數(shù)學建模案例研究線性代數(shù)在數(shù)學建模中應(yīng)用舉例

1、1基因間“距離”的表示1，A212i1i11234.的球面上.121212cosaa12a12.cosaa12187愛斯基摩人和班圖人之間的基因“距離”最大.2Euler的四面體問題）,(2a1a2a3a21aa12aa13bc11bc22bc33b21bb12bb13a1a2a3c21cc1cc23bc11bc22bc33aa12a22aa23bb12b22bb23cc12c22cc23aa13aa23a23bb13bb23b23cc13cc.23c23OAOAa2b2c2,OAOBaa11112bb12cc,12OAOCaa13bb13cc,OBOBa2b21322c22OBOCaa23b

2、b23cc,OCOCa2b2c2.233332p2p2q2n22p2r2m22p2q2n22p2p2r2l22p2r2m22p2r2l22r2.p2q2n2p2p2V23)2.3動物數(shù)量的按年齡段預(yù)測問題年齡組：第一組，05(k)i，2，3）.(k)14x3x2321x4x21121xkx,23xk1,3x31x.4212010 x(k)0120101x(k)2x(k)343x100 x2x34x(k)LxL012043100000,x1000.1100004111xLx111xLxxLx0120012001204310007000001000500,100025004437000275000

3、5003500,25012504432750143750035001375.12587504無窮大時的極限狀況得到.年），令(k)i更大年齡組人口的變化.(k)i1iibbiix,1(k)k111122nnai個年齡i組的每一個成員的女性后代的人數(shù)來表示的，通?？捎山y(tǒng)計資料來確定.)11)21)3223n11)n11)21)3)nn1n1)12123n1nn14企業(yè)投入產(chǎn)生分析模型0.55元的煤費及123XAXY,A)XY，（E-A設(shè)BA)（1，1，1）C.分別表示煤礦、電廠、鐵路得到的總投入.c11c21c31c12c22c32c13c23c33y1y2y3x1x2x3d1d2d35交通流量

4、的計算模型5.1給出了某城市部分單行街道的交通流量（每小時過車數(shù)）.x2x8x3x4x7x1x1x7x10 x3x4x5x6x2x5x8x9x9x10 x61000.011100000000011000000000011000A1110000000000000000010001000000000000000010000110000000100000010110100.100010000080001001000000B001000010000000000000000000000000100000000000200000005001010080001100100000010400000016000

5、00000000000.xx15xx25x3xx45xx68xx78x9x0.10121,1,0,1,1,0,0,0,0,0,1,1,0,0,x1x4x6x7x5xx25x3x5x8x8x9x600.10 x.xk11k22x*,6小行星的軌道模型11）.在1122334455ax22axyay22ax2ay101234512345123412345ax22axyay22ax2ay1012345ax2axyay2ax2ay1，ax2axyay2ax2ay1，ax2axyay2ax2ay1，ax2axyay2ax2ay1，ax2axyay2ax2ay1.21222324252x112x222x3

6、32x442x5521222324252x12x22x32x42x52y12y22y32y42y5123451X2Y22DC0.,橢;橢;橢22)1234512231,2hacac7人口遷移的動態(tài)分析y,z,0097510001001000100y1000100yz1000100y10z259910975975197597511000100y1000100yz10001001000100y210z25z2599z252109751100097511000100yz.1000100y100z2599100k1Auk9751A1000A1000100,1000100AAk1177Ak1177y5z7k0zzk01219352000k5075120.0z)7.2y00z0070z0Ayzz00128常染色體遺傳模型AAAAAAAAAAAAa)AAnnn,令x)x)nnn000a0b0c01.AAAAAAAAAAAAAAAAa1a1b20c.b1b2c,cn0.anbncnan1bn1c.n1anbncn1.我們利用矩陣表示(8.