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1、河南省北大附中河南分校2014屆高三最后一次沖刺(猜題卷)文科數(shù)學(xué)試題一、選擇題:本大題共12小題,每小題5分 共60分1定義集合運(yùn)算:ab=zz=xy(x+y),xa,yb,設(shè)集合a=0,1,b=2,3,則集合ab的所有元素之和為()a0b6c12d182已知復(fù)數(shù)z(cosi)(2sini)是純虛數(shù),0,2),則( )a. b. c. d.3已知集合,,若“”是“”的充分非必要條件,則的取值范圍是( )(a) (b) (c) (d)4下圖為某算法的程序框圖,則程序運(yùn)行后輸出的結(jié)果是( )a 3 b 4 c 5 d 65一個(gè)幾何體的三視圖如圖所示,其中正視圖和側(cè)視圖是腰長為4的兩個(gè)全等的等腰直
2、角三角形若該幾何體的體積為v,并且可以用n這樣的幾何體拼成一個(gè)棱長為4的正方體,則v,n的值是( ) a bc d 6在abc中,內(nèi)角a,b,c所對(duì)的邊分別是a,b,c.已知8b5c,c2b,則cos c() a. b c± d.7下列命題正確的個(gè)數(shù)是 命題“”的否定是“”; “函數(shù)的最小正周期為”是“”的必要不充分條件; 在上恒成立在上恒成立; “平面向量與的夾角是鈍角”的充分必要條件是“”.a1 b2 c3 d48已知函數(shù)的圖象在點(diǎn)處的切線與直線平行,若數(shù)列的前n項(xiàng)和為,則的值為( )a、b、c、d、9、如圖,在棱長為1的正方體abcd-a1b1c1d1中,p是棱上的點(diǎn), 則滿足
3、的點(diǎn)p的個(gè)數(shù)有( )a4b6 c8 d1210在集合中任取一個(gè)偶數(shù)a和一個(gè)奇數(shù)b構(gòu)成以原點(diǎn)為起點(diǎn)的向量,從所有得到的以原點(diǎn)為起點(diǎn)的向量中任取兩個(gè)向量為鄰邊作平行四邊形,記所有作成的平行四邊形的個(gè)數(shù)為,在區(qū)間1,和2,4分別各取一個(gè)數(shù),記為m和n,則方程1表示焦點(diǎn)在x軸上的橢圓的概率是 ( )a b. c. d. 11已知是內(nèi)一點(diǎn),且若、的面積分別為、, 則的最小值是( ) a9 b. 16 c. 18 d. 2012已知函數(shù) 函數(shù),若存在,使得成立,則實(shí)數(shù)的取值范圍是a. b. c. d.二、填空題:本大題共4小題,每小題5分,共20分。 40 50 60 70 80 90 體重(kg)0.0
4、050.0100.0200.0300.0350.0150.02513從某地高中男生中隨機(jī)抽取100名同學(xué),將他們的體重(單位:kg)數(shù)據(jù)繪制成頻率分布直方圖(如圖)由圖中數(shù)據(jù)可知體重的平均值為kg;若要從身高在 60 , 70),70 ,80) , 80 , 90三組內(nèi)的男生中,用分層抽樣的方法選取12人參加一項(xiàng)活動(dòng),再從這12人選兩人當(dāng)正負(fù)隊(duì)長,則這兩人身高不在同一組內(nèi)的概率為 (2個(gè)數(shù)據(jù)錯(cuò)一個(gè)不得分)14非零向量滿足,則與的夾 角大小為 15已知函數(shù)為r上的奇函數(shù),的導(dǎo)數(shù)為,且當(dāng)時(shí),不等式 成立,若對(duì)一切恒成立,則實(shí)數(shù)的取值 范圍是 。16.已知下列命題:函數(shù)的單調(diào)增區(qū)間是.要得到函數(shù)的圖
5、象,需把函數(shù)的圖象上所有點(diǎn)向左平行移動(dòng)個(gè)單位長度.已知函數(shù),當(dāng)時(shí),函數(shù)的最小值為在0,1上至少出現(xiàn)了100次最小值,則.其中正確命題的序號(hào)是_ 三、解答題:解答應(yīng)寫出文字說明、證明過程或演算步驟。17.(本小題滿分12分)數(shù)列各項(xiàng)均為正數(shù),其前項(xiàng)和為,且滿足.(1)求數(shù)列的通項(xiàng)公式;(2)設(shè), 求數(shù)列的前n項(xiàng)和,并求使 對(duì)所有的 都成立的最大正整數(shù)m的值18(本小題滿分12分)某班50名學(xué)生在一次百米測試中,成績?nèi)拷橛?3秒與18秒之間,將測試結(jié)果按如下方式分成五組:第一組,第二組,第五組右圖是按上述分組方法得到的頻率分布直方圖. (1)若成績大于或等于14秒且小于16秒認(rèn)為良好, 求該班在
6、這次百米測試中成績良好的人數(shù); (2)設(shè)表示該班某兩位同學(xué)的百米測試成績,且已知cbagdef19(本小題滿分12分)如圖,四邊形為矩形,四邊形為梯形,且平面平面,點(diǎn)為的中點(diǎn) (1)求證:平面; (2)求三棱錐的體積; 20(本小題滿分12分)如圖9-13,p是拋物線c:y=x2上點(diǎn),直線l過點(diǎn)p且與拋物線c交于另一點(diǎn)q (1)若直線l與過點(diǎn)p的切線垂直,求線段pq中點(diǎn) m的軌跡方程; ()若直線l不過原點(diǎn)且與x軸交于點(diǎn)s,與y軸交于點(diǎn)t,試求的取值范圍21(本小題滿分12分)已知函數(shù)是定義在上的奇函數(shù),當(dāng)時(shí), (其中e是自然界對(duì)數(shù)的底, )() 求的解析式;()設(shè)求證:當(dāng),時(shí),;()是否存在
7、負(fù)數(shù),使得當(dāng)時(shí),的最小值是3 ?如果存在,求出實(shí)數(shù)的值;如果不存在,請(qǐng)說明理由。請(qǐng)考生在第(22)、(23)、(24)三題中任選一題做答,如果多做,則按所做的第一題記分。做答時(shí)用2b鉛筆在答題卡上把所選題目對(duì)應(yīng)題號(hào)下方的方框涂黑。22.如圖,o的半徑ob垂直于直徑ac,m為ao上一點(diǎn),bm的延長線交o于n,過n點(diǎn)的切線交ca的延長線于p(1) 求證:;(2)若o的半徑為,求mn的長23已知橢圓c的極坐標(biāo)方程為,點(diǎn)f1、f2為其左,右焦點(diǎn),直線的參數(shù)方程為(t為參數(shù),tr) ()求直線和曲線c的普通方程; ()求點(diǎn)f1、f2到直線的距離之和.24(本小題滿分10分)選修45:不等式選講 已知函數(shù)
8、 ()當(dāng)時(shí),求不等式的解集; ()若不等式對(duì)任意實(shí)數(shù)恒成立,求的取值范圍 北大附中河南分校高考預(yù)測 若時(shí),有6種情況7分若分別在和內(nèi)時(shí),共有12種情況. 9分 abcdxxaxbxcxdyyaybycydzzazbzc zd 在中,af=fe, afe=60º, 是正三角形 aef=60º,由ef/ad知ead=60º, en=aesin60º=12分20解法:(1)設(shè)p(x1,y1)、q(x2,y2)、m (x0,y0),依題意x10,yl>0,y2>0由y=x2,得y'=x. 過點(diǎn)p的切線的斜率k切=x1, x1=0不合題意, x
9、10 直線l的斜率k1=,直線l的方程為y-x21=(x-x1)方法一:聯(lián)立消去y,得x2+-x21-2=0 由消去x,得y2-2(k2+b)y+b2=0則方法一: y1、y2可取一切不相等的正數(shù), 的取值范圍是(2,+)方法二:當(dāng)b>0時(shí),=|b|+2>2;當(dāng)b<0時(shí), =-b又由方程有兩個(gè)相異實(shí)根,得=4(k2+b) 2-4b2= 4k2(k2+2b)>0于是k2+2b>0,即k2>-2b 所以當(dāng)b>0時(shí),可取一切正數(shù),的取值范圍是(2+)方法三:由p、q、t三點(diǎn)共線得ktq=ktp,即則x1y2-bx1=x2y1-bx2,即b(x2-x1)=(x
10、2y1-x1y2)于是b=可取一切不等于l的正數(shù),的取值范圍是(2,+)21()設(shè),則,所以又因?yàn)槭嵌x在上的奇函數(shù),所以 故函數(shù)的解析式為 ()證明:當(dāng)且時(shí),設(shè) 因?yàn)?,所以?dāng)時(shí),此時(shí)單調(diào)遞減;當(dāng)時(shí),此時(shí)單調(diào)遞增,所以 又因?yàn)?,所以?dāng)時(shí),此時(shí)單調(diào)遞減,所以所以當(dāng)時(shí),即 ()解:假設(shè)存在負(fù)數(shù),使得當(dāng)時(shí),有最小值是3,則當(dāng),由于,則,故函數(shù) 是上的增函數(shù)所以,解得(舍去)當(dāng)時(shí),則當(dāng)時(shí),此時(shí)函數(shù)是減函數(shù);當(dāng)時(shí),此時(shí)函數(shù)是增函數(shù)所以,解得滿足題意。綜上可知,存在負(fù)數(shù),使得當(dāng)時(shí),有最小值22(1)連接on,因?yàn)閜n切o于n,所以,所以,因?yàn)閛b=on,所以因?yàn)橛?,所?故,所以.(2)因?yàn)?,所?23(
11、) 直線普通方程為 ; 曲線的普通方程為 () ,,點(diǎn)到直線的距離 點(diǎn)到直線的距離 24解:()當(dāng)時(shí),即,當(dāng)時(shí),得,即,所以;當(dāng)時(shí),得成立,所以;當(dāng)時(shí),得,即,所以.故不等式的解集為.(),由題意得,則或,解得或,故的取值范9jwkffwvg#tym*jg&6a*cz7h$dq8kqqfhvzfedswsyxty#&qa9wkxfyeq!djs#xuyup2knxprwxma&ue9aqgn8xp$r#͑gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tng
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29、vr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&am
30、p;qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqvadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&am
31、p;qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#
32、kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ks
33、v*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz84!z89
34、amv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$
35、vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&
36、;gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%madnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvk
37、um>xrm6x4ngpp$vstt#&ksv*adnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy
38、7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&am
39、p;gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue
40、%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz84!z89amv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpaza
41、dnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk
42、!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6
43、ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnugk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&g
44、txrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amy
45、wpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gx
46、gjqv3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849g
47、xgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6
48、ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mzadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gx
49、gjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk
50、!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum&g
51、txrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amv$ue9wewz#qcue%&qypeh5pdx2zvk
52、um>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk
53、8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz84!z89amv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp
54、$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9&am
55、p;gtxrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd
56、6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnugk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wew
57、z#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&
58、amp;qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqvue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv
59、*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!
60、z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywv*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz849gxgjqv$u*3tngk8!z89amywpazadnu#kn&muwfa5uxy7jnd6ywrrwwcvr9cpbk!zn%mz84!z89amv$ue9wewz#qcue%&qypeh5pdx2zvkum>xrm6x4ngpp$vstt#&ksv*3tngk8!z89amywpazadnu#kn&muwfa5uxgjqv$ue9wewz#qcue%&am
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