計算機等級考試三級PC技術(shù)上機20

1、2013年計算機等級考試三級pc技術(shù)上機（20）請編制程序，其功能是：有一抄表系統(tǒng)采集的數(shù)據(jù)中包括8位的竊水狀態(tài)字節(jié)(一個字節(jié)記錄4塊水表狀態(tài))，格式為：d7 d6 d5 d4 d3 d2 d1 d0s4 s3 s2 s1 x4 x3 x2 x1其中si，xi(i=1,2,3,4)分別表示第i塊水表短路和斷路狀態(tài)位，1表示有短路或斷路情況發(fā)生(表示有偷水情況)，現(xiàn)共采集了5個字節(jié)的竊水狀態(tài)，如果有竊水情況，則記錄在result中，記錄格式為：表號，狀態(tài)，表號，狀態(tài)沒有短斷路，則記錄e0h，斷路記錄e1h，短路記錄e2h，如01h,e1h,02h,e0h,03h,e2h,04h,e0h表示第一塊

2、表斷路，第二塊表無竊水狀態(tài)，第三塊表短路，第四塊表也無竊水發(fā)生。例如：內(nèi)存中有： 83h結(jié)果為： 01h,e1h,02h,e1h,03h,e0h,04h,e2h該內(nèi)存中從source開始有一字符串，其以00h結(jié)束，長度不超過100。試編程對其進行壓縮，結(jié)果存入result開始的內(nèi)存單元。部分程序已給出, 其中原始數(shù)據(jù)由過程load從文件input1.dat中讀入source開始的內(nèi)存單元中。運算結(jié)果要求從result開始存放,由過程save保存到文件output1.dat中。填空begin和end之間已給出的一段源程序使其完整(空白已用橫線標(biāo)出,每行空白一般只需一條指令, 但采用功能相當(dāng)?shù)亩鄺l

3、指令亦可),或刪除begin和end之間原有的代碼并自行編程來完成要求的功能。對程序必須進行匯編,并與io.obj鏈接產(chǎn)生prog1.exe執(zhí)行文件,最終運行程序產(chǎn)生結(jié)果(無結(jié)果或結(jié)果不正確者均不得分)。調(diào)試中若發(fā)現(xiàn)整個程序中存在錯誤之處, 請加以修改。試題程序：extrn load:far,save:farn equ 5esc_code equ 27stac segment stackdb 128 dup(?)stac endsdata segmentsource db n dup(?)result db n*8 dup(0)name0 db input1.dat,0name1 db out

4、put1.dat,0data endscode segmentassume cs:code,ds:data,ss:stacstart proc farpush dsxor ax,axpush axmov ax,datamov ds,axmov es,ax ;置附加段寄存器lea dx,source ;數(shù)據(jù)區(qū)起始地址lea si,name0 ;原始數(shù)據(jù)文件名mov cx,n ;字節(jié)數(shù)call load ;從input1.dat中讀取數(shù)據(jù);*begin*lea si,sourcemov di,offset resultmov dh,nlpm: mov al,simov bl,alinc simov

5、 cl,_shr bl,clmov cx,4mov bh,0lp0: shr al,1 ;bh放水表號inc bhmov di,bh_jc lp1shr bl,1jc lp2mov dl,0e0hjmp lpcomlplp: loop _jmp ret1lp1: shr bl,1mov dl,_jmp lpcomlp2: mov dl,0e2hlpcom: mov di,dl_jmp lplpret1: dec dh_ lpm;*end*lea dx,result ;結(jié)果數(shù)據(jù)區(qū)首址lea si,name1 ;結(jié)果文件名mov cx,n*2 ;字節(jié)數(shù)call save ;保存結(jié)果到文件retst

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