新高考數(shù)學(xué)一輪復(fù)習(xí)函數(shù)重難點(diǎn)專(zhuān)題05分段函數(shù)（原卷版）

專(zhuān)題05分段函數(shù)專(zhuān)項(xiàng)突破一分段函數(shù)函數(shù)值(解析式)1．若SKIPIF1<0為奇函數(shù)，則SKIPIF1<0（

）A．-8 B．-4 C．-2 D．02．已知函數(shù)SKIPIF1<0，則SKIPIF1<0（

）A．0 B．SKIPIF1<0 C．SKIPIF1<0 D．13．設(shè)SKIPIF1<0是定義域?yàn)镽，最小正周期為SKIPIF1<0的函數(shù)，若SKIPIF1<0，則SKIPIF1<0的值等于（

）A．SKIPIF1<0 B．SKIPIF1<0 C．0 D．SKIPIF1<04．已知函數(shù)SKIPIF1<0且SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．已知函數(shù)SKIPIF1<0，則SKIPIF1<0______．6．已知函數(shù)SKIPIF1<0，則SKIPIF1<0___________.7．已知定義域?yàn)镾KIPIF1<0的奇函數(shù)SKIPIF1<0，當(dāng)x>0時(shí)，有SKIPIF1<0，則SKIPIF1<0______．8．函數(shù)SKIPIF1<0，SKIPIF1<0，若SKIPIF1<0，則SKIPIF1<0________．9．對(duì)于實(shí)數(shù)a和b，定義運(yùn)算“*”：SKIPIF1<0，設(shè)SKIPIF1<0.(1)求SKIPIF1<0的解析式；(2)關(guān)于x的方程SKIPIF1<0恰有三個(gè)互不相等的實(shí)數(shù)根，求m的取值范圍.專(zhuān)項(xiàng)突破二分段函數(shù)定義域和值域1．已知函數(shù)SKIPIF1<0，若?SKIPIF1<0∈R，使得SKIPIF1<0成立，則實(shí)數(shù)m的取值范圍為(

)A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．已知SKIPIF1<0的最小值為2，則SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．(多選)設(shè)函數(shù)SKIPIF1<0則（

）A．SKIPIF1<0的定義域?yàn)镾KIPIF1<0 B．SKIPIF1<0的值域?yàn)镾KIPIF1<0C．SKIPIF1<0的單調(diào)遞增區(qū)間為SKIPIF1<0 D．SKIPIF1<0的解集為SKIPIF1<04．(多選)已知函數(shù)SKIPIF1<0，關(guān)于函數(shù)SKIPIF1<0的結(jié)論正確的是（

）A．SKIPIF1<0的定義域?yàn)镽 B．SKIPIF1<0的值域?yàn)镾KIPIF1<0C．若SKIPIF1<0，則x的值是SKIPIF1<0 D．SKIPIF1<0的解集為SKIPIF1<05．函數(shù)SKIPIF1<0的值域?yàn)開(kāi)___________．6．函數(shù)SKIPIF1<0的值域?yàn)開(kāi)__________.7．定義運(yùn)算SKIPIF1<0已知函數(shù)SKIPIF1<0，則SKIPIF1<0的最大值為_(kāi)_____.8．已知SKIPIF1<0、b、SKIPIF1<0都是實(shí)數(shù)，若函數(shù)SKIPIF1<0的反函數(shù)的定義域是SKIPIF1<0，則SKIPIF1<0的所有取值構(gòu)成的集合是________9．若函數(shù)SKIPIF1<0的值域?yàn)镾KIPIF1<0，則SKIPIF1<0的取值范圍是____________．10．已知函數(shù)SKIPIF1<0，SKIPIF1<0，對(duì)SKIPIF1<0，用SKIPIF1<0表示SKIPIF1<0，SKIPIF1<0中的較大者，記為SKIPIF1<0，則SKIPIF1<0的最小值為_(kāi)_____.專(zhuān)項(xiàng)突破三分段函數(shù)單調(diào)性1．函數(shù)SKIPIF1<0的單調(diào)遞增區(qū)間是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．已知函數(shù)SKIPIF1<0，則函數(shù)SKIPIF1<0是（

）A．偶函數(shù)，在SKIPIF1<0上單調(diào)遞增 B．偶函數(shù)，在SKIPIF1<0上單調(diào)遞減C．奇函數(shù)，在SKIPIF1<0上單調(diào)遞增 D．奇函數(shù)，在SKIPIF1<0上單調(diào)遞減3．若函數(shù)SKIPIF1<0是定義在R上的增函數(shù)，則實(shí)數(shù)m的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．設(shè)函數(shù)SKIPIF1<0，若SKIPIF1<0，則實(shí)數(shù)SKIPIF1<0______，SKIPIF1<0的單調(diào)增區(qū)間為_(kāi)_____．5．已知函數(shù)SKIPIF1<0，則SKIPIF1<0_____________，函數(shù)SKIPIF1<0的單調(diào)遞減區(qū)間是_______．6．函數(shù)SKIPIF1<0的單調(diào)減區(qū)間是______．7．函數(shù)SKIPIF1<0的單調(diào)遞減區(qū)間為_(kāi)_________．8．已知函數(shù)f(x)=(5?a)x?a+1,x<1ax,x≥1，滿(mǎn)足對(duì)任意SKIPIF1<0都有SKIPIF1<0成立，那么實(shí)數(shù)SKIPIF1<0的取值范圍是________．專(zhuān)項(xiàng)突破四分段函數(shù)求參1．設(shè)SKIPIF1<0，若SKIPIF1<0，則x的值為（

）A．1 B．2 C．8 D．1或82．設(shè)SKIPIF1<0，若SKIPIF1<0，則x的值為（

）A．3 B．1 C．SKIPIF1<0 D．1或33．已知函數(shù)SKIPIF1<0是SKIPIF1<0上的減函數(shù)，則SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．已知函數(shù)SKIPIF1<0，若不等式SKIPIF1<0在SKIPIF1<0上有解，則實(shí)數(shù)a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．若函數(shù)SKIPIF1<0的值域?yàn)镽，則a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<06．已知函數(shù)SKIPIF1<0與函數(shù)SKIPIF1<0的值域相同，則實(shí)數(shù)a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<07．已知函數(shù)SKIPIF1<0若SKIPIF1<0存在最小值，則實(shí)數(shù)a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<08．已知函數(shù)SKIPIF1<0若SKIPIF1<0，則實(shí)數(shù)SKIPIF1<0______．9．已知SKIPIF1<0，函數(shù)SKIPIF1<0若SKIPIF1<0，則SKIPIF1<0_______.10．若函數(shù)SKIPIF1<0是R上的減函數(shù)，則實(shí)數(shù)a的取值范圍是___．11．已知函數(shù)SKIPIF1<0，若SKIPIF1<0是SKIPIF1<0上的單調(diào)遞增函數(shù)，則SKIPIF1<0的取值范圍是__________．12．已知函數(shù)SKIPIF1<0，且SKIPIF1<0是SKIPIF1<0的最小值，則實(shí)數(shù)a的取值范圍是__________．專(zhuān)項(xiàng)突破五解分段函數(shù)不等式1．已知函數(shù)SKIPIF1<0，則不等式SKIPIF1<0的解集是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．已知函數(shù)SKIPIF1<0則不等式SKIPIF1<0的解集為（

）A．（0，5） B．SKIPIF1<0 C．SKIPIF1<0 D．（-5，5）3．已知函數(shù)SKIPIF1<0若SKIPIF1<0，則SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．設(shè)函數(shù)SKIPIF1<0，則滿(mǎn)足SKIPIF1<0的SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．已知