一維搜索方法與終止準(zhǔn)則實(shí)驗(yàn)

實(shí)驗(yàn)報(bào)告課程名稱：_現(xiàn)代機(jī)械設(shè)計(jì)設(shè)計(jì)方法__項(xiàng)目名稱：__一維搜索方法與終止準(zhǔn)則____實(shí)驗(yàn)預(yù)習(xí)部分：實(shí)驗(yàn)?zāi)康模?．實(shí)驗(yàn)原理：3．實(shí)驗(yàn)儀器：4．實(shí)驗(yàn)步驟及方法：實(shí)驗(yàn)過程記錄部分：1.%typbound.m;進(jìn)退法1function[lowbound,upbound]=typbound11(x0,step0,startopint,searchdirection)step=step0;f0=tryobjfun11(x0,startopint,searchdirection);x1=x0+step0;f1=tryobjfun11(x1,startopint,searchdirection);iff1<=f0whiletruestep=2*step;x2=x1+step;f2=tryobjfun11(x2,startopint,searchdirection);iff1<=f2lowbound=x0;upbound=x2;break;elsex0=x1;x1=x2;f0=f1;f1=f2;endendelsewhiletruestep=2*step;x2=x0-step;f2=tryobjfun11(x2,startopint,searchdirection);iff0<=f2lowbound=x2;upbound=x1;break;elsex1=x0;x0=x2;f1=f0;f0=f2;endendend%(2)tryobjfun.進(jìn)退法2functionf=tryobjfun11(a,startopint,searchdirection)f=objfun11(startopint+a.*searchdirection);%(3)確定函數(shù)，也就是你要確定搜索區(qū)間的目標(biāo)函數(shù)，你也可以改，這僅是一個(gè)例子。進(jìn)退法3functionf=objfun(x)f=x.^2-6.*x+9end2.function[x,y]=goldmin12(f,xa,xb,s)%黃金分割法求解函數(shù)最小值%輸入%f待優(yōu)化函數(shù)%a,b區(qū)間%s精度%輸出%x最優(yōu)解%y最優(yōu)解對(duì)應(yīng)的最小值g=(sqrt(5)-1)/2;%黃金分割比，0.618a=xa;b=xb;x2=a+g*(b-a);x1=a+b-x2;y1=f(x1);y2=f(x2);whileabs(b-a)>sify1<y2b=x2;x2=x1;x1=a+b-x2;endify1>=y2a=x1;x1=x2;x2=a+b-x1;endy1=f(x1);y2=f(x2);endx=x1;y=f(x); 實(shí)驗(yàn)報(bào)告成績（百分制）__________實(shí)驗(yàn)指導(dǎo)教師簽字：__________驗(yàn)