電視傳輸與組網(wǎng)作業(yè)

1、電視傳輸與組網(wǎng)作業(yè)作者: 日期:數(shù)字電視傳輸與組網(wǎng)實驗報告能量擴散二、塊交織與去交織三、(2, 1, 3)格狀編碼器姓名：侯文元學號：B1仙322專業(yè)：廣播電視工程12能量擴散一、實驗名稱能量擴散二、實驗?zāi)康挠胏語言模擬能戢的過程，理解能量擴散的算法原理和具體實現(xiàn)方法三、實驗原理能量擴散是使數(shù)字電視信號的能量不過分集中在載頻上或“0”，“1”電平相對應(yīng)的 頻率上，從而減小對其他通信設(shè)備的干擾，并有利于載波回復(fù)。具體的辦法是將二進制 數(shù)據(jù)中較集中的0或1按一泄的規(guī)律使之分散開來，這個規(guī)律由偽隨機信號發(fā)生器的生 成多項式?jīng)Q建。四、實驗過程c代碼如下：# include<stdio.h>

2、long m(char g.char n)intil;long k=l;for(訂=0;il<n;il+)k=k*g;return(k);void main()unsigned b=O.b 1 ,b2,t=0x00a9,t 1 J2jes=0,il jes 1;char i,c,i2;unsigned long a.yu,al;primf(y);scanf(H%61d% 1 OUT；&a 1 .&a);printf("%ld,%IdnHAal);for(i=9;i>=0;-i)c=al/m(10J);yu=al%m(10,i);if(c>0) b=b

3、+m(24+10);al=yu;for(i=9;i>0;-i)c=a/m(10j); yu=a%m(10,i); if(c>0) b=b+m(2.i);a=yu;if(yu>O)b=b+l; printf(Mb=%un,b): printf(Hres=M); for(il=0;il<=188;il+)b2=b;for(i2=0.res=0;i2< 16;i2+)if(i2!=0) res=res»l;tl=t&0x4000;t2=t&0x2000; t=t«l;t=t&0x7fff; t2=t2«l;tl=tl

4、At2; tl=tl»14;t=tltl; bl=b2&0x0001; bl=tlAbl: b2=b2»l;res=resl(bl«15);for(i2=0;i2< 16;i2+)if(i2!=0) res=res«l; resl=res&0x8000;if(resl>0) printf(T); else printf(HOH);)printf(HnH); -D:iaSlffilllllDebuglllll.exe-L°.l.E iB!gla=11111111000000001100000000,111111b=65

5、28Bres-1001000011000000110100110001000011100010000011080011011011000101111010011001 0011MW110001111011010110101111001101W10100WOW101W1M1110MUM11H11111111110111B0010 00001111001111011000011110100101101011011100111110111010011000000011000001011100 0R01131111001101 BRUnil BRI 11 flRBBll 1RRRR1R1 Bllll

6、R01 0B1Hi 31103111B11111101010010100100000110001001001100001101100001010101101001001011111111000101111 100O011101iaiW00001OW10110011WlM00011(10001011111100UM101110OllO0tJMlOWllJ0WllB00Ol 00011000110111001100000110101101010111110100100111111111100000101000011111010101 11101001111010111000010101111011

7、001001000001011101011100111110100111011010110111 10101101000000100011001000110101100100100110001110101110010111010011001101001101 110101101M0OWM011M01MM010001M100101B11110M111W11W111M1111M1OM111W11OWUO1110O1110 01100011011000001010111010011100011101110001110100100101101111011101010001000101 10010000

8、110001111010111110100110001100111100111010010010111000001110101000111100 01001000011001018011000111011111110101110110110000011001100110010000110101011110 110O0MlM000«11001101W1100111lJM01010111010101UM0U11111110tJ0WOl(«J0l410BlkJllW1110010' 001100001001000110010011100110001010111011011

9、11001110111001011001010110110101001 01110110010010101110100101000011110000010000010100011011001101111100000010100010 0001101110001101100001001101000110101100101010001011101010001010011101000001001110010000111110010010011110110110110101011100001011010100011001011101010011011111 1001000010101160001001

10、1110001001000110011101001011000001011010011101011100011010 1001000丄1.0JL丄丄丄1丄1丄丄0丄0丄丄0丄0001.003000丄丄001.00001.丄丄0000丄丄丄01.00丄01.丄00丄00丄0丄丄000丄丄01010111000110101010011000110101011110101110100101100011001100000110100100101010101 0111010100001011111010000011001100001101111000010100101001111100111111003

11、1010101 0108101011001011111111000010001100001110111011010100101100111001111111001618011010010310110010801110101000100010010010000110110110111001110110011011100101101110 10111001000110001111110100111110010010100618010010111080011011110111010111011000 01100000011011100010011111011000100丄 000丄1丄丄0丄丄丄00

12、丄丄000丄丄0 丄丄 1100010101110100丄 0丄10RA13111101M101R111RRR1 llfil BIRllllllflllfllllBllll RfiRR! RflRl 11 «R01101 Rflftt 10 810O1000010O0110101110O11106011011111181011001101.10000100S011110tl010110011111O0 1101010101010101010111000000101111111110111100110000111100丄丄000丄0丄00丄0丄丄1.0丄00000 1111110011

13、00110001001010101000010011000000001100L1010111111100010101110111110000 miiii nail 1nni 01 i«iri 附胸胴11 rwrri 胸他 冊附胸 11 ni 11 tw rri 肺陽骯 i nni 1 m ir«i 10000110101011101010110100001000111111100611001001001011011000011611100016011100 10111001100111010111010101011101111010000000110110000101111

14、100011010110001110000 10111010110100000111010000101000001001001110101000011000101110111000Press any key to continue1二、塊交織與去交織一、實驗名稱用Matlab實現(xiàn)5x5塊交織和去交織二、實驗?zāi)康挠肕atlab模擬塊交織的過程，理解塊交織的算法原理和具體實現(xiàn)方法三、實驗儀器計算機四、實驗原理交織器的實現(xiàn)框圖如圖18-1所示圖18-1分組（塊）交織器實現(xiàn)框圖由圖18-1可見，交織、解交織由如下幾步構(gòu)成：若發(fā)送數(shù)據(jù)（塊）經(jīng)信道編碼后為：乙=（舛吃“心）:發(fā)送端交織存儲器為一個行列交織

15、矩陣存儲器A,它按列寫入，按行讀出，即(0-1)命山順血(0-2)交織器輸岀后并送入突發(fā)信道的信號為X =（看兀召$6兀2】，兀甩，“ 叫）假設(shè)在突發(fā)信道中受到兩個突發(fā)干擾：第一個突發(fā)干擾影響5位，即產(chǎn)生于召至勺； 第二個突發(fā)干擾影響4位.即產(chǎn)生于知至“。則突發(fā)信道的輸岀端信號禺可以表示為Xs =心，“心和兀甩，毛兀呂）(0-3)在接收端，將受突發(fā)干擾的信號送入解交織器，解交織器也是一個行列交織矩陣的存儲器人，它是按行寫入，按列讀出（正好與交織矩陣規(guī)律相反），即冬 A*7X12 XI7 X22(0-4)(0-5)經(jīng)解交織存儲器解交織以后的輸出信號則兀為1 =（亡宀“丘內(nèi)九"忑兀心乂內(nèi)

16、心九心心対也出蟲“丄）五、實驗過程Matlab代碼如下：A=input ('請輸入個5*5的矩陣*');for i=l:5for j=l:5B(i, j)=A(j, i);endendfor i=l:5for j=l:5C(i, j)=B(j, i);endenddisp ('原矩陣 A=');disp(A);dispC交織后矩陣B=)；disp(B);dispC灰交織后矩陣c=)；disp(C);六、實驗結(jié)果格狀編碼器一、實驗名稱Matlab實現(xiàn)(2, 1, 3)格狀編碼器二、實驗?zāi)康挠肕atlab模擬格狀編碼的過程，理解格狀編碼的算法原理和具體實現(xiàn)方法三、實驗儀器計算機四、實驗原理格狀編碼又稱卷積碼，若以(n,k,m)來描述卷積碼，其中k為每次輸入到卷枳編碼器的bit數(shù)，n為每個k元組碼字對應(yīng)的卷積碼輸岀n元組碼字，m為編碼存儲度.也就是卷枳編碼器的k元組的級數(shù)(b)狀態(tài)轉(zhuǎn)移(a) (2.1.3)卷枳編碼器示恵圖2卷積編碼示童yo(j) = x1(j-i)yiG) = xi0-2)®xiG)五、實驗過程Matlab代碼如下:x=input C;n=length(x);for i=2:ny