2021年安徽省安慶市高考數(shù)學(xué)一模試卷(理科)

23nn223nn242021年安徽安慶市高數(shù)學(xué)一模試（理科）一選題共12小題）A{x0}{|log12}AA2

B3i|z

C1

D2Aa2Aab

B5blogcBac

C2D4abcCcbDcaA20

BD160234﹣11+2A1B

C

D{}3a{}A2Bg

C3Dcos2f2sinx

AC

BD

y

lddA4B2+CD3+

11111111nn1184021A

B

C

D10ab0M+2+23C2A

B

C

D11BCDBDFACABDCEBBDCEFCBEFCEFDB12fx+ffA1+C

01B01D1二填題共4?。?3y2+114xx+a1a15x2

+22xyPABC

16{}a

nN*anN*

n

三解題(共70分解應(yīng)出字明證過(guò)或演步)17ACabcosA+2bC124

D18ABCA'BCABCAAABCBC1'BAOA2ABC'B'C

191bx+

0CMFO1C

2Ml

xMAMBBl

AB203203142080

221

2a1fx2a0fx請(qǐng)生第22、23兩題任一作注:只做選的目如果做則所的第個(gè)目分[選：坐系參方選講]22xOyl

1l

C2l

MN02

[選修4-5：不等選23fx|x+1|1a2x12a0fx0a

235533r235533r參考答案一選題共12小題）A{x0}{|log12}AA2

B3

C1

D2{x3}B{14}{|1x5}B1CAz

i|zB5i

C2D424ii3+4iz

z

a2Aab

blogcBac

abcCcbDcaa2logcbCA20

log2log1c2BD160x6

T

r

26r

x62r

nn24n2nn24n223411162r0rD

160234﹣11+2A1B

C

D33m12m3m792+94m0{}3a{}A2B{}qaaaa6a+2a

C3Dq2

+62g

cos2f2sinxACgx

cos2

BD

xfxC

y

ldd

A4B2+CD3+x24yFPEPFPA|PA

PA|+d|+||+2PA|+d2+

84021A

B

C

Dc

10rr8r264eq\o\ac(△,)π10

ab0M+22y23

111111111111111112A

B

C

Dbxay(2,0)

11BCDBDFACABDCEBBDCEFCBEFCEFDBACDBDACCAACCBDCEFBEFeq\o\ac(△,)C到EFCEFCDC

CEF12fx+ff

A1+C

01B01D1[fx)lnx]f)+f(xlnx0,gx)()lnx+(lnxgx)(1,+)lnx0,g)0,f(1)()(x)0,(x0fx(fx)

x1x0,0+D二填題(共4小，題分共20分13y2+13A1z2+1yx+yx++1y314fxx+1eafa

nn1n11nn1n11fxx+1

+ax1+1ex11f3y73x330f11+1e1

+a1a115x2+2xyPABC

x+2x+202

y+121CC1r1

+

+

+

dr

drdd

16{}a2nN*nN*[)annN*2

n

n21n1n21n1nn3221nnnaaa+a+aa+a++

{}n+anN*a[,+)[,+)

0三解題(共70分解應(yīng)出字明證過(guò)或演步)17ACabcosA+2bC124

D1ccos++2bcos0CcosA+sinB0ACBC180C2ab

18ABCA'BCABCAAABCBC

1'BAOA2ABC'B'CBCAOBCAOOBCAOA'OAAOBCOBCBCCB'BCCBAAO2OAxy'z

AO

BC

OABCABCC

1122ABCC191bx+

0CMFO1C

2Ml

xMAMBBl

AB1

F4a

2MB

AxBx

AB2032031420802

2X180

抽案該獲得金數(shù)為Z

EZ21

2a1fx2a0fx1xea0'x

a0fRa0fx2a0lnfxlna+fx

2a0lnfxlnaf

2a2alna0a0f

lnaa2a0flnf

fln2aalnfxeax+1f+xxa2aln2a2aln2a2aln2

ff1f

f

x1x請(qǐng)生第22、23兩題任一作注:只做選的目如果做則所的第個(gè)目分[選：坐系參方選講]22xOylρcos

1l

C

1212122l

MN02

C2+2

l

ρxy