第四次課件第二章數(shù)學(xué)模型

mmsCsKKX(s)CsKX(s)KX21 1msCsKX(s)CsKX22 2X(s)Cs m2s2CsCsXo(s) K1CsK2 X(s)mms(mm)Cs43 1 Km(mm1 2 1sKCsK2 m1s2CsK1LRTuieutRit dtutRitTtKTitUsRIsLsIsEsTsKTITtTdtJssTsTdU(s)E(s)1LsIEsKesT1U(s)—1LsIKTT1UssJsLs 1 KT T TLJs2RJsKTKU(sU(s)1LsI TKT—11s Ls 1 KT LsLJs2RJsKT—U(s)—LJs2RJsKTKT1T2z2z、z 121 iz2T1TT2T齒輪1齒輪1Jd21(t)T(tCd1(tT1dt1 Td22T(t)d齒輪2：222T T(t)1T(t),(t) zzCT1z 12z2 z d2T1T 1 22dtCd(t)22z2 z2J dtd(t)2 Jd2d(t)z2d21T(t)1 122 d(t)12J J21d z21 1T(t)C C1d122 z21 2JJ 2 1 JJ CC CC2 12 Jd2I1dtdI1Jd22dJCJ JJi22 1 C CCi22 1 zz4J3,K3,C3 J2K2C2TIJ1,K1,iz2,iz4,i2，L1z231z3L bsmbsm1bs asasan1s1 p1- 025p=[1-120252.sys=tf(num,例：描述傳遞函數(shù)F(s)4s212ss36s211s4s^2-12s+8s^3+6s^2+11s+num=[4-12den=[1611sys=tf(num,sys=zpk(z,p,k)F(s4(s1)(s(s1)(s2)(s4(s-1)(s-2)z=[1zpk241可實(shí)現(xiàn)兩個(gè)多項(xiàng)式相乘。(s22)(2s33s23s2)(sden1=[1,2,den2=[2,3,3,2];den=conv(conv(den1,den2),結(jié)果為：F(s2s69s520s427s324s214sden 9202724 串連：sys=series(sys1,sys2)并聯(lián)：sysprrallel(sys1,反饋：sysfeedback(sys1,sys2,sys=cloop(sys1,-1)Gs1,Gs1s21snumc001denc120numb022denb120numf012denf121zpk1函數(shù)residue()用于實(shí)現(xiàn)部分分式展開：[r,p,k]=residue(num,其中，rp分別為展開后的留數(shù)及極點(diǎn)構(gòu)成的F(s)r(1)r(1)r(n)Ks ssr(jsp(jsp(jr(j1)r(jqsp(jFF(s) s410s335s250s展開式為：F(s12.530.5s4s3s2sk=pr=num=[1113952den=[1103550[r,p,k]=residue(num,F(ss510s25ss45s39s27s展開式為：F(s)4 s2s1(s1)2(ssk1-prnum=[100105den=[1597[r,p,k]=residue(num,[num,den]=residue(r,p,例：求F(s) s1s2s3s合并式為：Fs)32s410s335s250snum=1070150den=1103550r=[1234]';p=[-1-2-3-4]';k=[num,den]=residue(r,p, F(s)Lf f(t)e0 f(t)dt F1slimf(t)f()limsFt s典型信號(hào)的拉氏變換：fteatF11ss s22s2XoX(s) bsmbsm1bsG(s) Xi a0sa1 an