軟件類筆試題目參考

1、軟件類筆試題目參考 軟件類筆試題目參考下面的代碼輸出是什么，為什么？ void foo(void) unsigned int a = 6; int b = -20; (a+b6)?puts(6):puts(6就是考察隱式轉(zhuǎn)換int型變量轉(zhuǎn)化成unsigned int,b成了正數(shù)2. b)運行下面的函數(shù)會有什么結果？為什么？ void foo(void) char string10,str110; int i; for(i=0;i10;i+) str1i = a; strcpy(string, str1); printf(%s,string); 首先搞清strcpy函數(shù)的實現(xiàn)方法，char *

2、strcpy(char * strdest,const char * strsrc)if (strdest=null)|(strsrc=null) throw invalid argument(s);char * strdestcopy=strdest;while (*strdest+=*strsrc+)!=0); return strdestcopy;由于str1末尾沒有0結束標志，所以strcpy不知道拷貝到何時結束printf函數(shù)，對于輸出char* 類型，順序打印字符串中的字符直到遇到空字符（）或已打印了由精度指定的字符數(shù)為止下面是微軟的兩道筆試題.3. implement a str

3、ing class in c+ with basic functionality like comparison, concatenation, input and output. please also provide some test cases and using scenarios (sample code of using this class).please do not use mfc, stl and other libraries in your implementation.我的實現(xiàn)方案如下,這道題真地對c+的主要特性都進行了較好地考察.string.h:#ifndef

4、string_h#define string_h#include using namespace std;class string public: string(); string(int n,char c); string(const char* source); string(const string& s); /string& operator=(char* s); string& operator=(const string& s); string(); char& operator(int i)return ai; const char& operator(int i) const

5、return ai;/對常量的索引. string& operator+=(const string& s); int length(); friend istream& operator(istream& is, string& s);/搞清為什么將設置為友元函數(shù)的原因. /friend bool operator (const string& left, const string& right);/下面三個運算符都沒必要設成友元函數(shù),這里是為了簡單. friend bool operator= (const string& left, const string& right); frien

6、d bool operator!= (const string& left, const string& right); private: char* a; int size;#endifstring.cpp:#include string.h#include #include string:string() a = new char1; a0 = 0; size = 0;string:string(int n,char c)a = new charn + 1;memset(a,c,n);an = 0;size = n;string:string(const char* source)if(s

7、ource = null) a = new char1; a0 = 0; size = 0;else size = strlen(source); a = new charsize + 1; strcpy(a,source);string:string(const string& s)size = strlen(s.a);/可以訪問私有變量.a = new charsize + 1;/if(a = null)strcpy(a,s.a);string& string:operator=(const string& s)if(this = &s) return *this;else delete

8、a; size = strlen(s.a); a = new charsize + 1; strcpy(a,s.a); return *this;string:string()delete a;/ string& string:operator+=(const string& s) int j = strlen(a); int size = j + strlen(s.a); char* tmp = new charsize+1; strcpy(tmp,a); strcpy(tmp+j,s.a);delete a;a = tmp;return *this;int string:length()r

9、eturn strlen(a);main.cpp:#include #include string.husing namespace std;bool operator=(const string& left, const string& right)int a = strcmp(left.a,right.a); if(a = 0) return true;else return false;bool operator!=(const string& left, const string& right)return !(left = right);ostream& operator(ostre

10、am& os,string& s)int length = s.length();for(int i = 0;i length;i+) /os s.ai;這么不行,私有變量. os si;return os;string operator+(const string& a,const string& b)string temp;temp = a;temp += b;return temp;bool operator(const string& left,const string& right)int j = 0;while(leftj != 0) & (rightj != 0) if(left

11、j (const string& left, const string& right) int a = strcmp(left.a,right.a); if(a 0) return true;else return false;istream& operator(istream& is, string& s)delete s.a;s.a = new char20;int m = 20; char c;int i = 0;while (is.get(c) & isspace(c); if (is) do s.ai = c; i+; /*if(i = 20) cout input too much characters! f;/需要輸入.string g;g = a + b;/abcdwwwif(a b) cout a b endl;else cout = b endl;if(e = a) cout e = a endl;else cout e != a endl;b += a;cout a endl;cout b endl; cout c endl;cout d endl;cout e endl;cout f endl;cout g endl;cout g0 endl;return 0;4. implement a single-direction linked