2007年海南、寧夏卷數(shù)學(xué)(理科)含答案

Ix，x，，x12n11s[(xx)(xx)(xx)]V2223n12nxSh4VS4R，V2π3R3ShR第I卷5≤:xRx1，p）≥p:xRx1，≥p:xRx1，p:xRx1，p:xRx1，123a1)bba（）2((((1ππsin2xπ2y）3yy11xx6236121yy116OxO261323110aak110nd（）21312333S（）否是2px(p0)SyF，2(xyP(xy)P(x，y)點P1，112223332xxx且，）213FPFPFP1222231232FPFP2213213(ab)20y0，，，y成等差數(shù)列，，，，y知x，，的cd）Ｂ．12402cm（）cm33cm333322π24）721217221e(4e)2xy）29e24e22e2e22789555578964467894664sss）123ssssss312213ssssss123231h，h，h（）h:h:h12123:1:13:2:23:2:23:2:3第II卷345．(xxa)f(x)a．x5i，bRa）．i3i54ABBC與DsCA的仰角為AB．SABCSABSACSBAC90°OBC，為ABC；SOCOSCBABAx2(0，2)P和Q．kly122k，ByAkxOPOQ與k4SMMnnmMMmS，Mn10000XMDCXEX；MM()Mk(k)C0.250.75Ptt10000tABt02424242525742575kP(k)(x)ln(xa)x2f1f(x)af(x)xe(x)af．2，，C用AP是OPAC是OO，CO在PAC的M是PA，，，MOMBC，O和O．12O和O12O，O1245(x)2x1x4f．5(x)2f；f(x)y6．31．12i．△．．CDsinsin．sin)tansin)Rt△在．SAB=AC=SB=SCSA△ABC，2MOBOCSAOA2CAOBC△SBCSOBCO2BSA2．SO22A2△SOASOAO．O又AOBO．SOABC．A，O，由（Ⅰ）知SCSAA得取中點M，連結(jié)OMCM．S∴ASCBBC，AOSO，SOBCO得．由AO3AMSAAO，2AOAM26故sinAMO．3373SCBA．3，OA以O(shè)BOxyO．設(shè)BC(，(0，S(0．1111112M，，MOMASC(1)．22222∴MOSCMASC0z．SSCMASC<MO,MA故MO等于二面角ASCBMMOMA3cosMOMA，3MOMACO33BAxSCByA．kx2ly，x22(1．212kx22kx1022①1P和l222，Q8k4k4k2022222k或kk∞，∞．2222(xyQ(xy)OP(xxyy)，P1122121242k12kxx．②122yk(xx)22又y．③12128而A(B(．OPOQ與xx12(yy)，2122k．222kk或k．221．4pM1X~B4．1．4XP0.03410.03，10000XP0.03410.03P(2425X2575)10000C0.250.75ttttt0C0.250.75tC0.250.75t1tttt0.95700.04230.9147．1f2x，xa32f(0a．2x23x1f)．3232xx33f，∞x1f)0；229121x()0fx；當(dāng)1()0fx．當(dāng)x23112(x)1∞ff222x221xa(x)()()，fx．2x2104a8．2202a2f(x)f(x)0f(x)或0a2a2．(2x2x22，x(∞)()，fx若a當(dāng)x．222f(x)0x∞f(x)0f(x)以222(2x2x22，x(∞)()，fx0f(x)，若a0a2a22x2a10，則有兩個不同的實根（ⅲ）若，即或2aa2aa222x1，x．2222xxaf(x)f(x)有f(x)當(dāng)a當(dāng)a而122xaxaf(x)f(x)，，在12(x)xxxxf在12(x)(∞)．faf(x)1ef(x)f(x)xa)xxa)xa112．21222212122P（Ⅰ）證明：連結(jié)OP，OM．AAP與OP．OM是O180°．M．BCO在PAC，，，M，，，M．AP．O在PACAPM90°．APM90°．xcos4cosyx，為得2．y4xx22．y4x0O1即x22y4y0為Ox2224，2xyxx1x222．yy2y4y0x2212O，O(0yx．即和12yy2x1