人教A版高中數(shù)學(xué)（必修第一冊(cè)）同步講義 5.6函數(shù)y＝Asin(ωx＋φ)的圖象（原卷版）

第第頁(yè)5.6.2函數(shù)SKIPIF1<0的圖象課程標(biāo)準(zhǔn)學(xué)習(xí)目標(biāo)①掌握?qǐng)D象的變換規(guī)律，解決三角函數(shù)的變換問題。②靈活掌握平移、伸縮變換規(guī)律，掌握與函數(shù)SKIPIF1<0中變換量之間的關(guān)系.。③會(huì)利用圖象的特點(diǎn)求函數(shù)的解析式。④會(huì)求圖象變換前后函數(shù)的解析式。⑤會(huì)解決與三角函數(shù)有關(guān)的綜合問題。會(huì)畫函數(shù)的圖象，會(huì)結(jié)合圖象解決與函數(shù)有關(guān)的性質(zhì)問題，會(huì)求函數(shù)的解析式，掌握函數(shù)圖象的變換規(guī)律.知識(shí)點(diǎn)一：五點(diǎn)法作圖必備方法：SKIPIF1<0五點(diǎn)法步驟③SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0①SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0②SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0對(duì)于復(fù)合函數(shù)SKIPIF1<0，第一步：將SKIPIF1<0看做一個(gè)整體，用五點(diǎn)法作圖列表時(shí)，分別令SKIPIF1<0等于SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，對(duì)應(yīng)的SKIPIF1<0則取SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，SKIPIF1<0。，（如上表中，先列出序號(hào)①②兩行）第二步：逆向解出SKIPIF1<0（如上表中，序號(hào)③行。）第三步：得到五個(gè)關(guān)鍵點(diǎn)為：SKIPIF1<0，SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0知識(shí)點(diǎn)二：三角函數(shù)圖象變換參數(shù)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0對(duì)函數(shù)SKIPIF1<0圖象的影響1.SKIPIF1<0對(duì)函數(shù)SKIPIF1<0,SKIPIF1<0的圖象的影響2、SKIPIF1<0(SKIPIF1<0)對(duì)函數(shù)SKIPIF1<0圖象的影響3、SKIPIF1<0(SKIPIF1<0)對(duì)SKIPIF1<0的圖象的影響4、由SKIPIF1<0的圖象變換得到SKIPIF1<0(SKIPIF1<0，SKIPIF1<0)的圖象的兩種方法知識(shí)點(diǎn)三：根據(jù)圖象求解析式形如SKIPIF1<0的解析式求法：1、SKIPIF1<0求法：①觀察法：SKIPIF1<0代表偏離平衡位置的最大距離；SKIPIF1<0平衡位置.②代數(shù)法：記SKIPIF1<0的最大值為SKIPIF1<0,最小值為SKIPIF1<0；則：SKIPIF1<0，聯(lián)立求解.2、SKIPIF1<0求法：通過觀察圖象，計(jì)算周期SKIPIF1<0，利用公式SKIPIF1<0，求出SKIPIF1<0.3、SKIPIF1<0求法：①第一關(guān)鍵點(diǎn)法：通過觀察圖象找出第一關(guān)鍵點(diǎn)SKIPIF1<0，將第一關(guān)鍵點(diǎn)SKIPIF1<0代入SKIPIF1<0求解.（第一關(guān)鍵點(diǎn)判斷方法：圖象呈上升狀態(tài)與平衡位置的交點(diǎn),且該點(diǎn)離SKIPIF1<0軸最近）②最值代入法：通過觀察圖象的最高點(diǎn)SKIPIF1<0（或者最低點(diǎn)SKIPIF1<0）代入解析式SKIPIF1<0求解.③特殊點(diǎn)法：當(dāng)圖象給出的信息缺乏①②中的條件，可以尋找圖象的其它特殊點(diǎn)SKIPIF1<0代入解析式SKIPIF1<0求解，但用此法求解，若有多個(gè)答案注意根據(jù)條件取舍答案.題型01利用“五點(diǎn)法”作函數(shù)SKIPIF1<0的圖象【典例1】用“五點(diǎn)法”在給定的坐標(biāo)系中，畫出函數(shù)SKIPIF1<0在SKIPIF1<0上的大致圖像.

【典例2】）已知函數(shù)SKIPIF1<0

(1)請(qǐng)用“五點(diǎn)法”畫出函數(shù)SKIPIF1<0在一個(gè)周期上的圖象（先在所給的表格中填上所需的數(shù)字，再畫圖）；SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<00SKIPIF1<0SKIPIF1<00(2)求SKIPIF1<0在區(qū)間SKIPIF1<0上的最大值和最小值及相應(yīng)的SKIPIF1<0值.【典例3】已知函數(shù)SKIPIF1<0，SKIPIF1<0．(1)列表，并在所給坐標(biāo)系中用五點(diǎn)法作出一個(gè)周期內(nèi)的函數(shù)圖像．SKIPIF1<0SKIPIF1<0

(2)寫出SKIPIF1<0的單調(diào)區(qū)間，對(duì)稱軸，對(duì)稱中心．【變式1】已知函數(shù)SKIPIF1<0，SKIPIF1<0．在用“五點(diǎn)法”作函數(shù)SKIPIF1<0的圖象時(shí)，列表如下：SKIPIF1<0xSKIPIF1<0完成上述表格，并在坐標(biāo)系中畫出函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的圖象；

【變式2】已知函數(shù)SKIPIF1<0.

(1)利用“五點(diǎn)法”，完成如下表格，并畫出函數(shù)SKIPIF1<0在一個(gè)周期上的圖象；SKIPIF1<0_________________________x_________________________SKIPIF1<0_________________________(2)若SKIPIF1<0且SKIPIF1<0，求SKIPIF1<0的值.【變式3】已知函數(shù)SKIPIF1<0．

(1)請(qǐng)用“五點(diǎn)法”畫出函數(shù)SKIPIF1<0在一個(gè)周期上的圖像（先在所給的表格中填上所需的數(shù)字，再畫圖）；SKIPIF1<0SKIPIF1<0SKIPIF1<0(2)求SKIPIF1<0的單調(diào)遞增區(qū)間．題型02三角函數(shù)的圖象變換【典例1】已知曲線C1：SKIPIF1<0，C2：SKIPIF1<0，則錯(cuò)誤的是（

）A．把SKIPIF1<0上各點(diǎn)的橫坐標(biāo)縮短到原來的SKIPIF1<0倍，縱坐標(biāo)不變，再把得到的曲線向左平行移動(dòng)SKIPIF1<0個(gè)單位長(zhǎng)度，得到曲線SKIPIF1<0B．把SKIPIF1<0上各點(diǎn)的橫坐標(biāo)縮短到原來的SKIPIF1<0倍，縱坐標(biāo)不變，再把得到的曲線向右平行移動(dòng)SKIPIF1<0個(gè)單位長(zhǎng)度，得到曲線SKIPIF1<0C．把SKIPIF1<0向左平行移動(dòng)SKIPIF1<0個(gè)單位長(zhǎng)度，再把得到的曲線上各點(diǎn)的橫坐標(biāo)縮短到原來的SKIPIF1<0倍，縱坐標(biāo)不變，得到曲線SKIPIF1<0D．把SKIPIF1<0向左平行移動(dòng)SKIPIF1<0個(gè)單位長(zhǎng)度，再把得到的曲線上各點(diǎn)的橫坐標(biāo)縮短到原來的SKIPIF1<0倍，縱坐標(biāo)不變，得到曲線SKIPIF1<0【典例2】已知函數(shù)SKIPIF1<0的圖象向左平移SKIPIF1<0個(gè)單位長(zhǎng)度后得到函數(shù)SKIPIF1<0的圖象，則φ的可能值為（）A．0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【典例3】為了得到函數(shù)SKIPIF1<0的圖象，可以將函數(shù)SKIPIF1<0的圖象（

）A．向左平移SKIPIF1<0個(gè)單位長(zhǎng)度 B．向右平移SKIPIF1<0個(gè)單位長(zhǎng)度C．向左平移SKIPIF1<0個(gè)單位長(zhǎng)度 D．向右平移SKIPIF1<0個(gè)單位長(zhǎng)度【典例4】把函數(shù)SKIPIF1<0的圖像適當(dāng)變動(dòng)就可以得到SKIPIF1<0圖像，這種變動(dòng)可以是（

）A．向右平移SKIPIF1<0 B．向左平移SKIPIF1<0 C．向右平移SKIPIF1<0 D．向左平移SKIPIF1<0【變式1】（多選）要得到函數(shù)SKIPIF1<0的圖象，可以將函數(shù)SKIPIF1<0的圖象（

）A．向左平移SKIPIF1<0個(gè)單位長(zhǎng)度 B．向右平移SKIPIF1<0個(gè)單位長(zhǎng)度C．向左平移SKIPIF1<0個(gè)單位長(zhǎng)度 D．向右平移SKIPIF1<0個(gè)單位長(zhǎng)度【變式2】為了得到函數(shù)SKIPIF1<0的圖象，只需將函數(shù)SKIPIF1<0的圖象向右平移個(gè)單位長(zhǎng)度．【變式3】為了得到函數(shù)SKIPIF1<0的圖象，只需把函數(shù)SKIPIF1<0的圖象向（填“左、右”）平移個(gè)單位長(zhǎng)度．題型03由SKIPIF1<0的圖象確定其解析式(或參數(shù)值)【典例1】已知函數(shù)SKIPIF1<0的部分圖象如圖所示，為了得到函數(shù)SKIPIF1<0的圖象，只需要將SKIPIF1<0的圖象（

）

A．向左平移SKIPIF1<0個(gè)單位長(zhǎng)度 B．向右平移SKIPIF1<0個(gè)單位長(zhǎng)度C．向左平移SKIPIF1<0個(gè)單位長(zhǎng)度 D．向右平移SKIPIF1<0個(gè)單位長(zhǎng)度【典例2】（多選）已知函數(shù)SKIPIF1<0的部分圖象，則（

）

A．SKIPIF1<0B．SKIPIF1<0C．點(diǎn)SKIPIF1<0是SKIPIF1<0圖象的一個(gè)對(duì)稱中心D．SKIPIF1<0的圖象向左平移SKIPIF1<0個(gè)單位后所對(duì)應(yīng)的函數(shù)為偶函數(shù)【典例3】已知函數(shù)SKIPIF1<0的部分圖象如圖所示.

(1)求SKIPIF1<0；(2)將函數(shù)SKIPIF1<0圖象向左平移SKIPIF1<0個(gè)單位，得到函數(shù)SKIPIF1<0的圖象，求SKIPIF1<0在SKIPIF1<0上的值域.【典例4】已知函數(shù)SKIPIF1<0的部分圖象如圖所示.(1)求SKIPIF1<0的最小正周期及解析式；(2)將函數(shù)SKIPIF1<0的圖象向右平移SKIPIF1<0個(gè)單位長(zhǎng)度得到函數(shù)SKIPIF1<0的圖象，求函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的最大值和最小值.【變式1】（多選）如圖所示的曲線為函數(shù)SKIPIF1<0（SKIPIF1<0，SKIPIF1<0，SKIPIF1<0）的部分圖象，將SKIPIF1<0圖象上的所有點(diǎn)的橫坐標(biāo)伸長(zhǎng)到原來的SKIPIF1<0，再將所得曲線向右平移SKIPIF1<0個(gè)單位長(zhǎng)度，得到函數(shù)SKIPIF1<0的圖象，則（

）

A．函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞減 B．點(diǎn)SKIPIF1<0為SKIPIF1<0圖象的一個(gè)對(duì)稱中心C．直線SKIPIF1<0為SKIPIF1<0圖象的一條對(duì)稱軸 D．函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞增【變式2】已知函數(shù)SKIPIF1<0的部分圖象如圖所示．

(1)求函數(shù)SKIPIF1<0的解析式；(2)將SKIPIF1<0圖象上所有點(diǎn)先向右平移SKIPIF1<0個(gè)單位長(zhǎng)度，再將縱坐標(biāo)變?yōu)樵瓉淼?倍，得到函數(shù)SKIPIF1<0，求SKIPIF1<0在SKIPIF1<0上的值域．【變式3】已知函數(shù)SKIPIF1<0的部分圖像，如圖所示．

(1)求函數(shù)SKIPIF1<0的解析式；(2)將函數(shù)SKIPIF1<0的圖像向右平移SKIPIF1<0個(gè)單位長(zhǎng)度，再將得到的圖像上各點(diǎn)的橫坐標(biāo)縮短為原來的SKIPIF1<0，縱坐標(biāo)不變，得到函數(shù)SKIPIF1<0的圖像，當(dāng)SKIPIF1<0時(shí)，求函數(shù)SKIPIF1<0的值域．【變式4】函數(shù)SKIPIF1<0（SKIPIF1<0，SKIPIF1<0，SKIPIF1<0為常數(shù)，且SKIPIF1<0，SKIPIF1<0，SKIPIF1<0）的部分圖象如圖所示．(1)求函數(shù)SKIPIF1<0的解析式及圖中b的值；(2)將SKIPIF1<0的圖象向左平移SKIPIF1<0個(gè)單位后得到函數(shù)SKIPIF1<0的圖象，求SKIPIF1<0在SKIPIF1<0上的單調(diào)減區(qū)間.題型04函數(shù)SKIPIF1<0的圖象與性質(zhì)的綜合應(yīng)用【典例1】已知函數(shù)SKIPIF1<0在一個(gè)周期內(nèi)的圖象經(jīng)過SKIPIF1<0，SKIPIF1<0，且SKIPIF1<0的圖象關(guān)于直線SKIPIF1<0對(duì)稱．(1)求SKIPIF1<0的解析式；(2)若存在SKIPIF1<0，使得不等式SKIPIF1<0成立，求a的取值范圍．【典例2】函數(shù)SKIPIF1<0的圖象兩相鄰對(duì)稱軸之間的距離是SKIPIF1<0，若將SKIPIF1<0的圖象上每個(gè)點(diǎn)先向左平移SKIPIF1<0個(gè)單位長(zhǎng)度，再向上平移1個(gè)單位長(zhǎng)度，所得函數(shù)SKIPIF1<0為偶函數(shù)．(1)求SKIPIF1<0的解析式；(2)若對(duì)任意SKIPIF1<0，SKIPIF1<0恒成立，求實(shí)數(shù)m的取值范圍；【典例3】已知函數(shù)SKIPIF1<0的部分圖像如圖所示，且SKIPIF1<0，SKIPIF1<0的面積等于SKIPIF1<0.(1)求函數(shù)SKIPIF1<0的解析式；(2)將SKIPIF1<0圖像上所有的點(diǎn)向左平移SKIPIF1<0個(gè)單位長(zhǎng)度，得到函數(shù)SKIPIF1<0的圖像，若對(duì)于任意的SKIPIF1<0，當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0恒成立，求實(shí)數(shù)SKIPIF1<0的最大值.【典例4】已知函數(shù)SKIPIF1<0的部分圖象如圖所示，矩形SKIPIF1<0的面積為SKIPIF1<0．(1)求SKIPIF1<0的最小正周期和單調(diào)遞增區(qū)間．(2)先將SKIPIF1<0的圖象向右平移SKIPIF1<0個(gè)單位長(zhǎng)度，再將所得圖象上各點(diǎn)的橫坐標(biāo)伸長(zhǎng)為原來的2倍，縱坐標(biāo)縮小為原來的SKIPIF1<0，最后得到函數(shù)SKIPIF1<0的圖象．若關(guān)于SKIPIF1<0的方程SKIPIF1<0在區(qū)間SKIPIF1<0上僅有3個(gè)實(shí)根，求實(shí)數(shù)SKIPIF1<0的取值范圍．【變式1】已知函數(shù)SKIPIF1<0的部分圖象如圖所示．

(1)求函數(shù)SKIPIF1<0的解析式；(2)將函數(shù)SKIPIF1<0的圖象向左平移SKIPIF1<0個(gè)單位，再將圖象上各點(diǎn)的橫坐標(biāo)伸長(zhǎng)到原來的2倍（縱坐標(biāo)不變）得到函數(shù)SKIPIF1<0的圖象，若關(guān)于x的方程SKIPIF1<0在區(qū)間SKIPIF1<0上有兩個(gè)不同的實(shí)數(shù)解，求實(shí)數(shù)a的取值范圍．【變式2】已知函數(shù)SKIPIF1<0（其中常數(shù)SKIPIF1<0）的最小正周期為SKIPIF1<0．(1)求函數(shù)SKIPIF1<0的表達(dá)式；(2)作出函數(shù)SKIPIF1<0，SKIPIF1<0的大致圖象，并指出其單調(diào)遞減區(qū)間；(3)將SKIPIF1<0的圖象向左平移SKIPIF1<0個(gè)單位長(zhǎng)度得到函數(shù)SKIPIF1<0的圖象，若實(shí)數(shù)SKIPIF1<0滿足SKIPIF1<0，且SKIPIF1<0的最小值是SKIPIF1<0，求SKIPIF1<0的值．【變式3】已知函數(shù)SKIPIF1<0的兩個(gè)相鄰零點(diǎn)之間的距離為SKIPIF1<0，且（在下面兩個(gè)條件中任選擇其中一個(gè)，完成下面兩個(gè)問題）.條件①：SKIPIF1<0的關(guān)于SKIPIF1<0對(duì)稱；條件②：函數(shù)SKIPIF1<0為奇函數(shù).(1)求SKIPIF1<0的解析式；(2)將SKIPIF1<0的圖象向右平移SKIPIF1<0個(gè)單位，然后再將橫坐標(biāo)伸長(zhǎng)到原來2倍（縱坐標(biāo)不變），得到函數(shù)SKIPIF1<0的圖象，若當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0的值域?yàn)镾KIPIF1<0，求實(shí)數(shù)SKIPIF1<0的取值范圍.【變式4】如圖，函數(shù)SKIPIF1<0的圖象經(jīng)過SKIPIF1<0，SKIPIF1<0，SKIPIF1<0三點(diǎn).(1)求函數(shù)SKIPIF1<0的解析式；(2)將函數(shù)SKIPIF1<0圖象上所有點(diǎn)的橫坐標(biāo)縮短到原來的SKIPIF1<0，縱坐標(biāo)縮短到原來的SKIPIF1<0，得到SKIPIF1<0圖象.若SKIPIF1<0，求函數(shù)SKIPIF1<0的單調(diào)增區(qū)間.題型05函數(shù)SKIPIF1<0的圖象與三角恒等變換【典例1】函數(shù)SKIPIF1<0的部分圖象如圖所示.(1)求A，SKIPIF1<0，SKIPIF1<0的值；(2)將函數(shù)SKIPIF1<0的圖象向右平移SKIPIF1<0個(gè)單位長(zhǎng)度，得到函數(shù)SKIPIF1<0的圖象，若SKIPIF1<0，且SKIPIF1<0，求SKIPIF1<0的值.【典例2】函數(shù)SKIPIF1<0的部分圖象如圖所示．

(1)求函數(shù)SKIPIF1<0的解析式；(2)將函數(shù)SKIPIF1<0的圖象先向右平移SKIPIF1<0個(gè)單位，再將所有點(diǎn)的橫坐標(biāo)縮短為原來的SKIPIF1<0（縱坐標(biāo)不變），得到函數(shù)SKIPIF1<0的圖象，若關(guān)于SKIPIF1<0的方程SKIPIF1<0在SKIPIF1<0上有兩個(gè)不等實(shí)根SKIPIF1<0，求實(shí)數(shù)SKIPIF1<0的取值范圍，并求SKIPIF1<0的值．【變式1】已知函數(shù)SKIPIF1<0在一個(gè)周期內(nèi)的圖象如圖所示.

(1)求函數(shù)SKIPIF1<0的表達(dá)式；(2)把SKIPIF1<0的圖象上所有點(diǎn)的橫坐標(biāo)縮短到原來的SKIPIF1<0（縱坐標(biāo)不變），再把得到的圖象向下平移一個(gè)單位，再向左平移SKIPIF1<0個(gè)單位，得到函數(shù)SKIPIF1<0的圖象，若SKIPIF1<0且SKIPIF1<0，求角SKIPIF1<0的值.【變式2】已知函數(shù)SKIPIF1<0.(1)當(dāng)SKIPIF1<0時(shí)，求函數(shù)SKIPIF1<0的單調(diào)遞增區(qū)間；(2)將函數(shù)SKIPIF1<0的圖象先向左平移SKIPIF1<0個(gè)單位長(zhǎng)度后，再把橫坐標(biāo)伸長(zhǎng)為原來的2倍縱坐標(biāo)不變，得到函數(shù)SKIPIF1<0的圖象.若SKIPIF1<0，且SKIPIF1<0為銳角，SKIPIF1<0，求SKIPIF1<0的值.A夯實(shí)基礎(chǔ)一、單選題1．要得到函數(shù)SKIPIF1<0的圖象，只要將函數(shù)SKIPIF1<0的圖象（

）A．向左平移SKIPIF1<0個(gè)單位長(zhǎng)度 B．向右平移SKIPIF1<0個(gè)單位長(zhǎng)度C．向左平移SKIPIF1<0個(gè)單位長(zhǎng)度 D．向右平移SKIPIF1<0個(gè)單位長(zhǎng)度2．已知函數(shù)SKIPIF1<0的最小正周期為SKIPIF1<0，把函數(shù)SKIPIF1<0的圖象向右平移SKIPIF1<0個(gè)單位長(zhǎng)度，所得圖象對(duì)應(yīng)函數(shù)解析式為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．若函數(shù)SKIPIF1<0在SKIPIF1<0上恰有兩個(gè)零點(diǎn)，且在SKIPIF1<0上單調(diào)遞增，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．已知函數(shù)SKIPIF1<0，則將函數(shù)SKIPIF1<0的圖像向左平移SKIPIF1<0個(gè)單位后得到函數(shù)SKIPIF1<0的圖像，SKIPIF1<0圖像關(guān)于原點(diǎn)對(duì)稱，則（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．把函數(shù)SKIPIF1<0的圖象向左平移SKIPIF1<0個(gè)單位后，得到一個(gè)偶函數(shù)的圖像，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．將函數(shù)SKIPIF1<0的圖象向左平移SKIPIF1<0個(gè)單位長(zhǎng)度，得到函數(shù)SKIPIF1<0的圖象，則函數(shù)SKIPIF1<0在SKIPIF1<0時(shí)的值域?yàn)椋?/p>

）A．SKIPIF1<0B．SKIPIF1<0C．SKIPIF1<0D．SKIPIF1<07．將函數(shù)SKIPIF1<0的圖象向左平移SKIPIF1<0個(gè)單位長(zhǎng)度后得到函數(shù)SKIPIF1<0的圖象，則正實(shí)數(shù)SKIPIF1<0的最小值為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．28．已知函數(shù)SKIPIF1<0（SKIPIF1<0，SKIPIF1<0），其圖像與直線SKIPIF1<0相鄰兩個(gè)交點(diǎn)的距離為SKIPIF1<0，若SKIPIF1<0對(duì)于任意的SKIPIF1<0恒成立，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0二、多選題9．已知函數(shù)SKIPIF1<0，則（

）A．SKIPIF1<0的最小正周期為SKIPIF1<0 B．SKIPIF1<0是曲線SKIPIF1<0的一個(gè)對(duì)稱中心C．SKIPIF1<0是曲線SKIPIF1<0的一條對(duì)稱軸 D．SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)遞增10．已知SKIPIF1<0是函數(shù)SKIPIF1<0的一個(gè)對(duì)稱中心，則（

）A．SKIPIF1<0B．SKIPIF1<0是函數(shù)SKIPIF1<0的一條對(duì)稱軸C．將函數(shù)SKIPIF1<0的圖像向右平移SKIPIF1<0單位長(zhǎng)度后得到的圖像關(guān)于原點(diǎn)對(duì)稱D．函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的最小值是SKIPIF1<0三、填空題11．函數(shù)SKIPIF1<0一個(gè)周期的圖象如圖所示，則函數(shù)SKIPIF1<0的解析式為.

12．設(shè)函數(shù)SKIPIF1<0（A，SKIPIF1<0，SKIPIF1<0是常數(shù)，SKIPIF1<0，SKIPIF1<0）.若SKIPIF1<0在區(qū)間SKIPIF1<0上具有單調(diào)性，且SKIPIF1<0，則SKIPIF1<0的最小正周期是．四、解答題13．已知函數(shù)SKIPIF1<0的圖像上相鄰兩條對(duì)稱軸的距離是SKIPIF1<0，SKIPIF1<0的最大值與最小值之差為1，且SKIPIF1<0的圖像的一個(gè)對(duì)稱中心是SKIPIF1<0．(1)求函數(shù)SKIPIF1<0的解析式；(2)若方程SKIPIF1<0在區(qū)間SKIPIF1<0上有解，求實(shí)數(shù)m的取值范圍．14．已知函數(shù)SKIPIF1<0，滿足______．(1)求SKIPIF1<0的解析式，并寫出SKIPIF1<0的單調(diào)遞減區(qū)間；(2)把SKIPIF1<0的圖象向右平移SKIPIF1<0個(gè)單位，再向上平移SKIPIF1<0個(gè)單位，得到函數(shù)SKIPIF1<0的圖象，若SKIPIF1<0在區(qū)間SKIPIF1<0上的最大值為SKIPIF1<0，求實(shí)數(shù)SKIPIF1<0的最小值．在①函數(shù)SKIPIF1<0的一個(gè)零點(diǎn)為0；②函數(shù)SKIPIF1<0圖象上相鄰兩條對(duì)稱軸的距離為SKIPIF1<0；③函數(shù)SKIPIF1<0圖象的一個(gè)最低點(diǎn)的坐標(biāo)為SKIPIF1<0，這三個(gè)條件中任選兩個(gè)，補(bǔ)充在上面問題中，并給出問題的解答．B能力提升1．已知函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞增，在SKIPIF1<0上單調(diào)遞減，將函數(shù)SKIPIF1<0的圖象向左平移SKIPIF1<0個(gè)單位長(zhǎng)度，得到函數(shù)SKIPIF1<0的圖象，若函數(shù)SKIPIF1<0為偶函數(shù)，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．已知函數(shù)SKIPIF1<0（SKIPIF1<0，SKIPIF1<0），其圖像與直線SKIPIF1<0相鄰兩個(gè)交點(diǎn)的距離為SKIPIF1<0，若SKIPIF1<0對(duì)于任意的SKIPIF1<0恒成立，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0