版權(quán)說明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請進行舉報或認(rèn)領(lǐng)
文檔簡介
1、機械原理(yunl)大作業(yè)一課程名稱: 機械(jxi)原理 設(shè)計(shj)題目: 連桿機構(gòu)設(shè)計 院 系: 機電工程學(xué)院 班 級: 完 成 者: 學(xué) 號: 指導(dǎo)教師: 設(shè)計時間: 5月10日-5月19日 哈爾濱工業(yè)大學(xué)(13)在圖1-13所示的牛頭刨床機構(gòu)(jgu)中,已知各個構(gòu)建尺寸為:LAB=108mm,LCE=620mm,LEF=300mm,H1=350mm,H=635mm,曲柄1以等角速度轉(zhuǎn)動,轉(zhuǎn)速(zhun s)為n1=225r/min。試求滑塊5上點F的位移、速度和加速度。機構(gòu)的自由度計算(j sun)及基本桿組劃分(1)自由度計算 該機構(gòu)為平面機構(gòu),活動構(gòu)件的數(shù)目為n=5,低副PL
2、=7,高副數(shù)目PH=0,故該牛頭刨床機構(gòu)的自由度為 F=3n-2PL-PH=3*5-2*7-0=1(2)基本桿組的劃分 構(gòu)件1為原動件,故先移除,然后按照拆分法拆分桿組。桿3與滑塊2組成RPRII級桿組,桿4與滑塊5組成RPRII級桿組。拆分結(jié)果如下:2、各基本桿組的運動(yndng)分析 以C點為坐標(biāo)原點建立直角坐標(biāo)系,通過求出B點坐標(biāo)求出E點坐標(biāo),進而推出F點坐標(biāo),其與時間的函數(shù)即為位移(wiy)方程,對其求一次導(dǎo)得速度方程,求二階導(dǎo)得加速度方程。 圖一為一級桿組: xB = lABcos yB = lABsin 圖二為二級桿組: xE = lCEcos1 yE = lCEsin1 1 =
3、 arctan(H1+lAbsin)/lABcos 圖三為二級桿組: xF = xE - lEFcos2 2 = arcsin(H - yE)/lEF3、數(shù)學(xué)(shxu)建模(1)、位移圖2、速度圖3、加速度圖4、計算(j sun)程序Begin VB.Form 牛頭刨連桿機構(gòu) Caption = Form1 ClientHeight = 3030 ClientLeft = 120 ClientTop = 450 ClientWidth = 4560 LinkTopic = Form1 ScaleHeight = 3030 ScaleWidth = 4560 StartUpPosition =
4、 3 窗口(chungku)缺省 Begin VB.PictureBox Picture4 Height = 6495 Left = 2760 ScaleHeight = 6435 ScaleWidth = 11235 TabIndex = 4 Top = 120 Width = 11295 End Begin VB.PictureBox Picture3 Height = 6255 Left = 1680 ScaleHeight = 6195 ScaleWidth = 75 TabIndex = 3 Top = 240 Width = 135 End Begin VB.PictureBox
5、Picture2 Height = 6255 Left = 2280 ScaleHeight = 6195 ScaleWidth = 75 TabIndex = 2 Top = 0 Width = 135 End Begin VB.PictureBox Picture1 Height = 6255 Left = 960 ScaleHeight = 6195 ScaleWidth = 195 TabIndex = 1 Top = 120 Width = 255 End Begin VB.CommandButton Command1 Caption = Command1 Height = 495
6、Left = 120 TabIndex = 0 Top = 120 Width = 495 EndEndAttribute VB_Name = 牛頭刨連桿機構(gòu)Attribute VB_GlobalNameSpace = FalseAttribute VB_Creatable = FalseAttribute VB_PredeclaredId = TrueAttribute VB_Exposed = FalsePrivate f1(3600) As Double 1桿的轉(zhuǎn)角(zhunjio)Private xB0(3600) As Double Private yB0(3600) As Doub
7、le Private vxB0(3600) As Double Private vyB0(3600) As Double Private axB0(3600) As Double Private ayB0(3600) As Double Private xE0(3600) As Double Private yE0(3600) As Double Private vxE0(3600) As Double Private vyE0(3600) As Double Private axE0(3600) As Double Private ayE0(3600) As Double Private f
8、3(3600) As Double Private w3(3600) As Double Private e3(3600) As Double Private s5(3600) As Double Private vs5(3600) As Double Private as5(3600) As Double Private pi As DoublePrivate pa As DoublePrivate Sub Command1_Click()Dim i As DoubleDim j As LongDim RR1 As rrDim RPR1 As rprDim RRP1 As rrpSet RR
9、1 = New rrSet RPR1 = New rprSet RRP1 = New rrppi = 4 * Atn(1)pa = pi / 180Picture1.DrawWidth = 1Picture1.Scale (-20, 1000)-(390, -40) Picture1.Line (-20, 0)-(390, 0) X Picture1.Line (0, 1000)-(0, -40) Y Picture1.CurrentX = 330: Picture1.CurrentY = 40 Picture1.Print 主動(zhdng)件轉(zhuǎn)角/度 X表示 Picture1.Curren
10、tX = 10: Picture1.CurrentY = 960 Picture1.Print 滑塊位移(wiy)S /mm Y表示 For j = 30 To 390 Step 30 X軸坐標(biāo)(zubio) Picture1.Line (j, 5)-(j, 0) Picture1.CurrentX = j - 5: Picture1.CurrentY = 0 Picture1.Print j Next j For j = 0 To 1000 Step 80 Y軸坐標(biāo) Picture1.Line (0, j)-(5, j) Picture1.CurrentX = -20: Picture1.C
11、urrentY = j + 2 Picture1.Print j Next j Picture1.DrawStyle = 2 For j = 0 To 1000 Step 80 Picture1.Line (-20, j)-(390, j), vbBlack 橫向網(wǎng)格 Next j For j = 0 To 390 Step 30 Picture1.Line (j, -20)-(j, 1000), vbBlack 縱向網(wǎng)格 Next j Picture2.DrawWidth = 1Picture2.Scale (-20, 8000)-(390, -4000) Picture2.Line (-2
12、0, 0)-(380, 0) X Picture2.Line (0, 8000)-(0, -4000) Y Picture2.CurrentX = 340: Picture2.CurrentY = 400 Picture2.Print 主動(zhdng)件轉(zhuǎn)角/度 Picture2.CurrentX = 10: Picture2.CurrentY = 2400 Picture2.Print 滑塊速度(sd)V mm/s For j = 30 To 390 Step 30 X軸坐標(biāo)(zubio) Picture2.Line (j, 5)-(j, 0) Picture2.CurrentX = j
13、- 5: Picture2.CurrentY = 0 Picture2.Print j Next j For j = -4000 To 8000 Step 800 Y軸坐標(biāo) Picture2.Line (0, j)-(5, j) Picture2.CurrentX = -10: Picture2.CurrentY = j + 7 Picture2.Print j Next j Picture2.DrawStyle = 2 For j = -4000 To 8000 Step 800 Picture2.Line (-20, j)-(390, j), vbBlack 橫向網(wǎng)格 Next j For
14、 j = 30 To 390 Step 30 Picture2.Line (j, -4000)-(j, 8000), vbBlack 縱向網(wǎng)格 Next j Picture3.DrawWidth = 1Picture3.Scale (-20, 150000)-(380, -200000) Picture3.Line (-20, 0)-(390, 0) X Picture3.Line (0, 150000)-(0, -200000) Y Picture3.CurrentX = 300: Picture3.CurrentY = 10000 Picture3.Print 主動件轉(zhuǎn)角/度 Pictur
15、e3.CurrentX = 10: Picture3.CurrentY = 80000 Picture3.Print 滑塊加速度a mm/S2 For j = 30 To 390 Step 30 X軸坐標(biāo) Picture3.Line (j, 5)-(j, 0) Picture3.CurrentX = j - 5: Picture3.CurrentY = 0 Picture3.Print j Next j For j = -200000 To 150000 Step 10000 Y軸坐標(biāo) Picture3.Line (0, j)-(5, j) Picture3.CurrentX = -20: P
16、icture3.CurrentY = j + 7 Picture3.Print j Next j Picture3.DrawStyle = 2 For j = -200000 To 150000 Step 10000 Picture3.Line (-200000, j)-(150000, j), vbBlack 橫向(hn xin)網(wǎng)格 Next j For j = 0 To 390 Step 30 Picture3.Line (j, -200000)-(j, 150000), vbBlack 縱向(zn xin)網(wǎng)格 Next j 主程序For i = 0# To 3600# Step 0.
17、1 主動(zhdng)件轉(zhuǎn)角0-360,步長0.01RR類模塊屬性賦值f1(i) = i * pa / 10RR1.f = f1(i)RR1.L = 108RR1.w = 205 * 2 * pi / 60RR1.e = 0RR1.xA = 0RR1.yA = 0RR1.vxA = 0RR1.vyA = 0RR1.axA = 0RR1.ayA = 0RR1.calRR 執(zhí)行RR類模塊方法xB0(i) = RR1.xByB0(i) = RR1.yBvxB0(i) = RR1.vxBvyB0(i) = RR1.vyBaxB0(i) = RR1.axBayB0(i) = RR1.ayBRPR類模塊屬
18、性賦值RPR1.Li = 0RPR1.Lj = 620RPR1.Lk = 0RPR1.xB = xB0(i)RPR1.yB = yB0(i)RPR1.vxB = vxB0(i)RPR1.vyB = vyB0(i)RPR1.axB = axB0(i)RPR1.ayB = ayB0(i)RPR1.xD = 0RPR1.yD = -350RPR1.vxD = 0RPR1.vyD = 0RPR1.axD = 0RPR1.ayD = 0RPR1.calRPR 執(zhí)行(zhxng)RPR類模塊方法xE0(i) = RPR1.xEyE0(i) = RPR1.yEvxE0(i) = RPR1.vxEvyE0(i) = RPR1.vyEaxE0(i) = RPR1.axEayE0
溫馨提示
- 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
- 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁內(nèi)容里面會有圖紙預(yù)覽,若沒有圖紙預(yù)覽就沒有圖紙。
- 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
- 5. 人人文庫網(wǎng)僅提供信息存儲空間,僅對用戶上傳內(nèi)容的表現(xiàn)方式做保護處理,對用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對任何下載內(nèi)容負責(zé)。
- 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請與我們聯(lián)系,我們立即糾正。
- 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時也不承擔(dān)用戶因使用這些下載資源對自己和他人造成任何形式的傷害或損失。
最新文檔
- 文化產(chǎn)業(yè)示范基地復(fù)核書
- 河北省邢臺市威縣寺莊中學(xué)2024-2025學(xué)年八年級上學(xué)期期中地理試題(含答案)
- 實驗室用拭子實驗室工具產(chǎn)業(yè)鏈招商引資的調(diào)研報告
- 吉他弦橋市場需求與消費特點分析
- 單肩包市場發(fā)展預(yù)測和趨勢分析
- 人教版英語八年級下冊 Unit 1-3 單元閱讀訓(xùn)練
- 高效灌溉技術(shù)在蔬菜種植中的應(yīng)用分析報告
- 可充氣薄橡膠玩具市場需求與消費特點分析
- 土耳其氈帽產(chǎn)業(yè)規(guī)劃專項研究報告
- 城市公共設(shè)施門窗改造方案
- 諾貝爾生理學(xué)或醫(yī)學(xué)獎史話 知到智慧樹網(wǎng)課答案
- 太陽能光熱轉(zhuǎn)換和熱儲存技術(shù)
- AQ 2043-2012 石油行業(yè)安全生產(chǎn)標(biāo)準(zhǔn)化 陸上采氣實施規(guī)范
- 麻醉藥靶點的新發(fā)現(xiàn)和藥理機制
- MOOC 國際交流學(xué)術(shù)英文寫作-湖南大學(xué) 中國大學(xué)慕課答案
- 書香班級評選方案及總結(jié)
- 白內(nèi)障護理學(xué)習(xí)教案
- 30題高分子材料工程師崗位常見面試問題含HR問題考察點及參考回答
- 小班語言《會響的小路》課件
- 健康科普宣傳進社區(qū)活動方案
- 二年級上美術(shù)教案-我家的菜藍子-嶺南版
評論
0/150
提交評論