重慶市2022-2023學(xué)年高一上學(xué)期期末數(shù)學(xué)試題（原卷版）

高一上學(xué)期期末數(shù)學(xué)試題一、選擇題：本題共8小題，每小題5分，共40分.在每小題給出的四個選項中，只有一項是符合題目要求的.1.SKIPIF1<0化成弧度()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.已知集合SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<03.已知SKIPIF1<0：正整數(shù)SKIPIF1<0能被6整除，SKIPIF1<0，則SKIPIF1<0是SKIPIF1<0的()A.充分不必要條件 B.必要不充分條件C.充要條件 D.既不充分也不必要條件4.已知SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<05.命題SKIPIF1<0，使得函數(shù)SKIPIF1<0在SKIPIF1<0上不單調(diào)，則命題SKIPIF1<0的否定是()A.SKIPIF1<0，函數(shù)SKIPIF1<0在SKIPIF1<0上不單調(diào)B.SKIPIF1<0，函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)C.SKIPIF1<0，函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)D.SKIPIF1<0，函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)6.下列函數(shù)中既是奇函數(shù)又是減函數(shù)的是()ASKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<07.已知函數(shù)SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0的取值范圍是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<08.已知函數(shù)SKIPIF1<0，若SKIPIF1<0，則實數(shù)SKIPIF1<0取值范圍是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0二、選擇題：本題共4小題，每小題5分，共20分.在每小題給出的選項中，有多項符合題目要求.全部選對的得5分，部分選對的得2分，有選錯的得0分.9.下列說法中正確的是()A.任何集合都至少有兩個子集B.設(shè)SKIPIF1<0為全集，SKIPIF1<0，SKIPIF1<0，SKIPIF1<0是SKIPIF1<0的子集，若SKIPIF1<0，則SKIPIF1<0C.命題“SKIPIF1<0，SKIPIF1<0”的否定為“SKIPIF1<0，SKIPIF1<0”D.若SKIPIF1<0是SKIPIF1<0的必要不充分條件，SKIPIF1<0的必要不充分條件是SKIPIF1<0，則SKIPIF1<0是SKIPIF1<0的充分條件10.已知冪函數(shù)SKIPIF1<0，則()A.SKIPIF1<0，函數(shù)SKIPIF1<0的圖像與坐標(biāo)軸沒有交點B.SKIPIF1<0，使得SKIPIF1<0奇函數(shù)C.當(dāng)SKIPIF1<0時，函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞增D.當(dāng)SKIPIF1<0時，函數(shù)SKIPIF1<0的值域為SKIPIF1<011.已知SKIPIF1<0，則()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<012.已知函數(shù)SKIPIF1<0和函數(shù)SKIPIF1<0，關(guān)于SKIPIF1<0的方程SKIPIF1<0有SKIPIF1<0個實根，則下列說法中正確的是()A.當(dāng)SKIPIF1<0時，SKIPIF1<0 B.當(dāng)SKIPIF1<0時，SKIPIF1<0CSKIPIF1<0，SKIPIF1<0 D.SKIPIF1<0，SKIPIF1<0三、填空題：本題共4小題，每小題5分，共20分.13.函數(shù)SKIPIF1<0的定義域是______.14.SKIPIF1<0______.15.已知某扇形材料的面積為SKIPIF1<0，圓心角為SKIPIF1<0，則用此材料切割出的面積最大的圓的周長為______.16.已知函數(shù)SKIPIF1<0.若SKIPIF1<0，則SKIPIF1<0的值域是______；若SKIPIF1<0恰有2個零點，則實數(shù)SKIPIF1<0的取值范圍是______.四、解答題：本題共6小題，共70分.解答應(yīng)寫出文字說明、證明過程或演算步驟.17.已知SKIPIF1<0，集合SKIPIF1<0，SKIPIF1<0.(1)當(dāng)SKIPIF1<0時，求SKIPIF1<0，SKIPIF1<0；(2)若SKIPIF1<0，求SKIPIF1<0的取值范圍.18.(1)求SKIPIF1<0的值；(2)已知SKIPIF1<0，求SKIPIF1<0的值.19.已知SKIPIF1<0，SKIPIF1<0.(1)求SKIPIF1<0的取值范圍；(2)求SKIPIF1<0的最小值.20.已知SKIPIF1<0，集合SKIPIF1<0，SKIPIF1<0.(1)求集合SKIPIF1<0；(2)若SKIPIF1<0，求實數(shù)SKIPIF1<0的取值范圍.21.某電影院每天最多可制作500桶爆米花，每桶售價相同，根據(jù)影院的經(jīng)營經(jīng)驗，當(dāng)每桶售價不超過20元時，當(dāng)天可售出500桶；當(dāng)每桶售價高于20元時，售價每高出1元，當(dāng)天就少售出20桶.已知每桶爆米花的成本是4元，設(shè)每桶爆米花的售價為SKIPIF1<0(SKIPIF1<0且SKIPIF1<0)元，該電影院一天出售爆米花所獲利潤為SKIPIF1<0元.(總收入=總成本+利潤)(1)求SKIPIF1<0關(guān)于SKIPIF1<0的函數(shù)表達(dá)式；(2)試問每桶爆米花的售價定為多少元時，該電影院一天出售爆米花所獲利潤最大？最大利潤為多少元？22.已知函數(shù)SK