新高考數(shù)學(xué)二輪復(fù)習(xí)考點(diǎn)講義第七講函數(shù)圖像及函數(shù)與方程(原卷版)_第1頁(yè)
新高考數(shù)學(xué)二輪復(fù)習(xí)考點(diǎn)講義第七講函數(shù)圖像及函數(shù)與方程(原卷版)_第2頁(yè)
新高考數(shù)學(xué)二輪復(fù)習(xí)考點(diǎn)講義第七講函數(shù)圖像及函數(shù)與方程(原卷版)_第3頁(yè)
新高考數(shù)學(xué)二輪復(fù)習(xí)考點(diǎn)講義第七講函數(shù)圖像及函數(shù)與方程(原卷版)_第4頁(yè)
新高考數(shù)學(xué)二輪復(fù)習(xí)考點(diǎn)講義第七講函數(shù)圖像及函數(shù)與方程(原卷版)_第5頁(yè)
已閱讀5頁(yè),還剩3頁(yè)未讀, 繼續(xù)免費(fèi)閱讀

下載本文檔

版權(quán)說(shuō)明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請(qǐng)進(jìn)行舉報(bào)或認(rèn)領(lǐng)

文檔簡(jiǎn)介

第七講:函數(shù)圖像、函數(shù)與方程【考點(diǎn)梳理】1、函數(shù)的圖象(1)平移變換:SKIPIF1<0SKIPIF1<0(2)伸縮變換:SKIPIF1<0SKIPIF1<0(3)對(duì)稱變換:SKIPIF1<0SKIPIF1<0SKIPIF1<0(4)翻折變換:SKIPIF1<0SKIPIF1<02、函數(shù)與方程(1)判斷二次函數(shù)SKIPIF1<0在SKIPIF1<0上的零點(diǎn)個(gè)數(shù),一般由對(duì)應(yīng)的二次方程SKIPIF1<0的判別式SKIPIF1<0來(lái)完成;對(duì)于一些不便用判別式判斷零點(diǎn)個(gè)數(shù)的二次函數(shù),則要結(jié)合二次函數(shù)的圖象進(jìn)行判斷.(2)對(duì)于一般函數(shù)零點(diǎn)個(gè)數(shù)的判斷,不僅要用到零點(diǎn)存在性定理,還必須結(jié)合函數(shù)的圖象和性質(zhì)才能確定,如三次函數(shù)的零點(diǎn)個(gè)數(shù)問題.(3)若函數(shù)SKIPIF1<0在SKIPIF1<0上的圖象是連續(xù)不斷的一條曲線,且是單調(diào)函數(shù),又SKIPIF1<0,則SKIPIF1<0在區(qū)間SKIPIF1<0內(nèi)有唯一零點(diǎn).【典型題型講解】考點(diǎn)一:函數(shù)的圖像【典例例題】例1.(多選題)在同一直角坐標(biāo)系中,函數(shù)SKIPIF1<0的圖象可能是(

)A. B.C. D.【方法技巧與總結(jié)】1.熟練掌握高中八個(gè)基本初等函數(shù)的圖像的畫法2.函數(shù)的圖像變換:平移,對(duì)稱、翻折變換【變式訓(xùn)練】1.已知圖①中的圖象是函數(shù)SKIPIF1<0的圖象,則圖②中的圖象對(duì)應(yīng)的函數(shù)可能是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<02.已知函數(shù)SKIPIF1<0無(wú)最小值,則SKIPIF1<0的取值范圍是(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<03.若函數(shù)SKIPIF1<0(SKIPIF1<0且SKIPIF1<0)在R上為減函數(shù),則函數(shù)SKIPIF1<0的圖象可以是()A. B.C. D.4.函數(shù)SKIPIF1<0的圖象如圖所示,則函數(shù)SKIPIF1<0的圖象為()A. B.C. D.考點(diǎn)二:求函數(shù)的零點(diǎn)或零點(diǎn)所在區(qū)間判斷【典例例題】例1.已知函數(shù)SKIPIF1<0滿足SKIPIF1<0,且SKIPIF1<0是SKIPIF1<0的一個(gè)零點(diǎn),則SKIPIF1<0一定是下列函數(shù)的零點(diǎn)的是(

)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0例2.函數(shù)SKIPIF1<0的零點(diǎn)所在的區(qū)間是(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【方法技巧與總結(jié)】求函數(shù)SKIPIF1<0零點(diǎn)的方法:(1)代數(shù)法,即求方程SKIPIF1<0的實(shí)根,適合于宜因式分解的多項(xiàng)式;(2)幾何法,即利用函數(shù)SKIPIF1<0的圖像和性質(zhì)找出零點(diǎn),適合于宜作圖的基本初等函數(shù).【變式訓(xùn)練】1.已知函數(shù)SKIPIF1<0,則SKIPIF1<0的所有零點(diǎn)之和為(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.已知函數(shù)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的零點(diǎn)分別是a,b,c,則a,b,c的大小順序是(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<03.函數(shù)SKIPIF1<0的所有零點(diǎn)之和為__________.4.若SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則x、y、z由小到大的順序是___________.5.函數(shù)SKIPIF1<0的零點(diǎn)所在的區(qū)間為(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0考點(diǎn)三:函數(shù)零點(diǎn)個(gè)數(shù)的判斷【典例例題】例1.函數(shù)SKIPIF1<0的零點(diǎn)個(gè)數(shù)為___________.例2.定義在R上的偶函數(shù)SKIPIF1<0滿足SKIPIF1<0,且當(dāng)SKIPIF1<0時(shí),SKIPIF1<0,若關(guān)于x的方程SKIPIF1<0恰有5個(gè)解,則m的取值范圍為(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【方法技巧與總結(jié)】1.利用函數(shù)圖像判斷方程解的個(gè)數(shù).由題設(shè)條件作出所研究對(duì)象的圖像,利用圖像的直觀性得到方程解的個(gè)數(shù).2.利用函數(shù)圖像求解不等式的解集及參數(shù)的取值范圍.先作出所研究對(duì)象的圖像,求出它們的交點(diǎn),根據(jù)題意結(jié)合圖像寫出答案3.利用函數(shù)圖像求函數(shù)的最值,先做出所涉及到的函數(shù)圖像,根據(jù)題目對(duì)函數(shù)的要求,從圖像上尋找取得最值的位置,計(jì)算出結(jié)果,這體現(xiàn)出了數(shù)形結(jié)合的思想?!咀兪接?xùn)練】1.已知函數(shù)SKIPIF1<0是偶函數(shù),且SKIPIF1<0,當(dāng)SKIPIF1<0時(shí),SKIPIF1<0,則方程SKIPIF1<0在區(qū)間SKIPIF1<0上的解的個(gè)數(shù)是________2.已知函數(shù)f(x)=SKIPIF1<0和函數(shù)g(x)=SKIPIF1<0,則函數(shù)h(x)=f(x)-g(x)的零點(diǎn)個(gè)數(shù)是________.3.已知函數(shù)SKIPIF1<0若函數(shù)SKIPIF1<0有6個(gè)零點(diǎn),則m的取值范圍是(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<04.已知函數(shù)SKIPIF1<0,若函數(shù)SKIPIF1<0有4個(gè)零點(diǎn),則實(shí)數(shù)k的取值范圍為_______________.5.已知函數(shù)SKIPIF1<0,SKIPIF1<0若關(guān)于x的方程SKIPIF1<0有四個(gè)不同的解,則實(shí)數(shù)m的取值集合為()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<06.已知函數(shù)SKIPIF1<0,若關(guān)于SKIPIF1<0的方程SKIPIF1<0有且僅有三個(gè)不同的實(shí)數(shù)解,則實(shí)數(shù)SKIPIF1<0的取值范圍是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【鞏固練習(xí)】一、單選題1.函數(shù)SKIPIF1<0的圖象大致為(

)A. B.C. D.2.聲音是由物體振動(dòng)產(chǎn)生的.我們平時(shí)聽到的聲音幾乎都是復(fù)合音.復(fù)合音的產(chǎn)生是由于發(fā)音體不僅全段在振動(dòng),它的各部分如二分之一、三分之一、四分之一等也同時(shí)在振動(dòng).不同的振動(dòng)的混合作用決定了聲音的音色,人們以此分辨不同的聲音.己知刻畫某聲音的函數(shù)為SKIPIF1<0,則其部分圖象大致為(

)A. B.C. D.3.若函數(shù)SKIPIF1<0(SKIPIF1<0且SKIPIF1<0)在R上既是奇函數(shù),又是減函數(shù),則SKIPIF1<0的大致圖象是(

)A. B.C. D.4.已知函數(shù)SKIPIF1<0,若函數(shù)SKIPIF1<0與SKIPIF1<0的圖象恰有5個(gè)不同公共點(diǎn),則實(shí)數(shù)a的取值范圍是(

)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0二、多選題5.設(shè)函數(shù)SKIPIF1<0,則下列命題中正確的是(

)A.若方程SKIPIF1<0有四個(gè)不同的實(shí)根SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0的取值范圍是SKIPIF1<0B.若方程SKIPIF1<0有四個(gè)不同的實(shí)根SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0的取值范圍是SKIPIF1<0C.若方程SKIPIF1<0有四個(gè)不同的實(shí)根,則SKIPIF1<0的取值范圍是SKIPIF1<0D.方程SKIPIF1<0的不同實(shí)根的個(gè)數(shù)只能是1,2,3,66.已知SKIPIF1<0為常數(shù),函數(shù)SKIPIF1<0,若函數(shù)SKIPIF1<0恰有四個(gè)零點(diǎn),則實(shí)數(shù)SKIPIF1<0的值可以是(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<07.已知函數(shù)SKIPIF1<0若關(guān)于x的方程SKIPIF1<0有5個(gè)不同的實(shí)根,則實(shí)數(shù)a的取值可以為(

)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<08.已知SKIPIF1<0

溫馨提示

  • 1. 本站所有資源如無(wú)特殊說(shuō)明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請(qǐng)下載最新的WinRAR軟件解壓。
  • 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請(qǐng)聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
  • 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁(yè)內(nèi)容里面會(huì)有圖紙預(yù)覽,若沒有圖紙預(yù)覽就沒有圖紙。
  • 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
  • 5. 人人文庫(kù)網(wǎng)僅提供信息存儲(chǔ)空間,僅對(duì)用戶上傳內(nèi)容的表現(xiàn)方式做保護(hù)處理,對(duì)用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對(duì)任何下載內(nèi)容負(fù)責(zé)。
  • 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請(qǐng)與我們聯(lián)系,我們立即糾正。
  • 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時(shí)也不承擔(dān)用戶因使用這些下載資源對(duì)自己和他人造成任何形式的傷害或損失。

評(píng)論

0/150

提交評(píng)論