電視傳輸與組網(wǎng)作業(yè)

1、數(shù)字電視傳輸與組網(wǎng)實(shí)驗(yàn)報(bào)告-、能量擴(kuò)散八塊交織與去交織:、(2, 1, 3)格狀編碼器姓名：侯文元學(xué)號：B11011322專業(yè)：廣播電視工程能量擴(kuò)散1、 實(shí)驗(yàn)名稱能量擴(kuò)散2、 實(shí)驗(yàn)?zāi)康挠?C 語言模擬能量的過程，理解能量擴(kuò)散的算法原理和具體實(shí)現(xiàn)方法3、 實(shí)驗(yàn)原理能量擴(kuò)散是使數(shù)字電視信號的能量不過分集中在載頻上或“0” ， “1” 電平相對應(yīng)的頻率上， 從而減小對其他通信設(shè)備的干擾， 并有利于載波回復(fù)。 具體的辦法是將二進(jìn)制數(shù)據(jù)中較集中的 0 或 1 按一定的規(guī)律使之分散開來， 這個(gè)規(guī)律由偽隨機(jī)信號發(fā)生器的生 成多項(xiàng)式?jīng)Q定。4、 實(shí)驗(yàn)過程C 代碼如下：#include<stdio.h>

2、;long m(char g,char n)int i1;long k=1;for(i1=0;i1<n;i1+)k=k*g;return(k);void main()unsigned b=0,b1,b2,t=0x00a9,t1,t2,res=0,i1,res1;char i,c,i2;unsigned long a,yu,a1;printf("a=");scanf("%6ld%10ld",&a1,&a);printf("%ld,%ldn",a,a1);for(i=9;i>=0;-i)c=a1/m(10,i)

3、;yu=a1%m(10,i);if(c>0)b=b+m(2,i+10);a1=yu; for(i=9;i>0;-i)c=a/m(10,i);yu=a%m(10,i);if(c>0) b=b+m(2,i);a=yu;)if(yu>0)b=b+1;printf("b=%un",b);printf("res=");for(i1=0;i1<=188;i1+)b2=b;for(i2=0,res=0;i2<16;i2+) if(i2!=0)res=res>>1;t1=t&0x4000;t2=t&0x20

4、00;t=t<<1;t=t&0x7fff;t2=t2<<1;t1=t1At2;t1=t1>>14;t=t|t1;b1=b2&0x0001;b1=t1Ab1;b2=b2>>1;res=res|(b1<<15);)for(i2=0;i2<16;i2+)if(i2!=0)res=res<<1;res1=res&0x8000;if(res1>0) printf("1"); else printf("0");)printf("n");五、

5、實(shí)驗(yàn)結(jié)果=£1111111000140000人小如回lus-i331aoaoii80S0BO11ci00110日 oiaeBau1oaaieeaeoi1eeoailaiien0031011110101i6ei 1O1U11M1 Mill! UM11M1M1Ml U1M11LM0UU11U1111111111UL11900011110811110110080111101001Bltaiail81llBaiL1110111310311800S03G1100Q0310111SB nmi 1 m 1.110m 1 Qterofli 1 osi id nniini liqarhi cm bii

6、iir01bhim 回 i 1 offiionniBiii1118131081B1BB108000118001801081100001101100001010101161361001011111111B9S±eilll 1 L»U0111BllBlM0MOMtlll01U110Ul1 Id Ml 11111 ViVtGVH. Will MOI 1U0UU1HM1UMU11HW8100611 060110111 00110000011. El 01101 0101 It 11 0106100111111111100000131003011111010101 11101B811

7、110101110600101811110118090010111010111001111101031110111316110111 i 01.0iiei800e00i esetiioeiQsetiieici isbi BaiaaiioeaiiieieiiieaiaiiiaiaGiiSBiiaiaBiioi91100311Sil00000181UI1810011100911101110001110100100101181111011101018031080181 1081BBQ01100011110101111101061109011001111601110100100101116000611

8、1010189111100 91081 aeeoiieeieiaeiioMiiiei 111111010111611011003001100116011801360011019101 me 1kJOWUlll 101U1J SOlllUHBl 010111 Hl 91 bl WU0111111U01U11E9111W1U »et 103001 EMimoti 00i00j 11 eon 3001010111011 Qi 11103111 m 11 aeioii 00161611 eiicieieoi Bll 1011Q61Q1S1 SI 111110的 Qi 000001 QI B0

9、S1101191101 lllj QOWQ01C1 OE»10 00011 bi 11 aeeii si 1 eeoei 601 iei owl 101011 eei eieiaeeieiiiei 01 eaei bi 011181080601 eon 1Q1 eiieei 11 iiti0iemiw 01m lei i0Liei0iiuuuowi0ii0i tn ui tain tn0iii0imu«»iwii 1001036011111001010011110110110110101611100001011010160911001011101&1001

10、1011111 10010300101Ql100001O0111100O1B019001190111010010110000S191101001L1B101119S011010 01111111110101101600160960011SO10SO01 u a0soiiioieai 01 i0di0oiBiias0ii6i010111Ml 111111111 HUllWIUeiiUUUMdUlLlMUlMl 011110111301101010100110901101010111110101110100101130111160000119100100131010101 »11101O

11、ie0O101111iei0O09S116B1190O01LQ11110B0Ql01061010911111001111110991010101 &ia0i3i0ii00i0iiiiiiiie0e0io00iia00oiii0iiioii0iBi0oiBiiaeiiiB0iiiini00iei0Bii0loti mei itmmm. uoimflRm mi mifiAtrnmii tueiLMLiimi iihlibbi ibu ifiti Biieii io Leiii38i000iiM0iiiiii6ie8iiiiiaei00idia0QiMiotM.aiiiea03iiaiiii

12、M.iim.Qiii0iien an OBaeeeii0111sealom. 111xei19601001weiiiiaiiiaaiiooeiigiiiiBeoicifliiieieaiaiie 1411101 jlldUbllMlUlUlUllMllMll 11111111111 t»HlMUULM0Uldld»llllkllU»krillklUUlll it tIMUUllU kaei an 1101011 qi 011 ideoi 11010101111 it niieiiiaii 1101091 miiineoiiaiAoi 000110|10019311

13、0101101101b1110011100311011111101911001.101100(10960111101101011GO111110S 1010131010101310101110000001011111111101111091190001111301100013100101llCliOSBSB 11111001108110081001010181003010011111111 tMHlklltilllH 1111100M111111QA111 閹口H配 Afllilll01 «1 酈I麗g11 麗口用 ARA1 神廁向Fh 1明 11 廂 1 嗣 1 哪HAt 1011

14、R01 B0O011B10tlO11101QtigilGlB0O010O011i.11110d0ilB01OBlS6191191ie0BailQlllBOGlQ0ilJ.aB E11119B11001118181110IS16181116111101380300011B110BO0101U1100811610118031110080 B111310110100Q0011101O0S0iai3O03QiaBlO0111B1310B0BllB001QlllBlllB0B ress any kep to cnntimiR_二、塊交織與去交織一、實(shí)驗(yàn)名稱用Matlab實(shí)現(xiàn)5x5塊交織和去交織二、實(shí)驗(yàn)?zāi)?/p>

15、的用Matlab模擬塊交織的過程，理解塊交織的算法原理和具體實(shí)現(xiàn)方法三、實(shí)驗(yàn)儀器計(jì)算機(jī)四、實(shí)驗(yàn)原理交織器的實(shí)現(xiàn)框圖如圖 181所示I 4 4輸入;u信道編碼器鶯u交織 存儲器X- 突發(fā) 信道% 去交資 存儲器隨機(jī)獨(dú)立無記憶信道圖18-1分組（塊）交織器實(shí)現(xiàn)框圖由圖18-1可見，交織、解交織由如下幾步構(gòu)成：若發(fā)送數(shù)據(jù)（塊） U經(jīng)信道編碼后為：X1x1 x2 x3 L x25 ;發(fā)送端交織存儲器為一個(gè)行列交織矩陣存儲器A,它按列寫入，按行讀出，即A1寫 入 順 序X5X11X16X21X7X12X17X22X8X13X18X23XX14X19X24X10X15X20X25Xx2X3X4”X5讀出順

16、序(01)交織器輸出后并送入突發(fā)信道的信號為(02)X2X1X6X11X16X23X2L X22,L ,X5L X25假設(shè)在突發(fā)信道中受到兩個(gè)突發(fā)干擾：第一個(gè)突發(fā)干擾影響 5位，即產(chǎn)生于X1至x21 ;第二個(gè)突發(fā)干擾影響4位，即產(chǎn)生于xi3至乂。則突發(fā)信道的輸出端信號X3可以表示為X3x&1x&6&x11x&16x&21 ,x2x7 L x22 , x3x8 x&13x&18x&23 , x&4 x9 L x25(0-3)在接收端， 將受突發(fā)干擾的信號送入解交織器， 解交織器也是一個(gè)行列交織矩陣的存儲器A2 ，它是按行寫入

17、，按列讀出(正好與交織矩陣規(guī)律相反) ，即x&1x&6x&11x&16x&21x2x7x12x17x22A2x3x8x&13x&18x&23(0-4)x&4x9x14x19x24x5x10x15x20x25經(jīng)解交織存儲器解交織以后的輸出信號X4 ，則X4 為X4x&1x2x3x&4x5x&6x7x8x9x10x&11x12x&13x14x15x&16x17x&18x19x20x&21x22x&23x24x25(0-5)五、實(shí)驗(yàn)過程Matlab 代碼如下

18、： A=input( ' 請輸入一個(gè)5*5 的矩陣 A=' );for i=1:5for j=1:5 B(i,j)=A(j,i); endend for i=1:5 for j=1:5 C(i,j)=B(j,i); endenddisp( ' 原矩陣 A=');disp(A);disp( ' 交織后矩陣B=' );disp(B);disp( ' 去交織后矩陣C=' );disp(C);六、實(shí)驗(yàn)結(jié)果格狀編碼器、實(shí)驗(yàn)名稱Matlab實(shí)現(xiàn)（2, 1, 3）格狀編碼器二、實(shí)驗(yàn)?zāi)康挠肕atlab模擬格狀編碼的過程，理解格狀編碼的算法原理和具體實(shí)現(xiàn)方法三、實(shí)驗(yàn)儀器計(jì)算機(jī)四、實(shí)驗(yàn)原理格狀編碼又稱卷積