主線1#橋25米小箱梁鋼絞線伸長量計算書

1、25m小箱梁鋼絞線伸長量計算書一、主要計算公式1伸長量計算公式：乩=(PpXL)/(EpXAp)乩：鋼絞線伸長量，mmPp:鋼絞線平均張拉力，NL：鋼絞線長度，mmEp:鋼絞線彈性模量，MPa,般圖紙中有說明，但以試驗室實測數(shù)據(jù)為準；Ap:鋼絞線截面積，單根©15.24鋼絞線有效截面積為140mm22平均張拉力Pp=Px1-e-(kL+小/(KL+小P：張拉端張拉力，N1、N2、N3、N4鋼束單根鋼絞線張拉力P=976.5/5=195.3KNK:孔道摩擦影響系數(shù)；卩：鋼絞線與孔道的摩擦系數(shù)；0:從張拉端至計算截面的孔道切線轉(zhuǎn)角之和，當有平彎時同樣參與計算，Rad(弧度)。二、長度計算

2、（一）預(yù)應(yīng)力鋼絞線示意圖工作段橋梁中心線（二）N1鋼束長度1、計算長度Lab=7850/cos5.3852°-2822=5063mmLbc=2XnX60000X5.3852°/360°=5639.4mmLcd=4500-2822=1678mmLj=(Lab+Lbc+Lcd)X2=(5063+5639.4+1678)X2=24760.8mm2、下料長度Lx=(L工+Lab+Lbc+LcdX2=(450+5063+5638.4+1678)X2=25660.8mm（三）N2鋼束長度1、計算長度Lab=10350/cos4.1065°-1793=8584mmLb

3、c=2XnX50000X4.1065/360=3584mmLcD=2000-1793=207mmLj=(Lab+Lbc+Lcd)X2=(8584+3584+207)X2=24750mm2、下料長度張拉工作長度考慮450mmLx=(L工+Lab+Lbc+Lc?X2=(450+8584+3584+207)X2=25650mm(四) N3鋼束1、計算長度Lab=2850/cos1.0654°-279=2572mmLbc=2XnX30000X1.0654°/360°=558mmLcD=9500-279=9221mmLj=(Lab+Lbc+Lcd)X2=(2572+558+

4、9221)X2=24702mm2、下料長度Lx=(L工+Lab+Lbc+LcjX2=(450+2572+558+9221)X2=25602mm(五) 、N4鋼束1、計算長度Lab=2850/cos1.0654°-279=2572mmLbc=2XnX30000X1.0654°/360°=558mmLcD=9500-279=9221mmLj=(Lab+Lbc+Lcd)X2=(2572+558+9221)X2=24702mm2、下料長度Lx=(L工+Lab+Lbc+L吋X2=(450+2572+558+9221)X2=25602mm(六) 、根據(jù)通用圖可得出各線段參數(shù)，

5、詳見下表：鋼束a工作段（mr）Lab(mr)Lbc(mr)Lcd(mmN15.385245050635638.41678N24.106545085843584207N31.065445025725589221N41.065445025725589221三、伸長值計算根據(jù)試驗檢測報告可查得鋼絞線的平均彈性模量為：E=2.01X105,截面積A=140m2。根據(jù)橋規(guī)JTG/TF50-2011附表C-1可查得：尸0.17;k=0.0015。(一) 、工作段長度為千斤頂長度400mm工具錨厚度50mm工作段為直線則P工二P=195.3KN/L工=195300X450/(201000X140)=3.12

6、mm(二) 、N1鋼束1、AB段位直線，則PAb=P=195.3KN/Lab=(PabXLab)/(EpXAp)=195300X5063/(201000X140)=35.1mm2、BC段為曲線，0=5.3852Xn/180=0.0940(Rad);則根據(jù)Pbc=PX1-e-(kL+"0)/(KL+0)Pbc=195.3X(1-e-(0.0015X5.6384+0.17X0.0940)/(0.0015X5.6394+0.17X0.0940)=192.933KN/LbC=192933X5639.4/(201000X140)=38.7mm3、CD段為直線，C點位張拉端Pcd=2XPbc-P

7、b=2X192.93-195.3=190.6KN/Lcd=(PcdXLcd)/(EpXAp)=190600X1678/(201000X140)=11.4mm4、理論伸長值為/L=(/L工+/Lab+/Lb<+/Lcd)x2=(3.12+35.1+38.7+11.4)X2=176.6mm(三) 、N2鋼束1、AB段位直線，則PAb=P=195.3KN/Lab=(PabXLab)/(EpXAp)=195300X8584/(201000X140)=59.58mm2、BC段為曲線，0=4.1065Xn/180=0.0717(Rad);則根據(jù)Pbc=Px1-e-(kL+"0)/(KL+0

8、)-(0.0015X3.584+0.17X0.0717)PBc=195.3X(1-e()/(0.0015X3.584+0.17X0.0717)=193.59KN/Lbc=193590X3584/(201000X140)=24.66mm3、CD段為直線，C點位張拉端；PCd=2XPBc-Pb=2X193.59-195.3=191.88KN/Lcd=(PcdxLcd)/(EpxAp)=191880X207/(201000X140)=1.41mm4、理論伸長值為/L=(/L工+/Lab+/Lbc+/Lcd)X2=(3.12+59.58+24.66+1.41)X2=177.5mm(四) 、N3鋼束1、

9、AB段位直線，則PAb=P=195.3KN/Lab=(PabXLab)/(EpXAp)=195300X2572/(201000X140)=17.85mm2、BC段為曲線，0=1.0654Xn/180=0.0186(Rad);則根據(jù)Pbc=Px1-e-(kL+"0)/(KL+卩0)FBc=195.3x(1-e-(0.0015x0.558+0.17x0.0186)/(0.0015x0.558+0.17x0.0186)=194.91KN/LbC=194910x558/(201000x140)=3.87mm3、CD段為直線，C點位張拉端；FCd=2xFBc-Pb=2x194.91-195.3

10、=194.52KN/Lcd=(PcdxLcd)/(EpxAp)=194520x9221/(201000x140)=63.74mm4、理論伸長值為/L=(/L工+/Lab+/Lbc+/Lcd)x2=(3.12+17.85+3.87+63.74)x2=177.2mm(五) 、N4鋼束1、AB段位直線，則FAb=P=195.3KN/LaB=(PabxLab)/(EpxAp)=195300x2572/(201000x140)=17.85mm2、BC段為曲線，0=1.0654xn/180=0.0186(Rad);則根據(jù)Pbc=Px1-e-(kL+"0)/(KL+0)-(0.0015x0.558+0.17x0.0186)FBc=195.3x(1-e()/(0.0015x0.558+0.17x0.0186)=194.91KN/LbC=194910x558/(201000x140)=3.87mm3、CD段為直線，C點