課件b084stringio一串字符的輸入

1、（2）一串字符的輸出用 cout 輸出字符數(shù)組#include <iostream>using namespace std; int main()char a10 = "Computer" cout<<a;return 0;Computer00a0a1a2a3a4a5a6a7a8a9用 cout 輸出字符數(shù)組#include <iostream>using namespace std; int main()char a8 = 'C', 'o', 'm', 'p', '

2、u', 't', 'e', 'r' ;cout<<a; return 0;Computera0a1a2a3a4a5a6a7用 cout 輸出字符數(shù)組#include <iostream> using namespace std; int main()char weekday711 = "Sunday", "Monday","Tuesday", "Wednesday", "Thursday", "Friday

3、", "Saturday" ;for (int i = 0; i < 7; i+)cout << weekdayi << endl; return 0;Sunday00000Monday00000Tuesday0000Wednesday00Thursday000Friday00000Saturday000用 cout 輸出字符數(shù)組#include <iostream>using namespace std; int main()int a8 = 1,2,3,4,5,6 ;cout<<a; return 0;（2

4、）一串字符的輸入方法一：直接用cin輸入字符串#include <iostream>using namespace std; int main()char str10;cout << "enter a sentence:" << endl; while (cin >> str)cout << str<<endl; return 0;方法二：用cin.get( )函數(shù)輸入n 有3個(gè)參數(shù)的get函數(shù)cin.get(ch, 10,'n');10-1個(gè)字符（包含空格），賦給指定的字符數(shù)組;uu

5、如果在10-1個(gè)字符之前，遇到指定的終止字; （如果第3個(gè)參數(shù)沒有指符n，則提前結(jié)束定，則默認(rèn)為n返回非0值(真)，如失敗(遇文件結(jié)束符)則返回0值(假)。u方法二：用cin.get( )函數(shù)輸入#include <iostream> using namespace std; int main()char ch20;cout << "enter a sentence:" << endl; cin.get(ch, 10, o); /指定終止符為o cout << ch << endl;return 0;方法三：用ci

6、n.getline( )函數(shù)輸入#include <iostream> using namespace std; int main()char ch20;cout << "enter a sentence:" << endl; cin.getline(ch, 10, o); /指定終止符為o cout << ch << endl;return 0;方法三：用cin.getline( )函數(shù)輸入n getline與get的區(qū)別u getline遇到終止標(biāo)志字符時(shí)結(jié)束，緩沖區(qū)指針移到終止標(biāo)志字符之后；u get遇到終止

7、字符是停止，指針不移動(dòng)cin.get( )We are good friends.We are good friends.cin.getline( )方法三：用cin.getline( )函數(shù)輸入#include <iostream> using namespace std; int main()char weekday711; for (int i = 0; i < 7; i+)cin.getline(weekdayi, 11); for (int i = 0; i < 7; i+)cout << weekdayi << endl; retur

8、n 0;一個(gè)需要特別關(guān)注的程序#include<iostream> using namespace std; int main()char a1010; int n = 0;cin >> n;for (int i = 0; i < n; i+) cin.getline(ai, 10);for (int i = 0; i < n; i+) cout << ai << endl;return 0;Pass！#include<iostream> using namespace std; int main()char a1010; int n = 0;cin >> n;cin.get( );