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新版CCNA802v13題庫(kù)分析(三)100.Whichofthefollowingstatementsdescribethenetworkshowninthegraphic?(Choosetwo.)

A.Therearetwobroadcastdomainsinthenetwork.

B.Therearefourbroadcastdomainsinthenetwork.

C.Therearesixbroadcastdomainsinthenetwork.

D.Therearefourcollisiondomainsinthenetwork.

E.Therearefivecollisiondomainsinthenetwork.

F.Therearesevencollisiondomainsinthenetwork.

Answer:AF這是個(gè)廣播域和沖突域的問(wèn)題。首先我們需要知道HUB整體是一個(gè)廣播域和沖突域,而交換機(jī)整體是一個(gè)廣播域,每個(gè)接口都是一個(gè)沖突域。知道了這些,這個(gè)問(wèn)題的答案就很明顯了,有兩個(gè)廣播域和七個(gè)沖突域。都沒(méi)有到Attalla的映射,所以也無(wú)法和Attalla建立連通性。

101.Whichofthefollowingaretrueregardingthecommandoutputshowninthedisplay?(Choosetwo.)

A.ThereareatleasttworoutersparticipatingintheRIPprocess.

B.Apingtowillbesuccessful.

C.Apingto.2willbesuccessful.

D.RtrAhasthreeinterfacesparticipatingintheRIPprocess.

Answer:AC因?yàn)镽IP的metric是基于跳數(shù)的,在debugiprip中RtrA發(fā)出的路由的metric為2,所以在RIP進(jìn)程下至少有兩臺(tái)路由器;而.0metric1表示這個(gè)路由是自己直連的,所以是能成功的。

102.Whatthreepiecesofinformationcanbeusedinanextendedaccesslisttofiltertraffic?(Choosethree.)

A.protocolB.VLANnumberC.TCPorUDPportnumbers

D.sourceswitchportnumberE.sourceIPaddressanddestinationIPaddress

F.sourceMACaddressanddestinationMACaddress

Answer:ACEACL是基于三層的過(guò)濾,因此他可以基于ip,portnumber來(lái)過(guò)濾流量,擴(kuò)展的訪問(wèn)控制列表是可以基于源和目的的同時(shí)的過(guò)濾。

103.Refertotheexhibit.WhichtwostatementsaretrueaboutinterVLANroutinginthetopologythatisshownintheexhibit?(Choosetwo.)

A.HostEandhostFusethesameIPgatewayaddress.

B.Router1andSwitch2shouldbeconnectedviaacrossovercable.

C.Router1willnotplayaroleincommunicationsbetweenhostAandhostD.

D.TheFastEthernet0/0interfaceonRouter1mustbeconfiguredwithsubinterfaces.

E.Router1needsmoreLANinterfacestoaccommodatetheVLANsthatareshownintheexhibit.

F.TheFastEthernet0/0interfaceonRouter1andSwitch2trunkportsmustbeconfiguredusingthesameencapsulationtype.

Answer:DF為了實(shí)現(xiàn)相同相同交換機(jī)間的不同VLAN之間的通訊應(yīng)該用的三層的設(shè)備,借助trunk來(lái)實(shí)現(xiàn)。因此要將Router1和switch2相連的接口配置為trunk,trunk的模式還應(yīng)該是相同的,不同的trunk的封裝,是無(wú)法實(shí)現(xiàn)連通性的。

104.Whatistheeffectofusingtheservicepassword-encryptioncommand?

A.Onlytheenablepasswordwillbeencrypted.

B.Onlytheenablesecretpasswordwillbeencrypted.

C.Onlypasswordsconfiguredafterthecommandhasbeenenteredwillbeencrypted.

D.Itwillencryptthesecretpasswordandremovetheenablesecretpasswordfromtheconfiguration.

E.Itwillencryptallcurrentandfuturepasswords.

Answer:Epasswordencryption是為了給密碼加密。

A.Router1hasspecificbootsystemcommandsthatinstructittoloadIOSfromaTFTPserver.

B.Router1isactingasaTFTPserverforotherrouters.

C.Router1cannotlocateavalidIOSimageinflashmemory.

D.Router1defaultedtoROMMONmodeandloadedtheIOSimagefromaTFTPserver.

E.CiscorouterswillfirstattempttoloadanimagefromTFTPformanagementpurposes.

Answer:ACSystemimagefileis?°t29/Hampton/nitro/c7200-j-mz?±這句話表明系統(tǒng)的鏡像來(lái)自從tftp。引導(dǎo)程序首先使用flash中所找到的第一個(gè)有效的IOS鏡像,如果flash中沒(méi)有有效的IOS鏡像,引導(dǎo)程序?qū)⑸梢粋€(gè)TFTP本地廣播以定位TFTP服務(wù)器,如果沒(méi)有找到TFTP服務(wù)器,引導(dǎo)程序?qū)⒓虞dROM中的迷你IOS(RXBOOT模式),如果ROM中有迷你IOS,那么迷你IOS在隨后加載并且進(jìn)入RXBOOT模式;否則路由器不是重新試圖尋找IOS鏡像,就是加載ROMMON并且進(jìn)入ROMMonitor模式。因此說(shuō)明Router1在flash中沒(méi)有找到有效的IOS鏡像。從而加載了tftp中的鏡像。

106.AtwhichOSIlayerisalogicalpathcreatedbetweentwohostsystems?

A.sessionB.transportC.networkD.datalinkE.physical

Answer:C我們所說(shuō)的IP地址就是一個(gè)邏輯的地址,他是在OSI七層模型中的第三層network層創(chuàng)建的。是用于通訊的邏輯的地址。

107.Whatfunctionsdoroutersperforminanetwork?(Choosetwo.)

A.packetswitchingB.accesslayersecurityC.pathselection

D.VLANmembershipassignmentE.bridgingbetweenLANsegments

F.microsegmentationofbroadcastdomains

Answer:AC路由器在一個(gè)網(wǎng)絡(luò)中的作用是選擇路徑進(jìn)行轉(zhuǎn)發(fā)。

108.Refertotheexhibit.Theshowvtpstatuscommandisexecutedataswitchthatisgeneratingtheexhibitedoutput.Whichstatementistrueforthisswitch?

A.TheswitchforwardsitsVLANdatabasetootherswitchesintheICNDVTPdomain.

B.TheconfigurationrevisionnumberincrementseachtimetheVLANdatabaseisupdated.

C.TheswitchforwardsVTPupdatesthataresentbyotherswitchesintheICNDdomain.

D.TheVLANdatabaseisupdatedwhenVTPinformationisreceivedfromotherswitches.

Answer:CVTP是為了動(dòng)態(tài)學(xué)習(xí)和同步VLAN信息的,但是他的同步和學(xué)習(xí)都是以域?yàn)閱挝坏?,只有同一個(gè)域中的VLAN信息才可以同步和學(xué)習(xí)。而VTP的模式有三種:server,client,transparent。其中transparent模式為通明橋的模式,在這種模式下的VLAN的信息是不能被其他設(shè)備學(xué)習(xí)到的,而切這種模式下的設(shè)備也不學(xué)習(xí)其他設(shè)備的VLAN信息,他只是轉(zhuǎn)發(fā)VLAN的信息,但是不學(xué)習(xí)。

109.ACiscorouterisbootingandhasjustcompletedthePOSTprocess.ItisnowreadytofindandloadanIOS

image.Whatfunctiondoestherouterperformnext?

A.Itcheckstheconfigurationregister.

B.ItattemptstobootfromaTFTPserver.

C.Itloadsthefirstimagefileinflashmemory.

D.ItinspectstheconfigurationfileinNVRAMforbootinstructions.

Answer:A

110.Refertotheexhibit.Theoutputthatisshownisgeneratedataswitch.Whichthreeofthesestatementsaretrue?(Choosethree.)

A.Allportswillbeinastateofdiscarding,learning,orforwarding.

B.ThirtyVLANshavebeenconfiguredonthisswitch.

C.Thebridgepriorityislowerthanthedefaultvalueforspanningtree.

D.Allinterfacesthatareshownareonsharedmedia.

E.Alldesignatedportsareinaforwardingstate.

F.ThisswitchmustbetherootbridgeforallVLANsonthisswitch.

Answer:ACE

111.Whatisthefunctionofthecommandswitchporttrunknativevlan999onaCiscoCatalystswitch?

A.ItcreatesaVLAN999interface.

B.ItdesignatesVLAN999foruntaggedtraffic.

C.ItblocksVLAN999trafficfrompassingonthetrunk.

D.ItdesignatesVLAN999asthedefaultforallunknowntaggedtraffic.

Answer:Bnativevlan是不打標(biāo)簽的VLAN,這指定nativevlan為999,表明VLAN999為不用打標(biāo)簽的VLAN

112.Refertotheexhibit.AfteraRIProuteismarkedinvalidonRouter_1,howmuchtimewillelapsebeforethatrouteisremovedfromtheroutingtable?

A.30secondsB.60secondsC.90secondsD.180secondsE.240seconds

Answer:B

113.Whenanewtrunkisconfiguredona2950switch,whichVLANsbydefaultareallowedoverthetrunklink?

A.noVLANsB.allVLANsC.onlyVLANs1-64

D.onlytheVLANsthatarespecifiedwhencreatingthetrunk

Answer:BTrunk上默認(rèn)是可以轉(zhuǎn)發(fā)所有VLAN的數(shù)據(jù)的。

114.WhichthreestatementsdescribethedifferencesbetweenRIPversion1andRIPversion2?(Choosethree.)

A.RIPversion1broadcastsupdateswhereasRIPversion2usesmulticasts.

B.RIPversion1multicastsupdateswhileRIPversion2usesbroadcasts.

C.BothRIPversion1andRIPversion2areclasslessroutingprotocols.

D.RIPVersion2isaclasslessroutingprotocolwhereasRIPversion1isaclassfulroutingprotocol.

E.BothRIPversion1andversion2supportauthentication.

F.RIPversion2sendsthesubnetmaskinupdatesandRIPversion1doesnot.

Answer:ADF

115.Anaccesslistwaswrittenwiththefourstatementsshowninthegraphic.Whichsingleaccessliststatementwillcombineallfourofthesestatementsintoasinglestatementthatwillhaveexactlythesameeffect?

A.access-list10permit.255B.access-list10permit55

C.access-list10permit55D.access-list10permit55

E.access-list10permit55

Answer:C用一個(gè)單獨(dú)的語(yǔ)句來(lái)匹配上面寫出的四條ACL,也就一一個(gè)匯總的問(wèn)題,將,進(jìn)行匯總,將他們的第3個(gè)八字節(jié)以二進(jìn)制展開,相同的位作為他們的匯總的條目,然后計(jì)算他們的掩碼位數(shù)為多少,所以這四個(gè)條目匯總到一個(gè)條目為/22,掩碼用通配符來(lái)寫應(yīng)該是.255。

116.Refertotheexhibit.Alloftheroutersinthenetworkareconfiguredwiththeipsubnet-zerocommand.WhichnetworkaddressesshouldbeusedforLinkAandNetworkA?(Choosetwo.)2530F.LinkA-12/30

Answer:BD這是個(gè)IP地址規(guī)劃的考題。NetworkA中有120臺(tái)主機(jī),因此NetworkA中至少需要122個(gè)IP地址,根據(jù)公式2n>=122,可以解出n=7,因此網(wǎng)絡(luò)位為32-7=25,容納的IP地址為128。因此NetworkA的網(wǎng)段就可以為或。通過(guò)其他的設(shè)備分配的地址可以看到的地址已經(jīng)有一部分分配出去了,因此NetworkA分配的地址空間只能是只需要有兩個(gè)可用的IP地址,因此網(wǎng)段中需要有4個(gè)地址根據(jù)公式2n>=4,可以解出n=2,因此網(wǎng)絡(luò)位為32-2=30。而從其他路由器上的地址分配我們可以看到地址-5,2-27這些IP地址都已經(jīng)分配出去了,因此結(jié)合答案我們可以看到LinkA的地址空間只能為。

117.AtwhichlayersoftheOSImodeldoWANsoperate?(Choosetwo.)

A.applicationlayerB.sessionlayerC.transportlayerD.networklayer

E.datalinklayerF.physicallayer

Answer:EFWAN是工作在一層和二層的,比如現(xiàn)在常用的Frame-relay,ATM等這些都是工作在OSI的二層的。

A.HQ(config)#iproute

Branch(config)#iproute

B.HQ(config)#routerrip

HQ(config-router)#network

HQ(config-router)#network

Branch(config)#routerrip

Branch(config-router)#network

Branch(config-router)#network

C.HQ(config)#routereigrp56

HQ(config-router)#network

HQ(config-router)#network

Branch(config)#routereigrp56

Branch(config-router)#network

Branch(config-router)#network

D.HQ(config)#routerospf1

HQ(config-router)#network.3area0

HQ(config-router)#network.255area0

Branch(config)#routerospf1

Branch(config-router)#network.255area0

Branch(config-router)#network.3area0

Answer:A動(dòng)態(tài)路由協(xié)議都是需要有他的更新包來(lái)傳遞路由的,而這些都是會(huì)占用帶寬的,為了減小流量的沖突我們可以采用靜態(tài)路由,他是會(huì)占用任何帶寬的。

119.Refertotheexhibit.Whatisthepurposeoftheconfigurationthatisshown?

A.totranslateaddressesofhostsonthefa0/0andfa0/1networkstoasinglepublicIPaddressforInternetaccess

B.totranslatetheinternaladdressofeachhostonfa0/0andfa0/1toauniqueexternalIPaddressforInternetacces

C.toprovidesecurityonfa0/0andfa0/1throughtheapplicationofanaccesslist

D.toallowIPhostsontheInternettoinitiateTCP/IPconnectionstohostsonfa0/0andfa0/1

Answer:A

120.AnetworkadministratorwantstoensurethatonlytheservercanconnecttoportFa0/1onaCatalystswitch.TheserverispluggedintotheswitchFa0/1portandthenetworkadministratorisabouttobringtheserveronline.WhatcantheadministratordotoensurethatonlytheMACaddressoftheserverisallowedbyswitchportFa0/1?

A.ConfigureportFa0/1toacceptconnectionsonlyfromthestaticIPaddressoftheserver.

B.EmployaproprietaryconnectortypeonFa0/1thatisincompatiblewithotherhostconnectors.

C.ConfiguretheMACaddressoftheserverasastaticentryassociatedwithportFa0/1.

D.BindtheIPaddressoftheservertoitsMACaddressontheswitchtopreventotherhostsfromspoofingtheserverIPaddress.

E.ConfigureportsecurityonFa0/1torejecttrafficwithasourceMACaddressotherthanthatoftheserver.

F.ConfigureanaccesslistontheswitchtodenyservertrafficfromenteringanyportotherthanFa0/1.

Answer:CE交換機(jī)的f0/1端口上僅僅允許轉(zhuǎn)發(fā)server的流量,因此我們可以配置將server的mac地址和交換機(jī)的端口進(jìn)行綁定。然后用在端口f0/1上配置端口安全以過(guò)濾其他除server外的流量。

121.TheOSPFHelloprotocolperformswhichofthefollowingtasks?(Choosetwo.)

A.Itprovidesdynamicneighbordiscovery.

B.Itdetectsunreachableneighborsin90secondintervals.

C.Itmaintainsneighborrelationships.

D.Itnegotiatescorrectnessparametersbetweenneighboringinterfaces.

E.Itusestimerstoelecttherouterwiththefastestlinksasthedesignatedrouter.

F.ItbroadcastshellopacketsthroughouttheinternetworktodiscoverallroutersthatarerunningOSPF.

Answer:ACOSPF的Hello包的作用是發(fā)現(xiàn)并維持鄰居關(guān)系。

122.WhichtwopasswordsmustbesuppliedinordertoconnectbyTelnettoaproperlysecuredCiscoswitchandmakechangestothedeviceconfiguration?(Choosetwo.)

A.consolepasswordB.vtypasswordC.auxpasswordD.ttypassword

E.enablesecretpasswordF.usernamepassword

Answer:BE

123.Refertotheexhibit.WhatIPaddressshouldbeassignedtoWorkstationA?28CE.60/28

Answer:C因?yàn)榻粨Q機(jī)連接的設(shè)備是在同一個(gè)網(wǎng)段中的,因此WorkstationA分配的IP地址應(yīng)該是和路由器的Fa0/0的地址是在同一個(gè)網(wǎng)段的。Fa0/0的地址為,他包括的地址范圍為44-59,而為網(wǎng)絡(luò)地址為這個(gè)網(wǎng)段的廣播地址,所以可以使用的地址就是45-58.所以可以看出答案中可以分配給WorkstationA的地址為。

A.40B.52

C.640D.652

E.840F.852

Answer:C進(jìn)行匯總:還是將他們換算成二進(jìn)制的形式,然后找相同的位數(shù),就可以得到,即。

125.AninboundaccesslisthasbeenconfiguredonaserialinterfacetodenypacketentryforTCPandUDPports21,23and25.WhattypesofpacketswillbepermittedbythisACL?(Choosethree.)

A.FTPB.TelnetC.SMTPD.DNSE.HTTPF.POP3

Answer:DEF有些常用的公用端口號(hào)是我們需要記住的:FTP(20,21),Telnet(23),SMTP-Email(25),DNS(53),TFTP(69),WWW(80),POP郵件(110)。在這,我們過(guò)濾了端口號(hào)為21,23和25的端口號(hào)的流量,因此就是過(guò)濾了FTP,Telnet和SMTP的流量,剩下的就是可以允許的。

A.Thenetworkhasnotfullyconverged.B.IProutingisnotenabled.

C.Astaticrouteisconfiguredincorrectly.

D.TheFastEthernetinterfaceonCoffeeisdisabled.

E.Theneighborrelationshiptableisnotcorrectlyupdated.

F.TheroutingtableonCoffeehasnotupdated.

Answer:C中的用戶是無(wú)法訪問(wèn)中的server的,因?yàn)槁酚善鰿offee上沒(méi)有到達(dá)這個(gè)網(wǎng)段的路由。雖然說(shuō)路由器Coffee上有一條缺省的靜態(tài)路由,但是這個(gè)缺省路由的出接口卻是路由器Coffee上沒(méi)有的地址。因此無(wú)法訪問(wèn)的原因就是這個(gè)缺省路由的配置出現(xiàn)了問(wèn)題。

127.WhydoesthedatacommunicationindustryusethelayeredOSIreferencemodel?(Choosetwo.)

A.Itdividesthenetworkcommunicationprocessintosmallerandsimplercomponents,thusaidingcomponentdevelopment,design,andtroubleshooting.

B.Itenablesequipmentfromdifferentvendorstousethesameelectroniccomponents,thussavingresearchanddevelopmentfunds.

C.Itsupportstheevolutionofmultiplecompetingstandards,andthusprovidesbusinessopportunitiesforequipmentmanufacturers.

D.Itencouragesindustrystandardizationbydefiningwhatfunctionsoccurateachlayerofthemodel.

E.Itprovidesameansbywhichchangesinfunctionalityinonelayerrequirechangesinotherlayers.

Answer:ADswitchportport-securitymaximum1這個(gè)命令是配置這個(gè)端口為安全模式且只允許有學(xué)習(xí)一個(gè)mac地址。Switchportport-securityviolationshutdown:這句命令的意思是如果借口違反了安全策略就shutdown該接口。

128.Refertotheexhibit.RIPv2isinuseonthenetworkwithnostandardpolicyinplaceforsummarization.ApacketarrivesatCentralRouterwithadestinationIPaddressof1.Giventheoutputthatisshown,howwillCentralRouterprocessthatpacket?A.Itwillforwardthepacketto0.B.Itwillforwardthepacketto2.

C.Itwillforwardthepacketto.D.Itwillholdthepacketfor22seconds.

E.Itwillholdthepacketfor21seconds.F.Itwilldiscardthepacketbecausethereisnomatchingroute.

Answer:B

129.Thenetworksecuritypolicyrequiresthatonlyonehostbepermittedtoattachdynamicallytoeachswitchinterface.Ifthatpolicyisviolated,theinterfaceshouldshutdown.Whichtwocommandsmustthenetworkadministratorconfigureonthe2950Catalystswitchtomeetthispolicy?(Choosetwo.)

A.Switch1(config-if)#switchportport-securitymaximum1

B.Switch1(config)#mac-address-tablesecure

C.Switch1(config)#access-list10permitiphost

D.Switch1(config-if)#switchportport-securityviolationshutdown

E.Switch1(config-if)#ipaccess-group10

Answer:ADswitchportport-securitymaximum1這個(gè)命令是配置這個(gè)端口為安全模式且只允許有學(xué)習(xí)一個(gè)mac地址。Switchportport-securityviolationshutdown:這句命令的意思是如果借口違反了安全策略就shutdown該接口。

130.Refertotheexhibit.AnetworkassociatehasconfiguredOSPFwiththecommand:City(config-router)#network4.63area0Aftercompletingtheconfiguration,theassociatediscoversthatnotalltheinterfacesareparticipatinginOSPF.WhichthreeoftheinterfacesshownintheexhibitwillparticipateinOSPFaccordingtothisconfigurationstatement?(Choosethree.)

A.FastEthernet0/0B.FastEthernet0/1C.Serial0/0D.Serial0/1.102

E.Serial0/1.103F.Serial0/1.104

Answer:BCD4.63匹配的地址范圍是4-27,所以被激活的接口有FastEthernet0/1,Serial0/0,Serial0/1.102.

131.Refertotheexhibit.ExplainhowtheroutesinthetablearebeingaffectedbythestatuschangeoninterfaceEthernet0.

A.Switch2istherootbridge.

B.SpanningTreeisnotrunning.

C.HostDandServer1areinthesamenetwork.

D.NocollisionscanoccurintrafficbetweenHostBandHostC.

E.IfFa0/0isdownonRouter1,HostAcannotaccessServer1.

F.IfFa0/1isdownonSwitch3,HostCcannotaccessServer2.

Answer:E這個(gè)涉及到多個(gè)交換機(jī)的多個(gè)VLAN間的通訊。而在交換機(jī)之間有一個(gè)環(huán)路,因此生成樹阻斷了其中的一個(gè)接口,根據(jù)生成樹的原理,block的端口是在非根橋上的,因此switch2不會(huì)是根橋。而hostD和server一看就不是在相同的VLAN之間,因此是不在相同的網(wǎng)絡(luò)中的。我們說(shuō)整個(gè)hub是一個(gè)大的沖突域和廣播域,此hostB和hostC之間是有沖突存在的。HostA和server在不同的VLAN之間,他們之間通訊是要借助于Router1的接口Fa0/0的子接口來(lái)實(shí)現(xiàn)的,因此如果Router1的接口Fa0/0down了,那么HostA和server1之間就無(wú)法通訊了。同理hostC與server2之間的通訊也是借助于Router1的Fa0/0來(lái)實(shí)現(xiàn)的,如果switch3的Fa0/1down了,那么生成樹的就會(huì)重新選舉,以前block的接口就會(huì)起來(lái)轉(zhuǎn)發(fā)數(shù)據(jù),hostC就通過(guò)switch2將他的數(shù)據(jù)發(fā)送出去,他與server2之間的連通性還是不能失去的。

133.WhichstatementsaretrueaboutEIGRPsuccessorroutes?(Choosetwo.)

A.AsuccessorrouteisusedbyEIGRPtoforwardtraffictoadestination.

B.Successorroutesaresavedinthetopologytabletobeusediftheprimaryroutefails.

C.Successorroutesareflaggedas"active"intheroutingtable.

D.Asuccessorroutemaybebackedupbyafeasiblesuccessorroute.

E.Successorroutesarestoredintheneighbortablefollowingthediscoveryprocess.

Answer:ADEIGRP的successor路徑是他選出的最優(yōu)的路徑,路由器將選擇這條路徑到達(dá)目的地。而feasiblesuccessor則是successor的備份的路徑,如果successor路徑出了問(wèn)題,就立即將feasiblesuccessor路徑轉(zhuǎn)為successor路徑轉(zhuǎn)發(fā)數(shù)據(jù)。

134.Whichofthefollowingistrueregardingtheuseofswitchesandhubsfornetworkconnectivity?

A.Switchestakelesstimetoprocessframesthanhubstake.

B.Switchesdonotforwardbroadcasts.

C.Hubscanfilterframes.

D.Usinghubscanincreasetheamountofbandwidthavailabletohosts.

E.Switchesincreasethenumberofcollisiondomainsinthenetwork.

Answer:E

135.Whyhasthenetworkshownintheexhibitfailedtoconverge?

A.Thenoauto-summarycommandneedstobeappliedtotherouters.

B.Thenetworknumbershavenotbeenproperlyconfiguredontherouters.

C.Thesubnetmasksforthenetworknumbershavenotbeenproperlyconfigured.

D.Theautonomoussystemnumberhasnotbeenproperlyconfigured.

E.Thebandwidthvalueshavenotbeenproperlyconfiguredontheserialinterfaces.

Answer:A

136.DNSserversprovidewhatservice?

A.GivenanIPaddress,theydeterminethenameofthehostthatissought.

B.TheyconvertdomainnamesintoIPaddresses.

C.Theyrunaspellcheckonhostnamestoensureaccuraterouting.

D.TheymapindividualhoststotheirspecificIPaddresses.

Answer:B

137.WhataretwocharacteristicsofTelnet?(Choosetwo.)

A.Itsendsdataincleartextformat.

B.ItisnolongersupportedonCisconetworkdevices.

C.ItismoresecurethanSSH.

D.Itrequiresanenterpriselicenseinordertobeimplemented.

E.ItrequiresthatthedestinationdevicebeconfiguredtosupportTelnetconnections.

Answer:AE

138.WhatTCP/IPstackconfigurationfeaturescanDHCPprovide,inadditiontoassigninganIPaddress?(Choosethree.)

A.defaultgatewayB.DNSserversC.FTPserverD.helperaddress

E.subnetmaskF.TFTPserver

Answer:ABE

139.WhichofthefollowingarekeycharacteristicsofPPP?(Choosethree.)

A.canbeusedoveranalogcircuits

B.mapsLayer2toLayer3address

C.encapsulatesseveralroutedprotocols

D.supportsIPonly

E.provideserrorcorrection

Answer:ACE

140.Refertotheexhibit.ThenetworkadministratorhasdiscoveredthattheVLANconfigurationofSwitchCisotsynchronizedwiththerestoftheswitchednetwork.WhyisSwitchCnotreceivingVTPupdates?

A.SwitchBisnotrelayingVTPadvertisementstoSwitchC.

B.SwitchChasfewerexistingVLANsthandoesSwitchA.

C.SwitchAsupportsagreaternumberofVLANsthandoesSwitchC.

D.SwitchChasarevisionnumberhigherthanthatbeingadvertised.

E.SwitchCshouldbeoperatinginVTPservermodetoreceiveVTPupdates.

F.SwitchBshouldbeoperatinginVTPserverorclientmodetorelayVTPupdates.

Answer:D

141.ThenetworkadministratoroftheOregonrouteraddsthefollowingcommandtotherouterconfiguration:iproute.Whataretheresultsofaddingthiscommand?(Choosetwo.)

A.Thecommandestablishesastaticroute.

B.Thecommandinvokesadynamicroutingprotocolfor.

C.Trafficfornetworkisforwardedto.

D.Trafficforallnetworksisforwardedto.

E.Thisrouteisautomaticallypropagatedthroughouttheentirenetwork.

F.Trafficfornetworkisforwardedtothenetwork.

Answer:AC

142.WhatwillanEthernetswitchdoifitreceivesaunicastframewithadestinationMACthatislistedintheswitchtable?

A.Theswitchwillnotforwardunicastframes.

B.Theswitchwillforwardtheframetoaspecificport.

C.Theswitchwillreturnacopyoftheframeoutthesourceport.

D.TheswitchwillremovethedestinationMACfromtheswitchtable.

E.Theswitchwillforwardtheframetoallportsexcepttheportonwhichitwasreceived.

Answer:B

143.ACiscorouterthatwasprovidingFrameRelayconnectivityataremotesitewasreplacedwithadifferentvendor'sframerelayrouter.Connectivityisnowdownbetweenthecentralandremotesite.Whatisthemostlikelycauseoftheproblem?

A.mismatchedLMItypes

B.incorrectDLCI

C.mismatchedencapsulationtypes

D.incorrectIPaddressmapping

Answer:C

144.TheEthernetnetworksconnectedtorouterR1inthegraphichavebeensummarizedforrouterR2as/20.WhichofthefollowingpacketdestinationaddresseswillR2forwardtoR1,accordingtothissummary?(Choosetwo.)

A.B.1C.1D.54

E.45F.44

Answer:AD

145.Whichtwopracticeshelpsecuretheconfigurationutilitiesonwirelessaccesspointsfromunauthorizedaccess?(Choosetwo.)

A.assigningaprivateIPaddresstotheAPB.changingthedefaultSSIDvalue

C.configuringanewadministratorpasswordD.changingthemixedmodesettingtosinglemodeE.configuringtrafficfiltering

Answer:BC

A.CorporaterouterB.EngineeringrouterC.SalesrouterD.allrouters

E.allroutersandswitches

Answer:A

147.IfanethernetportonarouterwasassignedanIPaddressof/20,whatisthemaximumnumberofhostsallowedonthissubnet?

A.1024B.2046C.4094D.4096E.8190

Answer:C

148.WhichtablesofEIGRProuteinformationareheldinRAMandmaintainedthroughtheuseofhelloandupdatepackets?(Choosetwo.)

A.neighbortableB.SPFtableC.RTPtableD.topologytableE.querytable

A.HQ_Routerlastreceivedanupdatefrom2at3:30am.

B.IfHQ_Routerdoesnotreceiveanupdatefrom2in30seconds,allroutesfromthatsourcewillberemovedfromtheroutingtable.

C.IfHQ_Routerdoesnotreceiveanupdatefrom2in30seconds,allroutesfromthatsourcewillbeflaggedwithahold-downtimer.

D.2isexpectedtosendanupdatetoHQ_Routerfornetworkin3minutesand30seconds.

Answer:B

150.Refertotheexhibit.AnetworkassociateneedstoconfiguretheswitchesandrouterinthegraphicsothatthehostsinVLAN3andVLAN4cancommunicatewiththeenterpriseserverinVLAN2.WhichtwoEthernetsegmentswouldneedtobeconfiguredastrunklinks?(Choosetwo.)

A.AB.BC.CD.DE.EF.FAnswer:CF

151.Refertotheexhibit.WhyaretwoOSPFdesignatedroutersidentifiedonCore_Router?

A.Core_Routerisconnectedtomorethanonemultiaccessnetwork.

B.Therouterat30isasecondaryDRincasetheprimaryfails.

C.TworouterIDshavethesameOSPFpriorityandarethereforetiedforDRelection.

D.TheDRelectionisstillunderwayandtherearetwocontendersfortherole.

Answer:A

152.ArouterlearnsaboutaremotenetworkfromEIGRP,OSPF,andastaticroute.Assumingallroutingprotocolsareusingtheirdefaultadministrativedistance,whichroutewilltherouterusetoforwarddatatotheremotenetwork?

A.Therouterwillusethestaticroute.B.TherouterwillusetheOSPFroute.

C.TherouterwillusetheEIGRProute.D.Therouterwillloadbalanceanduseallthreeroutes.

Answer:A

153.Refertotheexhibit.Anewsubnetwith12hostshasbeenaddedtothenetwork.Whichsubnetaddressshouldthisnetworkusetoprovideenoughuseableaddresseswhilewastingthefewestaddresses?29CD.6/29

Answer:C

154.WhatisonereasonthatWPAencryptionispreferredoverWEP?

A.AWPAkeyislongerandrequiresmorespecialcharactersthantheWEPkey.

B.TheaccesspointandtheclientaremanuallyconfiguredwithdifferentWPAkeyvalues.

C.WPAkeyvaluesremainthesameuntiltheclientconfigurationischanged.

D.ThevaluesofWPAkeyscanchangedynamicallywhilethesystemisused.

Answer:D

155.AnaccesslisthasbeendesignedtopreventHTTPtrafficfromtheAccountingDepartmentfromreachingtheHRserverattachedtotheHolyokerouter.Whichofthefollowingaccesslistswillaccomplishthistaskwhengroupedwiththee0interfaceontheChicopee

A.permitipanyany

denytcp.25552eq80

B.permitipanyany

denytcp52.055eq80

C.denytcp5255eq80

permitipanyany

D.denytcp.25552eq80

permitipanyany

Answer:D

156.Refertotheexhibit.ThenetworkadministratormustcompletetheconnectionbetweentheRTAoftheXYZCompanyandtheserviceprovider.Toaccomplishthistask,whichtwodevicescouldbeinstalledatthecustomersitetoprovideaconnectionthroughthelocallooptothecentralofficeoftheprovider?(Choosetwo.)

A.WANswitchB.PVCC.ATMswitchD.multiplexerE.CSU/DSUF.modem

Answer:EF

157.WhenarouterisconnectedtoaFrameRelayWANlinkusingaserialDTEinterface,howistheinterfaceclockratedetermined?

A.ItissuppliedbytheCSU/DSU.B.Itissuppliedbythefarendrouter.

C.Itisdeterminedbytheclockratecommand.D.ItissuppliedbytheLayer1bitstreamtiming.

Answer:A

158.WhenanewtrunklinkisconfiguredonanIOSbasedswitch,whichVLANsareallowedoverthelink?

A.Bydefault,alldefinedVLANsareallowedonthetrunk.

B.EachsingleVLAN,orVLANrange,mustbespecifiedwiththeswitchportmodecommand.

C.EachsingleVLAN,orVLANrange,mustbespecifiedwiththevtpdomaincommand.

D.EachsingleVLAN,orVLANrange,mustbespecifiedwiththevlandatabasecommand.

Answer:A

159.Acknowledgements,sequencing,andflowcontrolarecharacteristicsofwhichOSIlayer?

A.Layer2B.Layer3C.Layer4D.Layer5E.Layer6F.Layer7

Answer:C

160.Whichofthefollowingaretypesofflowcontrol?(Choosethree.)

A.bufferingB.cut-throughC.windowingD.congestionavoidanceE.loadbalancing

Answer:ACD

161.WhichprotocolprovidesamethodofsharingVLANconfigurationinformationbetweenswitches?

A.VTPB.STPC.ISLD.802.1QE.VLSM

Answer:A

162.Refertotheexhibit.HowwillrouterAchooseapathtothe.0/24networkwhendifferentroutingpr

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