考前高分沖刺：小升初經(jīng)典奧數(shù)試題及答案1

第頁考前高分沖刺：小升初經(jīng)典奧數(shù)試題及答案1考前高分沖刺：小升初經(jīng)典奧數(shù)試題及答案1、In2019,16JunefallsonaWednesday.Onwhatdayoftheweekwill16Junefallin2019?2、Ifhalfofanumberis30,thenthree-quartersofthatnumberis____.3、Thesumofthedigitsofthefollowingproduct9995554、Threepositiveintegershaveasumof28.Thegreatestpossibleproductthattheseintegerscanhaveis_____.5、Inwhatfollows,□andaredifferentnumbers.When503isdividedby□theremainderis20.When503isdividedbytheremainderis20.When493isdividedby□xtheremainderis_____.6、Alady,herbrother,hersonandherdaughter(allrelatedbybirth)playedvolleyball.Theworstplayerstwin(whoisoneofthefourplayers)andthebestplayerareofoppositesex.Theworstplayerandthebestplayerareofthesameage.Whocannotbetheworstplayer(s)?A)brotheronlyB)daughteronlyC)sonanddaughteronlyD)ladyanddaughteronlyE)ladyonly7、Ifyoucontinuethegivennumberpattern,inwhatrowandinwhatpositioninthatrowwillthenumber320be?1row123row2456row378910row4Theanswersaregivenintheorderofrow;position.參考答案：1、Wednesday2、453、27(求數(shù)位上上的數(shù)字之和)4、28=9+9+10,因此答案為8105、503-20=483483=3723=2123,因此□x=483,因此此題余數(shù)是10.6、D7、25,201、Didyouknow?Inthedecimalnumbersystem(base10)tendifferentdigits,0to9,areusedtowriteallthenumbers.Inthebinarynumbersystem(base2)twodifferentdigitsareused,i.e.0and1.Whichoneofthefollowingnumbersisnotavalidnumberintheoctalnumbersystem(base8)?A)128B)127C)126D)125E)1242、Thenumberofdiagonalsthatcanbedrawninaregularpolygonwithtwentysides(icosagon)is_____.3、Ifaandbareintegers,10??3=1,152??7=3,andthen379??6isequalto_____.4、Twonumbersareintheratio2:3.When4isaddedtoeachnumbertheratiochangesto5:7.Thesumofthetwooriginalnumbersis____.5、ThegreatestnumberofMondayswhichcanoccurin45consecutivedaysis____6、Saulplaysavideogameinwhichhescores4forahitandlost6foramiss.After20roundshisscoreis30.Thenumberoftimeshehasmissedis____.7、ThreegirlsA,BandCrunina100mrace.WhenAfinishes,Bis10mbehindAandwhenBfinishesCis20mbehindB.HowfarinmetreswasCfromAwhenAfinished?(Letsassumealltheathletesrunataconstantspeed)8、Theareasofthefacesofarectangulaboxare84cm2,70cm2and30cm2.Thevolumeoftheboxincm3is____.9、Youhave3weights:1kg,3kgand9kgaswellasanequalarmbalance,asshown.Howmanydifferentweightobjectscanyouweighwiththesethree?[Remembertheweightsmaybeplacedoneitherside]參考答案：1、A考察我們學(xué)過的簡單的進(jìn)制問題,顯然8進(jìn)制中沒有8出現(xiàn)2、170找規(guī)律,公式為n(n-3)23、1定義新運(yùn)算,就是求3796的余數(shù)。4、40,16和245、76、57、28米,根據(jù)距離比求出速度比,三者的速度比為1：9/10：18/258、420分解質(zhì)因數(shù)9、13種每道題的答題時(shí)間不超過15分鐘?！径昙墶空n內(nèi)知識：368-199等于多少呢?課外趣題：按數(shù)字規(guī)律填出下列圖中空缺的數(shù)：【三年級】課內(nèi)知識：操場上的學(xué)生們進(jìn)行隊(duì)列表演,他們排成了8行8列的正方形隊(duì)列,如果去掉一行一列,請問要去掉多少人?還剩多少人?課外趣題：有7個(gè)數(shù),它們的平均數(shù)是18。去掉一個(gè)數(shù)后,剩下6個(gè)數(shù)的平均數(shù)是19;再去掉一個(gè)數(shù)后,剩下5個(gè)數(shù)的平均數(shù)是20。求去掉的兩個(gè)數(shù)的乘積。【四年級】課內(nèi)知識：(1686+1683+1689+1681+1691+1685+1687+1678)8等于多少?課外趣題：假設(shè)在等差數(shù)列2,5,8,的每相鄰兩項(xiàng)中間插入三項(xiàng),使它構(gòu)成一個(gè)新的等差數(shù)列,那么原數(shù)列的第10項(xiàng),是新數(shù)列的第項(xiàng)。【五年級】課內(nèi)知識：求4018和7257的最大公約數(shù)。課外趣題：把一個(gè)自然數(shù)的各個(gè)數(shù)位上的數(shù)碼相加,所得的和假設(shè)不是一位數(shù),那么再把它的各個(gè)數(shù)位上的數(shù)碼相加,直到和是一位數(shù)為止。將12009這2009個(gè)自然數(shù)都經(jīng)過上述方法處理后,所得到的2009個(gè)數(shù)中,2和3哪個(gè)多?【二年級】1.368-199等于多少呢?解答：原式=368-200+1=168+1=1692.按數(shù)字規(guī)律填出下列圖中空缺的數(shù)：解答：此題的規(guī)律為上面兩個(gè)數(shù)的和等于下面兩個(gè)數(shù)的乘積,因此應(yīng)該填7?！救昙墶?.操場上的學(xué)生們進(jìn)行隊(duì)列表演,他們排成了8行8列的正方形隊(duì)列,如果去掉一行一列,請問要去掉多少人?還剩多少人?解答：每行每列都有8個(gè)人,而這一行一列必有一個(gè)人是重復(fù)的,所以減少的人數(shù)是82-1=15(人),88-15=49(人)2.有7個(gè)數(shù),它們的平均數(shù)是18。去掉一個(gè)數(shù)后,剩下6個(gè)數(shù)的平均數(shù)是19;再去掉一個(gè)數(shù)后,剩下5個(gè)數(shù)的平均數(shù)是20。求去掉的兩個(gè)數(shù)的乘積。解答：第一個(gè)去掉的數(shù)是187-196=12,第二個(gè)去掉的數(shù)是196-205=14,這兩個(gè)數(shù)的乘積為1214=168還可以用移多補(bǔ)少的方法：18-(19-18)6=1219-(20-19)5=141214=168【四年級】1.(1686+1683+1689+1681+1691+1685+1687+1678)8解答：原式=(16808+6+3+9+1+11+5+7-2)8=168088+(6+3+9+1+11+5+7-2)8=1680+408=16852.假設(shè)在等差數(shù)列2,5,8,的每相鄰兩項(xiàng)中間插入三項(xiàng),使它構(gòu)成一個(gè)新的等差數(shù)列,那么原數(shù)列的第10項(xiàng),是新數(shù)列的第項(xiàng)。解答：在每相鄰兩項(xiàng)中間插入三項(xiàng),那么原數(shù)列的第10項(xiàng)之前共插入了39=27項(xiàng),故原數(shù)列的第10項(xiàng)是新數(shù)列的第10+27=37項(xiàng)?！疚迥昙墶?.求4018和7257的最大公約數(shù)。解答：(7257,4018)=(3239,4018)=(3239,779)=(123,779)=(123,41)=412.把一個(gè)自然數(shù)的各個(gè)數(shù)位上的數(shù)碼相加,所得的和假設(shè)不是一位數(shù),那么再把它的