版權(quán)說明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請進行舉報或認領(lǐng)
文檔簡介
1、EE141 Digital Integrated Circuits2ndCombinational Circuits1Nov 9, 2011EE141 Digital Integrated Circuits2ndCombinational Circuits2組合邏輯時序邏輯Output = f(In)Output = f(In, Previous In)Combina t i o n alLogicCircuitOutInCombina t i o n alLogicCircuitOutInStateEE141 Digital Integrated Circuits2ndCombination
2、al Circuits3q每一時刻每一時刻 (除了切換期間的瞬態(tài)效應(yīng))每個門除了切換期間的瞬態(tài)效應(yīng))每個門 的輸出通過一個低阻路徑連接到的輸出通過一個低阻路徑連接到q在任何時候該門的輸出即為該電路實現(xiàn)的布在任何時候該門的輸出即為該電路實現(xiàn)的布爾函數(shù)值爾函數(shù)值(再一次忽略切換期間的瞬態(tài)效應(yīng)再一次忽略切換期間的瞬態(tài)效應(yīng)) q不同于動態(tài)電路,后者依賴把信號值暫時存不同于動態(tài)電路,后者依賴把信號值暫時存放在高阻抗電路節(jié)點的電容上放在高阻抗電路節(jié)點的電容上VDD or Vss EE141 Digital Integrated Circuits2ndCombinational Circuits4VDDF(
3、In1,In2,InN)In1In2InNIn1In2InNPUNPDNPMOS onlyNMOS onlyPUN(上拉網(wǎng)絡(luò)) 和 PDN(下拉網(wǎng)絡(luò)) 是雙通道邏輯網(wǎng)絡(luò)EE141 Digital Integrated Circuits2ndCombinational Circuits5q一個晶體管可以看成是一個由其柵信號控制的開關(guān)qPDN由NMOS器件構(gòu)成,PUN由PMOS器件構(gòu)成q可以推導(dǎo)出一組規(guī)則來實現(xiàn)邏輯功能q互補CMOS結(jié)構(gòu)的上拉和下拉網(wǎng)絡(luò)互為對偶網(wǎng)絡(luò)q互補門本質(zhì)上是反相的,只能實現(xiàn)與非、或非和異或門q實現(xiàn)一個具有N個輸入的邏輯門需晶體管數(shù)目2N個EE141 Digital Integ
4、rated Circuits2ndCombinational Circuits6Transistors can be thought as a switch controlled by its gate signalNMOS switch closes when switch control input is highNMOS邏輯規(guī)則-串聯(lián)AND操作、并聯(lián)OR操作EE141 Digital Integrated Circuits2ndCombinational Circuits7PMOS邏輯規(guī)則-串聯(lián)NOR 操作、并聯(lián)NAND操作EE141 Digital Integrated Circuit
5、s2ndCombinational Circuits8VDDVDD 0PDN0 VDDCLCLPUNVDD0 VDD - VTnCLVDDVDDVDD |VTp|CLSDSDVGSSSDDVGSEE141 Digital Integrated Circuits2ndCombinational Circuits9PUN和PDN是互補網(wǎng)絡(luò) 符合DeMorgan定律 單級互補CMOS邏輯門是反相輸出的 同相:需加額外反相EE141 Digital Integrated Circuits2ndCombinational Circuits10EE141 Digital Integrated Circui
6、ts2ndCombinational Circuits11EE141 Digital Integrated Circuits2ndCombinational Circuits12C(a) pul l - d o wn netwo rkSN1SN4SN2SN3DFFADBCDFABCsub-net sDAABCVDDVDDB(c) com p l e t e g ateEE141 Digital Integrated Circuits2ndCombinational Circuits13OUT = D + A (B + C)DABCDABCEE141 Digital Integrated Cir
7、cuits2ndCombinational Circuits14EE141單元設(shè)計標(biāo)準單元通用邏輯可綜合等高,寬度可變數(shù)據(jù)通路單元規(guī)則、結(jié)構(gòu)化邏輯(算術(shù)運算)單元中包含互連線固定高度和寬度數(shù)字集成電路14組合邏輯電路EE141 Digital Integrated Circuits2ndCombinational Circuits15不包含維數(shù)信息表示了晶體管間的相對位置EE141 Digital Integrated Circuits2ndCombinational Circuits16EE141 Digital Integrated Circuits2ndCombinational Cir
8、cuits17不包含維數(shù)信息表示了晶體管間的相對位置InOutVDDGNDInverterAOutVDDGNDBNAND2EE141 Digital Integrated Circuits2ndCombinational Circuits18CABX = C (A + B)BACijABCEE141 Digital Integrated Circuits2ndCombinational Circuits19XCABABCXVDDGNDVDDGNDEE141 Digital Integrated Circuits2ndCombinational Circuits20CABX = C (A + B
9、)BACijjVDDXXiGNDABCPUNPDNABC邏輯圖EE141 Digital Integrated Circuits2ndCombinational Circuits21CABX = (A+B)(C+D)BADVDDXXGNDABCPUNPDNCDDABCDEE141 Digital Integrated Circuits2ndCombinational Circuits22GNDxabcdVDDxGNDxabcdVDDx(a) Logic graphs for (ab+cd)(b) Euler Paths a b c dacdxVDDGND(c) stick diagram fo
10、r ordering a b c dbEE141 Digital Integrated Circuits2ndCombinational Circuits23n 靜態(tài)特性靜態(tài)特性高噪聲容限高噪聲容限(NM ) VOH=VDD, VOL=VSS (GND)無靜態(tài)功耗無靜態(tài)功耗 穩(wěn)態(tài)時,穩(wěn)態(tài)時,VDD和和VSS(GND)間無直流通路間無直流通路n 動態(tài)特性動態(tài)特性上升、下降時延接近上升、下降時延接近 上下網(wǎng)絡(luò)有適當(dāng)?shù)某叽绫壤舷戮W(wǎng)絡(luò)有適當(dāng)?shù)某叽绫壤鼸E141 Digital Integrated Circuits2ndCombinational Circuits24q滿電源幅度開關(guān); 高噪聲容限q
11、電平幅度與器件尺寸無關(guān); ratiolessq穩(wěn)態(tài)時總有到VDD或GND之間的通路; 低輸出阻抗q高輸入阻抗; 輸入穩(wěn)態(tài)電流幾乎為零q電源與地之間無直接通路; 無靜態(tài)功耗q傳輸延時是負載電容和晶體管電阻的函數(shù)EE141 Digital Integrated Circuits2ndCombinational Circuits25AReqARpARpARnCLACLBRnARpBRpARnCintBRpARpARnBRnCLCintNAND2INVNOR2EE141 Digital Integrated Circuits2ndCombinational Circuits26q延時與輸入波形有關(guān)q輸
12、出高到低的轉(zhuǎn)換 A=B=0-1 延時: 0.69(2Rn)CL A=1,B=0-1- 延時: 0.69 (2Rn )CL A=0-1,B=1 延時: 0.69 (2Rn )CL 實際上單A跳變比單 B跳變快CLARnARpBRpBRnCintEE141 Digital Integrated Circuits2ndCombinational Circuits27q延時與輸入波形有關(guān)q輸出低到高的轉(zhuǎn)換 A=B=1-0 延時: 0.69 Rp/2 CL A=1,B=1-0- 延時: 0.69 Rp CL A=1-0,B=1 延時: 0.69 Rp CL 實際上單A跳變比單B跳變快CLARnARpBR
13、pBRnCintEE141 Digital Integrated Circuits2ndCombinational Circuits28A=B=10B=1, A=10B=1 0, A=1time psVoltage VInput DataPatternDelay(psec)A=B=0169A=1, B=0162A= 01, B=150A=B=1035A=1, B=1076A= 10, B=157NMOS = 0.5m/0.25 mPMOS = 0.75m/0.25 mCL = 100 fFEE141 Digital Integrated Circuits2ndCombinational Cir
14、cuits29DCBADCBACLC3C2C1 分布RC模型 (Elmore延時)tpHL = 0.69 Reqn(C1+2C2+3C3+4CL)傳輸延時隨扇入迅速惡化 - 最壞情況成平方關(guān)系 - 電阻電容同時起作用EE141 Digital Integrated Circuits2ndCombinational Circuits30tpLHtp (psec)fan-in避免扇入大于4的門tpHL平方線性tptpLHEE141 Digital Integrated Circuits2ndCombinational Circuits31tpNOR2tp (psec)eff. fan-out所有的
15、門具有相同驅(qū)動電流tpNAND2tpINV斜率是驅(qū)動力的函數(shù)EE141 Digital Integrated Circuits2ndCombinational Circuits32q扇入: 平方源于電容和電阻的增加q扇出: 每個額外扇出增加負載 CLEE141 Digital Integrated Circuits2ndCombinational Circuits33q晶體管尺寸規(guī)則 只要扇出電容為主q漸進尺寸規(guī)則InNCLC3C2C1In1In2In3M1M2M3MN分布RC線M1 M2 M3 MN (最接近輸出最小)使R1R2R3RNEE141 Digital Integrated Cir
16、cuits2ndCombinational Circuits34q晶體管排序C2C1In1In2In3M1M2M3CLC2C1In3In2In1M1M2M3CLcritical pathcritical path放電101放電放電1延時由CL, C1 and C2的放電時間決定延時由CL的放電時間決定1101放電放電結(jié)束放電結(jié)束EE141 Digital Integrated Circuits2ndCombinational Circuits35q不同的邏輯結(jié)構(gòu)F = ABCDEFGHEE141 Digital Integrated Circuits2ndCombinational Circu
17、its36q插入緩沖器將扇入和扇出隔離開CLCLEE141 Digital Integrated Circuits2ndCombinational Circuits37EE141晶體管尺寸規(guī)則假定典型p/n管比例為2/1并聯(lián)保持(考慮單個跳變;同時跳變時電阻,并聯(lián)速度更快)串聯(lián)加倍(考慮同時跳變時,電阻串聯(lián)折半,減小單個電阻)2 ARpBRp24 BRp單個信號輸入電容為INV的5/3單個信號 Rn輸入電容 2 B為INV的4/3CL4ARpCint2RnACint1RnARnB1CL數(shù)字集成電路28組合邏輯電路EE141 Digital Integrated Circuits2ndCombi
18、national Circuits38 CLBRnARpBRpARnCintBRpARpARnBRnCLCint22221144EE141 Digital Integrated Circuits2ndCombinational Circuits39OUT = D + A (B + C)DABCDABC12224488EE141 Digital Integrated Circuits2ndCombinational Circuits40OUT = D + A (B + C)DABCDABC12224488EE141 Digital Integrated Circuits2ndCombinatio
19、nal Circuits41EE141 Digital Integrated Circuits2ndCombinational Circuits42目標(biāo): 相對于靜態(tài)互補CMOS, 減少晶體管個數(shù)VDDVSSPDNIn1In2In3FRLLoadVDDVSSIn1In2In3FVDDVSSPDNIn1In2In3FVSSPDNResistiveDepletionLoadPMOSLoad(a) 電阻負載(b) 耗盡 NMOS負載(c) 偽NMOS負載VT 有比邏輯EE141 Digital Integrated Circuits2ndCombinational Circuits45VDDVSSP
20、DNIn1In2In3FRL電阻負載電阻負載NMOS+ 電阻負載電阻負載 VOH = VDD VOL = RPNRPN + RL 不對稱響應(yīng)不對稱響應(yīng) 存在靜態(tài)功耗存在靜態(tài)功耗 tpL= 0.69 RLCLVDDEE141 Digital Integrated Circuits2ndCombinational Circuits46耗盡負載 NMOS偽-NMOSVDDVSSIn1In2In3FVDDVSSPDNIn1In2In3FVSSPDN耗盡負載耗盡負載PMOS負載負載VT 寄生小=速度快l理想開關(guān) - 低導(dǎo)通電阻和低寄生電容EE141 Digital Integrated Circuits
21、2ndCombinational Circuits56BBAF =AB0EE141 Digital Integrated Circuits2ndCombinational Circuits57VDDInOutx0.5m/0.25m0.5m/0.25m1.5m/0.25m00.511.520.01.02.03.0Time nsVoltage VxOutInEE141 Digital Integrated Circuits2ndCombinational Circuits58A = 2.5 VBC = 2.5 VCLA = 2.5 VC = 2.5 VBM2M1Mn缺陷 -閾值損失 -后繼反相器有
22、短路 功耗EE141 Digital Integrated Circuits2ndCombinational Circuits59M2M1MnMrOutABVDDVDDLevel RestorerX 電平恢復(fù)器 -使Vx迅速拉到高電平 問題:尺寸規(guī)劃 -A=0,B=0-1時 -有比邏輯EE141 Digital Integrated Circuits2ndCombinational Circuits60EE141 Digital Integrated Circuits2ndCombinational Circuits61lCPL門的特點互補數(shù)據(jù)輸入用較少管子實現(xiàn)加法器和異或功能差分信號極性免去
23、了多余反相器屬于靜態(tài)邏輯,有較好抑噪能力模塊化結(jié)構(gòu)EE141 Digital Integrated Circuits2ndCombinational Circuits62ABCCABCCBCLC = 0 VA = 2.5 VC = 2.5 VBCLC = 0 VA = 0 VC = 2.5 VEE141 Digital Integrated Circuits2ndCombinational Circuits63Vout0 V2.5 V2.5 VRnRp0.01.02.00 10 20 30 Vout, VResistance, ohmsRnRpRn | RpEE141 Digital Inte
24、grated Circuits2ndCombinational Circuits64AM2M1BSSSFVDDABFBABBM1M2M3/M4EE141 Digital Integrated Circuits2ndCombinational Circuits65V1Vi-1C2.52.500ViVi+1CC2.50Vn-1VnCC2.50InV1ViVi+1CVn-1VnCCInReqReqReqReqCC(a)(b)CReqReqCCReqCCReqReqCCReqCInm(c)EE141 Digital Integrated Circuits2ndCombinational Circuit
25、s66EE141 Digital Integrated Circuits2ndCombinational Circuits67EE141 Digital Integrated Circuits2ndCombinational Circuits68q靜態(tài)電路在任何時候通過低阻通路,輸出連在VDD或VSS. 除非在開關(guān)的瞬間 扇入n需要2n個晶體管(一半為p管)q動態(tài)電路依賴高阻節(jié)點(電容)暫存信號電荷 結(jié)構(gòu)簡單,寄生小,速度快 易受噪聲影響 扇入n需要n+2晶體管(一個是p管)EE141 Digital Integrated Circuits2ndCombinational Circuits69
26、In1In2PDNIn3MeMpClkClkOutCLOutClkClkABCMpMe兩相位工作 預(yù)充電 (CLK = 0) 求值 (CLK = 1)EE141 Digital Integrated Circuits2ndCombinational Circuits70q動態(tài)門的輸出一旦放電后,要等到下一次預(yù)充電才能充電q在求值時,輸出最多完成一次1-0轉(zhuǎn)化 要么保持為1 要么放電到0,放電后不可能回到1,直到再次充電 級聯(lián)問題.q在求值期間或是求值之后,輸出可以是高組態(tài),狀態(tài)存儲在CL上,PDN網(wǎng)絡(luò)截至EE141 Digital Integrated Circuits2ndCombinati
27、onal Circuits71q邏輯函數(shù)僅由 PDN完成 晶體管數(shù)目為N+2 (靜態(tài)互補CMOS:2N)q全幅輸出 (VOL = GND and VOH = VDD)q器件尺寸不影響邏輯電平 與比例無關(guān)q開關(guān)速度更快 寄生電容?。–in,Cout)q無短路功耗 只有漏電和電容功耗EE141 Digital Integrated Circuits2ndCombinational Circuits72q總功耗通常高于靜態(tài)互補CMOS VDD 和GND之間無靜態(tài)電流和短路電流 無毛刺 較高的轉(zhuǎn)化概率 Clk額外負載q需要一個預(yù)充電或求值時鐘CLKEE141 Digital Integrated Ci
28、rcuits2ndCombinational Circuits73CLClkClkOutAMpMe漏電來源CLKVOut預(yù)充電求值主要是亞閾值漏電流EE141 Digital Integrated Circuits2ndCombinational Circuits74CLClkClkMeMpABOutMkp類似于傳輸晶體管中的電平恢復(fù)管維持管EE141 Digital Integrated Circuits2ndCombinational Circuits75CL 存儲的電荷在CL 和 CA 之間再分配(共享) ,降低了可靠性CLClkClkCACBB=0AOutMpMeEE141 Digit
29、al Integrated Circuits2ndCombinational Circuits76CL=50fFClkClkAABBB!BCCOutCa=15fFCc=15fFCb=15fFCd=10fFEE141 Digital Integrated Circuits2ndCombinational Circuits77MpMeVDDOutAB = 0CLCaCbMaMbXCLVDDCLVoutt CaVDDVTnVX+=or VoutVoutt VDDCaCL- - VDDVTnVX= VoutVDDCaCaCL+- - -=case 1) if Vout VTnB =0ClkXCLCaC
30、bAOutMpMaVDDMbClkMeEE141 Digital Integrated Circuits2ndCombinational Circuits78ClkClkMeMpABOutMkpClk對內(nèi)部節(jié)點進行預(yù)充電,采用時鐘驅(qū)動晶體管代價是增加面積和功耗EE141 Digital Integrated Circuits2ndCombinational Circuits79CL1ClkClkB=0A=0Out1MpMeOut2CL2In動態(tài) NAND靜態(tài) NAND=1=0EE141 Digital Integrated Circuits2ndCombinational Circuits80
31、VoltageTime, nsClkInOut1Out2EE141 Digital Integrated Circuits2ndCombinational Circuits81CLClkClkBAOutMpMe在輸出OUT和輸入時鐘CLK之間(預(yù)充電管),由于柵漏電容導(dǎo)致輸出電壓超出VDD。時鐘的快速上升沿(下降呀)耦合到輸出OUTEE141 Digital Integrated Circuits2ndCombinational Circuits82ClkClkIn1In2In3In4OutIn &ClkOutTime, nsVoltage時鐘饋通時鐘饋通EE141 Digital Integrated Circuits2ndCombinational Circuits83ClkClkOut1InMpMeMpMeClkClkOut2VtClkInOut1Out2VVTn輸入不允許10的轉(zhuǎn)化,只允許0 1 的轉(zhuǎn)化!EE141 Digital Integrated Circuits2ndCombinational Circuits84In1In2
溫馨提示
- 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
- 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁內(nèi)容里面會有圖紙預(yù)覽,若沒有圖紙預(yù)覽就沒有圖紙。
- 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
- 5. 人人文庫網(wǎng)僅提供信息存儲空間,僅對用戶上傳內(nèi)容的表現(xiàn)方式做保護處理,對用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對任何下載內(nèi)容負責(zé)。
- 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請與我們聯(lián)系,我們立即糾正。
- 7. 本站不保證下載資源的準確性、安全性和完整性, 同時也不承擔(dān)用戶因使用這些下載資源對自己和他人造成任何形式的傷害或損失。
最新文檔
- 2024屆海南省臨高縣新盈中學(xué)高三假期自主綜合能力測試(一)數(shù)學(xué)試題
- 餐飲住房合同
- 不動產(chǎn)買賣合同解除協(xié)議模板
- 畢業(yè)生就業(yè)協(xié)議書入戶地址
- 手術(shù)對骨骼健康的影響
- 防溺水模擬演練課件
- 山東省煙臺招遠市(五四制)2024-2025學(xué)年九年級上學(xué)期期中考試化學(xué)試題(含答案)
- 河北省石家莊市欒城區(qū)2024-2025學(xué)年七年級上學(xué)期期中生物學(xué)試題(含答案)
- 《化妝棉》規(guī)范要求
- 福建省泉州市安溪縣2024-2025學(xué)年高三上學(xué)期11月期中測評試題 數(shù)學(xué)(含解析)
- 人教版八年級上冊英語單詞表默寫版(直接打印)
- 五年級數(shù)學(xué)質(zhì)量分析經(jīng)驗交流發(fā)言稿(共3頁)
- 工程的材料及成型技術(shù)基礎(chǔ)概念鞠魯粵編
- (精選)國培結(jié)業(yè)典禮領(lǐng)導(dǎo)講話稿范文(3篇)
- 電脫水、電脫鹽講解
- 江西省科技創(chuàng)新平臺建設(shè)(PPT課件)
- 違約損失率(LGD)研究
- XSD3016輪式洗砂機結(jié)構(gòu)設(shè)計和實現(xiàn)機械設(shè)計和自動化專業(yè)論文設(shè)計
- 溝槽回填施工方案(完整版)
- 2021-2025鄉(xiāng)村5年規(guī)劃三篇
- 初中各篇文言文單字解釋大全
評論
0/150
提交評論