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3.6零點(diǎn)定理(精講)(提升版)思維導(dǎo)圖思維導(dǎo)圖考點(diǎn)呈現(xiàn)考點(diǎn)呈現(xiàn)例題剖析例題剖析考點(diǎn)一零點(diǎn)的區(qū)間【例1】(2022·河南開封·)函數(shù)SKIPIF1<0的一個(gè)零點(diǎn)所在的區(qū)間是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【一隅三反】1.(2022·湖南)函數(shù)SKIPIF1<0的零點(diǎn)所在區(qū)間是(
)A.SKIPIF1<0B.SKIPIF1<0C.SKIPIF1<0D.SKIPIF1<02.(2022·四川攀枝花)已知函數(shù)SKIPIF1<0的零點(diǎn)在區(qū)間SKIPIF1<0上,則SKIPIF1<0(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<03.(2022·云南德宏)方程SKIPIF1<0的解所在的區(qū)間為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0考點(diǎn)二零點(diǎn)的個(gè)數(shù)【例2-1】(2022·陜西)函數(shù)SKIPIF1<0的零點(diǎn)個(gè)數(shù)為(
)A.0 B.1 C.2 D.3【例2-2】(2022·山西)已知SKIPIF1<0若SKIPIF1<0,則SKIPIF1<0在SKIPIF1<0內(nèi)的零點(diǎn)個(gè)數(shù)為(
)A.8 B.9 C.10 D.11【一隅三反】1.(2022·安徽)已知函數(shù)SKIPIF1<0則方程SKIPIF1<0的解的個(gè)數(shù)是(
)A.0 B.1 C.2 D.32.(2022·全國·高三專題練習(xí))函數(shù)SKIPIF1<0的圖像與函數(shù)SKIPIF1<0的圖像的交點(diǎn)個(gè)數(shù)為(
)A.2 B.3 C.4 D.03.(2022·海南?。┰O(shè)函數(shù)SKIPIF1<0定義域?yàn)镽,SKIPIF1<0為奇函數(shù),SKIPIF1<0為偶函數(shù),當(dāng)SKIPIF1<0時(shí),SKIPIF1<0,則函數(shù)SKIPIF1<0有(
)個(gè)零點(diǎn)A.4 B.5 C.6 D.7考點(diǎn)三比較零點(diǎn)的大小【例3】(2022·安徽)已知函數(shù)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的零點(diǎn)分別為a,b,c則a,b,c的大小順序?yàn)椋?/p>
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【一隅三反】1.(2022·河南)若實(shí)數(shù)SKIPIF1<0滿足SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<02.(2022·安徽)已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<03.(2022·山西)正實(shí)數(shù)SKIPIF1<0滿足SKIPIF1<0,則實(shí)數(shù)SKIPIF1<0之間的大小關(guān)系為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0考點(diǎn)四已知零點(diǎn)求參數(shù)【例4-1】(2022·山東濰坊)已知函數(shù)SKIPIF1<0的圖像與直線SKIPIF1<0有3個(gè)不同的交點(diǎn),則實(shí)數(shù)m的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【例4-2】(2022·吉林)已知SKIPIF1<0若關(guān)于x的方程SKIPIF1<0有3個(gè)不同實(shí)根,則實(shí)數(shù)SKIPIF1<0取值范圍為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【例4-3】(2022·安徽·合肥市)已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上有且僅有4個(gè)零點(diǎn),則SKIPIF1<0的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【一隅三反】1.(2022·全國·高三專題練習(xí))已知函數(shù)SKIPIF1<0若關(guān)于x的方程SKIPIF1<0恰有三個(gè)不相等的實(shí)數(shù)解,則m的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<02.(2022·河南·模擬預(yù)測(cè)(理))已知函數(shù)SKIPIF1<0為定義在SKIPIF1<0上的單調(diào)函數(shù),且SKIPIF1<0.若函數(shù)SKIPIF1<0有3個(gè)零點(diǎn),則SKIPIF1<0的取值范圍為(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<03.(2022·廣西·貴港市高級(jí)中學(xué)三模)已知SKIPIF1<0在SKIPIF1<0有且僅有6個(gè)實(shí)數(shù)根,則實(shí)數(shù)SKIPIF1<0的取值范圍為(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<04.(2022·山西)已知函數(shù)SKIPIF1<0,若函數(shù)SKIPIF1<0恰好有兩個(gè)零點(diǎn),則實(shí)數(shù)k的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0考點(diǎn)五零點(diǎn)的綜合運(yùn)用【例5-1】(2022·新疆克拉瑪依)函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的所有零點(diǎn)之和為(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【例5-2】(2022·甘肅)若函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上有2個(gè)零點(diǎn)SKIPIF1<0,則SKIPIF1<0的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【例5-3】(2022·全國·高三專題練習(xí))已知函數(shù)SKIPIF1<0的零點(diǎn)為SKIPIF1<0,函數(shù)SKIPIF1<0的零點(diǎn)為SKIPIF1<0,則下列不等式中成立的是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【一隅三反】1.(2022·安徽·合肥一六八中學(xué))若SKIPIF1<0為奇函數(shù),且SKIPIF1<0是SKIPIF1<0的一個(gè)零點(diǎn),則SKIPIF1<0一定是下列哪個(gè)函數(shù)的零點(diǎn)(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.(2022·陜西·模擬預(yù)測(cè)(理))已知SKIPIF1<0是方程SKIPIF1<0的根,SKIPIF1<0是方程SKIPIF1<0的根,則SKIPIF1<0的值為(
)A.2 B.3 C.6 D.103.(2022·陜西·西安中學(xué)一模(理))函數(shù)SKIPIF1<0的所有零點(diǎn)之和為_________.3.6零點(diǎn)定理(精練)(提升版)題組一題組一零點(diǎn)的區(qū)間1.(2022·甘肅·天水市第一中學(xué))函數(shù)SKIPIF1<0的零點(diǎn)所在的區(qū)間是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02(2022·江蘇揚(yáng)州)函數(shù)SKIPIF1<0的零點(diǎn)所在的區(qū)間為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<03.(2022·天津紅橋·一模)函數(shù)SKIPIF1<0的零點(diǎn)所在的區(qū)間是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<04.(2022·廣東中山)函數(shù)SKIPIF1<0的零點(diǎn)所在的區(qū)間為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<05.(2022·北京師大附中)函數(shù)SKIPIF1<0的零點(diǎn)所在的區(qū)間是(
)A.(0,1) B.(1,2) C.(2,3) D.(3,4)6.(2022·云南玉溪·高一期末)函數(shù)SKIPIF1<0的零點(diǎn)所在的區(qū)間為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<07.(2022·寧夏·青銅峽市寧朔中學(xué)高二學(xué)業(yè)考試)函數(shù)SKIPIF1<0的零點(diǎn)所在的區(qū)間是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<08.(2022·新疆維吾爾自治區(qū)喀什第二中學(xué))函數(shù)SKIPIF1<0的零點(diǎn)所在區(qū)間為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<09.(2022·海南·嘉積中學(xué)高一期末)SKIPIF1<0零點(diǎn)所在的區(qū)間是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<010.(2022·四川·德陽五中)函數(shù)SKIPIF1<0的零點(diǎn)所在的區(qū)間是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<011.(2022·安徽·池州市第一中學(xué))函數(shù)SKIPIF1<0的零點(diǎn)所在的一個(gè)區(qū)間是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<012.(2022·廣東汕尾)函數(shù)SKIPIF1<0的零點(diǎn)所在區(qū)間為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0題組二題組二零點(diǎn)的個(gè)數(shù)1.(2022·四川省瀘縣第二中學(xué))函數(shù)SKIPIF1<0的零點(diǎn)的個(gè)數(shù)為(
)A.0 B.1 C.2 D.32.(2022·重慶)函數(shù)SKIPIF1<0的零點(diǎn)個(gè)數(shù)為(
)A.1 B.2 C.3 D.43.(2022·重慶·三模)已知函數(shù)SKIPIF1<0則函數(shù)SKIPIF1<0的零點(diǎn)個(gè)數(shù)為(
)A.0個(gè) B.1個(gè) C.2個(gè) D.3個(gè)4.(2022·新疆·三模(理))函數(shù)SKIPIF1<0的零點(diǎn)個(gè)數(shù)為___________.5.(2022·新疆)函數(shù)SKIPIF1<0的零點(diǎn)個(gè)數(shù)為_________.題組三題組三比較零點(diǎn)的大小1.(2022·山西·二模(理))已知SKIPIF1<0是SKIPIF1<0的一個(gè)零點(diǎn),SKIPIF1<0是SKIPIF1<0的一個(gè)零點(diǎn),SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0或SKIPIF1<02.(2022·湖南·益陽市箴言中學(xué))已知三個(gè)函數(shù)SKIPIF1<0的零點(diǎn)依次為SKIPIF1<0,則SKIPIF1<0的大小關(guān)系(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<03.(2022·陜西·長安一中模擬預(yù)測(cè))已知函數(shù)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的零點(diǎn)分別為SKIPIF1<0、SKIPIF1<0、SKIPIF1<0,則SKIPIF1<0、SKIPIF1<0、SKIPIF1<0的大小順序?yàn)椋?/p>
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<04.(2022·安徽·蚌埠二中模擬預(yù)測(cè)(文))已知SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<05.(2022·河南河南·三模)若實(shí)數(shù)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0滿足SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0題組四題組四已知零點(diǎn)求參數(shù)1.(2022·湖北宜昌)函數(shù)SKIPIF1<0,若函數(shù)SKIPIF1<0有兩個(gè)零點(diǎn),則實(shí)數(shù)SKIPIF1<0的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<02.(2022·首都師范大學(xué)附屬中學(xué))已知函數(shù)SKIPIF1<0,若SKIPIF1<0有三個(gè)不同的零點(diǎn),則實(shí)數(shù)k的取值范圍為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<03.(2022·河北唐山)已知函數(shù)SKIPIF1<0,若SKIPIF1<0有3個(gè)零點(diǎn),則a的取值范圍為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<04.(2022·安徽)已知函數(shù)SKIPIF1<0在(0,+∞)上有3個(gè)不同的零點(diǎn),則實(shí)數(shù)SKIPIF1<0的取值范圍是()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<05.(2022·江蘇泰州·模擬預(yù)測(cè))已知定義在R上的奇函數(shù)SKIPIF1<0滿足SKIPIF1<0,已知當(dāng)SKIPIF1<0時(shí),SKIPIF1<0,若SKIPIF1<0恰有六個(gè)不相等的零點(diǎn),則實(shí)數(shù)m的取值范圍為(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<06.(2022·內(nèi)蒙古·滿洲里市教研培訓(xùn)中心三模(文))已知函數(shù)SKIPIF1<0有唯一零點(diǎn),則SKIPIF1<0(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<07.(2022·全國·高三專題練習(xí))已知SKIPIF1<0是以2為周期的偶函數(shù),當(dāng)SKIPIF1<0時(shí),SKIPIF1<0,那么在區(qū)間SKIPIF1<0內(nèi),關(guān)于x的方程SKIPIF1<0(SKIPIF1<0且SKIPIF1<0)有4個(gè)根,則k的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<08.(2022·全國·高三專題練習(xí))已知函數(shù)SKIPIF1<0與函數(shù)SKIPIF1<0的圖象有兩個(gè)不同的交點(diǎn),則實(shí)數(shù)m取值范圍為(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<09.(2022·天津·南開中學(xué)模擬預(yù)測(cè))已知函數(shù)SKIPIF1<0,若函數(shù)SKIPIF1<0恰有兩個(gè)零點(diǎn)則實(shí)數(shù)SKIPIF1<0的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<010.(2022·天津南開·二模)已知定義在SKIPIF1<0上的函數(shù)SKIPIF1<0若函數(shù)SKIPIF1<0恰有2個(gè)零點(diǎn),則實(shí)數(shù)SKIPIF1<0的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<011.(2022·陜西·模擬預(yù)測(cè)(理))已知函數(shù)SKIPIF1<0SKIPIF1<0在SKIPIF1<0上有且只有5個(gè)零點(diǎn),則實(shí)數(shù)SKIPIF1<0的范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<012.(2022·陜西寶雞·二模(文))已知函數(shù)SKIPIF1<0(SKIPIF1<0是自然對(duì)數(shù)的底數(shù))在定義域SKIPIF1<0上有三個(gè)零點(diǎn),則實(shí)數(shù)SKIPIF1<0的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<013.(2022·全國·高三專題練習(xí))已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上既有極大值又有極小值,則實(shí)數(shù)a的取值范圍是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<014.(2022·河南·模擬預(yù)測(cè)(理))已知函數(shù)SKIPIF1<0至多有2個(gè)不同的零點(diǎn),則實(shí)數(shù)a的最大值為(
).A.0 B.1 C.2 D.e15(2022·天津市武清區(qū)楊村第一中學(xué)二模)設(shè)SKIPIF1<0,函數(shù)SKIPIF1<0.若SKIPIF1<0在SKIPIF1<0上單調(diào)遞增,且函數(shù)SKIPIF1<0與SKIPIF1<0的圖象有三個(gè)交點(diǎn),則SKIPIF1<0的取值范圍是(
)A.SKIPIF1<0 B.
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