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新版CCNA802v13題庫(kù)分析(三)100.Whichofthefollowingstatementsdescribethenetworkshowninthegraphic?(Choosetwo.)
A.Therearetwobroadcastdomainsinthenetwork.
B.Therearefourbroadcastdomainsinthenetwork.
C.Therearesixbroadcastdomainsinthenetwork.
D.Therearefourcollisiondomainsinthenetwork.
E.Therearefivecollisiondomainsinthenetwork.
F.Therearesevencollisiondomainsinthenetwork.
Answer:AF這是個(gè)廣播域和沖突域的問(wèn)題。首先我們需要知道HUB整體是一個(gè)廣播域和沖突域,而交換機(jī)整體是一個(gè)廣播域,每個(gè)接口都是一個(gè)沖突域。知道了這些,這個(gè)問(wèn)題的答案就很明顯了,有兩個(gè)廣播域和七個(gè)沖突域。都沒(méi)有到Attalla的映射,所以也無(wú)法和Attalla建立連通性。
101.Whichofthefollowingaretrueregardingthecommandoutputshowninthedisplay?(Choosetwo.)
A.ThereareatleasttworoutersparticipatingintheRIPprocess.
B.Apingtowillbesuccessful.
C.Apingto.2willbesuccessful.
D.RtrAhasthreeinterfacesparticipatingintheRIPprocess.
Answer:AC因?yàn)镽IP的metric是基于跳數(shù)的,在debugiprip中RtrA發(fā)出的路由的metric為2,所以在RIP進(jìn)程下至少有兩臺(tái)路由器;而.0metric1表示這個(gè)路由是自己直連的,所以是能成功的。
102.Whatthreepiecesofinformationcanbeusedinanextendedaccesslisttofiltertraffic?(Choosethree.)
A.protocolB.VLANnumberC.TCPorUDPportnumbers
D.sourceswitchportnumberE.sourceIPaddressanddestinationIPaddress
F.sourceMACaddressanddestinationMACaddress
Answer:ACEACL是基于三層的過(guò)濾,因此他可以基于ip,portnumber來(lái)過(guò)濾流量,擴(kuò)展的訪問(wèn)控制列表是可以基于源和目的的同時(shí)的過(guò)濾。
103.Refertotheexhibit.WhichtwostatementsaretrueaboutinterVLANroutinginthetopologythatisshownintheexhibit?(Choosetwo.)
A.HostEandhostFusethesameIPgatewayaddress.
B.Router1andSwitch2shouldbeconnectedviaacrossovercable.
C.Router1willnotplayaroleincommunicationsbetweenhostAandhostD.
D.TheFastEthernet0/0interfaceonRouter1mustbeconfiguredwithsubinterfaces.
E.Router1needsmoreLANinterfacestoaccommodatetheVLANsthatareshownintheexhibit.
F.TheFastEthernet0/0interfaceonRouter1andSwitch2trunkportsmustbeconfiguredusingthesameencapsulationtype.
Answer:DF為了實(shí)現(xiàn)相同相同交換機(jī)間的不同VLAN之間的通訊應(yīng)該用的三層的設(shè)備,借助trunk來(lái)實(shí)現(xiàn)。因此要將Router1和switch2相連的接口配置為trunk,trunk的模式還應(yīng)該是相同的,不同的trunk的封裝,是無(wú)法實(shí)現(xiàn)連通性的。
104.Whatistheeffectofusingtheservicepassword-encryptioncommand?
A.Onlytheenablepasswordwillbeencrypted.
B.Onlytheenablesecretpasswordwillbeencrypted.
C.Onlypasswordsconfiguredafterthecommandhasbeenenteredwillbeencrypted.
D.Itwillencryptthesecretpasswordandremovetheenablesecretpasswordfromtheconfiguration.
E.Itwillencryptallcurrentandfuturepasswords.
Answer:Epasswordencryption是為了給密碼加密。
A.Router1hasspecificbootsystemcommandsthatinstructittoloadIOSfromaTFTPserver.
B.Router1isactingasaTFTPserverforotherrouters.
C.Router1cannotlocateavalidIOSimageinflashmemory.
D.Router1defaultedtoROMMONmodeandloadedtheIOSimagefromaTFTPserver.
E.CiscorouterswillfirstattempttoloadanimagefromTFTPformanagementpurposes.
Answer:ACSystemimagefileis?°t29/Hampton/nitro/c7200-j-mz?±這句話表明系統(tǒng)的鏡像來(lái)自從tftp。引導(dǎo)程序首先使用flash中所找到的第一個(gè)有效的IOS鏡像,如果flash中沒(méi)有有效的IOS鏡像,引導(dǎo)程序?qū)⑸梢粋€(gè)TFTP本地廣播以定位TFTP服務(wù)器,如果沒(méi)有找到TFTP服務(wù)器,引導(dǎo)程序?qū)⒓虞dROM中的迷你IOS(RXBOOT模式),如果ROM中有迷你IOS,那么迷你IOS在隨后加載并且進(jìn)入RXBOOT模式;否則路由器不是重新試圖尋找IOS鏡像,就是加載ROMMON并且進(jìn)入ROMMonitor模式。因此說(shuō)明Router1在flash中沒(méi)有找到有效的IOS鏡像。從而加載了tftp中的鏡像。
106.AtwhichOSIlayerisalogicalpathcreatedbetweentwohostsystems?
A.sessionB.transportC.networkD.datalinkE.physical
Answer:C我們所說(shuō)的IP地址就是一個(gè)邏輯的地址,他是在OSI七層模型中的第三層network層創(chuàng)建的。是用于通訊的邏輯的地址。
107.Whatfunctionsdoroutersperforminanetwork?(Choosetwo.)
A.packetswitchingB.accesslayersecurityC.pathselection
D.VLANmembershipassignmentE.bridgingbetweenLANsegments
F.microsegmentationofbroadcastdomains
Answer:AC路由器在一個(gè)網(wǎng)絡(luò)中的作用是選擇路徑進(jìn)行轉(zhuǎn)發(fā)。
108.Refertotheexhibit.Theshowvtpstatuscommandisexecutedataswitchthatisgeneratingtheexhibitedoutput.Whichstatementistrueforthisswitch?
A.TheswitchforwardsitsVLANdatabasetootherswitchesintheICNDVTPdomain.
B.TheconfigurationrevisionnumberincrementseachtimetheVLANdatabaseisupdated.
C.TheswitchforwardsVTPupdatesthataresentbyotherswitchesintheICNDdomain.
D.TheVLANdatabaseisupdatedwhenVTPinformationisreceivedfromotherswitches.
Answer:CVTP是為了動(dòng)態(tài)學(xué)習(xí)和同步VLAN信息的,但是他的同步和學(xué)習(xí)都是以域?yàn)閱挝坏?,只有同一個(gè)域中的VLAN信息才可以同步和學(xué)習(xí)。而VTP的模式有三種:server,client,transparent。其中transparent模式為通明橋的模式,在這種模式下的VLAN的信息是不能被其他設(shè)備學(xué)習(xí)到的,而切這種模式下的設(shè)備也不學(xué)習(xí)其他設(shè)備的VLAN信息,他只是轉(zhuǎn)發(fā)VLAN的信息,但是不學(xué)習(xí)。
109.ACiscorouterisbootingandhasjustcompletedthePOSTprocess.ItisnowreadytofindandloadanIOS
image.Whatfunctiondoestherouterperformnext?
A.Itcheckstheconfigurationregister.
B.ItattemptstobootfromaTFTPserver.
C.Itloadsthefirstimagefileinflashmemory.
D.ItinspectstheconfigurationfileinNVRAMforbootinstructions.
Answer:A
110.Refertotheexhibit.Theoutputthatisshownisgeneratedataswitch.Whichthreeofthesestatementsaretrue?(Choosethree.)
A.Allportswillbeinastateofdiscarding,learning,orforwarding.
B.ThirtyVLANshavebeenconfiguredonthisswitch.
C.Thebridgepriorityislowerthanthedefaultvalueforspanningtree.
D.Allinterfacesthatareshownareonsharedmedia.
E.Alldesignatedportsareinaforwardingstate.
F.ThisswitchmustbetherootbridgeforallVLANsonthisswitch.
Answer:ACE
111.Whatisthefunctionofthecommandswitchporttrunknativevlan999onaCiscoCatalystswitch?
A.ItcreatesaVLAN999interface.
B.ItdesignatesVLAN999foruntaggedtraffic.
C.ItblocksVLAN999trafficfrompassingonthetrunk.
D.ItdesignatesVLAN999asthedefaultforallunknowntaggedtraffic.
Answer:Bnativevlan是不打標(biāo)簽的VLAN,這指定nativevlan為999,表明VLAN999為不用打標(biāo)簽的VLAN
112.Refertotheexhibit.AfteraRIProuteismarkedinvalidonRouter_1,howmuchtimewillelapsebeforethatrouteisremovedfromtheroutingtable?
A.30secondsB.60secondsC.90secondsD.180secondsE.240seconds
Answer:B
113.Whenanewtrunkisconfiguredona2950switch,whichVLANsbydefaultareallowedoverthetrunklink?
A.noVLANsB.allVLANsC.onlyVLANs1-64
D.onlytheVLANsthatarespecifiedwhencreatingthetrunk
Answer:BTrunk上默認(rèn)是可以轉(zhuǎn)發(fā)所有VLAN的數(shù)據(jù)的。
114.WhichthreestatementsdescribethedifferencesbetweenRIPversion1andRIPversion2?(Choosethree.)
A.RIPversion1broadcastsupdateswhereasRIPversion2usesmulticasts.
B.RIPversion1multicastsupdateswhileRIPversion2usesbroadcasts.
C.BothRIPversion1andRIPversion2areclasslessroutingprotocols.
D.RIPVersion2isaclasslessroutingprotocolwhereasRIPversion1isaclassfulroutingprotocol.
E.BothRIPversion1andversion2supportauthentication.
F.RIPversion2sendsthesubnetmaskinupdatesandRIPversion1doesnot.
Answer:ADF
115.Anaccesslistwaswrittenwiththefourstatementsshowninthegraphic.Whichsingleaccessliststatementwillcombineallfourofthesestatementsintoasinglestatementthatwillhaveexactlythesameeffect?
A.access-list10permit.255B.access-list10permit55
C.access-list10permit55D.access-list10permit55
E.access-list10permit55
Answer:C用一個(gè)單獨(dú)的語(yǔ)句來(lái)匹配上面寫出的四條ACL,也就一一個(gè)匯總的問(wèn)題,將,進(jìn)行匯總,將他們的第3個(gè)八字節(jié)以二進(jìn)制展開,相同的位作為他們的匯總的條目,然后計(jì)算他們的掩碼位數(shù)為多少,所以這四個(gè)條目匯總到一個(gè)條目為/22,掩碼用通配符來(lái)寫應(yīng)該是.255。
116.Refertotheexhibit.Alloftheroutersinthenetworkareconfiguredwiththeipsubnet-zerocommand.WhichnetworkaddressesshouldbeusedforLinkAandNetworkA?(Choosetwo.)2530F.LinkA-12/30
Answer:BD這是個(gè)IP地址規(guī)劃的考題。NetworkA中有120臺(tái)主機(jī),因此NetworkA中至少需要122個(gè)IP地址,根據(jù)公式2n>=122,可以解出n=7,因此網(wǎng)絡(luò)位為32-7=25,容納的IP地址為128。因此NetworkA的網(wǎng)段就可以為或。通過(guò)其他的設(shè)備分配的地址可以看到的地址已經(jīng)有一部分分配出去了,因此NetworkA分配的地址空間只能是只需要有兩個(gè)可用的IP地址,因此網(wǎng)段中需要有4個(gè)地址根據(jù)公式2n>=4,可以解出n=2,因此網(wǎng)絡(luò)位為32-2=30。而從其他路由器上的地址分配我們可以看到地址-5,2-27這些IP地址都已經(jīng)分配出去了,因此結(jié)合答案我們可以看到LinkA的地址空間只能為。
117.AtwhichlayersoftheOSImodeldoWANsoperate?(Choosetwo.)
A.applicationlayerB.sessionlayerC.transportlayerD.networklayer
E.datalinklayerF.physicallayer
Answer:EFWAN是工作在一層和二層的,比如現(xiàn)在常用的Frame-relay,ATM等這些都是工作在OSI的二層的。
A.HQ(config)#iproute
Branch(config)#iproute
B.HQ(config)#routerrip
HQ(config-router)#network
HQ(config-router)#network
Branch(config)#routerrip
Branch(config-router)#network
Branch(config-router)#network
C.HQ(config)#routereigrp56
HQ(config-router)#network
HQ(config-router)#network
Branch(config)#routereigrp56
Branch(config-router)#network
Branch(config-router)#network
D.HQ(config)#routerospf1
HQ(config-router)#network.3area0
HQ(config-router)#network.255area0
Branch(config)#routerospf1
Branch(config-router)#network.255area0
Branch(config-router)#network.3area0
Answer:A動(dòng)態(tài)路由協(xié)議都是需要有他的更新包來(lái)傳遞路由的,而這些都是會(huì)占用帶寬的,為了減小流量的沖突我們可以采用靜態(tài)路由,他是會(huì)占用任何帶寬的。
119.Refertotheexhibit.Whatisthepurposeoftheconfigurationthatisshown?
A.totranslateaddressesofhostsonthefa0/0andfa0/1networkstoasinglepublicIPaddressforInternetaccess
B.totranslatetheinternaladdressofeachhostonfa0/0andfa0/1toauniqueexternalIPaddressforInternetacces
C.toprovidesecurityonfa0/0andfa0/1throughtheapplicationofanaccesslist
D.toallowIPhostsontheInternettoinitiateTCP/IPconnectionstohostsonfa0/0andfa0/1
Answer:A
120.AnetworkadministratorwantstoensurethatonlytheservercanconnecttoportFa0/1onaCatalystswitch.TheserverispluggedintotheswitchFa0/1portandthenetworkadministratorisabouttobringtheserveronline.WhatcantheadministratordotoensurethatonlytheMACaddressoftheserverisallowedbyswitchportFa0/1?
A.ConfigureportFa0/1toacceptconnectionsonlyfromthestaticIPaddressoftheserver.
B.EmployaproprietaryconnectortypeonFa0/1thatisincompatiblewithotherhostconnectors.
C.ConfiguretheMACaddressoftheserverasastaticentryassociatedwithportFa0/1.
D.BindtheIPaddressoftheservertoitsMACaddressontheswitchtopreventotherhostsfromspoofingtheserverIPaddress.
E.ConfigureportsecurityonFa0/1torejecttrafficwithasourceMACaddressotherthanthatoftheserver.
F.ConfigureanaccesslistontheswitchtodenyservertrafficfromenteringanyportotherthanFa0/1.
Answer:CE交換機(jī)的f0/1端口上僅僅允許轉(zhuǎn)發(fā)server的流量,因此我們可以配置將server的mac地址和交換機(jī)的端口進(jìn)行綁定。然后用在端口f0/1上配置端口安全以過(guò)濾其他除server外的流量。
121.TheOSPFHelloprotocolperformswhichofthefollowingtasks?(Choosetwo.)
A.Itprovidesdynamicneighbordiscovery.
B.Itdetectsunreachableneighborsin90secondintervals.
C.Itmaintainsneighborrelationships.
D.Itnegotiatescorrectnessparametersbetweenneighboringinterfaces.
E.Itusestimerstoelecttherouterwiththefastestlinksasthedesignatedrouter.
F.ItbroadcastshellopacketsthroughouttheinternetworktodiscoverallroutersthatarerunningOSPF.
Answer:ACOSPF的Hello包的作用是發(fā)現(xiàn)并維持鄰居關(guān)系。
122.WhichtwopasswordsmustbesuppliedinordertoconnectbyTelnettoaproperlysecuredCiscoswitchandmakechangestothedeviceconfiguration?(Choosetwo.)
A.consolepasswordB.vtypasswordC.auxpasswordD.ttypassword
E.enablesecretpasswordF.usernamepassword
Answer:BE
123.Refertotheexhibit.WhatIPaddressshouldbeassignedtoWorkstationA?28CE.60/28
Answer:C因?yàn)榻粨Q機(jī)連接的設(shè)備是在同一個(gè)網(wǎng)段中的,因此WorkstationA分配的IP地址應(yīng)該是和路由器的Fa0/0的地址是在同一個(gè)網(wǎng)段的。Fa0/0的地址為,他包括的地址范圍為44-59,而為網(wǎng)絡(luò)地址為這個(gè)網(wǎng)段的廣播地址,所以可以使用的地址就是45-58.所以可以看出答案中可以分配給WorkstationA的地址為。
A.40B.52
C.640D.652
E.840F.852
Answer:C進(jìn)行匯總:還是將他們換算成二進(jìn)制的形式,然后找相同的位數(shù),就可以得到,即。
125.AninboundaccesslisthasbeenconfiguredonaserialinterfacetodenypacketentryforTCPandUDPports21,23and25.WhattypesofpacketswillbepermittedbythisACL?(Choosethree.)
A.FTPB.TelnetC.SMTPD.DNSE.HTTPF.POP3
Answer:DEF有些常用的公用端口號(hào)是我們需要記住的:FTP(20,21),Telnet(23),SMTP-Email(25),DNS(53),TFTP(69),WWW(80),POP郵件(110)。在這,我們過(guò)濾了端口號(hào)為21,23和25的端口號(hào)的流量,因此就是過(guò)濾了FTP,Telnet和SMTP的流量,剩下的就是可以允許的。
A.Thenetworkhasnotfullyconverged.B.IProutingisnotenabled.
C.Astaticrouteisconfiguredincorrectly.
D.TheFastEthernetinterfaceonCoffeeisdisabled.
E.Theneighborrelationshiptableisnotcorrectlyupdated.
F.TheroutingtableonCoffeehasnotupdated.
Answer:C中的用戶是無(wú)法訪問(wèn)中的server的,因?yàn)槁酚善鰿offee上沒(méi)有到達(dá)這個(gè)網(wǎng)段的路由。雖然說(shuō)路由器Coffee上有一條缺省的靜態(tài)路由,但是這個(gè)缺省路由的出接口卻是路由器Coffee上沒(méi)有的地址。因此無(wú)法訪問(wèn)的原因就是這個(gè)缺省路由的配置出現(xiàn)了問(wèn)題。
127.WhydoesthedatacommunicationindustryusethelayeredOSIreferencemodel?(Choosetwo.)
A.Itdividesthenetworkcommunicationprocessintosmallerandsimplercomponents,thusaidingcomponentdevelopment,design,andtroubleshooting.
B.Itenablesequipmentfromdifferentvendorstousethesameelectroniccomponents,thussavingresearchanddevelopmentfunds.
C.Itsupportstheevolutionofmultiplecompetingstandards,andthusprovidesbusinessopportunitiesforequipmentmanufacturers.
D.Itencouragesindustrystandardizationbydefiningwhatfunctionsoccurateachlayerofthemodel.
E.Itprovidesameansbywhichchangesinfunctionalityinonelayerrequirechangesinotherlayers.
Answer:ADswitchportport-securitymaximum1這個(gè)命令是配置這個(gè)端口為安全模式且只允許有學(xué)習(xí)一個(gè)mac地址。Switchportport-securityviolationshutdown:這句命令的意思是如果借口違反了安全策略就shutdown該接口。
128.Refertotheexhibit.RIPv2isinuseonthenetworkwithnostandardpolicyinplaceforsummarization.ApacketarrivesatCentralRouterwithadestinationIPaddressof1.Giventheoutputthatisshown,howwillCentralRouterprocessthatpacket?A.Itwillforwardthepacketto0.B.Itwillforwardthepacketto2.
C.Itwillforwardthepacketto.D.Itwillholdthepacketfor22seconds.
E.Itwillholdthepacketfor21seconds.F.Itwilldiscardthepacketbecausethereisnomatchingroute.
Answer:B
129.Thenetworksecuritypolicyrequiresthatonlyonehostbepermittedtoattachdynamicallytoeachswitchinterface.Ifthatpolicyisviolated,theinterfaceshouldshutdown.Whichtwocommandsmustthenetworkadministratorconfigureonthe2950Catalystswitchtomeetthispolicy?(Choosetwo.)
A.Switch1(config-if)#switchportport-securitymaximum1
B.Switch1(config)#mac-address-tablesecure
C.Switch1(config)#access-list10permitiphost
D.Switch1(config-if)#switchportport-securityviolationshutdown
E.Switch1(config-if)#ipaccess-group10
Answer:ADswitchportport-securitymaximum1這個(gè)命令是配置這個(gè)端口為安全模式且只允許有學(xué)習(xí)一個(gè)mac地址。Switchportport-securityviolationshutdown:這句命令的意思是如果借口違反了安全策略就shutdown該接口。
130.Refertotheexhibit.AnetworkassociatehasconfiguredOSPFwiththecommand:City(config-router)#network4.63area0Aftercompletingtheconfiguration,theassociatediscoversthatnotalltheinterfacesareparticipatinginOSPF.WhichthreeoftheinterfacesshownintheexhibitwillparticipateinOSPFaccordingtothisconfigurationstatement?(Choosethree.)
A.FastEthernet0/0B.FastEthernet0/1C.Serial0/0D.Serial0/1.102
E.Serial0/1.103F.Serial0/1.104
Answer:BCD4.63匹配的地址范圍是4-27,所以被激活的接口有FastEthernet0/1,Serial0/0,Serial0/1.102.
131.Refertotheexhibit.ExplainhowtheroutesinthetablearebeingaffectedbythestatuschangeoninterfaceEthernet0.
A.Switch2istherootbridge.
B.SpanningTreeisnotrunning.
C.HostDandServer1areinthesamenetwork.
D.NocollisionscanoccurintrafficbetweenHostBandHostC.
E.IfFa0/0isdownonRouter1,HostAcannotaccessServer1.
F.IfFa0/1isdownonSwitch3,HostCcannotaccessServer2.
Answer:E這個(gè)涉及到多個(gè)交換機(jī)的多個(gè)VLAN間的通訊。而在交換機(jī)之間有一個(gè)環(huán)路,因此生成樹阻斷了其中的一個(gè)接口,根據(jù)生成樹的原理,block的端口是在非根橋上的,因此switch2不會(huì)是根橋。而hostD和server一看就不是在相同的VLAN之間,因此是不在相同的網(wǎng)絡(luò)中的。我們說(shuō)整個(gè)hub是一個(gè)大的沖突域和廣播域,此hostB和hostC之間是有沖突存在的。HostA和server在不同的VLAN之間,他們之間通訊是要借助于Router1的接口Fa0/0的子接口來(lái)實(shí)現(xiàn)的,因此如果Router1的接口Fa0/0down了,那么HostA和server1之間就無(wú)法通訊了。同理hostC與server2之間的通訊也是借助于Router1的Fa0/0來(lái)實(shí)現(xiàn)的,如果switch3的Fa0/1down了,那么生成樹的就會(huì)重新選舉,以前block的接口就會(huì)起來(lái)轉(zhuǎn)發(fā)數(shù)據(jù),hostC就通過(guò)switch2將他的數(shù)據(jù)發(fā)送出去,他與server2之間的連通性還是不能失去的。
133.WhichstatementsaretrueaboutEIGRPsuccessorroutes?(Choosetwo.)
A.AsuccessorrouteisusedbyEIGRPtoforwardtraffictoadestination.
B.Successorroutesaresavedinthetopologytabletobeusediftheprimaryroutefails.
C.Successorroutesareflaggedas"active"intheroutingtable.
D.Asuccessorroutemaybebackedupbyafeasiblesuccessorroute.
E.Successorroutesarestoredintheneighbortablefollowingthediscoveryprocess.
Answer:ADEIGRP的successor路徑是他選出的最優(yōu)的路徑,路由器將選擇這條路徑到達(dá)目的地。而feasiblesuccessor則是successor的備份的路徑,如果successor路徑出了問(wèn)題,就立即將feasiblesuccessor路徑轉(zhuǎn)為successor路徑轉(zhuǎn)發(fā)數(shù)據(jù)。
134.Whichofthefollowingistrueregardingtheuseofswitchesandhubsfornetworkconnectivity?
A.Switchestakelesstimetoprocessframesthanhubstake.
B.Switchesdonotforwardbroadcasts.
C.Hubscanfilterframes.
D.Usinghubscanincreasetheamountofbandwidthavailabletohosts.
E.Switchesincreasethenumberofcollisiondomainsinthenetwork.
Answer:E
135.Whyhasthenetworkshownintheexhibitfailedtoconverge?
A.Thenoauto-summarycommandneedstobeappliedtotherouters.
B.Thenetworknumbershavenotbeenproperlyconfiguredontherouters.
C.Thesubnetmasksforthenetworknumbershavenotbeenproperlyconfigured.
D.Theautonomoussystemnumberhasnotbeenproperlyconfigured.
E.Thebandwidthvalueshavenotbeenproperlyconfiguredontheserialinterfaces.
Answer:A
136.DNSserversprovidewhatservice?
A.GivenanIPaddress,theydeterminethenameofthehostthatissought.
B.TheyconvertdomainnamesintoIPaddresses.
C.Theyrunaspellcheckonhostnamestoensureaccuraterouting.
D.TheymapindividualhoststotheirspecificIPaddresses.
Answer:B
137.WhataretwocharacteristicsofTelnet?(Choosetwo.)
A.Itsendsdataincleartextformat.
B.ItisnolongersupportedonCisconetworkdevices.
C.ItismoresecurethanSSH.
D.Itrequiresanenterpriselicenseinordertobeimplemented.
E.ItrequiresthatthedestinationdevicebeconfiguredtosupportTelnetconnections.
Answer:AE
138.WhatTCP/IPstackconfigurationfeaturescanDHCPprovide,inadditiontoassigninganIPaddress?(Choosethree.)
A.defaultgatewayB.DNSserversC.FTPserverD.helperaddress
E.subnetmaskF.TFTPserver
Answer:ABE
139.WhichofthefollowingarekeycharacteristicsofPPP?(Choosethree.)
A.canbeusedoveranalogcircuits
B.mapsLayer2toLayer3address
C.encapsulatesseveralroutedprotocols
D.supportsIPonly
E.provideserrorcorrection
Answer:ACE
140.Refertotheexhibit.ThenetworkadministratorhasdiscoveredthattheVLANconfigurationofSwitchCisotsynchronizedwiththerestoftheswitchednetwork.WhyisSwitchCnotreceivingVTPupdates?
A.SwitchBisnotrelayingVTPadvertisementstoSwitchC.
B.SwitchChasfewerexistingVLANsthandoesSwitchA.
C.SwitchAsupportsagreaternumberofVLANsthandoesSwitchC.
D.SwitchChasarevisionnumberhigherthanthatbeingadvertised.
E.SwitchCshouldbeoperatinginVTPservermodetoreceiveVTPupdates.
F.SwitchBshouldbeoperatinginVTPserverorclientmodetorelayVTPupdates.
Answer:D
141.ThenetworkadministratoroftheOregonrouteraddsthefollowingcommandtotherouterconfiguration:iproute.Whataretheresultsofaddingthiscommand?(Choosetwo.)
A.Thecommandestablishesastaticroute.
B.Thecommandinvokesadynamicroutingprotocolfor.
C.Trafficfornetworkisforwardedto.
D.Trafficforallnetworksisforwardedto.
E.Thisrouteisautomaticallypropagatedthroughouttheentirenetwork.
F.Trafficfornetworkisforwardedtothenetwork.
Answer:AC
142.WhatwillanEthernetswitchdoifitreceivesaunicastframewithadestinationMACthatislistedintheswitchtable?
A.Theswitchwillnotforwardunicastframes.
B.Theswitchwillforwardtheframetoaspecificport.
C.Theswitchwillreturnacopyoftheframeoutthesourceport.
D.TheswitchwillremovethedestinationMACfromtheswitchtable.
E.Theswitchwillforwardtheframetoallportsexcepttheportonwhichitwasreceived.
Answer:B
143.ACiscorouterthatwasprovidingFrameRelayconnectivityataremotesitewasreplacedwithadifferentvendor'sframerelayrouter.Connectivityisnowdownbetweenthecentralandremotesite.Whatisthemostlikelycauseoftheproblem?
A.mismatchedLMItypes
B.incorrectDLCI
C.mismatchedencapsulationtypes
D.incorrectIPaddressmapping
Answer:C
144.TheEthernetnetworksconnectedtorouterR1inthegraphichavebeensummarizedforrouterR2as/20.WhichofthefollowingpacketdestinationaddresseswillR2forwardtoR1,accordingtothissummary?(Choosetwo.)
A.B.1C.1D.54
E.45F.44
Answer:AD
145.Whichtwopracticeshelpsecuretheconfigurationutilitiesonwirelessaccesspointsfromunauthorizedaccess?(Choosetwo.)
A.assigningaprivateIPaddresstotheAPB.changingthedefaultSSIDvalue
C.configuringanewadministratorpasswordD.changingthemixedmodesettingtosinglemodeE.configuringtrafficfiltering
Answer:BC
A.CorporaterouterB.EngineeringrouterC.SalesrouterD.allrouters
E.allroutersandswitches
Answer:A
147.IfanethernetportonarouterwasassignedanIPaddressof/20,whatisthemaximumnumberofhostsallowedonthissubnet?
A.1024B.2046C.4094D.4096E.8190
Answer:C
148.WhichtablesofEIGRProuteinformationareheldinRAMandmaintainedthroughtheuseofhelloandupdatepackets?(Choosetwo.)
A.neighbortableB.SPFtableC.RTPtableD.topologytableE.querytable
A.HQ_Routerlastreceivedanupdatefrom2at3:30am.
B.IfHQ_Routerdoesnotreceiveanupdatefrom2in30seconds,allroutesfromthatsourcewillberemovedfromtheroutingtable.
C.IfHQ_Routerdoesnotreceiveanupdatefrom2in30seconds,allroutesfromthatsourcewillbeflaggedwithahold-downtimer.
D.2isexpectedtosendanupdatetoHQ_Routerfornetworkin3minutesand30seconds.
Answer:B
150.Refertotheexhibit.AnetworkassociateneedstoconfiguretheswitchesandrouterinthegraphicsothatthehostsinVLAN3andVLAN4cancommunicatewiththeenterpriseserverinVLAN2.WhichtwoEthernetsegmentswouldneedtobeconfiguredastrunklinks?(Choosetwo.)
A.AB.BC.CD.DE.EF.FAnswer:CF
151.Refertotheexhibit.WhyaretwoOSPFdesignatedroutersidentifiedonCore_Router?
A.Core_Routerisconnectedtomorethanonemultiaccessnetwork.
B.Therouterat30isasecondaryDRincasetheprimaryfails.
C.TworouterIDshavethesameOSPFpriorityandarethereforetiedforDRelection.
D.TheDRelectionisstillunderwayandtherearetwocontendersfortherole.
Answer:A
152.ArouterlearnsaboutaremotenetworkfromEIGRP,OSPF,andastaticroute.Assumingallroutingprotocolsareusingtheirdefaultadministrativedistance,whichroutewilltherouterusetoforwarddatatotheremotenetwork?
A.Therouterwillusethestaticroute.B.TherouterwillusetheOSPFroute.
C.TherouterwillusetheEIGRProute.D.Therouterwillloadbalanceanduseallthreeroutes.
Answer:A
153.Refertotheexhibit.Anewsubnetwith12hostshasbeenaddedtothenetwork.Whichsubnetaddressshouldthisnetworkusetoprovideenoughuseableaddresseswhilewastingthefewestaddresses?29CD.6/29
Answer:C
154.WhatisonereasonthatWPAencryptionispreferredoverWEP?
A.AWPAkeyislongerandrequiresmorespecialcharactersthantheWEPkey.
B.TheaccesspointandtheclientaremanuallyconfiguredwithdifferentWPAkeyvalues.
C.WPAkeyvaluesremainthesameuntiltheclientconfigurationischanged.
D.ThevaluesofWPAkeyscanchangedynamicallywhilethesystemisused.
Answer:D
155.AnaccesslisthasbeendesignedtopreventHTTPtrafficfromtheAccountingDepartmentfromreachingtheHRserverattachedtotheHolyokerouter.Whichofthefollowingaccesslistswillaccomplishthistaskwhengroupedwiththee0interfaceontheChicopee
A.permitipanyany
denytcp.25552eq80
B.permitipanyany
denytcp52.055eq80
C.denytcp5255eq80
permitipanyany
D.denytcp.25552eq80
permitipanyany
Answer:D
156.Refertotheexhibit.ThenetworkadministratormustcompletetheconnectionbetweentheRTAoftheXYZCompanyandtheserviceprovider.Toaccomplishthistask,whichtwodevicescouldbeinstalledatthecustomersitetoprovideaconnectionthroughthelocallooptothecentralofficeoftheprovider?(Choosetwo.)
A.WANswitchB.PVCC.ATMswitchD.multiplexerE.CSU/DSUF.modem
Answer:EF
157.WhenarouterisconnectedtoaFrameRelayWANlinkusingaserialDTEinterface,howistheinterfaceclockratedetermined?
A.ItissuppliedbytheCSU/DSU.B.Itissuppliedbythefarendrouter.
C.Itisdeterminedbytheclockratecommand.D.ItissuppliedbytheLayer1bitstreamtiming.
Answer:A
158.WhenanewtrunklinkisconfiguredonanIOSbasedswitch,whichVLANsareallowedoverthelink?
A.Bydefault,alldefinedVLANsareallowedonthetrunk.
B.EachsingleVLAN,orVLANrange,mustbespecifiedwiththeswitchportmodecommand.
C.EachsingleVLAN,orVLANrange,mustbespecifiedwiththevtpdomaincommand.
D.EachsingleVLAN,orVLANrange,mustbespecifiedwiththevlandatabasecommand.
Answer:A
159.Acknowledgements,sequencing,andflowcontrolarecharacteristicsofwhichOSIlayer?
A.Layer2B.Layer3C.Layer4D.Layer5E.Layer6F.Layer7
Answer:C
160.Whichofthefollowingaretypesofflowcontrol?(Choosethree.)
A.bufferingB.cut-throughC.windowingD.congestionavoidanceE.loadbalancing
Answer:ACD
161.WhichprotocolprovidesamethodofsharingVLANconfigurationinformationbetweenswitches?
A.VTPB.STPC.ISLD.802.1QE.VLSM
Answer:A
162.Refertotheexhibit.HowwillrouterAchooseapathtothe.0/24networkwhendifferentroutingpr
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