中考數(shù)學(xué)試卷精選合輯60之4課改試驗區(qū)初中畢業(yè)學(xué)業(yè)考試卷及答案

22232223試卷數(shù)》（試）、選題（本題分分共小每小題分）．實數(shù)、b在軸位圖示則與大小關(guān)是（）

圖A．bB．b．bD．斷．列計算錯誤是（）A－－）．

C．2x+3

=5

x

D．a(chǎn)．方程+1=0的（）1A．2

1B．2

．D．－2．點M在直線上則M點的坐標（）A，0））

C，））．如圖，直線截兩行線、b則下子定成是（）A．∠1=∠．∠C．∠D．∠2

l

．列說法正確是（）拋一幣，一定；．骰子，點數(shù)一定不大于；．一燈的用壽命宜用普查方；．的降水概率為”，明有80％地方下雨．下列圖形中，是軸對稱圖形但不是中心對稱圖形的是（）

圖

ABCD．如圖，在心角BOC圓周角等于（）A．60B．50C．．30

A．一函數(shù)yA第一象限

不經(jīng)的象是（）B第二限．三象限

D第限

B

圖．一個不透明的袋子中裝4個顏完同球中球個黃個紅2個摸一球放回，再出個，兩都到球的概率（）A

B

13

．

16

D．

18二填題（本題滿分分，共題小分11．式分：

2

____________12電視臺為滿足觀眾在北京奧運會間收看不同比賽項目的要求做一隨機查果如表最喜觀看項

游泳

體

操

球

類

田

徑人

數(shù)

3075200如果你是電視負責人在場直播，優(yōu)先考轉(zhuǎn)

比．

13函數(shù)

1

的變量的取值范圍．

F14如，、是

ABC

兩的中點，=3，=．15．已的徑，心O到線l的離，直l與

O的位置系．

圖4

C已邊形中A90

，添加一個條

件即可定該四邊形是方形，那么這個條可以是．17．知錐面是，母線是4，它的側(cè)積______．ABC．如圖5，D是AB邊上點將沿過的線折，使落BC上處若50__________．三、題題分分，共小題，每題6分）12sin30．計算()2

D

F圖5

20．解不等式組：5

21．題如圖，先將ABC向平移個得ABC，直線為軸作軸反射得到1111C22

，在所給的方紙中依次作出和C．1122l圖．汶川地搶險隊直升飛機去、B兩村莊搶險，飛機地米上的點，測得村的俯為30村俯角為圖A、兩個村莊的離果到米，參數(shù)

，1.732Q

．函數(shù)y＋b的圖與反比例函數(shù)

y

4x

450C圖的像交于（2(－m，求次數(shù)解析．、證題（本分如圖Δ腰形它邊BC翻折到請斷形ABDC的，并說你的由．

CD圖五、用（題滿分分，共題小分．我府年起對職中在校學(xué)給予生補貼．每生每年補1500．預(yù)年業(yè)中專在校生人數(shù)是年1.2要基礎(chǔ)上增加投入600該市職業(yè)中專在校有多少萬人，補多少萬？．我國府定從2008月日限制用塑料袋5的某一天，小明和小剛在本市A、C三型市市對限令的態(tài)度進行一次隨調(diào)查．結(jié)果如下面圖表：超

BC

合計

、、C三家超市共計態(tài)

人數(shù)贊同不贊無所

551501728105

贊同無所

50不贊15

50（1）此次共調(diào)了人（2）將表補完；

A兩超市計

圖9

贊同不贊無所

態(tài)度（3）你學(xué)過統(tǒng)知來明個市的查果能映費的態(tài)．六、合題（題滿分分）27如圖10平行四邊形ABCD中＝5＝BC邊上高AME為上的一動不與、重作線垂線，垂足為．FE與DC的延長線點，結(jié)，DF．求：BEF∽CEG．當點在段上eq\o\ac(△,動)eq\o\ac(△,和)的長有關(guān)？并說明你的理由．（3）設(shè)x，eq\o\ac(△,＝)的積為求yx間的函關(guān)，出x何值時y最大值，最大值是多少？

DF

x

圖

G2008數(shù)學(xué)參答案評分準答案答案選擇題本題滿分20分，共10小題，每題2分）CDBCDBADAC填空題本題滿分16分，共8題，每小題2分）題號

121318

乒乓球

6

切

=BC或者BC或者

CD=DA或者DA三、解題（本題滿分30分，共5小題，每題6分）19原式－1＋1····························································分＝．不等式①<②>-

···························································6分··················································2分·····················································4分所這個不等式組的解集為-x················································6分21．出圖形，每個分圖略）·············································6分22．：據(jù)題得30，以APB，以=PB在中，90PBC以3003sin

································分，=450，·······································5分以PB3520答：．

(米)·······························································6分423．解：因為（，）在上，以x所點的標為－1，－）··························································分又、點在一次函數(shù)的圖像上，,解得:所以b所所求的一次函數(shù)為=2x-2四、明（題分分）．四形ABCD形理由：

··················································5分·································6分················································2分由eq\o\ac(△,≌)DBC．以,ABBDeq\o\ac(△,因)為等腰角形，所以AB以＝＝＝，故邊形ABCD為形

····分·········································7分··········································8分注如果學(xué)生只答四邊形ABCD為行形1分說理確給分共分．五、應(yīng)題（本題滿分分，共小題每小題分）25．）設(shè)2007職業(yè)中專的在校生為x萬人根據(jù)題得：x1500x················································分解：所以．2.4

······································分2.43600·······································································分答：．．300（人）（2），，，略

····································分·························································分·······································分（3）超市說明，理合理行··········分、綜題（題滿分分）27）形是平行四形，以AB·······················分以GCE,

GBFE以eq\o\ac(△,所)BEF··········································································分）eq\o\ac(△,（)eq\o\ac(△,與)的周長之和定值．··············································分理由：過作行直AB于H，因為GF⊥AB以形為形所以＝，F(xiàn)G＝此，eq\o\ac(△,因)eq\o\ac(△,與)周和于BC＋由BC，＝5，＝4，可得，BH＝，所以BC＋＝·········································································6分理由：由＝5，AM＝，知Rteq\o\ac(△,在)與eq\o\ac(△,Rt)GCE中有：44EFBF,GEEC,GCCE，551212B以，eq\o\ac(△,所)的長是eq\o\ac(△,，)的周是55

FM

x

G

又＝10因BEF與周長之和是．······························分4)（3）設(shè)BE＝x，x,GC5136以y[(10)x2655121配方：y(x)．