新高考數(shù)學(xué)一輪復(fù)習(xí) 導(dǎo)數(shù)專項(xiàng)重點(diǎn)難點(diǎn)突破專題11 利用導(dǎo)數(shù)證明不等式(原卷版)_第1頁
新高考數(shù)學(xué)一輪復(fù)習(xí) 導(dǎo)數(shù)專項(xiàng)重點(diǎn)難點(diǎn)突破專題11 利用導(dǎo)數(shù)證明不等式(原卷版)_第2頁
新高考數(shù)學(xué)一輪復(fù)習(xí) 導(dǎo)數(shù)專項(xiàng)重點(diǎn)難點(diǎn)突破專題11 利用導(dǎo)數(shù)證明不等式(原卷版)_第3頁
新高考數(shù)學(xué)一輪復(fù)習(xí) 導(dǎo)數(shù)專項(xiàng)重點(diǎn)難點(diǎn)突破專題11 利用導(dǎo)數(shù)證明不等式(原卷版)_第4頁
新高考數(shù)學(xué)一輪復(fù)習(xí) 導(dǎo)數(shù)專項(xiàng)重點(diǎn)難點(diǎn)突破專題11 利用導(dǎo)數(shù)證明不等式(原卷版)_第5頁
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專題11利用導(dǎo)數(shù)證明不等式考點(diǎn)一單變量不等式的證明1.待證不等式的兩邊含有同一個(gè)變量時(shí),一般地,可以直接構(gòu)造“左減右”的函數(shù),利用導(dǎo)數(shù)研究其單調(diào)性,借助所構(gòu)造函數(shù)的單調(diào)性即可得證.2.若直接求導(dǎo)比較復(fù)雜或無從下手時(shí),可將待證式進(jìn)行變形,構(gòu)造兩個(gè)都便于求導(dǎo)的函數(shù),從而找到可以傳遞的中間量,達(dá)到證明的目標(biāo).3.導(dǎo)數(shù)的綜合應(yīng)用題中,最常見就是ex和lnx與其他代數(shù)式結(jié)合的難題,對(duì)于這類問題,可以先對(duì)ex和lnx進(jìn)行放縮,使問題簡化,便于化簡或判斷導(dǎo)數(shù)的正負(fù).常見的放縮公式如下:(1)ex≥1+x,當(dāng)且僅當(dāng)x=0時(shí)取等號(hào);(2)ex≥ex,當(dāng)且僅當(dāng)x=1時(shí)取等號(hào);(3)當(dāng)x≥0時(shí),ex≥1+x+eq\f(1,2)x2,當(dāng)且僅當(dāng)x=0時(shí)取等號(hào);(4)當(dāng)x≥0時(shí),ex≥eq\f(e,2)x2+1,當(dāng)且僅當(dāng)x=0時(shí)取等號(hào);(5)eq\f(x-1,x)≤lnx≤x-1≤x2-x,當(dāng)且僅當(dāng)x=1時(shí)取等號(hào);(6)當(dāng)x≥1時(shí),eq\f(2x-1,x+1)≤lnx≤eq\f(x-1,\r(x)),當(dāng)且僅當(dāng)x=1時(shí)取等號(hào).考點(diǎn)二雙變量不等式的證明破解含雙參不等式的證明的關(guān)鍵一是轉(zhuǎn)化,即由已知條件入手,尋找雙參所滿足的關(guān)系式,并把含雙參的不等式轉(zhuǎn)化為含單參的不等式;二是巧構(gòu)造函數(shù),再借用導(dǎo)數(shù),判斷函數(shù)的單調(diào)性,從而求其最值;三是回歸雙參的不等式的證明,把所求的最值應(yīng)用到雙參不等式,即可證得結(jié)果.考點(diǎn)三證明與數(shù)列有關(guān)的不等式(1)證明此類問題時(shí)常根據(jù)已知的函數(shù)不等式,用關(guān)于正整數(shù)n的不等式替代函數(shù)不等式中的自變量.通過多次求和達(dá)到證明的目的.此類問題一般至少有兩問,已知的不等式常由第一問根據(jù)待證式的特征而得到.(2)已知函數(shù)式為指數(shù)不等式(或?qū)?shù)不等式),而待證不等式為與對(duì)數(shù)有關(guān)的不等式(或與指數(shù)有關(guān)的不等式),還要注意指、對(duì)數(shù)式的互化,如ex>x+1可化為ln(x+1)<x等.專項(xiàng)突破一單變量不等式的證明1.已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0.(1)當(dāng)SKIPIF1<0時(shí),求函數(shù)SKIPIF1<0的極值;(2)當(dāng)SKIPIF1<0時(shí),求證:SKIPIF1<0.2.已知函數(shù)SKIPIF1<0.(1)若SKIPIF1<0在SKIPIF1<0上有2個(gè)零點(diǎn),求a的取值范圍;(2)證明:SKIPIF1<0.3.已知函數(shù)SKIPIF1<0,SKIPIF1<0.(1)求曲線SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線方程;(2)證明:SKIPIF1<0.4.已知函數(shù)SKIPIF1<0.(1)若函數(shù)SKIPIF1<0在定義域內(nèi)為增函數(shù),求實(shí)數(shù)SKIPIF1<0的取值范圍;(2)若SKIPIF1<0且SKIPIF1<0,求證:SKIPIF1<0.5.已知函數(shù)SKIPIF1<0.(1)當(dāng)SKIPIF1<0時(shí),SKIPIF1<0,求實(shí)數(shù)SKIPIF1<0的取值范圍;(2)證明:SKIPIF1<0.6.已知函數(shù)SKIPIF1<0.(1)若SKIPIF1<0有兩個(gè)極值點(diǎn),求實(shí)數(shù)a的取值范圍;(2)當(dāng)SKIPIF1<0時(shí),證明:SKIPIF1<0.7.已知函數(shù)SKIPIF1<0的最小值為SKIPIF1<0.(1)求實(shí)數(shù)SKIPIF1<0的值;(2)求證:當(dāng)SKIPIF1<0時(shí),SKIPIF1<0.8.已知函數(shù)SKIPIF1<0.(1)討論函數(shù)SKIPIF1<0的單調(diào)性;(2)當(dāng)SKIPIF1<0時(shí),證明:SKIPIF1<0.9.已知函數(shù)SKIPIF1<0.(1)當(dāng)SKIPIF1<0時(shí),求SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線方程;(2)當(dāng)SKIPIF1<0時(shí),證明:SKIPIF1<0(其中SKIPIF1<0為自然對(duì)數(shù)的底數(shù)).10.已知函數(shù)SKIPIF1<0.(1)求SKIPIF1<0的單調(diào)區(qū)間;(2)證明:SKIPIF1<0.11.已知函數(shù)SKIPIF1<0,SKIPIF1<0.(1)討論函數(shù)SKIPIF1<0的單調(diào)性,并求函數(shù)SKIPIF1<0的極值;(2)證明:對(duì)任意SKIPIF1<0,都有SKIPIF1<0.12.已知函數(shù)SKIPIF1<0,SKIPIF1<0(1)討論函數(shù)SKIPIF1<0的單調(diào)性;(2)當(dāng)SKIPIF1<0時(shí),求證:SKIPIF1<0.13.已知函數(shù)SKIPIF1<0.(1)求曲線SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線方程;(2)設(shè)SKIPIF1<0,討論函數(shù)SKIPIF1<0在SKIPIF1<0上的單調(diào)性;(3)證明:對(duì)任意的SKIPIF1<0,有SKIPIF1<0.14.已知函數(shù)SKIPIF1<0.(1)討論函數(shù)SKIPIF1<0的單調(diào)性;(2)若SKIPIF1<0,證明:SKIPIF1<0.專項(xiàng)突破二雙變量不等式的證明1.已知函數(shù)SKIPIF1<0,(SKIPIF1<0).(1)若SKIPIF1<0存在兩個(gè)極值點(diǎn),求實(shí)數(shù)SKIPIF1<0的取值范圍;(2)若SKIPIF1<0,SKIPIF1<0為SKIPIF1<0的兩個(gè)極值點(diǎn),證明:SKIPIF1<0.2.已知函數(shù)SKIPIF1<0.(1)若SKIPIF1<0在SKIPIF1<0上為單調(diào)函數(shù),求實(shí)數(shù)a的取值范圍;(2)記SKIPIF1<0的兩個(gè)極值點(diǎn)為SKIPIF1<0,SKIPIF1<0,求證:SKIPIF1<0.3.設(shè)函數(shù)SKIPIF1<0(1)當(dāng)SKIPIF1<0時(shí),求SKIPIF1<0的單調(diào)區(qū)間;(2)任意正實(shí)數(shù)SKIPIF1<0,當(dāng)SKIPIF1<0時(shí),試判斷SKIPIF1<0與SKIPIF1<0的大小關(guān)系并證明4.記函數(shù)SKIPIF1<0,其導(dǎo)函數(shù)為SKIPIF1<0.(1)討論SKIPIF1<0的極值點(diǎn)個(gè)數(shù);(2)當(dāng)SKIPIF1<0時(shí),令SKIPIF1<0,若SKIPIF1<0是關(guān)于SKIPIF1<0的方程SKIPIF1<0的兩個(gè)相異的實(shí)數(shù)根,證明:SKIPIF1<0.5.已知函數(shù)SKIPIF1<0,且SKIPIF1<0.(1)求曲線SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線方程;(2)若函數(shù)SKIPIF1<0有三個(gè)極值點(diǎn)SKIPIF1<0,且SKIPIF1<0,求證:SKIPIF1<0.6.已知函數(shù)SKIPIF1<0(1)當(dāng)SKIPIF1<0時(shí),若對(duì)任意的SKIPIF1<0都有SKIPIF1<0求m的最大值(2)若函數(shù)SKIPIF1<0有且只有兩個(gè)不同的零點(diǎn)SKIPIF1<0求證SKIPIF1<07.已知函數(shù)SKIPIF1<0有兩個(gè)零點(diǎn).(1)求a的取值范圍;(2)設(shè)SKIPIF1<0是SKIPIF1<0的兩個(gè)零點(diǎn),證明:SKIPIF1<0.8.已知函數(shù)SKIPIF1<0.(1)若SKIPIF1<0,曲線SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線方程為SKIPIF1<0,求實(shí)數(shù)SKIPIF1<0的值;(2)若SKIPIF1<0,SKIPIF1<0是SKIPIF1<0的兩個(gè)極值點(diǎn),且SKIPIF1<0,證明:SKIPIF1<0.9.已知函數(shù)SKIPIF1<0,SKIPIF1<0.(1)求SKIPIF1<0的單調(diào)區(qū)間;(2)證明:SKIPIF1<0;(3)設(shè)a,b為正數(shù),且SKIPIF1<0,證明:SKIPIF1<0.10.已知函數(shù)SKIPIF1<0.(1)討論函數(shù)SKIPIF1<0的單調(diào)區(qū)間;(2)當(dāng)SKIPIF1<0時(shí),若SKIPIF1<0滿足SKIPIF1<0,求證:SKIPIF1<0.11.已知函數(shù)SKIPIF1<0.(1)求曲線SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線方程;(2)設(shè)方程SKIPIF1<0的兩個(gè)根分別為SKIPIF1<0,SKIPIF1<0,證明:SKIPIF1<0.12.已知實(shí)數(shù)SKIPIF1<0,設(shè)函數(shù)SKIPIF1<0.(1)當(dāng)SKIPIF1<0時(shí),求函數(shù)SKIPIF1<0的單調(diào)區(qū)間;(2)若函數(shù)SKIPIF1<0單調(diào)遞增,求a的最大值;(3)設(shè)SKIPIF1<0是SKIPIF1<0的兩個(gè)不同極值點(diǎn),SKIPIF1<0是SKIPIF1<0的最大零點(diǎn).證明:SKIPIF1<0.注:SKIPIF1<0是自然對(duì)數(shù)的底數(shù).13.已知函數(shù)SKIPIF1<0.(1)若直線SKIPIF1<0與SKIPIF1<0的圖像相切,且切點(diǎn)的橫坐標(biāo)為1,求實(shí)數(shù)m和b的值;(2)若函數(shù)SKIPIF1<0在SKIPIF1<0上存在兩個(gè)極值點(diǎn)SKIPIF1<0,且SKIPIF1<0,證明:SKIPIF1<0.14.已知函數(shù)SKIPIF1<0(1)求函數(shù)SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線的方程;(2)若SKIPIF1<0有兩個(gè)極值點(diǎn)m,n,證明:SKIPIF1<0.專項(xiàng)突破三證明與數(shù)列有關(guān)的不等式1.已知關(guān)于SKIPIF1<0的函數(shù)SKIPIF1<0(1)討論SKIPIF1<0的單調(diào)性;(2)證明:當(dāng)SKIPIF1<0時(shí),SKIPIF1<02.設(shè)函數(shù)SKIPIF1<0(1)求曲線SKIPIF1<0在SKIPIF1<0處的切線方程;(2)證明:當(dāng)SKIPIF1<0且SKIPIF1<0時(shí),SKIPIF1<0.3.已知函數(shù)SKIPIF1<0.(1)若函數(shù)SKIPIF1<0在SKIPIF1<0處取得極值,求實(shí)數(shù)SKIPIF1<0的值,并求函數(shù)SKIPIF1<0的極值;(2)①若當(dāng)SKIPIF1<0時(shí),SKIPIF1<0恒成立,求實(shí)數(shù)SKIPIF1<0的取值范圍;②證明:當(dāng)SKIPIF1<0時(shí),SKIPIF1<0.4.已知函數(shù)f(x)=lnx﹣ax+1(a∈R).(1)求函數(shù)f(x)在區(qū)間[SKIPIF1<0

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