新高考數(shù)學(xué)一輪復(fù)習(xí)講與練第04講 函數(shù)的概念與性質(zhì)（練）（原卷版）

第01講函數(shù)的概念與性質(zhì)1．已知函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0，則函數(shù)SKIPIF1<0的定義域?yàn)開_________．2、設(shè)函數(shù)SKIPIF1<0，若SKIPIF1<0為奇函數(shù)，則曲線SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線斜率為（

）A．3 B．2 C．1 D．SKIPIF1<03．函數(shù)SKIPIF1<0的單調(diào)遞減區(qū)間為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．下列四組函數(shù)中，表示同一函數(shù)的是（

）A．SKIPIF1<0，SKIPIF1<0 B．SKIPIF1<0，SKIPIF1<0C．SKIPIF1<0，SKIPIF1<0 D．SKIPIF1<0，SKIPIF1<05．函數(shù)SKIPIF1<0的定義域?yàn)椋?/p>

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．函數(shù)SKIPIF1<0的圖像大致是（

）A． B．C． D．7．已知函數(shù)SKIPIF1<0，且SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<08．已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)遞增，則SKIPIF1<0，SKIPIF1<0的取值可以是（

）A．SKIPIF1<0，SKIPIF1<0 B．SKIPIF1<0，SKIPIF1<0C．SKIPIF1<0，SKIPIF1<0 D．SKIPIF1<0，SKIPIF1<09．已知函數(shù)SKIPIF1<0，則不等式SKIPIF1<0的解集為__________．10．定義在SKIPIF1<0上的單調(diào)增函數(shù)SKIPIF1<0滿足：對(duì)任意SKIPIF1<0都有SKIPIF1<0成立(1)求SKIPIF1<0的值；(2)求證：SKIPIF1<0為奇函數(shù)；(3)若SKIPIF1<0對(duì)SKIPIF1<0恒成立，求SKIPIF1<0的取值范圍．11．已知函數(shù)SKIPIF1<0是定義在SKIPIF1<0上的函數(shù)，且對(duì)任意SKIPIF1<0，都有SKIPIF1<0，SKIPIF1<0，求SKIPIF1<0.1、已知SKIPIF1<0是定義在SKIPIF1<0上的偶函數(shù)，且SKIPIF1<0，若當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0，則SKIPIF1<0（

）A．0 B．1C．6 D．2162、已知函數(shù)SKIPIF1<0是定義在SKIPIF1<0上的奇函數(shù)，當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0，則SKIPIF1<0__________.3．SKIPIF1<0是定義在SKIPIF1<0上的以SKIPIF1<0為周期的奇函數(shù)，且SKIPIF1<0，則方程SKIPIF1<0在區(qū)間SKIPIF1<0內(nèi)解的個(gè)數(shù)的最小值是_______.4．對(duì)任意實(shí)數(shù)SKIPIF1<0，均滿足SKIPIF1<0且SKIPIF1<0，則SKIPIF1<0_______.5、設(shè)函數(shù)SKIPIF1<0，若SKIPIF1<0，SKIPIF1<0滿足不等式SKIPIF1<0，則當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0的最大值為A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06、已知函數(shù)SKIPIF1<0，若SKIPIF1<0SKIPIF1<0，其中SKIPIF1<0，則SKIPIF1<0的最小值為A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<07、已知函數(shù)f（x）（x∈R）滿足f（x）=f（a-x），若函數(shù)y=|x2-ax-5|與y=f（x）圖象的交點(diǎn)為（x1，y1），（x2，y2），…，（xm，ym），且SKIPIF1<0=2m，則a=（）A．1 B．2 C．3 D．48、若函數(shù)SKIPIF1<0是SKIPIF1<0上的奇函數(shù)，又SKIPIF1<0為偶函數(shù)，且SKIPIF1<0時(shí)，SKIPIF1<0，比較SKIPIF1<0，SKIPIF1<0，SKIPIF1<0的大小為（）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<01．（2022·全國(guó)·高考真題（理））函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0的圖象大致為（

）A． B．C． D．2．（2022·全國(guó)·高考真題（文））如圖是下列四個(gè)函數(shù)中的某個(gè)函數(shù)在區(qū)間SKIPIF1<0的大致圖像，則該函數(shù)是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·全國(guó)·高考真題）已知函數(shù)SKIPIF1<0的定義域?yàn)镽，且SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．0 D．14．（2020·山東·高考真題）已知函數(shù)SKIPIF1<0的定義域是SKIPIF1<0，若對(duì)于任意兩個(gè)不相等的實(shí)數(shù)SKIPIF1<0，SKIPIF1<0，總有SKIPIF1<0成立，則函數(shù)SKIPIF1<0一定是（

）A．奇函數(shù) B．偶函數(shù) C．增函數(shù) D．減函數(shù)5．（2021·全國(guó)·高考真題（理））設(shè)函數(shù)SKIPIF1<0的定義域?yàn)镽，SKIPIF1<0為奇函數(shù)，SKIPIF1<0為偶函數(shù)，當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0．若SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．（2022·北京·高考真題）設(shè)函數(shù)SKIPIF1<0若SKIPIF1<0存在最小值，則a的一個(gè)取值為________；a的最大值為___________．7．（2022·全國(guó)·高考真題（文））若SKIPIF1<0是奇函數(shù)，則SKIPIF1<0_____，SKIPIF1<0______．8．（2022·浙江·高考真題）已知函數(shù)SKIPIF1<0則SKIPIF1<0________；若當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0，則SKIPIF1<0的最大值是_________．9．（2022·北京·高考真題）函數(shù)SKIPIF1<0的定義