匯編上機(jī)實(shí)驗(yàn)C-最大公約數(shù)

1、實(shí)驗(yàn)c最大公因數(shù)實(shí)驗(yàn)?zāi)康模簭逆I盤(pán)輸入兩個(gè)不超過(guò)65535的十進(jìn)制整數(shù)a、b,輸出a、b的最大公因數(shù) gcd(a,b)o實(shí)驗(yàn)要求：鍵盤(pán)輸入兩個(gè)十進(jìn)制整數(shù)a、b (其對(duì)應(yīng)的二進(jìn)制至多16位)，以回車(chē)結(jié)束 一個(gè)十進(jìn)制數(shù)的輸入。接著在下面的一行上輸出這兩個(gè)整數(shù)的最大公約數(shù)。如無(wú) 最大公因數(shù)，則輸出“nogcd”。注：為方便起見(jiàn)，最大公因數(shù)前允許有多余的前導(dǎo)0。實(shí)驗(yàn)結(jié)果：please input two numbers and press enter key when you want to stop a number!9600003do you want to continue(y/n)?ypleas

2、e input two numbers and press enter key when you want to stop a number!301200006do you want to continue(y/n)?yplease input two numbers and press enter key when you want to stop a number!50000050do you want to continue(y/n)?yplease input two numbers and press enter key when you want to stop a number!

3、00no gcddo you want to continue(y/n)?n實(shí)驗(yàn)報(bào)告要求：1、分析要點(diǎn)及調(diào)試后的正確程序。datas segmentusedb 10dup(0)bcnum dw?dcnum dw ?detail db 'please in put two numbers and press en ter key when you want to stop a number!'/$'continue db 'do you want to continue(y/n)?','$'nodbnogcd','$,tmp

4、db?datas endsexdatas segmentflg db 0；標(biāo)記是否為第一次計(jì)算，0是，1否exdatas endsstacks segmentdw 100 dup(o)stacks endscodes segmentassume cs:codes,ds:datas,ss:stacks,es:exdatasstart:mov ax,datasmov ds,axmov ax,exdatasmov es,axshowque:cmp flg,0；判斷是否為第一次計(jì)算jztwo；如果是第一次計(jì)算則跳過(guò)換行call changelinetwo:lea dx,detail ;顯示提示mov

5、ah,9int21hsub bx,bxsub cx,cxmov cx, 10mov si,10ready:call changelinesub ax,axsub bx,bxsub dx,dxinput:mov ahz01h ;輸入int21hcmpal,odhjz decsitemovtmp,alsub ax,axsub dx,dxmov ax,bxmul cxmov bx,axsubtmp,30h;轉(zhuǎn)換add bx,word ptrtmpmov si,bx保存sub ax,axjmp inputdecsite:mov dx,bxadd si,2cmp si,14jz nextjnz read

6、ynext:sub ax,axsub bx,bxsubcx,cxsub dx,dxmov ah,02hmov dx,odhint21hmov ah,02hmov dx,oahint21hmyready:sub ax,axmov dx,0mov ax,bcnummov cx,dcnumcmp cx,0jz result2div cxcmp dx,0jz resultjnzsub1sub1:mov bcnum,cxmov dcnum,dxjmpmyreadyresult2:cmp ax,0jz noticemov dx,axjmp mycallresult:mov dx,dx mycall: ca

7、ll transfermovah,02hint21hmovah,02hmov dx,odhint21hmovah,02hmov dx,oahint21hsub ax,axshow:movflg,1lea dx,continue movah,09hint21hsub ax,bxmovah,01hint21hcmpal/y* jzshowquecmp al,v jzshowque jnz exit；輸出轉(zhuǎn)換transfer proc near mov si,offset use add si,4sub bx,cxmov bl,$mov sl+l,blmov ax,dxmov cx,5ag1:mov

8、 dx,0mov bx,1odiv bxpush dxadd dl,30hmov si,dl dec si popdx loopag1 mov dx,si incdx m0vah,9int21hret transfer endp；換行changeline proc near movah,02h mov dx,0dh int21h movah,02h mov dx,0ah int21hretchangeline endpnotice:lea dx,nomovah,09hint21hmovah,02h mov dx,odh int21hmovah,02h movsi,oah int21h jmp showexit:m0vah,4chint21hcodes endsend start2、實(shí)驗(yàn)體會(huì)。這次實(shí)驗(yàn)并沒(méi)有什么技術(shù)方面的難度，但是它難在輸入數(shù)據(jù)長(zhǎng)度的處理。如 果輸入了五位數(shù)那么一個(gè)寄存器無(wú)法放下，必須增加一個(gè)寄存器,同時(shí)在進(jìn)行 乘法除法時(shí)也要考慮這一點(diǎn)。同時(shí)有些難到我的是用戶(hù)友好性的方面,為了去除一個(gè)開(kāi)頭顯示會(huì)換行的問(wèn) 題,我增加了一個(gè)flg標(biāo)記