電大1253+C語(yǔ)言程序設(shè)計(jì)A(7月)小抄參考1

1、c語(yǔ)言程序設(shè)計(jì)a課程試卷（6）題 號(hào)一二三四五總 分得 分2011年7月考 一、單選題（每小題2分，共20分） 1. c語(yǔ)言程序中的基本功能模塊為（ ）。 a. 表達(dá)式 b. 標(biāo)識(shí)符 c. 語(yǔ)句 d. 函數(shù) 2. 邏輯表達(dá)式（x0 | y=5）的相反表達(dá)式為（ ）。a. x=0 | y！=5 b. x0 | y！=5 d. x0 & y=5 3. 循環(huán)體至少被執(zhí)行一次的循環(huán)語(yǔ)句為（ ）。 a. for b. while c. do-while d. 任一種循環(huán) 4. 假定n的值為5，則表達(dá)式n+的值為（ ）。 a. 6 b. 5 c. 4 d. 7 5. 假定一個(gè)二維數(shù)組的定義為“int a3

2、4=3,4,2,8,6;”，則元素a20的值為（ ）。 a. 0 b. 2 c. 4 d. 6 6. 假定一個(gè)函數(shù)原型為“char* func（int n）”，則該函數(shù)的返回類型為（ ）。 a. int b. int* c. char d. char* 7. 假定a為一個(gè)字符數(shù)組名，則元素ai的指針訪問方式為（ ）。 a. a+i b. *（a+i） c. &a+i d. *a+i 8. 假定有語(yǔ)句為“int *p=calloc（10+20,sizeof（int）;”，則p所指向的動(dòng)態(tài)數(shù)組中所包含的元素個(gè)數(shù)為（ ）。 a. 10 b. 20 c. 30 d. 40 9十進(jìn)制數(shù)50表示成符合c語(yǔ)

3、言規(guī)定的八進(jìn)制數(shù)為_。 a. 20 b. 32 c. 62 d. 062 10. 若要以讀和寫兩種操作方式打開一個(gè)二進(jìn)制文件，當(dāng)文件不存在時(shí)返回打開失敗信息，則選用的打開方式字符串為（ ）。 a. r+ b. ab+ c. rb+ d. wb+ 二、填空題（每小題2分，共26分） 1. 在一個(gè)c語(yǔ)言程序文件中，若要包含另外一個(gè)頭文件或程序文件，則應(yīng)使用的預(yù)處理命令為_。 2. 用于從鍵盤上為變量輸入值的標(biāo)準(zhǔn)輸入函數(shù)的函數(shù)名為_。 3. 假定一個(gè)枚舉類型的定義為“enum raab,ac,ad,ae;”，則ac的值為_。 4double類型的長(zhǎng)度為_。 5. 執(zhí)行“int x=45,y=13;p

4、rintf（%d,x/y）;”語(yǔ)句序列后得到的輸出結(jié)果為_。 6. 把表達(dá)式x=x+y轉(zhuǎn)換成復(fù)合賦值表達(dá)式為_。 7. 假定x的值為5，則執(zhí)行“a=（！x? 10: 20）;”語(yǔ)句后a的值為_。 8. 假定一維字符指針數(shù)組的定義為“char* a8;”，則該數(shù)組占用的存儲(chǔ)空間的字節(jié)數(shù)為_。 9. 假定二維數(shù)組的定義為“double amn;”，則數(shù)組元素的行下標(biāo)取值范圍在_之間。 10. 空字符串的長(zhǎng)度為_。 11. 在所有函數(shù)定義之外定義的變量，若沒有被初始化則系統(tǒng)隱含對(duì)它所賦的初值為_。 12. 若p指向x，則_與x的表示是等價(jià)的。 13. 直接訪問表達(dá)式（*fp）.score所對(duì)應(yīng)的間接

5、訪問表達(dá)式為_。 三、寫出下列每個(gè)程序運(yùn)行后的輸出結(jié)果（每小題6分，共30分） 1. #include void main（） int i,j,k=0; for（i=0; i5; i+） for（j=i; j5; j+） k+; printf（%dn,k）; 2. #include void main（） int x=20; int i=2; while（ix） if（x%i=0） printf（%d ,i）; x/=i; i+; 3. #include void main（） int a8=76,63,54,95,40,75,90,66; int i, s=0; for（i=0; i=70

6、& ai=90） s+=ai; printf（s=%dn,s）; 4. #include int wf（int x, int y） x=x+y; y+=x; return x+y; void main（） int x=3, y=8; printf（%dn,wf（x,y）; 5. #include int la（int *a, int n） int i,s=0; for（i=0;in;i+） s+=ai; return s; void main（） int a5=1,2,3,4,5; int b=la（a,5）+la（a+2,3）; printf（b=%dn,b）; 四、寫出下列每個(gè)函數(shù)的功能（

7、每小題6分，共12分） 1. int wc（int a, int n, int k） int i, c=0; for（i=0;i=k） c+; return c; 函數(shù)功能： 2. void qa（struct worker a, int n） int i; for（i=0; iscore三、寫出下列每個(gè)程序運(yùn)行后的輸出結(jié)果（每小題6分，共30分）評(píng)分標(biāo)準(zhǔn)：根據(jù)答案正確程度酌情給分。 1. 15 2. 2 5 3. s=241 4. 30 5. b=27四、寫出下列每個(gè)函數(shù)的功能（每小題6分，共12分）評(píng)分標(biāo)準(zhǔn)：根據(jù)答案敘述正確與完整程度酌情給分。 1. 統(tǒng)計(jì)并返回一維整型數(shù)組an中大于等于k

8、的值的個(gè)數(shù)。 2. 從鍵盤上為具有struct worker類型的數(shù)組an輸入n個(gè)記錄。五、按題目要求編寫函數(shù)（每小題6分，共12分）評(píng)分標(biāo)準(zhǔn)：根據(jù)函數(shù)編寫的正確與完整程度酌情給分。 1. double mean（double amn,int m,int n） int i,j; double v=0.0; /1分 for（i=0; im; i+） for（j=0; jn; j+） v+=aij; /4分 v/=m*n; return v; /6分 /注：函數(shù)體的最后兩行可以合并為一條返回語(yǔ)句：return v/=m*n 2. int mm（int a,int m） int i,x1,x2; x

9、1=x2=a0; /1分 for（i=1; ix1） x1=ai; /3分 if（aix2） x2=ai; /4分 /5分 return x1-x2; /6分 winger tuivasa-sheck, who scored two tries in the kiwis 20-18 semi-final win over england, has been passed fit after a lower-leg injury, while slater has been named at full-back but is still recovering from a knee injury

10、 aggravated against usa.both sides boast 100% records heading into the encounter but australia have not conceded a try since josh charnleys effort in their first pool match against england on the opening day.aussie winger jarryd hayne is the competitions top try scorer with nine, closely followed by

11、 tuivasa-sheck with eight.but it is recently named rugby league international federation player of the year sonny bill williams who has attracted the most interest in the tournament so far.the kiwi - with a tournament high 17 offloads - has the chance of becoming the first player to win the world cu

12、p in both rugby league and rugby union after triumphing with the all blacks in 2011.id give every award back in a heartbeat just to get across the line this weekend, said williams.the (lack of) air up there watch mcayman islands-based webb, the head of fifas anti-racism taskforce, is in london for t

13、he football associations 150th anniversary celebrations and will attend citys premier league match at chelsea on sunday.i am going to be at the match tomorrow and i have asked to meet yaya toure, he told bbc sport.for me its about how he felt and i would like to speak to him first to find out what h

14、is experience was.uefa hasopened disciplinary proceedings against cskafor the racist behaviour of their fans duringcitys 2-1 win.michel platini, president of european footballs governing body, has also ordered an immediate investigation into the referees actions.cska said they were surprised and dis

15、appointed by toures complaint. in a statement the russian side added: we found no racist insults from fans of cska. baumgartner the disappointing news: mission aborted.the supersonic descent could happen as early as sunda.the weather plays an important role in this mission. starting at the ground, c

16、onditions have to be very calm - winds less than 2 mph, with no precipitation or humidity and limited cloud cover. the balloon, with capsule attached, will move through the lower level of the atmosphere (the troposphere) where our day-to-day weather lives. it will climb higher than the tip of mount

17、everest (5.5 miles/8.85 kilometers), drifting even higher than the cruising altitude of commercial airliners (5.6 miles/9.17 kilometers) and into the stratosphere. as he crosses the boundary layer (called the tropopause),e can expect a lot of turbulence.the balloon will slowly drift to the edge of s

18、pace at 120,000 feet ( then, i would assume, he will slowly step out onto something resembling an olympic diving platform.they blew it in 2008 when they got caught cold in the final and they will not make the same mistake against the kiwis in manchester.five years ago they cruised through to the fin

19、al and so far history has repeated itself here - the last try they conceded was scored by englands josh charnley in the opening game of the tournament.that could be classed as a weakness, a team under-cooked - but i have been impressed by the kangaroos focus in their games since then.they have been concentrating on the sort of stuff that wins you tough, even contests - strong defence, especially on their own goal-line, completing sets and a good kick-chase. theyve been great at all the unglamorous st