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2019-2020學(xué)年高一數(shù)學(xué)上學(xué)期期末試卷一、選擇題1.某幾何體的三視圖如圖所示(單位:cm),則該幾何體的體積(單位:SKIPIF1<0)是A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.若SKIPIF1<0,則SKIPIF1<0的值為SKIPIF1<0SKIPIF1<0A.SKIPIF1<0 B.SKIPIF1<0 C.2 D.33.已知函數(shù)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的零點分別為SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的大小關(guān)系是SKIPIF1<0SKIPIF1<0A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<04.設(shè)角的終邊經(jīng)過點,那么()A. B. C. D.5.已知SKIPIF1<0為方程SKIPIF1<0的解,且SKIPIF1<0,則SKIPIF1<0SKIPIF1<0A.1 B.2 C.3 D.46.如圖,在平面直角坐標(biāo)系SKIPIF1<0中,角SKIPIF1<0以SKIPIF1<0為始邊,終邊與單位圓SKIPIF1<0相交于點SKIPIF1<0.過點SKIPIF1<0的圓SKIPIF1<0的切線交SKIPIF1<0軸于點SKIPIF1<0,點SKIPIF1<0的橫坐標(biāo)關(guān)于角SKIPIF1<0的函數(shù)記為SKIPIF1<0.則下列關(guān)于函數(shù)SKIPIF1<0的說法正確的()A.SKIPIF1<0的定義域是SKIPIF1<0B.SKIPIF1<0的圖象的對稱中心是SKIPIF1<0C.SKIPIF1<0的單調(diào)遞增區(qū)間是SKIPIF1<0D.SKIPIF1<0對定義域內(nèi)的SKIPIF1<0均滿足SKIPIF1<07.已知實數(shù)SKIPIF1<0,SKIPIF1<0滿足約束條件SKIPIF1<0,則目標(biāo)函數(shù)SKIPIF1<0的最小值為()A.SKIPIF1<0 B.SKIPIF1<0 C.8 D.SKIPIF1<08.從1,2,3,…,9中任取兩數(shù),其中:①恰有一個偶數(shù)和恰有一個奇數(shù);②至少有一個奇數(shù)和兩個都是奇數(shù);③至少有一個奇數(shù)和兩個都是偶數(shù);④至少有一個奇數(shù)和至少有一個偶數(shù).在上述事件中,是對立事件的是().A.① B.②④ C.③ D.①③9.圓SKIPIF1<0的圓心到直線SKIPIF1<0的距離為1,則SKIPIF1<0()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.210.根據(jù)統(tǒng)計,一名工人組裝第x件某產(chǎn)品所用的時間(單位:分鐘)為f(x)=(A,c為常數(shù)).已知工人組裝第4件產(chǎn)品用時30分鐘,組裝第A件產(chǎn)品用時15分鐘,那么c和A的值分別是()A.75,25B.75,16C.60,25D.60,1611.一個三棱柱的底面是正三角形,側(cè)棱垂直于底面,它的三視圖及其尺寸如下(單位),則該三棱柱的表面積為()A.B.C.D.12.設(shè)SKIPIF1<0為定義在SKIPIF1<0上的函數(shù),當(dāng)SKIPIF1<0時,SKIPIF1<0,則SKIPIF1<0A.-3 B.-1 C.1 D.3二、填空題13.已知,則的最小值為____________。14.底面邊長為1,棱長為SKIPIF1<0的正四棱柱,各頂點均為在同一球面上,則該球的體積為__________.15.已知角SKIPIF1<0終邊上一點P的坐標(biāo)為SKIPIF1<0,則SKIPIF1<0是第____象限角,SKIPIF1<0____·16.函數(shù)SKIPIF1<0的部分圖象如圖,其中SKIPIF1<0,SKIPIF1<0,SKIPIF1<0.則SKIPIF1<0____;SKIPIF1<0_____.三、解答題17.已知向量SKIPIF1<0,SKIPIF1<0,設(shè)函數(shù)SKIPIF1<0.SKIPIF1<0ⅠSKIPIF1<0求函數(shù)SKIPIF1<0的最小正周期和單調(diào)遞增區(qū)間;SKIPIF1<0ⅡSKIPIF1<0求函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0的最大值和最小值.18.已知函數(shù)SKIPIF1<0SKIPIF1<0的圖象如圖所示.(1)求函數(shù)SKIPIF1<0的解析式;(2)求函數(shù)SKIPIF1<0的單調(diào)增區(qū)間;(3)當(dāng)SKIPIF1<0時,求函數(shù)SKIPIF1<0的值域.19.是單位圓上的點,點是單位圓與軸正半軸的交點,點在第二象限,記,且.(1)求點的坐標(biāo);(2)求的值.20.如圖,在四棱錐SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,平面SKIPIF1<0底面SKIPIF1<0,SKIPIF1<0,SKIPIF1<0和SKIPIF1<0分別是SKIPIF1<0和SKIPIF1<0的中點.求證:(1)SKIPIF1<0底面SKIPIF1<0;(2)SKIPIF1<0平面SKIPIF1<0;(3)平面SKIPIF1<0平面SKIPIF1<0.21.在平面直角坐標(biāo)SKIPIF1<0中,圓SKIPIF1<0與圓SKIPIF1<0相交與SKIPIF1<0兩點.(I)求線段SKIPIF1<0的長.(II)記圓SKIPIF1<0與SKIPIF1<0軸正半軸交于點SKIPIF1<0,點SKIPIF1<0在圓C上滑動,求SKIPIF1<0面積最大時的直線SKIPIF1<0的方程.22.如圖,三棱柱SKIPIF1<0的側(cè)面SKIPIF1<0是邊長為SKIPIF1<0的菱形,SKIPIF1<0,且SKIPIF1<0.(1)求證:SKIPIF1<0;(2)若SKIPIF1<0,當(dāng)二面角SKIPIF1<0為直二面角時,求三棱錐SKIPIF1<0的體積.【參考答案】***一、選擇題題號123456789101112答案AAADBBCCADBA二、填空題13.414.SKIPIF1<015.四SKIPIF1<016.SKIPIF1<0三、解答題17.(Ⅰ)最小正周期是SKIPIF1<0,增區(qū)間為SKIPIF1<0,SKIPIF1<0;(Ⅱ)最大值為5,最小值為4.18.(1)SKIPIF1<0(2)SKIPIF1<0,SKIPIF1<0(3)SKIPIF1<019.(1);(2).20.(1)證明見解析.(2)證明見解析.(3)證明見解析.21.(I)SKIPIF1<0;(II)SKIPIF1<0或SKIPIF1<0.22.(1)略(2)SKIPIF1<0
2019-2020學(xué)年高一數(shù)學(xué)上學(xué)期期末試卷一、選擇題1.設(shè)SKIPIF1<0是定義在SKIPIF1<0上恒不為零的函數(shù),對任意實數(shù)SKIPIF1<0,都有SKIPIF1<0,若SKIPIF1<0,SKIPIF1<0,則數(shù)列SKIPIF1<0的前SKIPIF1<0項和SKIPIF1<0的取值范圍是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.設(shè)是兩條不同的直線,是兩個不同的平面,則下列結(jié)論正確的是()A.若,,則 B.若,則C.若,則 D.若,則3.已知SKIPIF1<0、SKIPIF1<0是兩條不同的直線,SKIPIF1<0、SKIPIF1<0是兩個不同的平面,則下列命題正確的是()A.若SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0 B.若SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0C.若SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0 D.若SKIPIF1<0,SKIPIF1<0,則SKIPIF1<04.函數(shù)SKIPIF1<0的部分圖象如圖所示,則()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<05.若SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0的最小值為()A.2 B.SKIPIF1<0 C.4 D.SKIPIF1<06.設(shè)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0、SKIPIF1<0、SKIPIF1<0的大小關(guān)系為A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<07.動圓M與定圓SKIPIF1<0相外切,且與直線SKIPIF1<0相切,則動圓SKIPIF1<0的圓心SKIPIF1<0滿足的方程為()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<08.設(shè)集合SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<09.已知SKIPIF1<0且SKIPIF1<0,函數(shù)SKIPIF1<0,滿足對任意實數(shù)SKIPIF1<0,都有SKIPIF1<0成立,則實數(shù)SKIPIF1<0的取值范圍是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<010.容量為100的樣本,其數(shù)據(jù)分布在SKIPIF1<0,將樣本數(shù)據(jù)分為4組:SKIPIF1<0,得到頻率分布直方圖如圖所示,則下列說法不正確的是()A.樣本數(shù)據(jù)分布在SKIPIF1<0的頻率為0.32 B.樣本數(shù)據(jù)分布在SKIPIF1<0的頻數(shù)為40C.樣本數(shù)據(jù)分布在SKIPIF1<0的頻數(shù)為40 D.估計總體數(shù)據(jù)大約有10%分布在SKIPIF1<011.執(zhí)行如圖的程序框圖,如果輸入的,則輸出的值滿足()A.B.C.D.12.執(zhí)行如圖所示的程序框圖,輸出的SKIPIF1<0值為()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.2二、填空題13.已知在SKIPIF1<0中,角SKIPIF1<0的大小依次成等差數(shù)列,最大邊和最小邊的長是方程SKIPIF1<0的兩實根,則SKIPIF1<0__________.14.直三棱柱ABC-A1B1C1,內(nèi)接于球O,且AB⊥BC,AB=3.BC=4.AA1=4,則球O的表面積______.15.如圖,正方體SKIPIF1<0的棱長為1,線段SKIPIF1<0上有兩個動點SKIPIF1<0,且SKIPIF1<0,現(xiàn)有如下四個結(jié)論:SKIPIF1<0;SKIPIF1<0平面SKIPIF1<0;SKIPIF1<0三棱錐SKIPIF1<0的體積為定值;SKIPIF1<0異面直線SKIPIF1<0所成的角為定值,其中正確結(jié)論的序號是______.16.已知函數(shù)SKIPIF1<0,SKIPIF1<0,若存在實數(shù)SKIPIF1<0,SKIPIF1<0,使得SKIPIF1<0,且SKIPIF1<0,則實數(shù)a的取值范圍是_____.三、解答題17.已知數(shù)列SKIPIF1<0是公差不為0的等差數(shù)列,SKIPIF1<0成等比數(shù)列.(1)求SKIPIF1<0;(2)設(shè)SKIPIF1<0,數(shù)列SKIPIF1<0的前n項和為SKIPIF1<0,求SKIPIF1<018.已知函數(shù)SKIPIF1<0,SKIPIF1<0(1)求函數(shù)SKIPIF1<0的最小正周期;(2)設(shè)SKIPIF1<0的內(nèi)角SKIPIF1<0的對邊分別為SKIPIF1<0,且SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,求SKIPIF1<0的面積.19.已知函數(shù)SKIPIF1<0.SKIPIF1<0ⅠSKIPIF1<0若SKIPIF1<0,求SKIPIF1<0的值;SKIPIF1<0ⅡSKIPIF1<0設(shè)函數(shù)SKIPIF1<0,求函數(shù)SKIPIF1<0的值域.20.計算:。21.設(shè)二次函數(shù)SKIPIF1<0的圖像過點SKIPIF1<0和SKIPIF1<0,且對于任意實數(shù)SKIPIF1<0,不等式SKIPIF1<0恒成立.(1)求SKIPIF1<0的表達式;(2)設(shè)SKIPIF1<0,若SKIPIF1<0在SKIPIF1<0上是增函數(shù),求實數(shù)SKIPIF1<0的取值范圍.22.已知是奇函數(shù).求a的值并判斷的單調(diào)性,無需證明;若對任意,不等式恒成立,求實數(shù)k的取值范圍.【參考答案】***一、選擇題題號123456789101112答案AAAACABCDDCD二、填空題13.SKIPIF1<014.SKIPIF1<015.SKIPIF1<016.SKIPIF1<0三、解答題17.(1)SKIPIF1<0(2)SKIPIF1<018.(1)SKIPIF1<0;(2)SKIPIF1<0.19.SKIPIF1<0ⅠSKIPIF1<0;(2)SKIPIF1<020.21.(Ⅰ);(Ⅱ).22.(1)在R上為增函數(shù);(2)
2019-2020學(xué)年高一數(shù)學(xué)上學(xué)期期末試卷一、選擇題1.在長為SKIPIF1<0的線段SKIPIF1<0上任取一點SKIPIF1<0.現(xiàn)作一矩形,鄰邊長分別等于線段SKIPIF1<0,SKIPIF1<0的長,則該矩形面積大于SKIPIF1<0的概率為()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.設(shè),,是平面內(nèi)共線的三個不同的點,點是,,所在直線外任意-點,且滿足,若點在線段的延長線上,則()A., B., C. D.3.已知函數(shù)SKIPIF1<0在一個周期內(nèi)的圖象如圖所示.則SKIPIF1<0的圖象,可由函數(shù)SKIPIF1<0的圖象怎樣變換而來(縱坐標(biāo)不變)()A.先把各點的橫坐標(biāo)縮短到原來的SKIPIF1<0倍,再向左平移SKIPIF1<0個單位B.先把各點的橫坐標(biāo)縮短到原來的SKIPIF1<0倍,再向右平移SKIPIF1<0個單位C.先把各點的橫坐標(biāo)伸長到原來的2倍,再向左平移SKIPIF1<0個單位D.先把各點的橫坐標(biāo)伸長到原來的2倍,再向右平移SKIPIF1<0個單位4.已知SKIPIF1<0中,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的對邊分別是SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,且SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0邊上的中線的長為()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0或SKIPIF1<0 D.SKIPIF1<0或SKIPIF1<05.已知函數(shù)f(x)=Asin(ωx+φ)(A>0,ω>0,|φ|<π)的圖象經(jīng)過點P(SKIPIF1<0,0)和相鄰的最低點為Q(SKIPIF1<0,-2),則f(x)的解析式()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<06.下列函數(shù)中,值域是SKIPIF1<0的是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<07.已知邊長為1的菱形SKIPIF1<0中,SKIPIF1<0,點SKIPIF1<0滿足SKIPIF1<0,則SKIPIF1<0的值是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<08.設(shè),若僅有一個常數(shù),使得對于任意的,都有滿足方程,則的取值集合為()A. B. C. D.9.若SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0的最小值為()A.2 B.SKIPIF1<0 C.4 D.SKIPIF1<010.已知函數(shù)SKIPIF1<0,若方程SKIPIF1<0有三個不同的實數(shù)根,則實數(shù)SKIPIF1<0的取值范圍為()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<011.將進貨單價為40元的商品按60元一個售出時,能賣出400個.已知該商品每個漲價1元,其銷售量就減少10個,為了賺得最大利潤,售價應(yīng)定為A.每個70元B.每個85元C.每個80元D.每個75元12.如圖,三棱柱中,側(cè)棱底面,底面三角形是正三角形,是中點,則下列敘述正確的是()A.平面B.與是異面直線C.D.二、填空題13.如圖,一熱氣球在海拔60m的高度飛行,在空中A處測得前下方河流兩側(cè)河岸SKIPIF1<0,SKIPIF1<0的俯角分別為75°,30°,則河流的寬度SKIPIF1<0等于_____m.14.已知SKIPIF1<0,若SKIPIF1<0,則a的取值范圍是______.15.若函數(shù)是冪函數(shù),則函數(shù)(其中,)的圖象過定點的坐標(biāo)為__________.16.一個三角形的三條邊成等比數(shù)列,那么,公比q的取值范圍是__________.三、解答題17.某市食品藥品監(jiān)督管理局開展2019年春季校園餐飲安全檢查,對本市的8所中學(xué)食堂進行了原料采購加工標(biāo)準(zhǔn)和衛(wèi)生標(biāo)準(zhǔn)的檢查和評分,其評分情況如下表所示:中學(xué)編號12345678原料采購加工標(biāo)準(zhǔn)評分x10095938382757066衛(wèi)生標(biāo)準(zhǔn)評分y8784838281797775(1)已知x與y之間具有線性相關(guān)關(guān)系,求y關(guān)于x的線性回歸方程;(精確到0.1)(2)現(xiàn)從8個被檢查的中學(xué)食堂中任意抽取兩個組成一組,若兩個中學(xué)食堂的原料采購加工標(biāo)準(zhǔn)和衛(wèi)生標(biāo)準(zhǔn)的評分均超過80分,則組成“對比標(biāo)兵食堂”,求該組被評為“對比標(biāo)兵食堂”的概率.參考公式:SKIPIF1<0,SKIPIF1<0;參考數(shù)據(jù):SKIPIF1<0,SKIPIF1<0.18.如圖,已知以點SKIPIF1<0為圓心的圓與直線SKIPIF1<0相切.過點SKIPIF1<0的動直線SKIPIF1<0與圓A相交于M,N兩點,Q是SKIPIF1<0的中點,直線SKIPIF1<0與SKIPIF1<0相交于點P.(1)求圓A的方程;(2)當(dāng)SKIPIF1<0時,求直線SKIPIF1<0的方程.19.已知如圖,在直三棱柱SKIPIF1<0中,SKIPIF1<0,且SKIPIF1<0,SKIPIF1<0是SKIPIF1<0的中點,SKIPIF1<0是SKIPIF1<0的中點,點SKIPIF1<0在直線SKIPIF1<0上.(1)若SKIPIF1<0為SKIPIF1<0中點,求證:SKIPIF1<0平面SKIPIF1<0;(2)證明:SKIPIF1<020.已知函數(shù)SKIPIF1<0(1)求函數(shù)SKIPIF1<0的最小正周期;(2)求函數(shù)SKIPIF1<0的單調(diào)遞減區(qū)間;(3)求函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的最小值.21.已知函數(shù)SKIPIF1<0的定義域為SKIPIF1<0,且對任意實數(shù)SKIPIF1<0恒有SKIPIF1<0(SKIPIF1<0且SKIPIF1<0)成立.(1)求函數(shù)SKIPIF1<0的解析式;(2)討論SKIPIF1<0在SKIPIF1<0上的單調(diào)性,并用定義加以證明.22.已知等差數(shù)列SKIPIF1<0的前3項和為6,前8項和為SKIPIF1<0.(1)求數(shù)列SKIPIF1<0的通項公式;(2)設(shè)SKIPIF1<0,求數(shù)列SKIPIF1<0的前SKIPIF1<0項和SKIPIF1<0【參考答案】***一、選擇題題號123456789101112答案CABCBDACCAAD二、填空題13.SKIPIF1<014.SKIPIF1<015.(3,0)16.SKIPIF1<0三、解答題17.(1)SKIPIF1<0;(2)SKIPIF1<018.(1)SKIPIF1<0.(2)SKIPIF1<0或SKIPIF1<019.(1)略;(2)略20.(1)SKIPIF1<0;(2)SKIPIF1<0;(3)SKIPIF1<021.(1)SKIPIF1<0(2)當(dāng)SKIPIF1<0時,SKIPIF1<0在SKIPIF1<0上為單調(diào)減函數(shù);當(dāng)SKIPIF1<0時,SKIPIF1<0在SKIPIF1<0上為單調(diào)增函數(shù).22.(1)SKIPIF1<0(2)SKIPIF1<0
2019-2020學(xué)年高一數(shù)學(xué)上學(xué)期期末試卷一、選擇題1.已知SKIPIF1<0是常數(shù),那么“SKIPIF1<0”是“SKIPIF1<0等式對任意SKIPIF1<0恒成立”的()A.充分非必要條件 B.必要非充分條件C.充要條件 D.既不充分也不必要條件2.已知函數(shù)SKIPIF1<0,若函數(shù)SKIPIF1<0是周期為SKIPIF1<0的偶函數(shù),則SKIPIF1<0可以是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<03.已知半圓C:SKIPIF1<0(SKIPIF1<0),A、B分別為半圓C與x軸的左、右交點,直線m過點B且與x軸垂直,點P在直線m上,縱坐標(biāo)為t,若在半圓C上存在點Q使SKIPIF1<0,則t的取值范圍是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<04.已知SKIPIF1<0,當(dāng)m∈[0,1]時,SKIPIF1<0恒成立,則實數(shù)a的取值范圍是()A.0≤a≤1 B.0<a<1 C.a≤0或a≥1 D.a<0或a>15.如圖所示,平面內(nèi)有三個向量SKIPIF1<0,其中SKIPIF1<0與SKIPIF1<0的夾角為SKIPIF1<0,SKIPIF1<0與SKIPIF1<0的夾角為SKIPIF1<0,且SKIPIF1<0,若SKIPIF1<0,則SKIPIF1<0SKIPIF1<0A.1 B.2 C.3 D.46.已知定義在SKIPIF1<0上的函數(shù)SKIPIF1<0的圖象關(guān)于SKIPIF1<0軸對稱,且函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞減,則不等式SKIPIF1<0的解集為()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<07.設(shè)函數(shù)f(x)=cos(x+SKIPIF1<0),則下列結(jié)論錯誤的是A.f(x)的一個周期為?2π B.y=f(x)的圖像關(guān)于直線x=SKIPIF1<0對稱C.f(x+π)的一個零點為x=SKIPIF1<0 D.f(x)在(SKIPIF1<0,π)單調(diào)遞減8.已知集合SKIPIF1<0,則SKIPIF1<0()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<09.下列函數(shù)的最小值為SKIPIF1<0的是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<010.冪函數(shù)SKIPIF1<0在SKIPIF1<0時是減函數(shù),則實數(shù)m的值為SKIPIF1<0SKIPIF1<0A.2或SKIPIF1<0 B.SKIPIF1<0 C.2 D.SKIPIF1<0或111.已知,,,則,,的大小關(guān)系為()A. B. C. D.12.下列函數(shù)中,在區(qū)間SKIPIF1<0上是增函數(shù)的是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0二、填空題13.對任意實數(shù)SKIPIF1<0,不等式SKIPIF1<0恒成立,則實數(shù)SKIPIF1<0的取值范圍是____.14.已知SKIPIF1<0是SKIPIF1<0上的增函數(shù),那么SKIPIF1<0的取值范圍是______.15.已知x<0,且x-y=1,則SKIPIF1<0的最大值是____.16.已知數(shù)列SKIPIF1<0滿足SKIPIF1<0,若SKIPIF1<0,則數(shù)列SKIPIF1<0的通項SKIPIF1<0______.三、解答題17.某快餐連鎖店招聘外賣騎手,該快餐連鎖店提供了兩種日工資方案:方案(1)規(guī)定每日底薪50元,快遞業(yè)務(wù)每完成一單提成3元;方案(2)規(guī)定每日底薪100元,快遞業(yè)務(wù)的前44單沒有提成,從第45單開始,每完成一單提成5元.該快餐連鎖店記錄了每天騎手的人均業(yè)務(wù)量.現(xiàn)隨機抽取100天的數(shù)據(jù),將樣本數(shù)據(jù)分為[25,35),[35,45),[45,55),[55,65),[65,75),[75,85),[85,95]七組,整理得到如圖所示的頻率分布直方圖。(1)隨機選取一天,估計這一天該連鎖店的騎手的人均日快遞業(yè)務(wù)量不少于65單的概率;(2)若騎手甲、乙選擇了日工資方案(1),丙、丁選擇了日工資方案(2).現(xiàn)從上述4名騎手中隨機選取2人,求至少有1名騎手選擇方案(1)的概率;18.設(shè)圓SKIPIF1<0,圓SKIPIF1<0,(1)判斷圓SKIPIF1<0與圓SKIPIF1<0的位置關(guān)系;(2)點SKIPIF1<0、SKIPIF1<0分別是圓SKIPIF1<0,SKIPIF1<0上的動點,SKIPIF1<0為直線SKIPIF1<0上的動點,求SKIPIF1<0的最小值。19.已知函數(shù)SKIPIF1<0,將SKIPIF1<0的圖象向右平移SKIPIF1<0單位長度,再向下平移SKIPIF1<0個單位長度得到函數(shù)SKIPIF1<0的圖象.(1)求函數(shù)SKIPIF1<0的遞增區(qū)間;(2)當(dāng)SKIPIF1<0時,求SKIPIF1<0的最小值以及取得最小值時SKIPIF1<0的集合.20.某市從高二年級隨機選取1000名學(xué)生,統(tǒng)計他們選修物理、化學(xué)、生物、
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