《C語言典型例題集》程序(共31頁)

1、第一章 基礎(chǔ)知識例1.1 分析下面程序的輸出結(jié)果。void main() int a,b,c; a=2;b=3; c=a+b; printf(nThe sum of a and b is:); printf(%d,c); 例1.2 C程序的構(gòu)成，簡單的函數(shù)調(diào)用。main( ) /* 主函數(shù) */ int a1,a2,b; /* 定義變量通常放在函數(shù)最開始 */scanf( %d%d,&a1,&a2); /* 輸入 a1，a2的值 */b=max(a1,a2); /* 調(diào)用函數(shù)max（）*/printf(n max=%d,b); /* 輸出b 的值 */int max (int x1,int x

2、2) /* 定義max 函數(shù)及形參x1，x2 */ int y; /* 定義中間變量y */ if (x1x2) y=x1;else y=x2;return(y); /*返回y 的值至調(diào)用處*/例1.3 簡單的輸出程序，寫出輸出結(jié)果。main()int a=2,b=3; int c; int k;c=a+b; k=c+a;printf(%d,%d,c,k);例1.4 寫出輸出結(jié)果main()printf(*n);printf(?n);printf(*n);第二章 數(shù)據(jù)與運(yùn)算例2.1寫結(jié)果main()int a,b,c;clrscr();a=8; b=015; c=0x1a;printf(%d,

3、%d,%d,a,b,c);例2.2寫結(jié)果void main()printf(1234567890);printf(nhellobyoun);例2.3寫結(jié)果main( ) clrscr(); printf(t166t288r59t43n); printf(x3ft327bb8tn); 例2.4寫結(jié)果main()char x=a,y=b;printf(t%d,%dn,x,y);例2.5寫結(jié)果main()int i,j;clrscr();i=2; j=i+3; i=j+4;j=i+5;printf(%d,%d,i,j);例2.6寫結(jié)果main()float x=55555.12345;printf(

4、%10.5f,x);例2.7寫結(jié)果main( ) float a； double b； a=555555.555； b=555555.555； printf(“a=%12.3fn b=%12.3f”，a，b，)；例2.8寫結(jié)果main()char x,y;clrscr(); x=a; y=b;printf(%c,%c,%c,%c,x,x-32,y,y-32);例2.9 寫結(jié)果。main()int a,b,c;a=b=c=5; printf(n%d,%d,%dn,a,b,c);a=5+(c=6); printf(n%d,%d,%dn,a,b,c);a=(b=4)+(c=6); printf(n%

5、d,%d,%dn,a,b,c);a=(b=10)/(c=2); printf(n%d,%d,%dn,a,b,c); 例2.10 寫結(jié)果main()int t=5; t+=t-=t*t; printf(%d,t); 例2.11寫結(jié)果 main()int a=5; int b=9; float c=2.2; int x,y,m,n; clrscr(); x=a/b; y=b/a; m=a%b; n=b%a;printf(n%d,%d,%d,%d,x,y,m,n);例2.12寫結(jié)果main()int x=1,y=3; clrscr(); x=9-(-y)-(-y);printf(%d,%d,x,y)

6、; 例2.13寫結(jié)果main()int x=3,y=5,z=3,m,n; clrscr();m=(+x)*(y-); n=(z+)*(-y);printf(%d,%d,%d,%d,m,n,x,z); 例2.14寫結(jié)果main() int x=3,y=5,z=3,m,n;clrscr();m=(x(yy=yz);printf(%d,%d,m,n); 例2.15寫結(jié)果main()int x;scanf(%d,&x);if(x%3=0&x%5!=0)printf(yes);else printf(no); 例2.16寫結(jié)果main()int s=4;printf(ts=%d,(s+)=%d,(s-)

7、=%d,s,s+,s-); 例2.17寫結(jié)果main()int x=2,y=4;y=(x+)+(x+)+(+x);printf(%d,%d,x,y); 例2.18寫結(jié)果main()int a=3,b=8,c;c=(ab)?a:b; printf(c=%d,c); 例2.19寫結(jié)果：各種輸出格式的應(yīng)用。main() float y1=1.42;double y2=2.56789;printf(float:%f,%fn,y1,y2);printf(float:%e,%en,y1,y2);printf(float:%g,%gn,y1,y2);printf(float:%5.2f,%-5.2f,%3.

8、2fn ,y1,y2,y1);printf(%s%d%n ,2占5的百分比是,2*100/5);例2.20寫結(jié)果：字符輸入及輸出函數(shù)的使用。getchar（）和putchar（）函數(shù)。單個(gè)字符的輸入和輸出。#include void main()char ch; int ch1;ch1=99; ch =getchar();printf(t%c,%dn,ch,ch);putchar(t); putchar(100);putchar(t); putchar(ch1+5); 例2.21寫結(jié)果：從鍵盤接收一個(gè)字符，再將這個(gè)字符輸出。#include void main() int c; printf(

9、input a character:); c=getchar(); printf(character is %cn,c) 例2.22比較輸出結(jié)果，a和b有什么不同？#includevoid main()char a; int b; clrscr(); a=getchar()； b=getch();printf(t%c,%c,a,b);例2.23從鍵盤接收3個(gè)字符，再分別輸出。注意b的數(shù)據(jù)類型？#includevoid main()char a; int b; char c;putchar(t); a=getchar(); b=getche(); c=getch();printf(a=%c,b=

10、%c,c=%c,a,b,c); 例2.24整數(shù)與字符型數(shù)據(jù)是通用的。整數(shù)與ascii碼的關(guān)系。#include void main() int a; a=100; putchar(a); 例2.25求三個(gè)數(shù)的平均值。#include void main() int a,b,c;float average; printf(n please input a、b and c：); scanf(%d%d%d,&a,&b,&c);printf(na=%d b=%d c=%d,a,b,c);average=(a+b+c)/3;printf(n average=%f,average); 例2.26寫出程序的

11、輸出結(jié)果。主要考查輸入輸出格式知識點(diǎn)。#include main ( ) char a,b,c,d; int m,n; a=B; b=o; c=y; putchar(a); putchar(b); putchar(c); putchar(n);putchar(a);putchar(n);putchar(b);putchar(n);putchar(c);putchar(n);printf(input a character);d=getchar();printf(The character is );putchar(d); putchar(n);printf(input two integer)

12、;printf(two integer compart by blankn);scanf(%d%d,&m,&n);printf(two integer is :%d and %dn,m,n);printf(input two integer and compart by ,);scanf(%d,%d,&m,&n);printf(two integer is :%d and %dn,m,n);printf(input two integer and compart by blankn);scanf(%d %d,&m,&n);printf(two integer is :%d and %dn,m,

13、n);printf(input two integer and compart by “:”);scanf(%d:%d,&m,&n);printf(two integer is :%d and %dn,m,n);第三章 循環(huán)語句例3.1 if語句的第一種形式。結(jié)果？main()int a=8,b=7;if(ab)printf(%d,a);printf(%d,b);例3.2 if語句的嵌套使用。計(jì)算出租車費(fèi)。void main()int m;float g,price;printf(pleaseinputcarmodel:1-xiali;2-santana;3-aodi);scanf(%d,&m

14、);printf(please input kilometers :);scanf(%f,&g);if(m=1)if(g=3)price=5;else price=5+(g-3)*1.0;else if(m=2)if(g=3)price=5;else price=5+(g-3)*1.0;else if(m=3)if(g=3)price=5;else price=5+(g-3)*1.0;printf(the money you should pay is %5.2f RMB,price); /*getch(); */例3.3 從鍵盤輸入分?jǐn)?shù)等級（ABCDE中的一個(gè)），輸出該等級的分?jǐn)?shù)范圍。如，輸

15、入A，則輸出“90-100”。#include void main()char grade; printf(input the grade(A,B,C,D,E):); scanf(%c,&grade); switch (grade) case A: printf(90-100n);break; case B: printf(80-89n); break; case C: printf(70-79n); break; case D: printf(60-69n); break; case E: printf(0-59n); break; default : printf(errorn); 例3.

16、4 上題，去掉所有的break后，執(zhí)行結(jié)果會有什么變化？#include void main()char grade; printf(input the grade(A,B,C,D,E):); scanf(%c,&grade); switch (grade) case A: printf(90-100n); case B: printf(80-89n); case C: printf(70-79n); case D: printf(60-69n); case E: printf(0-59n); default : printf(errorn); 例3.5 某些case語句為空，執(zhí)行結(jié)果會有什么

17、變化？#include void main()char grade; printf(input the grade(A,B,C,D,E):); scanf(%c,&grade); switch (grade)case A: case B : case C : printf(pass!n); break; case D : printf(failure!n); break; default : printf(errorn); break; 例3.6 嵌套switch語句的使用？#include void main()int x,y; scanf(%d%d,&x,&y); switch(x) ca

18、se 1: switch(y) case 11: printf(Morningn);break; case 12:printf(afternoonn); break; default:printf(eveningn); break; case 2:printf(interestingn); break; default:printf(Errorn);例3.7 求12+22+32+42+52+1002#include stdio.hvoid main( )int k;long int result=0;for(k=1;k=100;k+) result+=k*k;printf(result=%ld

19、n,result);例3.8 求輸出結(jié)果？#include stdio.hmain()int i;for (i=0;i8;i+) printf ( %d,+i); printf ( %d,i+);例3.9 從鍵盤輸入一個(gè)數(shù)n，判斷n是否為素?cái)?shù)？void main()int n,k;scanf(%d,&n);for(k=2;kn;k+)if(n%k=0)break;if(k=n)printf(n%d is sushu!,n);else printf(n%d is not sushu,n);例3.10 輸出1100之間是5的倍數(shù)的數(shù)。void main()int m;for(m=1;m=100;m

20、+)if(m%5!=0)continue;else printf(%5d,m);例3.11打印輸出九九乘法表。void main() int i,j; clrscr(); for(i=1;i=9;i+)for(j=1;j=i;j+)printf(%d*%d=%-5d,i,j,i*j);printf(n); 例3.12打印輸出水仙花數(shù)。（水仙花數(shù)：三位的、各位數(shù)碼立方和等于數(shù)本身大小。）main() int m,a,b,c;for(m=100;m1000;m+)a=m/100;b=m%100/10;c=m%10;if(m=a*a*a+b*b*b+c*c*c) printf(%6d,m);例3.1

21、3從鍵盤接收一個(gè)字符串，統(tǒng)計(jì)期中字母、數(shù)字、空格和其他字符的個(gè)數(shù)。#includemain()char x;int zm=0,kg=0,sz=0,qt=0;while(x=getchar()!=n)if(x=a&x=A&x=0&x=9)sz+;else qt+;printf(zm=%d,kg=%d,sz=%d,qt=%d,zm,kg,sz,qt);例3.14求數(shù)列的前20項(xiàng)的和。main()float f1=1,f2=2,f,sum=0;int n=1;while(n=20)sum+=f2/f1;f=f2;f2=f1+f2;f1=f;n+;printf(sum=%f,sum);例3.15打印輸

22、出菲波那契數(shù)列的前40項(xiàng)。main()long int f1=1,f2=1;int n; clrscr();for(n=1;n=20;n+)printf(%10ld%10ld,f1,f2);f1=f1+f2;f2=f1+f2;if(n%3=0)printf(n);第四章 數(shù)組例4.1利用數(shù)組求10個(gè)數(shù)的和。main() int i,a10,sum=0; for(i=0;i=9;i+) scanf(%d,&ai); sum+=ai; printf(nsum=%d,sum); getch();例4.2統(tǒng)計(jì)12個(gè)數(shù)中正數(shù)和負(fù)數(shù)的個(gè)數(shù)。#includestdio.hmain() float data1

23、2,result1=0.0,result2=0.0; int i; for(i=0;i=11;i+) scanf(%f,&datai); for(i=0;i0.0) result1+=datai; else result2+=datai; printf(positive %fn,result1); printf(negative %fn,result2); getch();例4.3定義一個(gè)23的數(shù)組，從鍵盤接收元素的值，并以矩陣的形式輸出數(shù)組元素的值。main()int a23,i,j;for(i=0;i2;i+)for(j=0;j3;j+)scanf(%d,&aij);for(i=0;i2;

24、i+)for(j=0;j3;j+)printf(%5d,aij);printf(n);例4.4浮點(diǎn)型二維數(shù)組元素的輸入，要用中間變量。下面代碼中加粗的部分。main()float a23,i,j,t;for(i=0;i2;i+)for(j=0;j3;j+)scanf(%f,&t); aij=t;for(i=0;i2;i+)for(j=0;j3;j+)printf(%5.2f,aij);printf(n);例4.5將一個(gè)數(shù)組a的元素轉(zhuǎn)置存放于數(shù)組b中，并輸出顯示數(shù)組a和b。main () int a23 = 1,2,3,4,5,6; int b32, i,j; printf(array a:n)

25、; for(i=0;i2;i+) for(j=0;j3;j+) printf(%5d,aij); printf(n); /*輸出一行后換行 */ for(i=0;i=1;i+) for(j=0;j=2;j+) bji = aij; printf(array b:n); for(i=0;i=2;i+) for(j=0;j=1;j+) printf(%5d,bij); printf(n); /*輸出一行后換行 */ 例4.6利用數(shù)組計(jì)算fibonaqi數(shù)列的前40項(xiàng)，每行5個(gè)輸出。main()long int a40=1,1;int k;for(k=2;k40;k+)ak=ak-1+ak-2;fo

26、r(k=0;k40;k+)printf(%10ld,ak);if(k+1)%5=0)printf(n);例4.7在一個(gè)二維數(shù)組中找鞍點(diǎn)。一個(gè)數(shù)在它所在的行最大，在它所在的列最小。main()int a34,max,k,l,min,i,j; clrscr(); printf(please input number:n); for(i=0;i3;i+) for(j=0;j4;j+) scanf(%d,&aij); printf(nshu ru de shu zu yuan shu shi:n); for(i=0;i3;i+) printf(n); for(j=0;j4;j+) printf(%8d

27、,aij); for(i=0;i3;i+) max=ai0; l=i; for(j=1;jmax) max=alj; k=j; min=max; for(l=0;lalk) max=alk; if(max= =min) printf(nandianshu shi:a%d%d=%d.n,l,k,min);例4.8“冒泡”排序法。main() int a11,i,j,t; clrscr(); printf(input 10 numbers:n); for(i=1;i=10;i+) scanf(%d,&ai); printf(n); for(j=1;j=9;j+) for(i=1;iai+1) t=

28、ai;ai=ai+1;ai+1=t; printf(the sorted numbers:n); for(i=1;i11;i+) printf(%5d,ai); getch();例4.9將數(shù)組元素逆序輸出。main() int a10,i; clrscr(); printf(Please input 10 numbers:n); for(i=0;i=0;i-) printf(%d ,ai); getch();例4.10求10個(gè)數(shù)的平均值。main()int a10, i ,sum=0,ave;printf(please input score:n);for(i=0; i10; i+)scanf

29、(%d,&ai);for(i=0; i10; i+)sum+=ai;ave=sum/10;printf(%d,ave);例4.11在10個(gè)數(shù)中找最大、最小。main()float a10，m，max，min；for(m=0;m10;m+)scanf(%f,&am);max=min=a0;for(m=1;m10;m+)if(maxam)min=am;printf(max=%f,min=%f,max,min);例4.12連接2個(gè)字符串，輸出結(jié)果？main( ) char s110=hellohell,s27=xyz;strcat(s1,s2);printf(%s,s1);例4.13字符串比較。結(jié)果

30、？main( )char a=china;char b5;int y;gets(b);y=strcmp(a,b);printf(t%d,y);例4.14大小寫轉(zhuǎn)換。main()char a10=hello;strupr(a);puts(a);strlwr(a);puts(a);例4.15打印輸出鉆石圖形。main()char a56= *, * *,* *, * *, *;int i;clrscr();for(i=0;i5;i+)puts(ai);例4.16字符串復(fù)制。結(jié)果？#include string.hmain() char str110,str250; clrscr(); gets(s

31、tr1); gets(str2); strcpy(str1+5,str2); puts(str1); 第五章 函數(shù)及其應(yīng)用例5.1簡單的函數(shù)調(diào)用main（）pri（）； void pri（）printf(“*n”);printf(“*hello*n”);printf(“*n”);例5.2函數(shù)調(diào)用。被調(diào)函數(shù)在主調(diào)函數(shù)之前。#include void F(int a)a+;printf(“%d”,a);void main()int a=10;F(a); Printf(“%d”,a);例5.3利用函數(shù)實(shí)現(xiàn)求一個(gè)變量的絕對值。double abs（double x）if（x0)return x;els

32、e return x； Main（）double x，y；yabs（x）；printf(“f”，y)；例5.4設(shè)計(jì)一個(gè)函數(shù)用來求兩個(gè)數(shù)的最大值。int max(float x,float y);main() float a=1.5,b=2.5; int c; c=max(a,b); printf(“Max is %dn”,c);max(float x,float y) float z; z=xy?x:y; return z;例5.5求1！+2！+3！+5！+5！+20！ main（）float sum(int);float add;add=sum(20);printf(“add=%f”,add

33、);float sum(int n)float fac(int);int i;flaot s=0;for(i=1;i=n;i+)s+=fac(i);return (s);float fac(int i)float t=1;int n=1;dot=t*n;n+;while(n=i);return t;例5.6無返回值的函數(shù)調(diào)用。void printstar( )printf(*n); void print_message( )printf(Tsinghua Universityn); printf(Copyright Protectedn);main( ) printstar( ); print

34、_message( ); printstar( );例5.7討論程序運(yùn)行結(jié)果？實(shí)參與形參之間是單向的值傳遞。形參的改變對實(shí)參沒有影響。# include “stdio.h”swap (float f1，float f2) float temp； temp=f1;f1=f2;f2=temp;void main() float x，y； scanf(”%f %f”,&x,&y)； printf(”x=%f,y=%f”,x,y)； swap(x，y)； printf(”x=%f y=%fn”,x,y); 例5.8數(shù)組元素作函數(shù)的參數(shù)。#include stdio.h#include math.hma

35、in() float a10,b=0; int i; for (i=1;i0) b=b+sqrt(ai); printf(b=%fn,b);例5.9數(shù)組名作函數(shù)參數(shù)，求10個(gè)數(shù)的平均值。#include stdio.hfloat average(float arr100 ) int i; float av,sum=arr0; for (i=1;i100;i+) sum=sum+arri; av=sum/100; return(av);main()float sal100,aver; int i; for(i=0;i100;i+) scanf(%f,&sali); aver=average(sa

36、l); printf(%6.3f,aver);例5.10字符串的連接#include#includemain()char s120=“abcd”,s210=“efghijk”; strcat(s1,s2); puts(s1);例5.11字符串的連接。#include#includemain()char s120=“abcd”,s210=“efghijk”;int i,j;for(i=0;s1i!=0;i+);for(j=0;s2j!=0;j+,i+)s1i=s2j;puts(s1);例5.12利用函數(shù)實(shí)現(xiàn)字符串的連接。#include#includevoid zfclj(char ss1,ch

37、ar ss2);main()char s120=abcd,s210=efghijk;zfclj(s1,s2);puts(s1);void zfclj(char ss1,char ss2)int i,j;for(i=0;ss1i!=0;i+);for(j=0;ss2j!=0;j+,i+)ss1i=ss2j; 比較5.10、5.11、5.12三個(gè)程序？例5.13利用px函數(shù)實(shí)現(xiàn)數(shù)組元素的排序，排序算法為“冒泡法”。#includevoid px(int b,int n);main()int a10=8,5,2,9,1,6,7,4,1,9 ;int i,n;scanf(%d,&n);px(a,n);

38、for(i=0;in;i+)printf(%5d,ai);void px(int b,int n)int t;int i,j;for(i=0;in;i+)for(j=0;jbj+1)t=bj;bj=bj+1;bj+1=t;例5.14靜態(tài)局部變量static的使用。討論程序的執(zhí)行結(jié)果？main() int a=2,i; clrscr(); for (i=0;iy?x:y; return c; main() int a=8; printf(%dn,max(a,b); 例5.17全局變量作用域的擴(kuò)展。（extern）void num() extern int x,y; int a=15,b=10;

39、x=a-b; y=a+b;int x,y;main() int a=7,b=5; x=a+b; y=a-b; num(); printf(%d,%dn,x,y); 例5.18程序執(zhí)行的結(jié)果？int a; /*討論：要是改為：int a5？*/fun(int i) a+=2*i;return a; main() int a=10; printf(%d,%dn,fun(a),a);例5.19計(jì)算15的和。main( ) int i=5; printf(%dn,sub(i);sub(int n) int a; if (n=1) return 1; a=n+sub(n-1); return a; 例5

40、.20全局變量的使用。結(jié)果？int a=3,b=2;max(int x,int y) int c; c=xy?x:y; return c; main() int a=4; printf(t%dn,max(a,b); 第六章 指針例6.1指針變量的簡單使用。注意“*”運(yùn)算符的作用。main()int a=10;int * p1;p1=&a;printf(%d,*p1);例6.2指針變量的引用main()int a=100;int *p;clrscr();p=&a;p=0x1000;*p=20; printf(%d,%x,%p,*p,p,p);例6.3指針變量的引用main() int a; in

41、t *p; clrscr(); p=&a; printf(%p,%x,p,p);例6.6輸出結(jié)果。main( ) int a; int *p; clrscr(); p=&a; *p=100; printf(%d,*p);例6.7先大后小的順序輸出兩個(gè)數(shù)。不交換變量a、b的值，交換指針的指向。main( )int *p1, *p2, *p, a, b; scanf(%d,%d,&a,&b); p1 = &a; p2 = &b; if (a b) p = p1; p1 = p2; p2 = p; printf(a=%d,b=%dn,a,b); printf(max=%d,min=%dn, *p1,

42、 *p2);例6.8指針加法運(yùn)算。void main()int a=10;int* p=&a;printf(%x,p);printf(%x,p+9);例6.9變量值傳遞。結(jié)果：交換了main函數(shù)中的a、b嗎？int swap(int a,int b)int c;c=a;a=b;b=c;main()int a=10,b=20;swap(a,b);printf(%d,%d,a,b);例6.10利用指針傳遞地址。結(jié)果：交換了main函數(shù)中的a、b嗎？int swap(int *a,int *b)int *c;c=a;a=b;b=c;main()int a=10,b=20;int *p1=&a,*p2

43、=&b,p3;swap(p1,p2);printf(%d,%d,a,b);printf(%d,%d,*p1,*p2);例6.11結(jié)果：交換了main函數(shù)中的a、b嗎？int swap(int *a,int *b)int *c;c=a;a=b;b=c;main()int a=10,b=20;int *p1=&a，*p2=&b,p3；swap(*p1,*p2);printf(%d,%d,a,b);printf(%d,%d,*p1,*p2);例6.12結(jié)果？int swap(int *p1, int *p2)int p; p = *p1;*p1 = *p2; *p2 = p;main()int a=

44、10, b=20; int *p1, *p2; p1= &a;p2 = &b; swap(p1 , p2); printf(n%d,%dn,a,b);例6.13三個(gè)數(shù)從大到小的順序的排序。intswap(int *pt1, int *pt2)int p; p = *pt1; *pt1 = *pt2; *pt2 = p; intexchange(int *q1, int *q2, int *q3)if (*q1 *q2) swap(q1,q2); if (*q1 *q3) swap(q1,q3); if (*q2 *q3) swap(q2,q3); main() int a,b,c, *p1, *p2, *p3; scanf(%d,%d,%d, &a, &b, &c);