故障處短路電流和電壓計(jì)算二

第十章不對(duì)稱故障的分析和計(jì)算第十章不對(duì)稱故障的分析和計(jì)算第二節(jié)非故障處電流和電壓的計(jì)算第十章第十章不對(duì)稱故障的分析和計(jì)第一節(jié)故障點(diǎn)短路電流和電壓的計(jì)四、正序等效定兩相相間短G~Lf邊界條.Ia= Ib+Ic= Ub=.. . Ib+Ic= Ub=Ia=序分量表 Ia1+Ia2+Ia0=a2Ia1+aIa2+Ia0+aIa1+a2Ia2+Ia0=. . aUa1+aUa2+Ua0=aUa1+aUa2+Ua 2..................................................................2.Ua1=Ua Ia1+Ia2=.Ia0=復(fù)合序jX.I+E+-U.jX I+-UjX.I.IjX+E.+.U-U例G-例G-~X"=fLG-~.E"=jX=X=X=X=X"=X=0.33X=.E"=jj1jjjjjj12 I45X=(X+X)//(X+X+X=(0.2+0.18)//(0.12+0.33+0.4jX1=j.Ia=+E1=j+-Ua例G-~X"=fLG-~.E"=jjX=X=X=X"=X=X=0.33X=.E"=jjjjj12 I45X=(X+X)//(X+X+X=(0.26+0.18)//(0.12+0.33+0.51)jX=j=.I+U-..合序jX=j+E=jI.I=+. E jX+jXjj0.26+j.-U=jX=j.I.I=-+U U=E-jXI=j1-j0.26=j U=-jX2Ia=-j0.30(-1.79=j.解各相電流.Ia=Ib=aIa1+aIa2+Ia0=12401.79+1120(-.=-j3.10Ic=j 2 各相電 Ua=Ua1+Ua2+Ua0=j0.54+j0.54+0=jUb=aUa1+aUa2+Ua=1240j0.54+1120j0.54+ 2 =-Uc=-.解相量解相量...Ic.Ic Ua Ua.Ia.Ia.Ib..Ub.Uc.Uc.Ub..Uc兩相接地短G~Lf(1,邊界條.Ia= Ub=Uc=.... UaUa1=Ua2=Ua Ia1+Ia2+Ia0=邊界條件Ia=.Ia1+Ia2+Ia0= Ub=Uc=0aUa1+aUa2+Ua0=aUa1+aUa2+Ua 2 2 =jX.I+E+-U.jX I+Ua1=Ua2=Ua -UIa1+Ia2+Ia0=. jX.I+U-復(fù)合復(fù)合序.jXjX+E.I.UI+I-.U jXU2=Ua+Ia0=..例G-~X"=f(1,L.E"=jX=X=X=X=G-~X"=X=0.33X=.E"=jj1jjjjjj12.I345jX=j.IX=(X+X)//(X+X+X)+=(0.2+0.18)//(0.12+0.33+0E4)=j=+U-例例G-~X"=f(1,LG-~X=X=X"=.E"=jjX=X=X=0.33X=.E"=jjjjj12.I345jX=j.IX=(X+X)//(X+X+X=(0.26+0.18)//(0.12+0.33+0.51=+U-例G-~X"=f(1,LG-~X=.E"=jX=X=X=X"=X=0.33X=.E"=jj2.Ij3j4X=X//(X+X=0.18//(0.24+0.33=jX=j.I+U-解j解jX=j+E=j.I.I+-U. E =jX+jX//jXj=j0.26+j0.30//j= X .(-IjX=j.II+ X+X(-2.850.30+-UjX0=j.I=-.I=-+U U=U=U=-jXI=-j0.13(-=j 解各相電流.Ia= Ib=a2Ia1+aIa2+Ia=12402.85+1120(-0.86)+(-=-2.99-j3.21=4.39Ic=aIa1+aIa2+Ia=-2.99+j3.21=4.39 Ua=Ua1+