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1、Geometry Practice Questions1. In a 30-60-90 triangle, the length of the hypotenuse is 6. What is the length of the shortest sidea.2b. 3c.邛d.邛2. What is the area of a circle with a diameter of 16a.Sib. 16- c. 64A d. 128He. 25613. The figure below contains only horizontal and vertical lines. Calculate

2、 its perimetera. 540° b. 720 °c. 810 0d. 1080 ° e. 1440 °a. 27 b. 33 c. 36 d. 42 e . 484. Find the measure of the missing angle in the triangle below.a. 35° b. 40 0 c. 45 0 d. 50 0 e. 55 05. The circumference of a circle is 3 What is its areaa. 15伉b. 225-c. 40(T d. 90( e. 30

3、0(6. What is the sum of the measures of the interior angles of a hexagon7. Find the area of the triangle below.Therefore, the missing angle is 50.o9. Which of the following could be the side lengths of a right trianglea. 3, 13, and 14 b. 4, 5, and 6 c. 4, 9, and 10b. 5, 10, and 15 e. 5, 12, and 1310

4、. The figure below is an equilateral triangle with sides of length 6. What isthe area of the triangleBXCa. 12b. 18c. 36 d. 9石 eAnswer Key1.a 30-60-90 triangle, the ratio of the lengths of the sides isother words,the length of the longer leg isrimes the length of the shorter leg, and thehypotenuse is

5、 twice the length of the shorter leg. Therefore, the smallest side is half the length of the hypotenuse, so its length is2. area of a circle is given by the formulaA?2?-2, where ris the radius of the circle. The problem provides the diameter of the circle,which is twice the radius. So,Now substitute

6、 this value into the area formula and calculate the area.A =邂):=64 優(yōu)3. perimeter of a figure is the length around it. To find the perimeter of a polygon, add the lengths of its sides Start by filling in the missing lengths of the sides. For instance, the length of the shorter missing side is 6 becau

7、se if you add it to the 3 on the left, the result should be the 9 on the right.3963Finally, add the side lengths together to find the perimeter.12 + 3+9 + 9 + 6 + 3 二 424. sum of the angles of a triangle is 180. Therefore, °if we subtract the two given angles from 180 , the °result will be

8、 the missing angle.180 95 35 = 505. circumference of a circle is given by the formulaC= 2 箱whereris the radius of the circle. Substitute the given circumference into this formula and solve forr.30=加r= 15Therefore, the radius of the circle is 15. Use this to find the area of the cii*cle. The area of

9、a circle is given by the formulaA . Substitute the length of the radius into this formula and calculate the area.A氓 15)2二 225兀6. sum of the measures of the interior angles of a polygon withnsides is 180 (n- 2) A hexagon has six sides. Therefore, substitute 6 forninto the formula and calculate.180 (6

10、 -2) = 180 (4)=720Therefore, the sum of the measures is 720.=丄bh7.area of a triangle is given by the formula、where bis the length of the5.base andhis the triangle ' s height. In the figure, the base is 8 and the height is Substitute these values into the formula and calculate the area.8. a para

11、lie logram, adjacent angles are complimentary; that is, they add to 180.Use this to set up an equation, and then solve it forx.+ 12) + (3% + 14) = 1807x + 26 = 1807x = 154= 229. E. If a triangle is a right triangle, then the lengths of its sides satisfy the2 2 2Pythagorean Theorem,a +b二c To determin

12、e which choice is correct, test each set of values by substituting them into the Pythagorean Theorem. S tart with the first set of numbers: 3, 13, and 14.齊1亍=19+169=196178=196Since the result is not a true equality, the frst set of values does not represent the side lengths of a right triangle Test

13、the other four choices The only values that satisfy the Pythagorean Theorem are 5, 12, and 13.5a+123=Ba25 + 144 = 169169 =16910. the triangle is an equilateral triangle, its angles are 60. In addition, the vertical0 lineAXbisects the angleBAC, so it splits it into two congruent angles of 30 each Therefore, the two smaller triangles are 30-60-90 triangles Thus, the ra tio of the lengths of the sides isUse this to fill in the information of the figure asfollows.B 3 X 3 CH = 2 bhThe ar

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