新高考數(shù)學二輪復習重難點突破專題39 利用項的系數(shù)求參數(shù)(原卷版)

專題39利用項的系數(shù)求參數(shù)一、單選題1．在SKIPIF1<0的展開式中，若含SKIPIF1<0項的系數(shù)為SKIPIF1<0，則正實數(shù)SKIPIF1<0（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．設(shè)常數(shù)SKIPIF1<0.若SKIPIF1<0的二項展開式中SKIPIF1<0項的系數(shù)為－15，則SKIPIF1<0（）A．－2 B．2 C．3 D．－33．SKIPIF1<0展開式中x的系數(shù)為80，則a等于（）A．-3 B．3 C．-2 D．24．SKIPIF1<0的展開式中SKIPIF1<0項的系數(shù)為4，則SKIPIF1<0（）A．0 B．2 C．SKIPIF1<0 D．-25．SKIPIF1<0的展開式的常數(shù)項為SKIPIF1<0，則實數(shù)SKIPIF1<0（）A．2 B．-2 C．1 D．-16．二項式SKIPIF1<0的展開式中SKIPIF1<0的系數(shù)是SKIPIF1<0，則SKIPIF1<0（）A．1 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<07．已知二項式SKIPIF1<0的展開式的第二項的系數(shù)為SKIPIF1<0，則SKIPIF1<0（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0或SKIPIF1<0 D．SKIPIF1<0或SKIPIF1<08．已知SKIPIF1<0的展開式中SKIPIF1<0的系數(shù)為SKIPIF1<0，則SKIPIF1<0（）A．1 B．2 C．3 D．49．使得SKIPIF1<0的展開式中含有常數(shù)項的最小的n為()A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<010．若SKIPIF1<0，則SKIPIF1<0（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<011．若SKIPIF1<0的展開式中SKIPIF1<0的系數(shù)之和為SKIPIF1<0，則實數(shù)SKIPIF1<0的值為（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．112．已知SKIPIF1<0的展開式中SKIPIF1<0的系數(shù)為15，則SKIPIF1<0（）A．SKIPIF1<0 B．1 C．1或SKIPIF1<0 D．SKIPIF1<0或SKIPIF1<013．SKIPIF1<0的展開式中，SKIPIF1<0的系數(shù)是20，則SKIPIF1<0（）A．2 B．SKIPIF1<0 C．4 D．114．已知SKIPIF1<0的展開式中所有項的系數(shù)和為SKIPIF1<0，則展開式中的常數(shù)項為（）A．80 B．SKIPIF1<0 C．40 D．SKIPIF1<015．已知SKIPIF1<0展開式中含SKIPIF1<0項的系數(shù)為SKIPIF1<0，則正實數(shù)SKIPIF1<0的值為（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<016．SKIPIF1<0的展開式中的常數(shù)項為14，則正整數(shù)SKIPIF1<0的值為（）A．4 B．5 C．6 D．7二、多選題17．若SKIPIF1<0的展開式中SKIPIF1<0的系數(shù)是SKIPIF1<0，則（）A．SKIPIF1<0 B．所有項系數(shù)之和為1C．二項式系數(shù)之和為SKIPIF1<0 D．常數(shù)項為SKIPIF1<018．已知SKIPIF1<0的展開式中各項系數(shù)的和為2，則下列結(jié)論正確的有（）A．SKIPIF1<0B．展開式中常數(shù)項為160C．展開式系數(shù)的絕對值的和1458D．若SKIPIF1<0為偶數(shù)，則展開式中SKIPIF1<0和SKIPIF1<0的系數(shù)相等19．已知SKIPIF1<0的展開式中，SKIPIF1<0的系數(shù)為56，則實數(shù)SKIPIF1<0的取值可能為（）A．-1 B．4 C．5 D．6三、填空題20．SKIPIF1<0的展開式中SKIPIF1<0的系數(shù)為4，則SKIPIF1<0的展開式中常數(shù)為______．21．若對任意SKIPIF1<0，都有SKIPIF1<0，（SKIPIF1<0為正整數(shù)），則SKIPIF1<0的值等于_______.22．已知SKIPIF1<0，若SKIPIF1<0，則實數(shù)m＝________.23．若在SKIPIF1<0關(guān)于SKIPIF1<0的展開式中，常數(shù)項為4，則SKIPIF1<0的系數(shù)是______________．24．若SKIPIF1<0的展開式的常數(shù)項為60，則SKIPIF1<0_________.25．SKIPIF1<0展開式中的常數(shù)項為180，則SKIPIF1<0_________________.26．已知SKIPIF1<0的展開式中常數(shù)項為SKIPIF1<0，則實數(shù)SKIPIF1<0_______.27．已知SKIPIF1<0的展開式中SKIPIF1<0的系數(shù)為30，則SKIPIF1<0為______.28．若SKIPIF1<0的展開式中的常數(shù)項為60，則a的值為______.29．設(shè)二項式SKIPIF1<0的展開式中SKIPIF1<0的系數(shù)為SKIPIF1<0，常數(shù)項為SKIPIF1<0，若SKIPIF1<0，則SKIPIF1<0的值是______.30．已知關(guān)于SKIPIF1<0的方程SKIPIF1<0的實數(shù)根的個數(shù)為SKIPIF1<0，若SKIPIF1<0SKIPIF1<0，則SKIPIF1<0的值為______.31．SKIPIF1<0的展開式中含SKIPIF1<0的項的系數(shù)為8，則SKIPIF1<0__________.32．若SKIPIF1<0的展開式中SKIPIF1<0的系數(shù)為20，則SKIPIF1<0的值為______.33．已知SKIPIF1<0的展開式中第SKIPIF1<0項為常數(shù)項，則該式中所有項系數(shù)的和為__________.四、雙空題34．在SKIPIF1<0的展開式中，若a＝2，則x項的系數(shù)為________；若所有項的系數(shù)之和為－32，則實數(shù)a的值為________.35．已知二項式SKIPIF1<0的各項系數(shù)和為243，則SKIPIF1<0___________，展開式中常數(shù)項為___________.36．早在11世紀中葉，我國宋代數(shù)學家賈憲在其著作《釋鎖算數(shù)》中就給出了二、三、四、五、六次冪的二項式系數(shù)表．已知SKIPIF1<0的展開式中SKIPIF1<0的系數(shù)為SKIPIF1<0，則實數(shù)SKIPIF1<0________；展開式中各項系數(shù)之和為________．（用數(shù)字作答）37．已知SKIPIF1<0展開式的前三項系數(shù)成等差數(shù)列，則SKIPIF1<0______，其展開式中的有理項依次為______．五、解答題38．已知SKIPIF1<0的展開式中第5項的系數(shù)與第3項系數(shù)之比為SKIPIF1<0，（1）求展開式中的常數(shù)項；（2）求展開式中系數(shù)最大的項.39．已知SKIPIF1<0中，且SKIPIF1<0.（1）求m的值；（2）求SKIPIF1<0的值.40．已知二項式SKIPIF1<0．（1）若該二項式的展開式中前三項的系數(shù)成等差數(shù)列，求正整數(shù)n的值；（2）在（1）的條件下，求展開式中SKIPIF1<0項的系數(shù)．41．在SKIPIF1<0的展開式中，前3項的系數(shù)的和為73.（1）求SKIPIF1<0的值及展開式中二項式系數(shù)最大的項；（2）求展開式中的有理項.42．已知SKIPIF1<0的展開式中，第4項的系數(shù)與第5項的系數(shù)之比為SKIPIF1<0.（1）求n值；（2）求展開式中的常數(shù)項.43．已知二項式SKIPIF1<0（1）求二項式展開式中各項系數(shù)之和；（2）若二項式展開式中第9項，第10項，第11項的二項式系數(shù)成等差數(shù)列，求n的值；（3）在SKIPIF1<0的條件下寫出它展開式中的有理項.44．已知SKIPIF1<0（SKIPIF1<0，SKIPIF1<0