系統(tǒng)工程解析結(jié)構(gòu)模型解決電腦選購(gòu)問(wèn)題

1、高校生選購(gòu)電腦 說(shuō)明結(jié)構(gòu)模型和層次分析法的運(yùn)用規(guī)范分析說(shuō)明結(jié)構(gòu)模型1、 要素分析找到系統(tǒng)構(gòu)件電腦的價(jià)格電腦的性能操作電腦的壽命電腦的攜帶電腦的平安性電腦的體積電腦的消遣性售后的修理便利依據(jù)上述要素，假設(shè)電腦購(gòu)買(mǎi)系統(tǒng)中共9個(gè)要素，其集合為S，則要素組成的集合S=S1,S2,S3,S4,S5,S6,S7,S8,S9。2、要素之間的關(guān)聯(lián)有向圖表達(dá)3128657943、要素結(jié)構(gòu)的矩陣表達(dá)鄰接矩陣：依據(jù)系統(tǒng)各要素之間的相關(guān)關(guān)系，可得到鄰接矩陣如下： S1 S2 S3 S4 S5 S6 S7 S8 S9 S1 0 1 0 0 0 0 0 0 0 S2 0 0 1 0 0 0 0 1 0 S3 0 0 0

2、0 0 0 0 1 0 S4 0 0 0 0 0 0 0 0 1 A= S5 0 0 0 0 0 1 0 0 0 S6 0 0 0 0 0 0 0 0 0 S7 0 0 0 0 1 0 0 0 0 S8 0 0 0 0 0 0 0 0 0 S9 0 0 0 1 0 0 1 0 0可達(dá)矩陣：依據(jù)公式M=(A+I)r 得到可達(dá)矩陣M S1 S2 S3 S4 S5 S6 S7 S8 S9 S1 1 1 0 0 0 0 0 0 0 S2 0 1 1 0 0 0 0 1 0 S3 0 0 1 0 0 0 0 1 0 S4 0 0 0 1 0 0 0 0 1 A+I= S5 0 0 0 0 1 1 0 0

3、 0 S6 0 0 0 0 0 1 0 0 0 S7 0 0 0 0 1 0 1 0 0 S8 0 0 0 0 0 0 0 1 0 S9 0 0 0 1 0 0 1 0 1 S1 S2 S3 S4 S5 S6 S7 S8 S9 S1 1 1 1 0 0 0 0 1 0 S2 0 1 1 0 0 0 0 1 0 S3 0 0 1 0 0 0 0 1 0 S4 0 0 0 1 0 0 1 0 1 （A+I）2 = S5 0 0 0 0 1 1 0 0 0 S6 0 0 0 0 0 1 0 0 0 S7 0 0 0 0 1 1 1 0 0 S8 0 0 0 0 0 0 0 1 0 S9 0 0 0

4、1 1 0 1 0 1 S1 S2 S3 S4 S5 S6 S7 S8 S9 S1 1 1 1 0 0 0 0 1 0 S2 0 1 1 0 0 0 0 1 0 S3 0 0 1 0 0 0 0 1 0 S4 0 0 0 1 0 0 1 0 1 （A+I）3= S5 0 0 0 0 1 1 0 0 0 S6 0 0 0 0 0 1 0 0 0 S7 0 0 0 0 1 1 1 0 0 S8 0 0 0 0 0 0 0 1 0 S9 0 0 0 1 1 1 1 0 1 S1 S2 S3 S4 S5 S6 S7 S8 S9 S1 1 1 1 0 0 0 0 1 0 S2 0 1 1 0 0 0 0

5、 1 0 S3 0 0 1 0 0 0 0 1 0 S4 0 0 0 1 0 0 1 0 1 （A+I）4 = S5 0 0 0 0 1 1 0 0 0 S6 0 0 0 0 0 1 0 0 0 S7 0 0 0 0 1 1 1 0 0 S8 0 0 0 0 0 0 0 1 0 S9 0 0 0 1 1 1 1 0 1所以，r=34、區(qū)域劃分SiR(Si)A(Si)C(Si)B(S)11，2，3，811122,3,81,2233,81,2,3,9344，5，6，7，944455,64,5,7,95664,5,6,7,9675,6,74,7,97881,2,3,8195,6,7,94,99 S1

6、 S2 S3 S8 S4 S5 S6 S7 S9 S1 1 1 1 1 S2 0 1 1 1 S3 0 0 1 1 S8 1 0 0 0 M(P)= S4 1 1 1 1 1 S5 0 1 1 0 0 S6 0 0 1 0 0 S7 0 1 1 1 0 S9 0 1 1 1 15、級(jí)位劃分要素集合SiR(Si)A(Si)C(Si)C(Si)=R(Si)(P1)P1-L011,2,3,811L1=S822,3,81,2233,81,2,3,93881,2,3,88P1-L0-L111,2,311L2=S322,31,22331,2,93P1-L0-L1-L211,211L3=S2221,22P1

7、-L0-L1-L2-L31111L4=S1對(duì)該區(qū)域進(jìn)行位級(jí)劃分的結(jié)果為(P1)=S8,S3,S2,S1要素集合SiR(Si)A(Si)C(Si)C(Si)=R(Si)(P2)P1-L044,5,6,7,944L1=S655,65,7,95665,6,7,9675,6,77,9795,6,7,999P1-L0-L144,5,7,944L2=S5555，7，9575,74,7,9795,7,999P0-L0-L1-L244,7,944L3=S7777,979999P0-L0-L1-L2-L344,944L4=S4,S99999對(duì)該區(qū)域進(jìn)行位級(jí)劃分的結(jié)果為(P2)=S6,S5,S7,S9,S46、提

8、取骨架 S8 S3 S2 S1 S6 S5 S7 S9 S4 S8 1 0 0 0 S3 1 1 0 0 S2 1 1 1 0 S1 1 1 1 1 M(L)= S6 1 0 0 0 0 S5 1 1 0 0 0 S7 1 1 1 0 0 S9 1 1 1 1 1 S4 1 1 1 1 1 S8 S3 S2 S1 S6 S5 S7 S9 S8 0 0 0 0 S3 1 0 0 0 S2 1 1 0 0 S1 0 1 1 0 M(L)= S6 0 0 0 0 S5 1 0 0 0 S7 1 1 0 0 S9 0 1 1 0 831265794A、合理選購(gòu)電腦樣式B1、價(jià)格B2、性能B3、體積B4

9、、修理便利C1、筆記本C2、臺(tái)式電腦購(gòu)機(jī)評(píng)價(jià)體系中各要素的推斷矩陣及其有關(guān)分析計(jì)算表AB1B2B3B4WiWi0miB111351.9680.3824.402B211552.2360.4434.068B31/31/5110.5080.0984.067B41/51/5110.4470.0874 (5.159)max4.032 CI=0.011 RL=0.89 CR=0.0120.1B1C1C2WiWi0miC1131.7320.752C21/310.5770.252 (2.309)max2 CI=0 CR=00.1B2C1C2WiWi0miC111/30.5770.252C2311.7320.752 (2.309)max2 CI=0 CR=00.1B3C1C2WiWi0miC1152.2360.8332.002C21/510.4470.1671.998 (2.683)max2 CI=0 CR=00.1B4C1C2WiWi0miC111/50.4470.1671.998C2512.2360.