NOJ答案c++版

1、計(jì)算A+B圓及圓球等的相關(guān)計(jì)算計(jì)算成績(jī)找最大數(shù)找幸運(yùn)數(shù)計(jì)算A+B#include <iostream>using namespace std;int main()int A,B,c;cin>>A>>B;c=A+B;cout<<c<<endl;return 0;圓及圓球等的相關(guān)計(jì)算#include <iostream>#include <iomanip>using namespace std;#define PI 3.1416int main()double r,h,l,s,sq,vq,vz;cin>>

2、;r>>h;l=2*PI*r;s=PI*r*r;sq=4*PI*r*r;vq=4*PI*r*r*r/3;vz=s*h;cout<<fixed<<setprecision(2)<<l<<endl;cout<<fixed<<setprecision(2)<<s<<endl;cout<<fixed<<setprecision(2)<<sq<<endl;cout<<fixed<<setprecision(2)<<

3、vq<<endl;cout<<fixed<<setprecision(2)<<vz<<endl;return 0;計(jì)算成績(jī)#include <iostream>#include <iomanip>using namespace std;int main()double a,b,c,A,B;/定義數(shù)學(xué)成績(jī)a,英語成績(jī)b,c語言成績(jī)ccin>>a>>b>>c;A=a+b+c;B=A/3.0;cout<<fixed<<setprecision(6)<&

4、lt;A<<endl;cout<<fixed<<setprecision(6)<<B<<endl;return 0; 找最大數(shù)#include <iostream>using namespace std;int main()int A,B,C;cin>>A>>B>>C;if(A>B && A>C) cout<<A<<endl;elseif(B>A && B>C) cout<<B<<en

5、dl;else cout<<C<<endl; return 0;找幸運(yùn)數(shù)#include <iostream>using namespace std;int main()int m,n,a,b,c,d,e,f;cin>>m;a=m%10;b=m/10%10;c=m/100%10;d=m/1000%10;e=m/10000%10;if(e=0) if(d=0) if(c=0)if(b=0) if(a=0) n=0;else n=a;else n=a*10+b;else n=a*100+b*10+c;else n=a*1000+b*100+c*10+

6、d;else n=a*10000+b*1000+c*100+d*10+e;if(m=n) cout<<"yes"<<endl;else cout<<"no"<<endl;return 0;獎(jiǎng)金發(fā)放#include <iostream>#include <iomanip>using namespace std;int main()double w,y;cin>>w;if(w<=10) y=0.1*w;else if(w<=20) y=(w-10)*0.075+1

7、;else if(w<=40) y=(w-20)*0.05+1.75;else if(w<=60) y=(w-40)*0.03+2.75;else if(w<=100) y=(w-60)*0.015+3.35;else y=(w-60)*0.01+3.95;cout<<fixed<<setprecision(6)<<y<<endl;return 0;出租車費(fèi)難點(diǎn)：不足一公里按一公里收費(fèi)?！綾eil函數(shù)】法一【“%”取余的充分運(yùn)用】 #include <iostream>#include <iomanip>

8、using namespace std;int main()double s,y;int a,b,c;cin>>s;c=s; a=s*10;b=a%10;if(s<=2) y=7;else if(s<=15) if(b=0) y=7+1.5*(s-2);else y=7+1.5*(c-1);else if(b=0) y=26.5+2.1*(s-15);else y=26.5+2.1*(c-14);cout<<fixed<<setprecision(6)<<y<<endl;return 0;法二【ceil函數(shù)】#include <iostream>#include <cmath>#include <iomanip>using namespace std;int main()double s,y;int a;cin>>s;a=ceil(s);if(s<=