曲線擬合最小二乘法C++程序

1、課題八曲線擬合的最小二乘法實(shí)驗(yàn)?zāi)繕?biāo)：在某冶煉過程中，通過實(shí)驗(yàn)檢測得到含碳量與時(shí)間關(guān)系的數(shù)據(jù)如下，試求含碳量y與時(shí)間t內(nèi)在關(guān)系的擬合曲線。t05101520253035404550Y01.272.162.863.443.874.154.374.514.584.02最小二乘法：#include#includeusingnamespacestd;intArray(double*Arr,intn)double*p;inti;p=(double*)malloc(n*sizeof(double*);if(!p)return0;for(i=0;in;cout請？輸?入？節(jié)2點(diǎn)I?值|I(eixi)e?：eo

2、xi;cout請?輸?入?節(jié)2點(diǎn)I?函匚數(shù)y值II(ejYi)e?：eoYi;if(!Array(&A,3)cout內(nèi)s存?分O?配？失“敗a!?;elsefor(i=0;i3;i+)for(j=0;j3;j+)Aij=0;for(i=0;in;i+)A00+=1;/coutA00;A01+=xi;A02+=xi*xi;A10=A01;A11=A02;A12+=xi*xi*xi;A20=A02;A21=A12;A22+=xi*xi*xi*xi;for(i=0;i3;i+)Bi=0;for(i=0;in;i+)B0+=Yi;B1+=xi*Yi;一for(k=pk2-k+)for(ik+ri3八i

3、+)doubleT二k八HT*-for(j=k+1-j3-j+)Ai二jHAi二jT*Ak二S2for(i=riVHO-i)doubleTemp=pfor(inr+j=i+rj2二+)Temp=Temp+Aij*sg-si=mTemp)、Ai二一cou7:2B7aCDo、endrcour+、yL、so、+、s二、x+s2、x2、endlendl、s:B7CDo、endrfor(i=0-in-i+)亠cour+、Y、i、Ya、i、Y、so+s二*xiC:U5er5AppleDe5ktop-C:U5er5AppleDe5ktop-譚冒分聽O12.5-.28ztiixkaoDebugzciixia.exed士有N個(gè)節(jié)占v11歸A%（叱：S510IS2253S3546455&請輸天節(jié)點(diǎn)函數(shù)值Jwi）E1.272-1&2.863.443.874-154-374514.584.02擬合曲線為*9=113727+町.08S2182x*-S-002B745?xA2誤差為總yS-=l-19727Vl-0-256459y2-=-l-2?B3kJ3-2-30951kJ4-=-5.313y7e+304W5-=-4