2023年計(jì)算機(jī)網(wǎng)絡(luò)實(shí)驗(yàn)報(bào)告郵件服務(wù)的配置與分析

四川大學(xué)計(jì)算機(jī)學(xué)院、軟件學(xué)院

實(shí)驗(yàn)報(bào)告

學(xué)號(hào):。姓名：也專(zhuān)業(yè)：計(jì)算機(jī)科學(xué)與技術(shù)班級(jí):班第周

課程

計(jì)算機(jī)網(wǎng)絡(luò)課程設(shè)計(jì)實(shí)驗(yàn)課時(shí)2

名稱(chēng)

實(shí)驗(yàn)

郵件服務(wù)的配置與分析實(shí)驗(yàn)時(shí)間

項(xiàng)目

為了加深對(duì)郵件協(xié)議的理解，直觀清楚的感受郵件協(xié)議的工作流程，本實(shí)

驗(yàn)借助Wireshark網(wǎng)絡(luò)分析工具，結(jié)合郵件用戶代理，運(yùn)用現(xiàn)有的郵件服

實(shí)驗(yàn)務(wù)提供商，完畢對(duì)郵件收發(fā)過(guò)程的解析。

目的(1)理解SMTP和POP3協(xié)議的基本原理；

(2)理解SMTP和POP3協(xié)議的工作流程；

(3)理解SMTP和POP3協(xié)議在郵件收發(fā)過(guò)程的作用。

實(shí)驗(yàn)1、Windows10;

環(huán)境2、Wireshark-win64-2.2.3;

1、實(shí)驗(yàn)原理：

SMTP協(xié)議:簡(jiǎn)樸郵件傳輸協(xié)議(SimpleMai1TransferProt

ocol),發(fā)送郵件的標(biāo)準(zhǔn)協(xié)議，默認(rèn)使用端口25在TCP/IP連接上工

實(shí)

驗(yàn)作，目的是可靠高效地傳送郵件，它獨(dú)立于傳送子系統(tǒng)并且僅規(guī)定一條可以保

內(nèi)

容證傳送數(shù)據(jù)單元順序的通道。

<協(xié)議：郵局協(xié)議(

算P0P3Post0fficeProtoco1-Version3),

法接受郵件的標(biāo)準(zhǔn)協(xié)議之一,默認(rèn)使用端口110在TCP/IP連接上工作，目

、

程的是允許工作站用戶從郵件服務(wù)器中收取郵件。

序2、實(shí)驗(yàn)環(huán)節(jié)：

、

環(huán)

節(jié)A、創(chuàng)建Foxmail郵箱來(lái)作為用戶代理

和觸鞋號(hào)X

方

法

,⑦幫助

接收服務(wù)器雌：POP3

郵件帳號(hào)：carsonyang518@163.com

空瑪：

POP服務(wù)器：□SSL:110

SMTP服務(wù)器:|口SSL端口：25

口如果股務(wù)器支持.就使用STARTTISUQ堂傳幃⑴

代建設(shè)白

返回創(chuàng)建取消

B、打開(kāi)wireshark進(jìn)行發(fā)送郵件的抓包

■計(jì)網(wǎng)naw實(shí)稿wnn而去已保存―c>?

l-w■wjm?zjjji上網(wǎng)二產(chǎn)

收忤人：7718SM97gqxom

?

￡■：計(jì)同售九網(wǎng)*

MicrosoftY,卜*10.5*￡-□干■=1=

計(jì)阿第九周實(shí)驗(yàn)酒試

（接

carsonyang518@163.com

上）

實(shí)驗(yàn)

內(nèi)容

（算

法、

程

序、

環(huán)節(jié)

和方

法）

2WB??(￡)?UEMKK<G)分析(A)由iSM無(wú)MKW)IMCDWfcOl)

4■??e_、、、“

??<1?X：-?

%.t:aeScoreOesttnittcnProtocolLes?thInfo

206516.419495220.181.12.1416.132.29.69SMTP119S:220163.co?AntispamGTforCOTCIMIISyiteo(16Jco?(2014U01))

200616.42143410.132.29.69220.181.12.14SMTP76C:EHLODESKTOP-CSQQGOC

205716.713M2220.181.12.1410.132.29.69SKIP2J9S:250mall|250PIPfLlNING|250AUTHLOGINPLAIN|2S0AU1H?LOGINPLAIN|2S0corewil..

205816.714iS610.132.29,69220.181.12.14SMTP66C:AUTHLOGIN

2M716.755352220.181.12.1410.132.29.69SMTP72S:334<!XNlcw5hbhU6

206916.78107710.132.29.69220.181.12.14SMTP84C:User：Y2Fyc29ueWuZzUxOEAxNjNuY29t

288sl6.813184220.181.12.1410.132.29.69SMTP72$:3MUGFzc3dvc?Q6

208616.81339410.132.29.69229.181.12.14SMTP76C:Pass:Y2Fyc29uMTkM<zAlMTg?

710616.99318s220.181.12.1410.132.29.69SMTP8SS:235AutbentRation?ucc???ful

210916.94775219.132.29.69220.181.12.14SMTP96C:NAILFROM:<car$onyang518^163.co?>

213316.985169220.181.12.1410.132.29.69SMTP67S:250MillOK

2B416.98S46110.132.29.69220.181.12.14SNTP83C:RCPTTO:<771858897^Qq.co?>

?14817.017801220.181.12.1410.132.29.69SMTP67S:250MallOK

214917.01818110.132.29.69220.181.12.14SMTP60C:DATA

215217.053191220.181.12.1410.132.29.69SMTP91S:354Enddatawith<CRxLF>><CR><LF>

215317.05341710.132.29.69226.181.12.14SMTP444C:OATAfragoent,390byte*

228917.12835910.132.29.69229.181.12.14IMF976frat:"carsonyangS18^163.coa*<carsonyang518^163.C0M>>subject:??GB2312?8?vMbfHLXav$XW3Mq.

219517.172974220.181.12.1410.132.29.69SMTP128S:250MallOKqueuedass?itplO,DsCowABX*rZAsPlZBJK9Bw.16642S21509797953

219617.17369610.132.29,69220.181.12.14SMTP60C:QUIT

221417.209210220.181.12.1410.132.29.69SMTP63S:221Bye

Fr?ne2805:119bytesonwire(952bits),119bytescaptured(952bits)oninterfacee

EthernetII.Src:Ruiji?Ne_4c:47:53(58:69:6c:4c:47:53),Ost:Microsof_S?:25:ba(98:Sf:d3:S8:2S:b?)

InternetProtocolVersion4,Src:220.181.12.14,Dst:10.132.29.69

TranuiisslonControlProtocol,SrcPort:25,OstPort:49882,Saq:1,Ack:1,L?n:6s

,SimpleMailTransferProtocol

J“53e845ga

S82sS847IL

98t>a6c4cb5ecee0306一

0e6984794e30b589(kfee84

c00“M6b750

sle.:;:

ld450019dasdf83633686318

816?3

73416S0e3231

eeWee3e2eM2e472e29GT

6d2e41742d70615466pa

i)w639jM刈g(

心

M肛4

fe..-

5'0110Ac

C、啟動(dòng)wireshark,點(diǎn)擊收取，進(jìn)行收取郵件的抓包

Foxmail一□

&收取，1'寫(xiě)郵件，.叵、,.awisn-u險(xiǎn)方二、nW?：v

▼常喇快排序:日距"

“標(biāo)簽as件

▼163163(carsonyangS18)

3收件18

?博隋

1

0

垃圾IS件

無(wú)內(nèi)容

國(guó)工口目

XWB?W(D皿M?w依）j?軟g分析3）就計(jì)0?tsco無(wú)牧工Am

4"?2t?*.二生'、4"

'IKV。RUX—,

No.tiaeSourceDe?ttna:ionProtocolLengthInfo

8989.089061121.19S.178.5210.132.29.69141S:?OKWCICMCtoCorel1MallPopJS?rv?r(163com?[726cd87d72d896?lic393507346040f?*])

8999.。893的10.132.29.69121.19S.178.S282C:USERcarsonyangS189163.coa

9039.1275W121.195.178.5210.132.29.6969S:?0Kcoreaall

9069.12809618.132.29.69275C:PASSc*rsonl997eS18

9229.229184121.19S.178.5210.132.29.6988S:?0K3messaee(s)(14S04byte(s)]

9239.23046610.132.29.6912260C:STAT

9249.270547121.195.178.52IS.132.29.6967S:?(*314564

9259.27197610.132.29.6912260C：LIST

9269.31155412210.132.29.6994S:?(X314W4

9279.31211610.132.29.69121.19S.178.5260C:UIDL

9369.351390121.195.178.S216.132.29.69148S:40K314504

9379.3615671B.132.M.69262C:RETR3

9389.40317212210.132.29.6971S:?0K4172octets

9399.40810712218.132.29.691448S:DATAfragaent,1394bytes

9419.40M27121.19S.178.5210.132.29.691448S:DATAfragment,1394bytes

9429.40859712210.132.29.691438fro?:B=?gbl8830?B?O^/qtGr?=?<771B58897^qq.coa>,subject:x?gb18630?B>u914tK06vMt>N*LX4VS_

9439.4M598121.19S.178.S2W.132.29.6968.

9529.47903110.132.29.69121.19S.178.S260C:QUIT

9619.529117121.19S.178.5210.132.29.6969S:?0Kcor*mail

Frame898:141t>ytesonwire(1128bits),141bytescaptured(1128bits)onInterface9

EthernetII,Src:Ruiji?fte_4c:47:53(58:69:6c:4c:47:53),0*t:Microsof_M:25:ba(98:5f:d3:S8:2S:ba)

InternetProtocolVersion4,Src:121.195.178.52,Dst:10.132.29.69

TranwilsslonControlProtocol,SrePort:lie,OstPort:49167,Scq:1,Ack:1,L?n:87

PostOfficeProtocol

25b4753?瓷

a?

“

98d3S8S8696c4c08ee4s0IX111二GS.E.

4ee"79c3M84(

ee47le33eg696b20a143E.y--

ceefe2218epg.

ld0e9f8c6s5se總Kwewl

6"e"eed6l6s&

e:e7eee62"b4b2Me5756c63

￡“f

7dlae66<-6>1dlcMa

，067>6s6107A4d

SMTP協(xié)議分析：

(1)郵件發(fā)送方與郵件服務(wù)器端建立連接,服務(wù)器返回連接成功信息是狀態(tài)是什

么，具體信息有哪些？

▼SimpleMailTransferProtocol

vResponse:220163.comAnti-spamGTforCoremailSystem(163com[20141201])\r\n

Responsecode:<domain>Serviceready(220)

Responseparameter:163.comAnti-spamGTforCoremailSystem(163com[20141201])

答：220,具體信息有220163.comAnti-spamGTforCoremai1System

(163com[20231201])。

(2)郵件服務(wù)器收到發(fā)送方的消息后EHLO后，服務(wù)器返回什么信息？

vSimpleMailTransferProtocol

▼Response:250-mail\r\n

Responsecode:Requestedmailactionokay,completed(250)

Responseparameter:mail

▼Response:250-PIPELINING\r\n

Responsecode:Requestedmailactionokay,completed(250)

Responseparameter:PIPELINING

▼Response:250-AUTHLOGINPLAIN\r\n

數(shù)據(jù)Responsecode:Requestedmailactionokay,completed(250)

Responseparameter:AUTHLOGINPLAIN

記錄vResponse:250-AUTH=LOGINPLAIN\r\n

Responsecode:Requestedmailactionokay,completed(250)

和計(jì)Responseparameter:AUTH=LOGINPLAIN

?Response:250-coremaillUxr2xKj7kG0xkI17xGrU7I0s8FY2U3Uj8Cz28xlUUUUU7Ic2I0Y2UrN7QTFUCa0xDrUUUUj\r\n

算Responsecode:Requestedmailactionokay,completed(250)

Responseparameter:coremaillUxr2xKj7kG0xkI17xGrU7I0s8FY2U3Uj8Cz28xlUUUUU7Ic2I0Y2UrN7QTFUCa0xDrllUUUj

vResponse:250-STARTTLS\r\n

Responsecode:Requestedmailactionokay,completed(250)

Responseparameter:STARTTLS

vResponse:2508BITMIME\r\n

Responsecode:Requestedmailactionokay,completed(250)

Responseparameter:8BITMIME

答：返回了250mai1|250PIPELINING250AUTHLOGINPLAIN250

AUTH=L0GINPLAIN|250coremai1Wxr2xKj7kG0xkIl7xGrU7I0s8F

Y2U3UJ8Cz28x1UUUUU7Ic2I0Y2UrN7QTFUCaOxDrUUUUjI250STARTTLS|25

08BITMIME

(3)郵件服務(wù)器收到發(fā)送方的身份驗(yàn)證請(qǐng)求后，服務(wù)器將返回什么信息？

205816.71438694SMTP66C：AUTHLOGIN

206716.75535249SMTP72S:334dXNlcm5hbWU6

206916.78107794SMTP84C:User:Y2Fyc29ueWFuZzUxOEAxNjMuY29t

208516.81318449SMTP72S:334UGFzc3dvcmQ6

208616.81339494SMTP76C:Pass:Y2Fyc29uMTk5NzAlMTg=

210616.90338549SMTP85S:235Authenticationsuccessful

答：返回了334dXN1cm5hbWU60

(4)請(qǐng)描述SMTP協(xié)議將郵件投遞到相應(yīng)用戶郵箱中的工作流程。

答:一方面建立本機(jī)與郵件服務(wù)器之間的TCP連接，之后向服務(wù)器標(biāo)記用戶身份,

然后輸入密碼登陸服務(wù)器,之后指定發(fā)信者,再指定收信者，最后發(fā)送數(shù)據(jù)即完畢

了所有工作流程。

POP協(xié)議分析：

(1)郵件接受方與郵件服務(wù)器端建立連接，服務(wù)器返回連接成功信息是什么，

具體信息有哪些？

vPostOfficeProtocol

>+0KWelcometocoremailMailPop3Server(163coms[726cd87d72d896alac393507346040fas])\r\n

答：返回了+0KWeicometocoremai1Mai1Pop3Server(163coms[726cd87d72d896a

1acfas])o

(2)運(yùn)用USER<name>和PASS<password>向郵件服務(wù)器發(fā)送認(rèn)證信息，

服務(wù)器返回什么信息？

8999.08936092POP82C:USERcarsonyang51%163.com

9039.12758029POP69S:+0Kcoremail

9069.12809092POP75C:PASScarsonl9970518

9229.22918429POP88S:+0K3message(s)[14504byte(s)]

答：返回了+0Kcoremai1和+0K3message(s)[14504by

te(s)]o

(3)接受方發(fā)送LIST命令，用于查詢郵件服務(wù)器狀態(tài)以及每封郵件的狀態(tài)，將

返回什么信息？

9259.27197692POP60C:LIST

9269.31155429POP94S:+0K314504

▼PostOfficeProtocol

▼+0K314504\r\n

Responseindicator:+0K

Responsedescription:314504

19125\r\n

21207\r\n

34172\r\n

答:返回了ANno

(4)在進(jìn)行POP3協(xié)議的分析時(shí)，當(dāng)賬戶沒(méi)有新郵件到來(lái)時(shí)，點(diǎn)擊“收取”，

會(huì)出現(xiàn)什么情況？

2?(￡)SWD?a：y)分本依)優(yōu)計(jì)oes(n無(wú)板sIM(DWO(H)

4■?一■匕、?????.三044”

,pop°a達(dá)式?1?

[So.ti*?S<w?D?*tln*tlonProtorolLanfthlafo

4s9.$03421220.181.12.ne192.168.191.6POP141$:??(WelcometocoreKallHailPop3Server(163co?s(726cd87d72d896dlac393M7M6040fas])

469.503864192.168.191.6226.181.12.110POP82C:USERcaronyan”】酩631.co?

489.550678220.181.12.110192.168.191.6POP69$：*0Kcorerail

499.5S0970192.16B.191.6229.181.12.110POP7SC:PASSc?rsonl997e518

519.647999220.181.12.110192.168.191.6POP885:?(*3message(s)(14504byte(s)]