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完好word版,必修一第一章會(huì)集與函數(shù)看法同步練習(xí)(含答案),介紹文檔完好word版,必修一第一章會(huì)集與函數(shù)看法同步練習(xí)(含答案),介紹文檔33/33完好word版,必修一第一章會(huì)集與函數(shù)看法同步練習(xí)(含答案),介紹文檔EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.第一章會(huì)集與函數(shù)看法同步練習(xí)1.1.1會(huì)集的含義與表示一.選擇題:1.以下對(duì)象不能夠組成會(huì)集的是()A.小于100的自然數(shù)B.大熊貓自然保護(hù)區(qū)C.立方體內(nèi)若干點(diǎn)的全體D.拋物線yx2上所有的點(diǎn)2.以下關(guān)系正確的選項(xiàng)是()A.N與Z里的元素都相同B.{a,b,c}與{b,a,c}為兩個(gè)不相同的會(huì)集C.由方程x(x1)20的根組成的會(huì)集為{0,1,1}D.數(shù)集Q為無(wú)量集3.以下說(shuō)法不正確的選項(xiàng)是()A.0N*B.0.1ZC.0ND.2Q4.方程x2y1的解集是()2xy3A.{1,1}B.(1,1)C.{(1,1)}D.1,1二.填空題:5.不大于6的自然數(shù)組成的會(huì)合用列舉法表示______________.6.試用合適的方式表示被3除余2的自然數(shù)的會(huì)集____________.7.已知會(huì)集M{0,2,3,7},由M中任取兩個(gè)元素相乘獲取的積組成的會(huì)集為_(kāi)_______.8.已知會(huì)集M{xRax22x10}只含有一個(gè)元素,則實(shí)數(shù)a______,若M為空集,可a的取值范圍為_(kāi)________..解答題:9.代數(shù)式(x2x8){x},求實(shí)數(shù)x的值。10.設(shè)會(huì)集A={(x,y)yx2,x,yN},試用列舉法表示該會(huì)集。11.已知1{x2,x23x3}試求實(shí)數(shù)x的值。1EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.會(huì)集的含義與表示一.選擇題:1.會(huì)集與{0}的關(guān)系,以下表達(dá)正確的選項(xiàng)是()A.={0}B.{0}C.{0}D.{0}2.已知會(huì)集A={1,2,3},則以下能夠作為A的子集的是()A.{1,4}B.{2,3}C.{2,4}D.{1,3,4}3.會(huì)集{a,b,c}的非空真子集個(gè)數(shù)是()4.已知會(huì)集M={正方形},N={菱形},則()A.MNB.MNC.MND.NM二.填空題5.用合適的符號(hào)填空①0_____{xx2n,nZ}②1_____{質(zhì)數(shù)}③{a}_____{a,b,c}④{a,b}_____{x(xa)(xb)0}⑤{xx41,kN}______{xx21,kN}kk6.寫(xiě)出會(huì)集{xx21}的所有子集_______________________7.設(shè)會(huì)集A{x3x6},B{xxa},且滿足AB,則實(shí)數(shù)a的取值范圍是_________三.解答題8.已知會(huì)集B滿足{1,2}B{1,2,3,4,5},試寫(xiě)出所有這樣的會(huì)集9.已知A{xx5},B{x3x},試判斷A與B的關(guān)系10.已知A=2},B{1,4,3a},且AB,求a的值{1,a2EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.會(huì)集的基本運(yùn)算(一)一.選擇題1.已知會(huì)集A={1,2,3,4},B{1,4,6},則AB()A.{1,2,4}B.{1,2,3,4,6}C.{1,4}D.{1,3,4}2.設(shè)A={xx2},B{x1x2},則AB()B.{xx2}C.{xx1}D.{xx2}3.設(shè)A{等腰三角形},B={等邊三角形},C={直角三角形},(AB)C()A.{等腰三角形}B.{直角三角形}C.D.{等腰直角三角形}已知會(huì)集M{xZ0x9},N{xx2n,nN},則MN()4.A.2,4,6B.2,4,6,8C.2,3,4,5,6,7D.1,2,3,4,5,6,7,8二.填空題5.{偶數(shù)}{奇數(shù)}=__________.6.已知會(huì)集A{x1x3},B{x3x1},則AB__________.7.若會(huì)集ABA,則AB___________.8.已知會(huì)集A{x3x3},B{xx2},則AB___________.三.解答題9.會(huì)集A{(x,y)3x2y5,x,yR}B{(x,y)2x3y1,x,yR},求AB10.已知會(huì)集A{1,3,a},B{1,a2a1},且ABA,求a的值11.已知會(huì)集A{xR2x2axb0},B{xR6x2(a2)x5b0}且AB{1},求AB23EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.1.1.3會(huì)集的基本運(yùn)算(二)一.選擇題1.已知全集UR,會(huì)集M{xx1},則CuM為()A.{xx1}B.{xx1}C.{xx1}D.{xx1}2.設(shè)全集U{2,3,4},A{a3,2},CuA{3},則a的值是()B.1或1或73.已知全集UR,會(huì)集A{x2x3},則CuA=()A.{xx2或x3}B.{xx2或x3}C.{xx2或x3}D.{xx2或x3}4.已知全集U{1,2,3,4,5,6,7,8},會(huì)集A{3,4,5},B{1,3,6},那么會(huì)集C={2,7,8}可以表示為()A.CuBB.ABC.CuACuBD.CuACuB二.填空題5.設(shè)全集UR,A{x2x6},B{xx4},則AB=__,ACuB__,CuAB__.6.全集U{三角形},A{直角三角形},則CuA=____________.7.設(shè)全集U{0,1,2,3,4}A{0,1,2,3},B{2,3,4},則CuAB____8.已知全集U{0,1,2},且CuA{2},則A的真子集共有___個(gè).三.解答題9.設(shè)全集UR,會(huì)集M{x3x4,xR},N{x1x5,xR},求①M(fèi)N②CuMCuN10.設(shè)全集U{1,2,3,4,5,6,7,8,9},會(huì)集AB{2},CuACuB{1,9},CuAB{4,6,8},求A,B11.已知U{2,4,x2x1},B{2,x1},CuB{7},求x的值4EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.函數(shù)的看法(一)一.選擇題1.函數(shù)f(x)3x1的定義域?yàn)椋ǎ〢.(,1)B.(1,)C.[1,)D.(,1]33332.已知函數(shù)f(x)x2pxq滿足f(1)f(2)0,則f(1)的值為(B.5D.63.以下函數(shù)中f(x)與g(x)表示同一函數(shù)的是()A.f(x)x0與g(x)1B.f(x)x與g(x)x2xC.f(x)x2與g(x)(x1)2D.f(x)x與g(x)3x34.以下各圖象中,哪一個(gè)不能能為yf(x)的圖象()yyyyoxoxoxo(A)(B)(C)(D)填空題5.已知f(x)x22x,則f(2)______________.6.已知f(x1)2x21,則f(x)______________.7.已知f(x)的定義域?yàn)閇2,4],則f(3x2)的定義域?yàn)開(kāi)______________.8.函數(shù)f(x)1x2x21的定義域?yàn)開(kāi)_____________.三.解答題

)x二.5EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.2x1(x0)9.設(shè)f(x)22(x,求f(2)和f(3)2x0)10.求以下函數(shù)的定義域(1)1()g(x)(x10)01xf(x)2x311.已知f(x)為一次函數(shù),且f[f(x)]4x3,求f(x)6EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.函數(shù)的看法(二)一、選擇題1.函數(shù)yx22x的定義域?yàn)閧0,1,2,3},其值域?yàn)椋ǎ〢.{1,0,3}B.{0,1,2,3}C.{y1y3}D.{y0y3}2.函數(shù)f(x)1x2(xR)的值域是()1A.(0,1)B.(0,1]C.[0,1)D.[0,1]3.以下命題正確的有()①函數(shù)是從其定義域到值域的照射②f(x)x32x是函數(shù)③函數(shù)y2x(xN)的圖象是一條直線④f(x)x2與g(x)x是同一函數(shù)xA.1個(gè)B.2個(gè)C.3個(gè)D.4個(gè)4.函數(shù)y(2x3)0的定義域?yàn)椋ǎ﹛xA.xx0且x3B.xx032C.xx0D.xRx0且x2二.填空題x2,x15.已知函數(shù)f(x)x2,1x2,若f(x)3,則x的值為_(kāi)_________.2x,x26.設(shè)函數(shù)f(x)x23x3,則f(a)f(a)等于____________.7.設(shè)函數(shù)f(x)x1x,則f[f(1)]____________.8.函數(shù)yx22x3,x1,3的值域是________________.三.解答題7EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.9.求函數(shù)y24xx2的值域10.已知函數(shù)y1x2x21,求x2008y2007的值11.已知函數(shù)f(x)x(a.b為常數(shù),且a0)滿足f(2)1,f(x)x有獨(dú)一解,求axb函數(shù)yf(x)的剖析式和f[f(3)]的值.8EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.1.2.2函數(shù)表示法(一)一、選擇題1.設(shè)會(huì)集Aa,b,c,會(huì)集B=R,以下對(duì)應(yīng)關(guān)系中,必然能成建立A到B的照射的是()A.對(duì)A中的數(shù)開(kāi)B.對(duì)A中的數(shù)取倒數(shù)C.對(duì)A中的數(shù)取算術(shù)平方D.對(duì)A中的數(shù)開(kāi)立方2.某人從甲村去乙村,一開(kāi)始沿公路乘車,此后沿小路步行,圖中橫軸表示走的時(shí)間,縱軸表示某人與乙村的距離,則較吻合該人走法的圖是()ddddd0d0d0d00t0t0t0t0t0tt0t0ABCD3.已知函數(shù)f(2x1)3x2,且f(a)2,則a的值等于()D.14.若f(1)xx,則當(dāng)x0且x1時(shí),f(x)等于()x1A.11C.111xB.1D.xx1x二.填空題5.若fg(x)6x3,且g(x)2x1,則f(x)______________.6.二次函數(shù)的圖象以下列圖,則此函數(shù)的剖析式為_(kāi)__________.x1y012x,x07.已知函數(shù)f(x)2,x則f(2)________,f(4)=_______x09EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.8.會(huì)集B{1,3,5},f(x)2x1是A到B的函數(shù),則會(huì)集A能夠表示為_(kāi)___________________三.解答題9.已知函數(shù)f(x)是一次函數(shù),且f[f(x)]4x1,求f(x)的剖析式10.等腰三角形的周長(zhǎng)為24,試寫(xiě)出底邊長(zhǎng)y對(duì)于腰長(zhǎng)x的函數(shù)關(guān)系式,并畫(huà)出它的圖象11.作出函數(shù)yx1x3的圖象,并求出相應(yīng)的函數(shù)值域10EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.函數(shù)表示法(二)一、選擇題1.已知會(huì)集Ax0x4,By0y2,按對(duì)應(yīng)關(guān)系f,不能夠成為從A至B的照射的一個(gè)是()A.f:xy1xB.f:xyx22C.f:xyxD.f:xyx22.如圖,函數(shù)yx1的圖象是()yy-1ox-1oxAByyx1xo1o-1CD3.設(shè)A{0,1,2,4},B{1,0,1,2,6,8},以下對(duì)應(yīng)關(guān)系能組成A到B的照射的是()2A.f:xx31B.f:x(x1)2C.f:x2x1D.f:x2xx1,x1f(5)=()4.已知函數(shù)f(x)x3,x,則f12135D.9A.B.C.2222二.填空題11EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.2x2,1x05.設(shè)函數(shù)f(x)1x,0x2,則f(3)的值為_(kāi)_____,f(x)的定義域?yàn)開(kāi)____.243,x26.f(x)的圖象如圖,則f(x)=____________.y1ox-1o7.對(duì)于任意xR都有f(x2f(x),當(dāng)021)x1時(shí),f(x)3x(1x),則f(1.5)的值是____________.28.f(x1)3x2,且f(a)2,則a的值等于____________.三.解答題9.作出以下函數(shù)的圖象()y1x(xZ且x2)()y2x24x3,(0x3)1,2x4,x4,求f(1)的值10.已知函數(shù)f(x)x),xf(3411.求以下函數(shù)的剖析式(1)已知f(x)是二次函數(shù),且f(0)2,f(x1)f(x)x1,求f(x)(2)已知3f(x)f(x)5x,求f(x)12EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.函數(shù)單調(diào)性與最大(小)值(一)一.選擇題1.若(a,b)是函數(shù)yf(x)的單調(diào)遞加區(qū)間,x1,x2a,b,且x1x2,()A.f(x1)f(x2)B.f(x1)f(x2)C.f(x1)f(x2)D.以上都不正確2.以下結(jié)論正確的選項(xiàng)是()A.函數(shù)yx在R上是增函數(shù)B.函數(shù)yx2在R上是增函數(shù)C.yx在定義域內(nèi)為減函數(shù)D.y1在(,0)上為減函數(shù)1x3.函數(shù)y)1(x1A.在(1,)內(nèi)單調(diào)遞加B.在(1,)內(nèi)單調(diào)遞減C.在(1,)內(nèi)單調(diào)遞加D.在(1,)內(nèi)單調(diào)遞減4.以下函數(shù)在區(qū)間(0,)上為單調(diào)增函數(shù)的是()A.y12xB.yx22xC.yx2D.y2x二.填空題5.已知函數(shù)f(x)在(0,)上為減函數(shù),那么f(a2a1)與f(3)的大小關(guān)系是________.46.函數(shù)yf(x)的圖象以下列圖,則該函數(shù)的單調(diào)遞減區(qū)間為_(kāi)___________.y2ox127.已知f(x)ax23axa21(a0),則f(3),f(3),f(3)從小到大的序次為_(kāi)_____.28.函數(shù)yx24x3的單調(diào)遞加區(qū)間為_(kāi)______,當(dāng)x_______時(shí),y有最______值為_(kāi)___.三.解答題9.已知yf(x)在定義域(1,1)上為減函數(shù),且f(1a)f(a21)求a的取值范圍。10.證明f(x)x1在(1,)上為增函數(shù)x13EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.11.證明f(x)2x24x3,(1)若x[1,4],求f(x)的單調(diào)區(qū)間(2)若x[0,5],求函數(shù)的最大值和最小值14EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.函數(shù)單調(diào)性與最大(小)值(二)一.選擇題1.函數(shù)yx1在2,0上的最大值為()2x6,x1,2的最大值,最小值為()2.函數(shù)f(x)7,x則f(x)x1,1,6,8,6D.以上都不對(duì)3.以下命題正確的選項(xiàng)是()A.函數(shù)y3x4的最大值為4B.函數(shù)y(xa)2b的最大值為b(a,bR)C.函數(shù)y6的最小值為0xD.函數(shù)yax2bxc的最大值為4acb2(a0)4a4.函數(shù)yf(x)在R上單調(diào)遞加,且f(m2)f(m)則實(shí)數(shù)m的取值范圍是()A.,1B.0,C.1,0D.,10,二.填空題5.已知yax1在1,3上的最小值為4,則a=____________.6.函數(shù)y2,x4,1則函數(shù)y的最大值為_(kāi)______,最小值為_(kāi)_____x7.函數(shù)f(x)9ax2(a0)在0,3上的最大值為_(kāi)__________.8.已知f(x)x22(a1)x2在區(qū)間x1,5上的最小值為f(5),則a的取值范圍是________.三.解答題9.求f(x)x22x3在x1,1上的值域10.判斷函數(shù)y2x1,x3,5的單調(diào)性,并求出最值x115EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.11.已知f(x)是定義在0.上的減函數(shù),且滿足f(1/3)=1fxyf(x)f(y)①求f(1)②若f(x)f(2x)2,求x的取值范圍16EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.1.3.2奇偶性一、選擇題1.奇函數(shù)yf(x),xR的圖象必然經(jīng)過(guò)點(diǎn)()A.a,f(a)B.a,f(a)C.a,f(a)D.a,f(1)a2.已知f(x)1x2()xA.是偶函數(shù)B.是奇函數(shù)C.既是奇函數(shù),又是偶函數(shù)D.既不是奇函數(shù),也不是偶函數(shù)3.對(duì)定義域?yàn)镽的任意奇函數(shù)f(x)均有()A.f(x)f(x)0B.f(x)f(x)0C.f(x)f(x)0D.f(x)f(x)04.已知函數(shù)f(x)x5ax3bx8,且f(2)10,那么f(2)等于()二.填空題5.已知f(x)為偶函數(shù),f(3)1,則f(3)________6.若函數(shù)f(x)kxb為奇函數(shù),則b_________7.若f(x)(m1)x22mx3m3為偶函數(shù),則實(shí)數(shù)m的值為_(kāi)________8.已知偶函數(shù)yf(x)在(0,4)上為增函數(shù),則f(1),f(1),f(7)的大小關(guān)系是(用小于22號(hào)連接)______三.解答題判斷以下函數(shù)的奇偶性①f(x)x42x23,x4,4②f(x)x1x17EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.10.已知f(x)ax2bx3ab為偶函數(shù),其定義域?yàn)閍1,2a,求a,b值11.已知f(x)為偶函數(shù),g(x)為奇函數(shù),且在公共定義域xx1上滿足f(x)g(x)1,求f(x)和g(x)的表達(dá)式x118EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.第一章會(huì)集與函數(shù)單元練習(xí)一、選擇題1.以下不能夠組成會(huì)集的是()A.某校高一(4)班的學(xué)生B.某校高一(4)班的男學(xué)生C.某校高一(4)班的學(xué)生D.某校高一(4)班喜歡學(xué)習(xí)數(shù)學(xué)的學(xué)生2.函數(shù)f(x)1x的定義域是()A.1,B.,1C.0,3.已知會(huì)集P{x0x4},Q{y0y2},以下從P到Q的對(duì)應(yīng)關(guān)系f不是照射的是()A.f:xy1xB.f:xy1x23C.f:xy2xD.f:xy1x2384.已知f(x)x2,x1,1,則f(2)()x,x1,6D.無(wú)法確定5.點(diǎn)集M{(x,y)xy0}是指()A.第一.三象限的點(diǎn)集B.不在第一.三象限的點(diǎn)集C.第二.四象限的點(diǎn)集D.不在第二.四象限的點(diǎn)集6.以下各組函數(shù)f(x),g(x)表示同一函數(shù)的是()A.f(x)x2,g(x)(x2)2B.f(x)x,g(x)x2xC.f(x)(x)2,g(x)x2D.f(x)x,g(x)x,x0x,x07.函數(shù)f(x)3x1的值域是()x2A.{yy2}B.{yy1}C.{yy3}D.{yy1}338.定義在R上的偶函數(shù)在0,7上是增函數(shù),在7,上是減函數(shù)且f(7)6,則f(x)19EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.()A.在7,0上是增函數(shù),且最大值為6B.在7,0上是減函數(shù),且最大值為6C.在7,0上是增函數(shù),且最小值為6D.在7,0上是減函數(shù),且最小值為6二.填空題9.已知f(x1)x22x3,則f(2)________10.設(shè)會(huì)集A{x1x2},B{xxa},若AB,則a的取值范圍是_______11.已知f(x)是奇函數(shù),且f(3)1,則f(3)________12.函數(shù)f(x)x24x3的單調(diào)遞加區(qū)間是___,當(dāng)x=___時(shí),有最__值為_(kāi)___.三.解答題13.已知會(huì)集A{1,3,a},B{1,a2a1},若BA,求a的值14.求以下函數(shù)的定義域(1)f(x)x2(x1)0x1(2)f(x)xx15.已知函數(shù)f(x)2xm,其中m為常數(shù)(1)證明函數(shù)f(x)在R上為減函數(shù)(2)當(dāng)函數(shù)f(x)為奇函數(shù)時(shí),求實(shí)數(shù)m的值16.已知函數(shù)f(x)是正比率函數(shù),函數(shù)g(x)是反比率函數(shù),且f(1)1,g(1)2(1)求函數(shù)f(x)和g(x)(2)判斷函數(shù)f(x)g(x)的奇偶性20EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.第一章會(huì)集與函數(shù)看法參照答案1.1.1會(huì)集的含義與表示一、選擇題1、C,2、D,3、A,4、C,二、填空題5、{0、1、2、3、4、5},6、XX3n2,nN7、{0、6、14、21},8、0或1a1,三、解答題9、解:由題意得x2x8x,解得x14,x22,由元素互異得都吻合題意。10、解:因?yàn)閤,yN,所以x0,y2;x1,y1;x2,y0.即0,2,1,1,2,011、解:當(dāng)x21時(shí)x1,當(dāng)x23x3=1時(shí)x2,1。由元素互異得x2吻合題意。1.1.2會(huì)集的含義與表示一、選擇題1、B,2、B,3、C,4、C,二、填空題5、①②③④⑤6、,1,1,1,1,7、a6三、解答題8、、解:會(huì)集B的元素個(gè)數(shù)大于2小于等于5,而且必有1,2兩個(gè)元素。所以會(huì)集B為{1,2,3}{1,2,4}{1,2,5}{1,2,3,4}{1,2,3,5}{1,2,4,5}{1,2,3,4,5}.9、解:35由圖解得AB.10、解:由a2=4得a2,由a2=3a得a1。由元素互異得都吻合題意。a1,221EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.1.1.3會(huì)集的基本運(yùn)算(一)一、選擇題1、C,2、D,3、D,4、B,二、填空題5、,6、X|1X1,7、B,8、X|X3}三、解答題、解:由題意得3x2y5,解得x1,AB={(1,-1)}92x3y1y110、解:當(dāng)a2a13得a2或1,當(dāng)aa2a1得a1(不合元素互異舍去),檢驗(yàn)得a2或1。、解:由111ab0,解得a7,b4。會(huì)集AAB}得方程2211{312(a2)5b022解集{1,4}會(huì)集B解集{1,1}所以AB={1,1,4}。223231.1.3會(huì)集的基本運(yùn)算(二)一、選擇題1、A,2、C,3、D,4、C,二、填空題5、{x|2x4},{x|4x6},{x|x2}6、{斜三角形},7、{4},8、3三、解答題9、解:MN={x|3x5},CuMCuNCu(MN){x|x3或x5}22EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.10、解:A={2,3,5,7},B={2,4,6,8},11、解:由x2x17得x3,或2,當(dāng)x2,x11,1U,不符題意舍去,所以x3。函數(shù)的看法(一)一、選擇題1.C2.C3.D4.C二、填空題5.2226.2x24x37.4,28.{-1,1}3三、解答題9.解:20,f(2)2(2)1530,f(3)2322810.①解:2x30,x3,f(x)1的定義域?yàn)閤x322x32②解:x100x10原函數(shù)的定義域?yàn)閤x1且x101x0,x1,11.解:設(shè)f(x)kxb,f[f(x)]k(kxb)bk2xkbb4x3即k24,k2或k2,kbb3b1b323EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.f(x)2x1或f(x)2x31.2.3函數(shù)的看法(二)一、選擇題1.A2.B3.A4.A二、填空題5.36.6a7.18.2,6三、解答題9.解:4xx2(x24x)(x2)244又4xx20,4xx20,2,4xx22,0y2(4xx2)0,2,即原函數(shù)的值域?yàn)?,210.解:由已知得:1x20,x1,x210當(dāng)x1時(shí),y0x2008y2007=120081當(dāng)x1時(shí),y0x2008y2007=(1)2008111.解:由已知得:f(2)21,即2ab22abx又f(x)axx有獨(dú)一解,即ax2(b1)x0有獨(dú)一解,a0,b(b1)24a00b1,a1,f(x)1x2x2x1x226123f(3)6f[f(3)]f(6)32622函數(shù)表示法(一)一、選擇題1.D2.D3.B4.B24EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.二、填空題5.3x6.x22x7.4,48.A{0,2,3}三、解答題9.解:設(shè)f(x)kxb,f[f(x)]k(kxb)bk2xkbb4x1k24k2k2即b,b1或1,kb13bf(x)2x1或f(x)2x1310.解:y242x,2xy6x12其圖像以下列圖:242x0y1260612x4,(x3)11.解:由絕對(duì)值的性質(zhì)得:y2x2,(1x3),其圖像以下列圖:4,(x1)25EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.y4x134函數(shù)值域的值域?yàn)?,41.2.2函數(shù)表示法(二)一、選擇題1.B2.A3.C4.B二、填空題5.1x1,1x0.18.1,[1,)6.f(x)3x,0x722164三、解答題9.解:(1)列表得:x-2-1012y3210-126EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.y321·210·x121·27EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.圖像是五個(gè)孤立的點(diǎn)。(2)y2x24x32(x1)25,(0x3)列表得:x-10123y3-3-5-33先作出張口向上的整支拋物線的圖像,以x1為對(duì)稱軸,以(1,5)為極點(diǎn)坐標(biāo),作出圖像,再依照x3,抹去x0及x3部分圖像,再將x3對(duì)應(yīng)的圖像改為空心點(diǎn)。10.解:當(dāng)x4時(shí),f(x)f(3x)f(1)f(2)f(5)又54,f(5)541,即f(1)111.解:(1)設(shè)f(x)ax2bxc,f(0)c2f(x1)f(x)a(x1)2b(x1)cax2bxc2axabx1a1,b3,c2即f(x)1x23x22222(2)3f(x)f(x)5x,3f(x)f(x)5x,消去f(x)得:3[5x3f(x)]f(x)5xf(x)5x21.3.1函數(shù)單調(diào)性與最大(?。┲担ㄒ唬┮?、選擇題1.A2.D3.C4.B二、填空題5.f(a2a1)f(3)6.2,01,27.f(3)f(3)f(3)8.,2;42;大;728EvaluationOnly.CreatedwithAspose.PDF.Copyright2002-2020AsposePtyLtd.三、解答題1aa21、解:由已知得:11a1,解得:0a191a21110、證明:設(shè)任取x1,x2(1,)且x1x2,則有f(x1)f(x2)x11x21(x1x2)x2x1(x1x2)(11x1x2x1x2)x1x2x1x2,x1x20又x1,x2(1,)11,110,(x1x2)(11)0x1x2x1x2x1x2f(x1)f(x2)0,即f(x1)f(

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