成都市八年級(上)期末數(shù)學試卷含答案

A. B. C.

= A.

B.

C.

=-2+1 A.

B.

C.

A.

=B.

C.

=

= M A.

B.

C.

A.

B.

C.

m+mmn A. B. C. =3=2

A.

B.

C.

2+3

+b

+A.

B.C.

E

F

BF=12=10 A.

B.

C.

______

=-2+b______

=______

DE

E______

+

____

______

=4

E

+PE______

=-+2

m=-2+6m______

==10

E

BE=6

DE______

-3×

+3+

EF

BE=DF

l=

l=3

l

eq

\o\ac(△,Rt)

E

CF

DEF

BF

FDBBE=4

=8BF=4

BFBFGECFDECF=DE

M

=+6

=

eq

\o\ac(△,，將)

M

N

MN

M

=3b

b=b

=-2+1

=-2+1

=-2+1

=-2+1=+b

=+b

=M

m+m

m

n

DE

E==

BE==2DE==3=EC=DE=3=BE+CE=2+3=5

DE

E

BE==2DE==3

EC b b

=+b

b

b b bbbb

=+b

=+bb=+b

b=+b

=+bb<0

=-+

=

E===BE==BE

ABEF=

ABEFBF===

BF=6= = =8=2=16ABEFBF===

BF=6ABEF

=-2+b

=-2

=+b

=|=3-

=

=-DE

==

DE=

=2

=-5

=-+5

mm+5

=-m+5=m

mm+5=10=-+5

mm+5DE

=4

E

=BE=2=DEDE

EC

+PE=+EP=CEDE=

=2CE=

=

=2

+PE

DE=BE=2=DE

EC

+PE=+EP=CEmm =-+2+m

=-2+6mmm=-+2

m=-+2+m

=-+2+m

=-2+6mm

mm

==10

=+BCE

=eq

\o\ac(△,在)

eq

\o\ac(△,與)

===CE=CEDE==BE+

DE=+BE

=

DE=+6

eq

\o\ac(△,Rt)

+=DE+4=+6

DE，交=

=DE==BE+DE×3+=20=2

=2=1

=-7=-3

=-3=1 =2 +2=2+ +1=3- =2

=EF DE=BFDEBF

BFDEBE=DFBE=DF

BEDF

=83

=84

l=

l=3

l=3

=eq

\o\ac(△,S)

+eq

\o\ac(△,S)

=

×10×3+

×10×9-

×9×4=42

l=

l=3l=3

=eq

\o\ac(△,S)

+eq

\o\ac(△,S)

eq

\o\ac(△,S)

CFECF=E

CE=BECEF=CEFCF=

CF

==

M

eq

\o\ac(△,Rt)

=BE=2=2

eq

\o\ac(△,Rt)

= =2 =2 +2

=

××=

×2

×

+2

=4+4CFCF===

M

==5=5

=+b

=5

=5

=1

=5

=

=

=5

=5

BFGE====8BE=BF=FG=4=CBFCE=BE=8-4=4CE=BFeq

\o\ac(△,在)

eq

\o\ac(△,和)

CBF CBFCF=DE

N

GF

=

+FG=

×8+4=6=

+BF=

×8+4=6=BF=6-4=2= = =2

N

==2NQ==8=NQ=8-6=2== =

=

QM=

=+QM=2+

=

====8BE=BF=FG=4=CBF

CE=BE=4

CE=BF

eq

\o\ac(△,證得)

CBF

N

GF

=

+FG=6=

+BF=6

N

==2NQ==8=NQ=2，由=

=eq

\o\ac(△,證得)

=

QM=

=+6

=

=3

=+6=2

=2+6==6

=-+6eq

\o\ac(△,將)

Mm

Nnn+6=

N