2024年Java認(rèn)證歷年考試高頻考點(diǎn)試題附帶答案

2024年Java認(rèn)證歷年考試高頻考點(diǎn)試題附帶答案（圖片大小可自由調(diào)整）第1卷一.參考題庫(共25題)1.金星和地球在某一時(shí)刻相對于太陽處于某一確定位置，已知金星繞太陽一周為225日，地球繞太陽一周為365日，問兩個(gè)行星至少經(jīng)過多少日仍同時(shí)回到原來的位置上2.Assume?a?tag?handler?extends?TagSupport.?Which?is?used?within?the?tag?handler?to?get?an?attribute?“foo”?that?is?in?the?application?scope？（）A、?pageContext.getAttribute（“foo”）；B、?getPageContext（）.getAttribute（“foo”）；C、?pageContext.getApplicationScope（“foo”）；D、?pageContext.getAttribute（“foo”，pageContext.APPLICATION_SCOPE）.getAttribute（“foo”）；E、?getPageContext（）.getScope（pageContext.APPLICATION_SCOPE）.getAttribute（“foo”）；3.下列哪項(xiàng)是用于輸入的字符流？（）?A、?WriterB、?ReaderC、?OutputStreamD、?Stream4.已知： 則輸出為（）A、elcB、elC、lD、lco5.class?Beta?{? public?static?void?main（String?[]?args）?{? Integer?x?=?new?Integer（6）?*?7；? if?（x?!=?42）?{? System.out.print（"42?"）；? }?else?if?（x?〈?new?Integer（44-1））?{? System.out.println（"less"）；? }?else?{? System.out.print（"done"）； }?}?}? 結(jié)果是什么？（）?A、lessB、42C、doneD、編譯失敗6.Java源文件的后綴名是？（）??A、.classB、.cC、.javaD、.txt7.public?class?CreditCard?{? private?String?cardlD；? private?Integer?limit；? public?String?ownerName；? public?void?setCardlnformation（String?cardlD，? String?ownerName，?28.?Integer?limit）?{? this.cardlD?=?cardlD；? this.ownerName?=?ownerName；? this.limit?=?limit；? }? } Which?is?true？（）?A、?The?class?is?fully?encapsulated.B、?The?code?demonstrates?polymorphism.C、?The?ownerName?variable?breaks?encapsulation.D、?The?cardlD?and?limit?variables?break?polymorphism.E、?The?setCardlnformation?method?breaks?encapsulation.8.現(xiàn)有：? class?ThreadBoth?extends?Threaa?implements?Runnable??{????? public?void?run（）??（System.out.print（"hi"）；??}???? public?static?voicl?main?（String??[]??args）??{???? Thread?tl=new?ThreadBoth（）：????? Thread?t2?=?new?Thread?（tl）：???? tl.run（）：????? t2.run（）：???? }????????? 結(jié)果為：（）??????A、?hi?hiB、?hiC、編譯失敗D、運(yùn)行時(shí)異常被拋出9.A?developer?chooses?to?avoid?using?SingleThreadModel?but?wants?to?ensure?that?data?is?updated?in?athread-safe?manner. Which?two?can?support?this?design?goal？（）A、Store?the?data?in?a?local?variable.B、Store?the?data?in?an?instance?variable.C、Store?the?data?in?the?HttpSession?object.D、Store?the?data?in?the?ServletContext?object.E、Store?the?data?in?the?ServletRequest?object.10.Which?can?be?used?to?decode?charS?for?output？（）??A、?Java.io.InputStream.B、?Java.io.EncodedReader.C、?Java.io.InputStreamReader.D、?Java.io.InputStreamWriter.E、?Java.io.BufferedInputStream.11.What?is?the?result？（） A、7B、49C、343D、Compilation?fails.E、An?exception?is?thrown?at?runtime.12.1.?class?super?{? 2.?public?float?getNum（）?{return?3.0f；}? 3.?}? 4.??? 5.?public?class?Sub?extends?Super?{ 6.?? 7.?}?? Which?method，?placed?at?line?6，?will?cause?a?compiler?error？（）??A、??Public?float?getNum（）???{return?4.0f；?}B、??Public?void?getNum?（）??{?}C、??Public?void?getNum?（double?d）???{?}D、??Public?double?getNum?（float?d）?{retrun?4.0f；?}13.同構(gòu)數(shù)? 一個(gè)數(shù)出現(xiàn)在該數(shù)的平方數(shù)的右邊，稱這個(gè)數(shù)為“同構(gòu)數(shù)”。例如，5出現(xiàn)在平方數(shù)25的右邊，25出現(xiàn)在平方數(shù)625的右邊，則5、25都是“同構(gòu)數(shù)”。求[1，1000]之間的所有“同構(gòu)數(shù)”的個(gè)數(shù)14.高次方程尾數(shù)的問題：求13的298次方的最后三位數(shù)是多少？編程實(shí)現(xiàn)之15.已知： 則輸出為（）A、GraduateStudentB、StudentC、PersonD、Object16.已知： 那么結(jié)果為？（）A、BDB、DBC、CD、編譯錯(cuò)誤17.寫一個(gè)類，并在一個(gè)方法拋出一個(gè)異常。試著在沒有異常規(guī)范的前提下編譯它，觀察編譯器會報(bào)告什么。接著添加適當(dāng)?shù)漠惓Ｒ?guī)范。在一個(gè)try-catch從句中嘗試自己的類以及它的異常。18.共有幾組i、j、k符合算式ijk+kji=1333，其中i、j、k是0~9之間的一位整數(shù)19.完成數(shù)組int[]a={100，40，60，87，34，11，56，0}的快速排序、冒泡排序20. Which?two?are?true？（）A、?The?function?method?must?have?the?signaturepublic：?String?spin（）.B、?The?method?must?be?mapped?to?the?logical?name?“spin”?in?the?web.xml?file.C、?The?function?method?must?have?the?signature：public?String?spinIt（）.D、?The?function?method?must?have?the?signature：public?static?String?spin（）.E、?The?function?method?must?have?the?signature：public?static?String?spinIT（）.F、?The?function?class?must?be?named?Spinner，?and?must?be?in?the?package?com.example.21.文本框的常用功能函數(shù)和屬性有哪些？（）A、selectAll函數(shù)，選中文本框中的所有文字B、getText函數(shù)，獲得用戶輸入的文字內(nèi)容C、在構(gòu)造函數(shù)中設(shè)置文本框中可以顯示的字符長度D、setUnicodeChar，設(shè)置文本框能否顯示的字符長度E、seLineWrap，設(shè)置文本框能否顯示多于一行的內(nèi)容22.用公式pi/4=1-1/3+1/5-1/7+…求pi（pi為圓周率）的近似值，直到最后一項(xiàng)的絕對值小于指定的數(shù)（參數(shù)num）為止23.接口中的成員方法被隱含地聲明為（）A、publicstaticfinalB、protectedabstactC、privateD、publicabstract24.在一個(gè)單CPU的處理機(jī)中，有P1，P3，P5三個(gè)作業(yè)，有兩個(gè)IO設(shè)備IO1，IO2，并且能夠?qū)崿F(xiàn)搶先式多任務(wù)并行工作的多道程序環(huán)境中，投入運(yùn)行優(yōu)先級由高到低P5，P1，P3三個(gè)作業(yè)，他們使用設(shè)備的先后順序和占用設(shè)備的時(shí)間分別為：P1：IO2（10ms）CPU（10ms）IO1（30ms）CPU（10ms）P3：IO1（30ms）CPU（10ms）IO2（30ms）CPU（10ms）P5：CPU（20ms）IO1（30ms）CPU（10ms）IO2（15ms）忽略其他的時(shí)間損耗，3個(gè)作業(yè)投入到全部完成的情況下。請問下列哪些選項(xiàng)為IO2的設(shè)備利用率（）。A、0.55B、0.26C、0.48D、0.5E、0.3925.Which?two，?inserted?at?line?11，?will?allow?the?code?to?compile？（） A、public?class?MinMax{B、public?class?MinMax{C、public?class?MinMax{D、public?class?MinMax{E、public?class?MinMax{F、public?class?MinMax{第2卷一.參考題庫(共25題)1.框架中包括哪些窗格？?（）A、有根窗格、分層窗格、內(nèi)容窗格、工具欄、玻璃窗格等B、只有根窗格、內(nèi)容窗格、工具藍(lán)C、只有內(nèi)容窗格、工具欄D、只有內(nèi)容窗格2.public?class?Wow?{? public?static?void?go（short?n）?{System.out.println（”short”）；?}? public?static?void?go（Short?n）?{System.out.println（”SHORT”）；}? public?static?void?go（Long?n）?{System.out.println（”?LONG”）；?}? public?static?void?main（String?[]?args）?{? Short?y=?6；? int?z=7；? go（y）；? go（z）；? }? }? What?is?the?result？（）?A、?short?LONGB、?SHORT?LONGC、?Compilation?fails.D、?An?exception?is?thrown?at?runtime.3.Click?the?’Select?and?Place’?button. Place?the?events?in?the?order?they?occur. 4.現(xiàn)有：?? 1.??class?HorseRadish?｛?? 2.????//?insert?code?here?? 3.????protected?HorseRadish（int?x）?｛??? 4.??????System.out.println（"bok?choy"）；? 5.????｝? 6.??｝?? 7.??class?Wasabi?extends?HorseRadish?｛?? 8.????public?static?void?main（String?[]?args）?｛?? 9.??????Wasabi?w?＝?new?Wasabi（）；? 10.???｝??? 11.?｝?? 分別插入到第?2?行，哪兩項(xiàng)允許代碼編譯并產(chǎn)生"bok?choy"?輸出結(jié)果？（）?A、?//?just?a?commentB、?protected?HorseRadish（）?｛?｝C、?protected?HorseRadish（）?｛?this（42）；｝D、?protected??HorseRadish（）?｛?new?HorseRadish?（42）；｝5.public?class?Test?{? public?static?void?main（String[]?args）?{? int?x?=?0；? assert?（x?>?0）?？?“assertion?failed”?：?“assertion?passed”；? System.out.println（“Finished”）；? }? }? What?is?the?result？（）??A、?finishedB、?Compilation?fails.C、?An?AssertionError?is?thrown?and?finished?is?output.D、?An?AssertionError?is?thrown?with?the?message?“assertion?failed”.E、?An?AssertionError?is?thrown?with?the?message?“assertion?passed”.6.84.?try?{? 85.?ResourceConnection?con?=?resourceFactory.getConnection（）；? 86.?Results?r?=?con.query（”GET?INFO?FROM?CUSTOMER”）；? 87.?info?=?r.getData（）；? 88.?con.close（）；? 89.?}?catch?（ResourceException?re）?{? 90.?errorLog.write（re.getMessage（））；? 91.?}? 92.?return?info；? Which?is?true?if?a?ResourceException?is?thrown?on?line?86？（）?A、?Line?92?will?not?execute.B、?The?connection?will?not?be?retrieved?in?line?85.C、?The?resource?connection?will?not?be?closed?on?line?88.D、?The?enclosing?method?will?throw?an?exception?to?its?caller.7.public?class?Transfers?{? public?static?void?main（String[]?args）?throws?Exception?{? Record?r1?=?new?Record（）；? Record?r2?=?new?Record（）；? doTransfer（r1，?r2，?5）；? doTransfer（r2，?r1，?2）；? doTransfer（r1，?r2，?1）；? //?print?the?result? System.out.println（”rl?=?“?+?r1.get（）?+“，?r2=”?+?r2.get（））；? }? private?static?void?doTransfer（? final?Record?a，?final?Record?b，?final?int?amount）?{? Thread?t?=?new?Thread（）?{? public?void?run（）?{? new?Clerk（）.transfer（a，?b，?amount）；? }? }；? t.start（）；? }? }? class?Clerk?{? public?synchronized?void?transfer（Record?a，?Record?b，?int?amount）{? synchronized?（a）?{? synchronized?（b）?{? a.add（-amount）；? b.add（amount）；? }? }? }? }? class?Record?{? int?num=10；? public?int?get（）?{?return?num；?}? public?void?add（int?n）?{?num?=?num?+?n；?}? }? If?Transfers.main（）?is?run，?which?three?are?true？（）A、?The?output?may?be?“r1?=?6，?r2?=?14”.B、?The?output?may?be?“r1?=?5，?r2?=?15”.C、?The?output?may?be?“r1?=?8，?r2?=?12”.D、?The?code?may?run?（and?complete）?with?no?output.E、?The?code?may?deadlock?（without?completing）?with?no?output.F、?M?IllegalStateException?or?InterruptedException?may?be?thrown?at?runtime.8.如何在框架中顯示標(biāo)題？（）???A、?調(diào)用根窗格的set?Title?函數(shù)顯示B、?調(diào)用內(nèi)容窗格的setTitle函數(shù)顯示C、?調(diào)用框架對象的setTitle函數(shù)顯示D、?調(diào)用框架對象的Border對象的setTitle函數(shù)顯示9.現(xiàn)有2?個(gè)文件： ?1.?package?x；? 2.?public?class?X?{? 3.?public?static?void?doX（）?{?System.out.print（"doX?"）；?}? 4.?}? 和：? 1.?class?Find?{? 2.?public?static?void?main（String?[]?args）?{? 3.?//insert?code?here? 4.?}? 5.?}? 哪兩行分別插入到類Find?的第3?行將編譯并產(chǎn)生輸出“doX”？?（）A、doX（）；B、X.doX（）；C、x.X.doX（）；D、x.X?myX?=?new?x.X（）；?myX.doX（）；10.A?RequestDispatcher?can?be?obtained?from?which?two?objects？?（）A、?ServletConfigB、?ServletContextC、?HttpServletRequestD、?HttpServletResponse11.Given： 11. Which?three?EL?expressions?are?valid?and?evaluate?to?true？（）A、${not?map.c}B、${map.d?or?map.a}C、${map.a?and?map.d}D、${map.false?or?map.true}E、${map.a?and?map.b?or?map.a}12.關(guān)閉框架時(shí)，缺省地也會關(guān)閉整個(gè)應(yīng)用程序。13.11.?abstract?class?Vehicle?{?public?int?speed（）?{?return?0；?}?}? 12.?class?Car?extends?Vehicle?{?public?int?speed（）?{?return?60；?}?}? 13.?class?RaceCar?extends?Car?{?public?int?speed（）?{?return?150；?}} ?? 21.?RaceCar?racer?=?new?RaceCar（）；? 22.?Car?car?=?new?RaceCar（）；? 23.?Vehicle?vehicle?=?new?RaceCar（）；? 24.?System.out.println（racer.speed（）?+?“，???+?car.speed（）? 25.?+?“，?“+?vehicle.speed（））；? What?is?the?result？（）?A、?0，?0，0B、?150，?60，?0C、?Compilation?fails.D、?150，?150，?150E、?An?exception?is?thrown?at?runtime.14.設(shè)有方法： 則b可以為（）A、nullB、b的類型為AC、b的類型為A的子類D、b的類型為A的父類15.A?programmer?is?designing?a?class?to?encapsulate?the?information?about?an?inventory?item.?A?JavaBeans?component?is?needed?to?do?this.?The?Inventoryltem?class?has?private?instance?variables?to?store?the?item?information：? 10.?private?int?itemId；? 11.?private?String?name；? 12.?private?String?description；? Which?method?signature?follows?the?JavaBeans?naming?standards?for?modifying?the?itemld?instance?variable？（）?A、?itemID（int?itemId）B、?update（int?itemId）C、?setItemId（int?itemId）D、?mutateItemId（int?itemId）E、?updateItemID（int?itemId）16.1.?import?java.util.*；? 2.? 3.?Class?FindStuff?｛? 4.?public?static?void??main（String?[]?args）?｛? 5.?//?insert?code?here? 6.?c.put（"x"，?123）；? 7.?｝? 8.?｝ 分別插入到第5行，哪三行允許代碼編譯？（）?A、Map?c?＝?new?SortedMap（）；B、HashMap?c?＝?new?HashMap（）；C、HashMap?c?＝?new?Hashtable（）；D、SortedMap?c?＝?new?TreeMap（）；17.求1～200之間的能被7整除的數(shù)的平方和18.import?java.util.*；? public?class?WrappedString?{? private?String?s；? public?WrappedString（String?s）?{?this.s?=?s；?}? public?static?void?main（String[]?args）?{? HashSet?hs?=?new?HashSet（）；? WrappedString?ws1?=?new?WrappedString（”aardvark”）；? WrappedString?ws2?=?new?WrappedString（”aardvark”）；? String?s1?=?new?String（”aardvark”）；? String?s2?=?new?String（”aardvark”）；? hs.add（ws1）；?hs.add（ws2）；?hs.add（s1）；?hs.add（s2）；? System.out.println（hs.size（））；?}?}? What?is?the?result？（）? A、?0B、?1C、?2D、?3E、?4F、?Compilation?fails.G、?An?exception?is?thrown?at?runtime.19.表格包約束的“gridwidth”，“gridheight”屬性有什么作用？（）A、表示用戶垃大框架時(shí)，單元格所能夠分配到的空間B、表示單元格的寬度和高度C、表示組件的寬度和高度D、表示組件在寬度和高度上分別占用了幾個(gè)單元格20.Swing界面一般都會有一個(gè)頂級Swing容器，但特殊情況下也可以沒有。21.When?using?a?form-based?authentication，?which?action?must?be?used?in?the?login?form？（）A、?j_loginB、?j_get_userC、?j_login_checkD、?j_get_securityE、?j_security_check22.下面哪些類是抽象類（）A、java.io.InputStreamB、java.io.PrintStringC、java.io.FileWriterD、java.io.Reader23.下面關(guān)于abstract關(guān)鍵字描述錯(cuò)誤的是（）。A、abstract關(guān)鍵字可以修飾類或方法B、final類的方法都不能是abstract，因?yàn)閒inal類不能有子類C、abstract類不能實(shí)例化D、abstract類的子類必須實(shí)現(xiàn)其超類的所有abstract方法24.Given?an?HttpSession?session，a?ServletRequest?request，and?a?ServletContext?context，which?retrieves?aURL?to?/WEB-INF/myconfig.xml?within?a?web?application？（）A、session.getResource（"/WEB-INF/myconfig.xml"）B、request.getResource（"/WEB-INF/myconfig.xml"）C、context.getResource（"/WEB-INF/myconfig.xml"）D、getClass（）.getResource（"/WEB-INF/myconfig.xml"）25.1）?class?Person?{? 2）?public?void?printValue（int?i，?int?j）?{/*…*/?}???? 3）?public?void?printValue（int?i）{/*...*/?}???? 4）?}? 5）?public?class?Teacher?extends?Person?{???? 6）?public?void?printValue（）?{/*...*/?}???? 7）?public?void?printValue（int?i）?{/*...*/}???? 8）?public?static?void?main（String?args[]）{???? 9）?Person?t?=?new?Teacher（）；???? 10）?t.printValue（10）；???? 11）?}??? 12）?}? Which?method?will?the?statement?on?line?10?call？?（）??A、?on?line?2B、?on?line?3C、?on?line?6D、?on?line?7第3卷一.參考題庫(共25題)1.Which?statement?is?true？（） A、Compilation?fails?because?the?hashCode?method?is?not?overridden.B、A?HashSet?could?contain?multiple?Person?objects?with?the?same?name.C、All?Person?objects?will?have?the?same?hash?code?because?the?hashCode??method?is?not?overridden.D、If?a?HashSet?contains?more?than?one?Person?object?with?name="Fred"，?then?removing?another?Person，?also?with?name="Fred"，?will?remove?them?all.2.靜態(tài)方法可以訪問類中的所有成員3.說明覆蓋和重載之間的區(qū)別。4.What?is?the?result？（） A、r，?t，?t，B、r，?e，?o，C、Compilation?fails.D、An?exception?is?thrown?at?runtime.5.float?f[][][]?=?new?float[3][][]；? float?f0?=?1.0f；? float[][]?farray?=?new?float[1][1]；? What?is?valid？（）??A、?f[0]?=?f0；B、?f[0]?=?farray；C、?f[0]?=?farray[0]；D、?f[0]?=?farray[0][0]；6.現(xiàn)有? class?Beverage?{? Beverage?（）??{??System.out.print?（"beverage?"）；??}??????? }? class?Beer?extends?Beverage?{? public?static?void?main{string?[]?args）?{??????? Beer?b?=?new?Beer?（14）?；?????? }? public?int?Beer（int?x）?{?????? this?（）?；? System.out.print?（"beerl"）?；????? }? public?Beer（）?{?System.out.print（"beer2?"）；?}???? }? 結(jié)果是什么？（）?A、beerl?beverageB、beer2?beverageC、beverage?beer2?beerlD、編譯失敗7.下列有關(guān)類、對象和實(shí)例的敘述，正確的是哪一項(xiàng)？（）?A、類就是對象，對象就是類，實(shí)例是對象的另一個(gè)名稱，三者沒有差別B、對象是類的抽象，類是對象的具體化，實(shí)例是對象的另一個(gè)名稱C、類是對象的抽象，對象是類的具體化，實(shí)例是類的另一個(gè)名稱D、類是對象的抽象，對象是類的具體化，實(shí)例是對象的另一個(gè)名稱8.簡述Java語言有什么特點(diǎn)？9.import?java.awt*；?? public?class?X?extends?Frame?（?? public?static?void?main（string?args）?（? X?x?=?new?X?（）；?? X.pack（）；?? x.setVisible（true）；? ）? public?X?（）?（?? setlayout?（new?GridLayout?（2，2））；?? Panel?p1?=?new?panel（）；?? ?Add（p1）；?? ?Button?b1=?new?Button?（“One”）；?? ?P1.add（b1）；? ?Panel?p2?=?new?panel（）；?? ?Add（p2）；?? Button?b2=?new?Button?（“Two”）；?? ?P2.add（b2）；?? ?Button?b3=?new?Button?（“Three”）；? ?add（b3）；?? Button?b4=?new?Button?（“Four”）；?? add（b4）；?? ）?? ）?? Which?two?statements?are?true？?（）A、?All?the?buttons?change?height?if?the?frame?height?is?resized.B、?All?the?buttons?change?width?if?the?Frame?width?is?resized.C、?The?size?of?the?button?labeled?“One”?is?constant?even?if?the?Frame?is?resized.D、?Both?width?and?height?of?the?button?labeled?“Three”?might?change?if?the?Frame?is?resized.10.下列類Account的構(gòu)造方法中，聲明正確的是？（）????A、Account?（String?name）（）B、Account?（String??name）C、Account?（name）（）D、NewAccount?（String?name）（）11.以下列出的為組件添加動(dòng)作監(jiān)視器的過程中，錯(cuò)誤的是（）A、將動(dòng)作監(jiān)聽器添加到組件上；B、將事件響應(yīng)函數(shù)貼到框架的事件響應(yīng)函數(shù)上；C、編寫事件響應(yīng)函數(shù)；D、創(chuàng)建動(dòng)作監(jiān)聽器對象；12.Assume?the?scoped?attribute?priority?does?NOT?yet?exist.?Which?two?create?and?set?new?request-scoped?attribute?priority?to?the?value?“medium”？（）?A、?${priority?=?‘medium’?}?B、?${requestScope[?‘priority’?]?=?‘medium’?}?C、??D、?medium?E、??F、?medium?G、?13.Which?two?create?an?instance?of?an?array？（）?A、?int?ia?=?new?int?[15]；B、?float?fa?=?new?float?[20]；C、?char?ca?=?“Some?String”；D、?Object?oa?=?new?float[20]；E、?Int?ia?=?（4，?5，?6）?（1，?2，?3）14.Click?the?’Select?and?Place’?button. Place?the?events?in?the?order?they?occur. 15. Which?is?equivalent?（） A、AB、BC、CD、DE、E16.如下代碼，result變量的輸出結(jié)果是多少（）。 A、10B、11C、9D、12E、817.Which?thetwo?are?true?about?the?JSTL?core?iteration?custom?tags？（）A、?It?may?iterate?over?arrays，?collections，?maps?and?strings.B、?The?body?of?the?tag?may?contain?EL?code，?but?not?scripting?code.C、?When?looping?over?collections，?a?loop?status?object?may?be?used?in?the?tag?body.D、?It?may?iterate?over?a?map，?but?only?the?key?of?the?mapping?may?be?used?in?the?tag?body.E、?When?looping?over?integers?（for?example?begin1=’1’?end=’10’），?a?loop?status?object?may?not?beused?in?the?tag?body.18.Your?company?has?a?corporate?policy?that?prohibits?storing?a?customer’s?credit?card?number?in?any corporate?database.?However，?users?have?complained?that?they?do?NOT?want?to?re-?enter?their?credit?cardnumber?for?each?transaction.?Your?management?has?decided?to?use?client-side?cookies?to?record?the?user’scredit?card?number?for?120?days.?Furthermore，?they?also?want?to?protect?this?information?during?transit?fromthe?web?browser?to?the?web?container；?so?the?cookie?must?only?be?transmitted?over?HTTPS. Which?codesnippet?creates?the?"creditCard"?cookie?and?adds?it?to?the?out?going?response?to?be?stored?on?the?user’s?webbrowser？（）A、B、C、D、19.class?Output?｛? public?static?void?main（String?[]?args）?｛? int?i?＝?4；? System.out.print（"3"?+?i?+?"?"）；? System.out.print（i?+?4?+?"6"）；? System.out.println（i?+?"7"）；? ｝? ｝? 結(jié)果為（）?A、7?8611B、7?44647C、34?8611D、34?864720.Which?statement?is?true?about?web?container?session?management？（）A、Access?to?session-scoped?attributes?is?guaranteed?to?be?thread-safe?by?the?web?container.B、To?activate?URL?rewriting，?the?developer?must?use?the?HttpServletResponse.setURLRewriting?method.C、If?the?web?application?uses?HTTPS，?then?the?web?container?may?use?the?data?on?the?HTTPS?requeststream?to?identify?the?client.D、The?JSESSIONID?cookie?is?stored?permanently?on?the?client?so?that?a?user?may?return?to?the?webapplication?and?the?web?container?will?rejoin?that?session.21.小程序的起始執(zhí)行函數(shù)是什么？（）???A、?init