j<s1.Length;j+)(wi,j=Convert.ToDouble(s1j);)i+;)sr.Close();)catch(Exceptione)?(/Lettheuserknowwhatwentwrong.Console.WriteLine("Thefilecouldnotberead:");Console.WriteLine(e.Message
16、);)讀取矩陣b1,b2publicvoidreadMatrixB(doubleb,stringfilename)(StreamReadersr;try?sr=newStreamReader(filename,Encoding.GetEncoding("gb2312");?Stringline;inti=0;?while(line=sr.ReadLine()!=null)?bi=Convert.ToDouble(line);i+;sr.Close();catch(Exceptione)?/Lettheuserknowwhatwentwrong.Console.WriteLi
17、ne("Thefilecouldnotberead:");Console.WriteLine(e.Message);?/endbpnet/endnamespace主調(diào)用程序namespaceBpANNet(/<summary>/Classi的摘要說(shuō)明。/</summary>classClassl(/<summary>/應(yīng)用程序的主入口點(diǎn)。/</summary>STAThreadstaticvoidMain(stringargs)(/0.1399,0.1467,0.1567,0.1595,0.1588,0.1622,0.1611
18、,0.1615,0.1685,0.1789,0.1790/double,p1=newdouble,0.05,0.02,0.09,0.11,0.12,0.20,0.15,0.22,0.20,0.25,0.75,0.75,0.80,0.83,0.82,0.80,0.90,0.89,0.95,0.89,0.09,0.04,0.1,0.1,0.14,0.21,0.18,0.24,0.22,0.28,0.77,0.78,0.79,0.81,0.84,0.82,0.94,0.93,0.98,0.99;/double,t1=newdouble,1,0,1,0,1,0,1,0,1,0,0,1,0,1,0,1,
19、0,1,0,1,1,0,1,0,1,0,1,0,1,0,0,1,0,1,0,1,0,1,0,1;/p1是輸入的信息,一共5組,輸入層為六個(gè)節(jié)點(diǎn),p156double,p1=newdouble,0.1399,0.1467,0.1567,0.1595,0.1588,0.1622,0.1467,0.1567,0.1595,0.1588,0.1622,0.1611,0.1567,0.1595,0.1588,0.1622,0.1611,0.1615,0.1595,0.1588,0.1622,0.1611,0.1615,0.1685,0.1588,0.1622,0.1611,0.1615,0.1685,0
20、.1789;/t1是輸出信息,一共6組,t161double,t1=newdouble,0.1622,0.1611,0.1615,0.1685,0.1789,0.1790;BpNetbp=newBpNet(p1,t1);intstudy=0;dostudy+;bp.train(p1,t1);bp.rate=0.95-(0.95-0.3)*study/50000;/Console.Write("第"+study+"次學(xué)習(xí):");Console.WriteLine("均方差為"+bp.e);while(bp.e>0.001&&study<50000);Console.Write("第"+study+"次學(xué)習(xí):");Console.WriteLine("均方差為"+bp.e);bp.saveMatrix(bp.w,"w.txt");bp.saveMatri
溫馨提示
- 1. 本站所有資源如無(wú)特殊說(shuō)明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請(qǐng)下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請(qǐng)聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
- 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁(yè)內(nèi)容里面會(huì)有圖紙預(yù)覽,若沒(méi)有圖紙預(yù)覽就沒(méi)有圖紙。
- 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
- 5. 人人文庫(kù)網(wǎng)僅提供信息存儲(chǔ)空間,僅對(duì)用戶上傳內(nèi)容的表現(xiàn)方式做保護(hù)處理,對(duì)用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對(duì)任何下載內(nèi)容負(fù)責(zé)。
- 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請(qǐng)與我們聯(lián)系,我們立即糾正。
- 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時(shí)也不承擔(dān)用戶因使用這些下載資源對(duì)自己和他人造成任何形式的傷害或損失。
最新文檔
- 酒店資產(chǎn)投資與經(jīng)營(yíng)管理合伙協(xié)議書(shū)二零二五
- 二零二五年度私人住宅裝修工人安全責(zé)任合同
- 2025年度海洋資源開(kāi)發(fā)橫向課題執(zhí)行協(xié)議
- 二零二五年度小程序游戲運(yùn)營(yíng)合作協(xié)議
- 2025年度電子元器件采購(gòu)合同主要內(nèi)容簡(jiǎn)述
- 二零二五年度購(gòu)房合同定金支付及變更協(xié)議書(shū)
- 2025年度酒店員工勞動(dòng)權(quán)益保障合同
- 二零二五年度綠色建筑股權(quán)協(xié)議及合伙人合作開(kāi)發(fā)協(xié)議
- 2025年度美發(fā)店員工工傷事故處理勞動(dòng)合同
- 空調(diào)安裝工勞動(dòng)合同
- 2025人教版一年級(jí)下冊(cè)數(shù)學(xué)教學(xué)進(jìn)度表
- DeepSeek教案寫(xiě)作指令
- 2025年安徽省合肥熱電集團(tuán)招聘50人歷年高頻重點(diǎn)模擬試卷提升(共500題附帶答案詳解)
- 休學(xué)復(fù)學(xué)申請(qǐng)書(shū)
- 北京2025年02月北京市地質(zhì)礦產(chǎn)勘查院所屬事業(yè)單位公開(kāi)招考工作人員筆試歷年典型考題(歷年真題考點(diǎn))解題思路附帶答案詳解
- GB/T 36548-2024電化學(xué)儲(chǔ)能電站接入電網(wǎng)測(cè)試規(guī)程
- 土力學(xué)與地基基礎(chǔ)(課件)
- 城市供水計(jì)劃統(tǒng)計(jì)指標(biāo)解釋
- 塑膠原料檢驗(yàn)規(guī)范
- 建筑公司內(nèi)部管理流程-課件PPT
- 中國(guó)古典舞PPT課件
評(píng)論
0/150
提交評(píng)論