系統(tǒng)工程期末大作業(yè)

試建立這些因素之間的解釋結(jié)構(gòu)模型。100011111000000011001000000101000110000101011100000000000001010000100110001001100001000000001000000001000000001000110111000111001011111111（2）因?yàn)橐蛩豍4和P5所在行元素完全相同，即為最大回路集，選取P4為代表因素，即得縮減可達(dá)矩陣：1100111000001000000000011010100000001001100000001000000000001000000000001000000000001000011011101101111011111101101011001（3）對(duì)縮減可達(dá)矩陣按每行元素為1的數(shù)目多少，由少到多將因素依次排列，可得排序后的縮減可達(dá)矩陣：10011000000000101000000001111111110011011011001111001101101001011001001000001000000001000000001000000001000000001（4）根據(jù)排序后的縮減可達(dá)矩陣，建立結(jié)構(gòu)模型如下：3189726（5）根據(jù)建立的結(jié)構(gòu)模型，可得解釋結(jié)構(gòu)模型：ACCC123C1131C1132C1/31/313判斷矩陣C－P1CPPP1123P1351P1/3132P1/51/313判斷矩陣C－P2CPPP2123P1231P1/2112P1/3113判斷矩陣C－P3CPPP3123P1571P1/5132P1/71/313試?yán)脤哟畏治龇?，給出該廠生產(chǎn)哪種商品為最佳支柱產(chǎn)品。（1）構(gòu)造判斷矩陣A-CC11C1C2C31.4421.4420.4810.4280.4280.1433.0073.0073.0051131/31/31λmax=3.006,C.I.=0.003,R.I.=0.58,C.R.=0.005<0.1滿足一致性檢驗(yàn)（2）構(gòu)造判斷矩陣C1-PC1P1P2P3P110.6370.2580.1053.0403.0403.0361/31/51/310.406λmax=3.039,C.I.=0.002,R.I.=0.58,C.R.=0.003<0.1滿足一致性檢驗(yàn)（3）構(gòu)造判斷矩陣C2-PC2P1P2P3P111.8170.7940.6930.5500.2400.2103.0183.0173.0201/21/311λmax=3.018,C.I.=0.009,R.I.=0.58,C.R.=0.016<0.1滿足一致性檢驗(yàn)（4）構(gòu)造判斷矩陣C3-PC3P1P2P3P113.2710.7313.0630.8430.1883.0640.3620.0813.0671/51/71/31λmax=3.065,C.I.=0.0325,R.I.=0.58,C.R.=0.056<0.1滿足一致性檢驗(yàn)（5）層次總排序A-Pii=1jj0.4280.6370.2580.1050.4280.5500.2400.2100.1430.7310.1880.081P1P2P30.8220.2400.137層次總排序的一致性檢驗(yàn)C.I.=0.428×0.02+0.428×0.009+0.143×0.0325=0.017R.I.=0.428×0.58+0.428×0.58+0.143×0.58=0.58C.R.=C.I./R.I.=0.017/0.58=0.029<0.1滿足一致性檢驗(yàn)對(duì)于該工廠按照三條準(zhǔn)則：經(jīng)濟(jì)效益、社會(huì)效益、技術(shù)可行性，對(duì)所考慮的3種產(chǎn)品，經(jīng)分析計(jì)算得到優(yōu)劣排序?yàn)椋篜1